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Veronica Parsons 2015
VCE Biology TSFX REVISION LECTURE
UNIT 3 Part 1
Biomolecules
CellsBiochemistry
Coordination & Regulation
Pathogens
Immune System
Area of Study 1
Area of Study 2
Unit 3: Signatures of Life
v
Revision‐What Can you Do?
• Lecture today-Listen!• Past VCAA Exams from
Website Going Backwards from 2014 including Sample. Keep Notebook Close by divided into 4 sections for each area of Study-write down theory from questions you are getting wrong
• Read over TSFX notes with highlighter regularly.
• Study Groups-Make Kahoots
• Teach someone!
Exam Horror Stories
Exam Horror Stories
Exam Horror Stories
2014 Exam Horror Stories
Exam Horror Stories
Drawing or Labelling a Plasma Membrane
AB
C
D
Exam Horror Stories
What to Learn from these Horrors???
• Avoid one word answers for one mark questions
• Use the word ‘whereas’ in comparative statements
• Use the word ‘so’ twice in an explain question.
• Draw simple, big, clearly labeled diagrams
• Use data to support your answers• Read questions very carefully-
look for distractors!• One dot point per mark + one for
luck• Ask yourself..”what is the
intention of the question”• Be positive-use the exam as an
opportunity to show them how much you know and how hard you have worked.
Practice Exam QuestionWhich of the following combination of polysaccharides and function is correct:
a. Chitin: Structural component of cell membranes.b. Cellulose: Energy storec. Starch: structural component of plant cell wallsd. Glycogen: Store of energy.
Read each word very carefully!
Veronica Parsons 2013
If a cell could talk??? I exist in this watery world because I have an
insoluble selectively permeable membrane I need to receive inputs, remove wastes & export
products I need to make essential biomacromolecules (by
condensation) You think you have a management problem!
(talking about biology teachers). I need to control & regulate a host of simultaneous reactions that are energy dependent. Provide a constant supply of reactants and export a constant supply of products.
I need to know everything. I need to receive signals and respond.
I need to divide, copy accurately and pass on my information manual to my daughter cells.
Most of the time I get it right, but sometimes things go wrong.
https://www.youtube.com/watch?v=oqGuJhOeMek
The cell is a bag of molecules
Pg 15 Water‐a unique molecule
• Water is the most abundant compound in our
bodies
• Water is the most common solvent (dissolves solid,
liquid, or gaseous solutes, resulting in a solution) in
everyday life.
• Substances that dissolve readily in water are
called hydrophilic or polar.
“Like dissolves Like”“Polar dissolves Polar”“Non Polar dissolves Non Polar”
Pg 18 Biological Hierarchy
Pg 18 Organic vsInorganic
organicmeans that a molecule has a carbon backbone, with some hydrogensthrown in for good measure. Living creatures are made of various kinds of organic compounds. Eg: Carbohydrates, Lipids,Proteins, Nucleic Acids, Coenzymes eg ATP
Inorganicmolecules are composed of other elements. They can contain hydrogen or carbon, but if they have both, they are organic.Eg, H2O, CO2, O2, Cofactors
Pg 19 Organic Molecules
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Organic Molecule
Elements Monomer or Subunit
Polymer orlarger unit
Examples
Carbohydrate C H O MonosaccharideGlucose, Ribose
Polysaccharides
Eg Starch, Glycogen, Cellulose, Chitin
ProteiNS C H O N (S) Amino Acid (20)
PolypeptidesProteins
Enzymes, Hormones, AntibodiesNeurotransmitters
Lipid C H O (P) Fatty Acid Phospholipids, Cholesterol. Tryglycerides.Hormones
Nucleic Acid CHONP Nucleotide Nucleic Acids DNA, mtDNA, tRANA, rRNA, mRNA
Diagrammatic Representations of Molecules
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VCAA 2006
Veronica Parsons 2015
Pg 20 Synthesis of biomacromoleculesthrough the Condensation Reaction
• Making Polymers is Wet Work!
• Condensation (water releasing)
makes bonds.
• Loss of OH from one monomer
and H from another results in
overall loss of one water
molecule in forming the bond
• Anabolic‐building up reactions eg
protein synthesis
Veronica Parsons 2015
FAQ’s
Veronica Parsons 2015
• Students are expected to recognise diagrammatic representations of glucose, identify glucose as a monomer of polysaccharides and other carbohydrates, and understand the mechanism of the condensation reaction (that is, a water molecule is lost when a monomer is added to another monomer or a polysaccharide structure).
