Tutormansor Wordpress Com Latihan Matematik Tingkatan 4 05 Straight Line Answer

5/22/2018 Tutormansor Wordpress Com Latihan Matematik Tingkatan 4 05 Straight Line Answer

1/17

https://tutormansor.wordpress.com/

ANSWER /JAWAPANCHAPTER 05THE STRAIGHT LINE

(MATHEMATICS FORM 4)BAB 05GARIS LURUS

(MATEMATIK TINGKATAN 4)

HAK CIPTA TERPELIHARA MAY 2013


1

Latihan Matematik Tingkatan 4

Exercise Mathemtics Form 4

Bab 05THE STRAIGHT LINE

Chapter 05 GARIS LURUS

JAWAPAN / ANSWER

Question:http://goo.gl/Ny39Z

EXERCISE 1

1. _(a)y-intercept /pintasan-y= 1(b)Gradient / Kecerunan

Select two points along the straight line /Pilih dua titik sepanjang garis lurus.

(0,1)and (1,1)

=

=

1 1

1 0 = 2

2. _(a)Gradient PQ

(0, 3) (5,18)

=18 35 0 = 3

(b) = 3 = + = 3 + 3
https://tutormansor.wordpress.com/https://tutormansor.wordpress.com/https://tutormansor.wordpress.com/https://tutormansor.wordpress.com/http://goo.gl/Ny39Zhttp://goo.gl/Ny39Zhttp://goo.gl/Ny39Zhttps://tutormansor.wordpress.com/https://tutormansor.wordpress.com/


2/17







2

3. = + 9

Gradient, =

4. (2,6) (0, ) = 1

1 =

(6)0 (2)

=

62

2 = 6 = 8

(0,8)

5. = + 10 = + 8100 = + 64 = 36 = 6

= 6

6. Change first into gradient form / Tukar dulu kepada bentuk kecerunan.2 + 6 = 136 = 2 + 13 =

26

+136

=

13

+136

Gradient / Kecerunan, =
https://tutormansor.wordpress.com/https://tutormansor.wordpress.com/https://tutormansor.wordpress.com/https://tutormansor.wordpress