Pg 21 Glucose
Glucose is created in the process of photosynthesis and is used in the process of cellular respiration.
Polysaccharides
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Pg 26 FAQ’s
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• For lipids, students are expected to recognisediagrammatic representations of fats (triglycerides) and phospholipids, and identify the role of phospholipids in the cell membrane. Students should understand that the formation of triglycerides involves condensation reactions. Although the role of cholesterol in the plasma membrane should be understood, the specific chemical structure of cholesterol is not required.
LipidsTriglycerides Phospholipids
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• Fats & Oils-saturated fats & unsaturated fats
• Triglycerides have three fatty acid molecules attached to a single glycerol molecule.
• Formation involves Condensation Reactions.
• Functions include o insulation layers which resist heat loss or gaino Energy storageo Buoyancy for aquatic animals.
Structural backbone of membranes.Phospholipids have two fatty acids attached to a glycerol.
Pg 26‐Functions of Lipids‐SHIP
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Function of Lipids• Lipids can serve many
functions within the cell, including:
• Storage of energy for long-term use (e.g. triglycerides)
• Hormonal roles (e.g. steroids such as estrogen and testosterone)
• Insulation (retention of thermal energy)
• Protection of internal organs (e.g. triglycerides and waxes)
• Structural components (e.g. phospholipids, cholesterol)
•
Pg 31 Phospholipids
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• Consists of a phosphate group (hydrophillic) and 2 fatty acid tails (hydrophobic).
• Within a membrane, the phosphate faces aqueous areas both inside cell (cytosol) and outside cell (extracellular fluid).
• The fatty acid tails are buried in the middle.
• The hydrophobic nature of the tails ensure that only lipid soluble (lipophillic, hydrophobic) or non polar substances (eg steroid hormones, alcohol, chloroform etc) can directly diffuse through cell membranes.
Role of lipids in the plasma membrane
• Lipids move laterally and can change place in the one layer =dynamic nature
• Can fuse with vesicles for endocytosis and exocytosis.
• Kinks in Fatty Acid tails enhance fluidity
• Cholesterol reduces fluidity by reducing phospholipid movement.
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Pg 35 FAQ’s
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• Students are expected to understand that polypeptides and proteins are polymers of amino acids, formed
through condensation reactions. They are also expected to understand that the primary structure of a
polypeptide or protein is the sequence of amino acids that form the polypeptide or protein, and that the way
that polypeptides and proteins are folded, coiled or pleated can be described by secondary (within the chain)
and tertiary (overall chain shape) structures, and that those proteins made up of two or more polypeptide chains
may be described by a quaternary structure. Students are expected to identify α-helices and β-pleated sheets as
being the most common secondary structures. They are expected to understand that the shape of a protein
determines its properties and that protein denaturation through changes in temperature, changes in pH or
reaction with various chemicals may lead to a loss of biological function. Classifications of, and differences
between, different types of proteins such as globular and fibrous proteins are not required.
Pg 35 Amino AcidsAn amino acid is a relatively small molecule with characteristic groups of atoms that determine its chemical behaviour.
The structural formula of an amino acid is shown at the end of the animation below. The R group is the only part that differs between the 20 amino acids.
O
RO
HH
HH N C CH3C
CH3
C HCH
H H
GlycineAlanineValineCysteinePhenylalanine
HH
CS
H HCH H
Amino Acid
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Pg 38‐40 Levels of Protein Structure
• 4 different levels of organization:
• Primary Structure: The order of amino acids
in the molecule.
• Secondary Structure (within the chain)Local
3D folding structure formed by hydrogen
bonds.
• Tertiary Structure: T(overall chain shape) he
total folding of the protein, held together
by hydrogen or ionic bonds.
• Quaternary Structure: Is a structure
consisting of two or more polypeptide
chains.
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Pg 42 Functions of Proteins (HITSME)
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• Proteins are very diverse and serve a number of different roles within the cell, including:
• Structure: Support for body tissue (e.g. collagen, elastin, keratin)
• Hormones: Regulation of blood glucose (e.g. insulin, glucagon)
• Immunity: Bind antigens (e.g. antibodies / immunoglobulins)
• Transport: Oxygen transport (e.g. haemoglobin, myoglobin)
• Movement: Muscle contraction (e.g. actin / myosin, troponin / tropomyosin)
• Enzymes: Speeding up metabolic reactions (e.g. catalase, lipase, pepsin)
• Amino acids can be joined together in a condensation reaction to form a dipeptide and water
• This results in the formation of a peptide bond, and for this reason long chains of covalently bonded amino acids are called polypeptides
Protein Structure FunctionEnzymes Specifically shaped
active site that is complementary to a specific substrate
Catalyse chemical reactions
Channel Proteins Specific shape that allows a particular chemical (often hydrophilic) to move through
Transport
Receptors Specific shape that allows a specific signalling molecule to bind which will lead to a cellular response
Initiate signal transduction
Antibodies Y shaped molecule with 2 complementary antigen binding
Deactivate a pathogen
Hormones Specific shape that is complementary to a
Initiate cellular responseVeronica Parsons 2015
Pg 42How does Structure relates to Protein Function
Pg 43 Nucleic Acids(Polynucleotides)
There are two kinds of nucleic acid:
• deoxyribonucleic acid (DNA) is
located in chromosomes in the
nucleus of eukaryotic cells and in
cytosol of prokaryotic cells.
• It it also found in the
mitochondria and chloroplasts
• ribonucleic acid (RNA) –there
are 3 types-ribosomal, messenger
and transfer.
• Nucleic Acids are mostly
information storage molecules.Veronica Parsons 2015
FAQ’s
Veronica Parsons 2015
• Students are expected to recognise the monomers of DNA and RNA and identify complementary base pairs.
Monomer of a Nucleotide
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• Nucleotides are the building blocks of DNA &RNA and contain a phosphate component (not phosphorus), a 5-carbon sugar component (not sugar) and a nitrogenous base component (not base).
DNA Template Strand
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• The DNA Strand has the sequence
5’ A-G-C-T 3’What is the complementary mRNA strand
Pg 48 DNA vs RNA SummaryDNA RNA
No. of Nucleotide Strands
2 1
Sugar Deoxyribose RiboseBases Adenine
CytosineGuanineThymine
AdenineCytosineGuaninUracil
Functional Location Nucleus (Eukaryotes)Cytoplasm (Prokaryotes)
Nucleus & Ribosome (Eukaryote)Cytoplasm & Ribosome (prokaryote)
Do task pg 49 +pg 50Stop Codons: UGA UAA UAG
Pg 57 Proteomics
Veronica Parsons 2015
• An emerging branch of biology which revolves around the structure and function of proteins. This involves a thorough study of the proteome ( all proteins expressed within a cell for the duration of the life of the cell) and is very closely related to the study of the genome ( the entire DNA content of the cell).
• The genome carries genes (sections of DNA) that provide the blueprint for protein synthesis. Certain sections of the DNA are transcribed into RNA and then translated into a protein within the cell so that the specific function of the cell can occur.
Why did the phospholipid scream?
• …because it saw the cytoskeleton
The Cell Theory pg 61• All living things are
composed of cells and/or
their products
• All cells come from pre-
existing cells.
• The cell is the basic unit
of life.
Veronica Parsons 2015
Pg 82 STRUCTURE =FUNCTION
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Cell Ultrastructures‐Structures Function
Veronica Parsons 2014
• the role played by organelles in the export of proteins
• Ribosomes- Free (intracellular protein synthesis)
• Rough endoplasmic reticulum- Transport of extracellular proteins
• Golgi apparatus –packaging of extracellular proteins into vesicles
• Mitochondria-ATP for endocytosis, Active transport or exocytosis
•
Absorptive Cell Kidney
Endocrine Pancreatic Cell
End of Part 1Enjoy a 10 minute break!
Veronica Parsons 2014
• the structure and function of the plasma membrane and the movement of substances across it:– the fluid‐mosaic model of a plasma membrane– the packaging, transport, import and export of biomacromolecules (specifically proteins)– the role played by organelles including ribosomes, endoplasmic reticulum, Golgi apparatus and associated vesicles in the export of proteins
Pg 89 Fluid Mosaic Model of Plasma Membrane
Veronica Parsons 2014
VCAA 2006 EXAM
VCAA 2012
Veronica Parsons 2013
VCAA 2012
Veronica Parsons 2013
VCAA 2011 (2 Marks)
Veronica Parsons 2013
Answer
Veronica Parsons 2013
FAQ’s
Veronica Parsons 2014
• Diffusion, osmosis, active transport, facilitated diffusion, endocytosis and exocytosis are required in Unit 3. Although simple diffusion, active transport and facilitated diffusion are introduced in Unit 1, they are also relevant in Unit 3, in particular with respect to protein transport, movement of neurotransmitters across a synapse and the movement of other substances important in cellular processes such as photosynthesis and cellular respiration. Exocytosis and endocytosis are also important in both Units 3 and 4 as they are relevant to events including the release of signalling molecules, secretion of antibodies from plasma cells and the phagocyticity of macrophages and neutrophils.
Movement Across Plasma Membrane
• Diffusion • Osmosis• Facilitated
Diffusion• Active
Transport• Vesicular
TransportVeronica Parsons 2014
Osmosis Osmosis
• Osmosis is the passive movement of water molecules from a regions of lower solute concentration to a region of higher solute concentration across a partially permeable membrane until equilibrium is reached.
• Passive (does not require energy).
Pg 92 Movement Across the Plasma Membrane
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Pg 94 Osmosis in Animal and Plant Cells
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Porins
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Plasma Membrane
Active Transport Active Transport
• DOES require energy
• Movement of substances is AGAINST THE CONCENTRATION GRADIENT:
from low high concentration
• This type of transport will only occur in the presence of ATP
• eg. Na+/K+ Pump
Movement Across the Plasma Membrane
Veronica Parsons 2014
Vesicular Transport Vesicular Transport
• Vesicular transport is transport of substances that
requires the use of a vesicle
• It requires ENERGY
• Vesicles are used to transport substances both within
the cell (intracellular) and out of the cell
(extracellular)
• Possible because:
1) Membrane has some fluidity
2) Small amounts can be added or removed without
tearing the membrane (endo‐ & exo‐ cytosis)
3) Membranes of all organisms are the same
Movement Across the Plasma Membrane
Veronica Parsons 2014
Exam Question• How does a monosaccharide enter an epithelial
cell?
Acceptable Answers
Facilitated DiffusionActive TransportProtein Channels
Protein Carrier Molecules
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Veronica Parsons 2014
• the nature of biochemical processes within cells:– catabolic and anabolic reactions in terms of reactions that release or require energy
– the role of enzymes as protein catalysts, their mode of action and the inhibition of
the action of enzymes both naturally and by rational drug design
– the role of ATP and ADP in energy transformation
– requirements for photosynthesis – excluding differences between CAM, C3 and C4
plants
– including: the structure and function of the chloroplast; the main inputs and outputs
of the light dependent and light independent stages
– requirements for aerobic and anaerobic cellular respiration: the location, and main
inputs and outputs, of glycolysis; the structure of the mitochondrion and its function
in aerobic cellular respiration including main inputs and outputs of the Krebs Cycle
and the electron transport chain
Book 2 Pg 3 CATS EX SPIRE
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• Catabolic Processes are Exergonic (breakdown)
• Example Cellular Respiration
• Hydrolysis reactions are also catabolic.
Role of ATP & ADP in Energy Transformations
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Enzymes
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• Enzymes are large protein molecules responsible for the thousands of metabolic processes that sustain life. They are highly selective catalysts, greatly accelerating both the rate and specificity of metabolic reactions, from the digestion of food to the synthesis of DNA
• Like all catalysts, enzymes work by lowering the activation energy for a reaction, thus dramatically increasing the rate of the reaction.
• As a result, products are formed faster and reactions reach their equilibrium state more rapidly.
• Enzymes are not consumed by the reactions they catalyze, nor do they alter the equilibrium of these reactions. However, enzymes do differ from most other catalysts in that they are highly specific for their substrates.
Pg 5‐ Enzymes Lower Activation Energy
Activation Energy
Q9 p 16
MOVIE
Pg 8 Competitive Inhibition
Veronica Parsons 2014
• Similar shape to substrate so compete for the active site & prevent the formation of Enzyme-Substrate Complex
• They fit into the Active Site, but remain unreacted since they have a different structure to the substrate but less substrate molecules can bind to the enzymes so the reaction rate is decreased.
• Competitive Inhibition is usually temporary, and the Inhibitor eventually leavesthe enzyme.
Non Competitive Inhibition
Veronica Parsons 2014
• Prevent formation of Enzyme-Product
Complexes. So they prevent the substrate
from reacting to form product.
• Usually, Non-competitive Inhibitors bind to a
site other than the Active Site, called an
Allosteric Site.
• Doing so distorts the 3D Tertiary structure of
the enzyme, such that it can no longer
catalyse a reaction.
• Many Non-competitive Inhibitors are
irreversible and permanent, and denature the
Rational Drug Design
Veronica Parsons 2015
• A focussed approach using information about structure of a drug receptor or it’s ligand to identify or create candidate drugs.
• *Ligand-substances that are able to bind to a biomolecule such as substrates, inhibitors, neurotransmitters
Relenza
Veronica Parsons 2015
End of Part 2Enjoy a 20 minute break
2011 Question
2011 Answer
The ChloroplastThe chloroplast is enclosed by an envelope consisting of two membranes separated by a very narrow intermembrane space.
Membranes also divide the interior of the chloroplast into compartments:
flattened sacs called thylakoids, which in places are stacked into structures called grana.
the stroma (fluid) outside the thylakoids.
They contain DNA and also ribosomes, which are used to synthesize some of the proteins within the chloroplast.
Stroma, the liquid interior of the chloroplast
Thylakoid sac (disc)
Thylakoid membranes
Grana, are stacks of thylakoid membranes containing chlorophyll
Outer membrane
Inner membrane
Veronica Parsons 2014
Light Dependant Phase
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• INPUTS: Light, ADP +Pi
12H2O (Water), NADP+,
• OUTPUTS: NADPH, 6O2, ATP
• Inputs=LAWN• Outputs= NOA• *NADP= nicotinamide
adenine dinucleotide phosphate
Light Independent Phase
Veronica Parsons 2015
• INPUTS: CO2• ATP• NADPH
• OUTPUTS: 6H2O Water• ADP +Pi• NADP+• Gucose
• CAN WANG
Veronica Parsons 2015
Biochemical Processes
Photosynthesis
Stage Site Inputs Outputs ProcessLight Dependent Eukaryote: Grana of
ChloroplastProkaryote: Free Floating Chlorophyll
Light12 H2ONADP+
ADP + Pi
*6O2
NADPHATP
Light energy absorbed by chlorophyll
Water molecules split to form H+
ions + O2 gas O2 gas released via stomata Excited electrons flow through an
electron transport chain to provide energy for ATP synthesis
Unloaded electron acceptor molecules NADP+ accept H+ ions to form NADPH
Light Independent Eukaryote: Stroma of ChloroplastProkaryote: Cytosol
6CO2
NADPHATP
C6H12O6
6 H2ONADP+
ADP +Pi
In the Calvin Cycle, 6CO2 + H+ ions (from NADPH) used to synthesise sugars. This is called carbon fixation.
This is catalysed by tshe enzyme RuBisCO
Energy provided by the ATP produced in LD reaction.
GLYCOLYSIS (NAG NAP)
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• INPUTS: NAD+• ADP +Pi• Glucose
• OUTPUTS: 2NADH • 2ATP • 2Pyruvate
Anaerobic Respiration
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Veronica Parsons 2015
Anaerobic Respiration
Glycolysis Cytosol C6H12O6
2NAD+
4ADP + Pi
2 Pyruvate2NADH +H ions2ATP
Glucose molecule is broken down to 2 pyruvate molecules
Hydrogen ions are removed from glucose and used to form loaded acceptor molecules NADH.
2 molecules of ATP are also produced
Anaerobic (Fermentation)(Plants&Yeast)
Cytosol Pyruvate is further broken down into ethanol & CO2
Anaerobic(Fermentation) (Animals)
Cytosol Pyruvate is further broken down into Lactic acid & Water
Veronica Parsons 2015
Aerobic RespirationStage Site Inputs Outputs Process
Glycolysis Cytosol C6H12O6
2NAD+
4ADP + Pi
2 Pyruvate2NADH +H ions2ATP
Glucose molecule is broken down to 2 pyruvate molecules
Hydrogen ions are removed from glucose and used to form loaded acceptor molecules NADH.
2 molecules of ATP are also producedKreb’s Cycle (Citric Acid Cycle)
Eukaryote: Matrix of MitochondriaProkaryote: Cytosol
2 Pyruvate6NAD+
2FAD2ADP + Pi
4CO2
6NADH +H ions2FADH2
2ATP
Pyruvate is converted to acetyl CoA and 1 Co2molecule is released
Acetyl CoA enters Krebs Cycle and another 2 Co2 are released for each pyruvate.
The hydrogen ions are released from cycle and used to form NADH & FADH2
2 molecules ATP produced.
Electron Transport Eukaryote: Cristae of MitochondriaProkaryote: Cytosol
OxygenNADH +H ionsFADH2
32(34) ADP + Pi
6 H2ONAD+
FAD32(34)ATP
NADH & FADH2 come to cristae to transfer electrons from one cytochrome to another releasing ATP in the process. Oxygen is the final electron acceptor forming water
Krebs Cycle
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• INPUTS: NAD+• 2 ADP+Pi• Pyruvate• FAD• NAPS are FADS ?
• OUTPUTS: 6CO2• 2ATP• NADH• FADH2
Aerobic Respiration; Electron Transport
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• INPUTS: O2• FADH2• 32-34 ADP+Pi• NADH
• OUTPUTS: FAD• 32-34 ATP• Water• NAD
2010 Metabolism
Answer
VCAA 2006 EXAM
Summary Experimental Design
Year Topic Marks Command Terms2006 Designer Drugs 3 Design
2007 Enzymes 3 Outline ExperimentExplain Results
2008 Disease 5 State hypothesisOutline ExperimentDescribe Results
2009 Signalling Molecules (Pheromones)
4 Outline ExperimentDescribe Results
2010 Metabolism (Energy) 3 State hypothesisOutline ExperimentDescribe Results
2006 Experimental Design• Design an experiment, using
mice, to test the
effectiveness of the (anti‐
viral) drug you have
designed.
(3 Marks)
Examiner Report‐Common Errors
• Selecting only two mice without referring to repetition of the experiment;
• Not mentioning the similarity of the mice and/or environment;
• Injecting mice with the virus and then waiting days or weeks before the
drug was used;
• Administering the drug first and then exposing the mice to the virus days
or weeks later;
• General statements about comparing the results, without any reference to
what result would indicate effectiveness of the drug.
Some Guys Prefer IndiViduals That Really Rock pg 10‐14
• Sample‐eg Two large groups of identical members of the sample kept in
the same environmental conditions . State a specific number (of reasonable
magnitude) in each group, instead of simply describing a ‘large’ group or
replication of the experiment.
Group_ Divide the sample into two groups of equal size‐One is the
experimental Group and One is the Control Group.I
• Pretest‐ infection of both groups with the virus against which the drug has been designed.
• Independent Variable‐One of the groups then needed to receive no further treatment (the control group), the other group (the trial group)
receives the drug under investigation
• Time after a few days, each of the groups needs to Examined ‐the number of mice that have developed the viral disease in each group
counted.
• Results‐ If the number of mice in the trial group is significantly less than
the number in the control group, the drug has been effective.
• Repeat‐experiment a number of times
S Sample
G Allocate to 2 Groups (Experimental group and Control Group)
P Pretreatment
IV State the Independe4nt Variable
T Time
R Results
R Repeat
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2007 Experimental DesignA student predicted that if a temperature graph was
prepared for carrot catalase activity, the optimal
temperature would be expected to be much lower
than that shown by catalase from humans.
WHY????Describe (or outline) an experiment you would
carry out with pieces of carrot to test the accuracy
of the prediction. Hydrogen peroxide is available as
a 3% in water solution.
Explain fully what results would support or negate
the student.s prediction.
(3 marks)
Veronica Parsons 2015
Examiner’s Report• The use of at least two groups of identical pieces of carrot, placed at various temperatures (for
example, 16°C and 37°C) in the same concentration of hydrogen peroxide. A specific number of
carrot pieces could have been given (for example, 10). Students who mentioned the variable and
other factors which were controlled adequately demonstrated their understanding of the
experimental design and were awarded the first mark.
• For the second mark, students needed to discuss how catalase activity would have been measured.
For example, collecting the gas to measure the production of oxygen gas, or observing the bubbles
being produced.
• The third mark was awarded for a discussion of the expected results and a conclusion based on the
student’s prediction. For example, more oxygen gas produced at 16°C compared to 37°C would
support the prediction
Veronica Parsons 2015
2008 Experimental DesignThe human hormone vitamin D is found in high levels in some
immunological tissues. A scientist predicted
that a defi ciency of vitamin D may play a role in the
development of rheumatoid arthritis and hence treatment
with vitamin D tablets may reduce development of the
disease. The scientist decided to test this idea by using a
strain of laboratory mice that normally developed
rheumatoid arthritis.
Design an experiment to test the scientist’s prediction.
In your answer you should
state the hypothesis that you are testing
outline the experimental procedure that you follow
describe results that would support your hypothesis.
(5 Marks)
Veronica Parsons 2015
Examiner’s ReportHypothesis
That treatment with Vitamin D reduces the chance of mice developing
rheumatoid arthritis
Experimental Design
Use two large groups (for example, 20) of similar mice which normally
develop rheumatoid arthritis.
Treat the experimental group with Vitamin D. The other group, the Control
group, are given a placebo and do not receive Vitamin D.
Keep all other factors constant, such as diet, space, water and
temperature.
Results
For the hypothesis to be supported, fewer mice that are given Vitamin D should
develop rheumatoid arthritis than those in the Control group.
Veronica Parsons 2015
2009 Experimental DesignThe beet caterpillar is an insect pest of the tomato plant.
When a beet caterpillar starts to eat a tomato plant,
the plant responds by producing a chemical known as
jasmonic acid. Jasmonic acid and its derivatives have a
variety of odours.
Some scientists have suggested that these odours attract
wasps to the caterpillar‐affected plants.
i. Outline an experiment you would carry out to test this
hypothesis.
ii. Describe the results that would support the hypothesis.
(4 marks)
Veronica Parsons 2015
Examiner’s Report• Take two groups of tomato plants that are the same age type and state of
health. One group is affected with beet caterpillars, the other is
unaffected.
• Both groups are kept in the same environment (for example, the same
temperature and water availability).
• Wasps are released and their activity is observed.
• Large numbers of plants are used or the experiment is repeated many
times.
Veronica Parsons 2015
2010 Experimental DesignA pet food company has made two different types of food pellets,
one hard and the other soft. Each kind of pellet has the same
energy content. The company intends to test the pellets on a group
of adult mice.
You are provided with
• many adult mice. Each mouse is genetically identical and of the same
weight
• two types of pellets, one hard and one soft.
Outline an experiment that would allow you to determine if the
hardness of the food pellets affects the balance between energy
intake and energy expenditure.
In your answer you should
• state the hypothesis that you are testing
• outline the experimental procedure
• describe the results that would support or negate your hypothesis.
(3 Marks)
Veronica Parsons 2015
Examiner’s Report• Hypothesis: That the mice fed hard pellets will weigh more than mice that are fed soft pellets
• Experimental procedure: Two groups of mice: one group fed hard pellets and the other soft,
and all other variables controlled
• Results: Mice fed hard pellets weighed more than mice fed soft pellets
• Students did not need to state the features of the mice as these were given in the stem of the
question; however, they needed to identify a factor which should have been controlled, for
example, water availability.
• The results needed to relate directly to the hypothesis. Measuring weight was by far the most
feasible method; however, measuring the activity of each group was also considered a suitable
measure in this case.
Veronica Parsons 2015
Look for Patterns and Make Acronyms
• STARR (Sample-Treatment-All Factors Same-Results-Repeat)• RUDD(Rapid Burial-Undisturbed-Decomposer Free-Downward Pressure)• BADFEW(Biochemistry-Anatomy-Distribution-Fossils-Embryology-Witness)• IPMAT (Stages of Mitosis)• UGA UAA UAG (Stop Codons)• COD (Cross with homozygous Recessive-Observe Offspring-Decision)• VSSI (Variation-Struggle-Survival of Fittest-Inheritance)• VSSI with a B (Barrier)• GIFTS (Gene-Insert-From-Transform-Select)• Crocs Are Never Fine- (CO2-ATP-NADH-FADH2)• SHIP- (Storage-Hormones-Insulation-Protection-Structure)• HITSME ( Hormone-Structure-Immunity-Transport-Movement-Enzymes)• CATSEXSPIRE (Catabolic-Exergonic=Respiration)• PRIMATES• COAL (Complement Proteins-Chemotaxis, oponise, Agglutinate, Lysis)
Psychic Predictions• Dihybrid test cross
linked vs unlinked• Describe PCR• Speciation• GMO Mosquitos• Tassie Devils-Founder
Effects• Out of Africa vs
Multiregional.
Veronica Parsons 2015
• Signal Transduction of Lipid Based (Hydrophobic)vs Protein Based (Hydrophillic)
• Explain Active Transport• Cell Mediated-T Cells-
draw one• Explain how T Cells
protect against pathogens or T cells vaccination
• Transcription• Autosomal Dominant
Pedigree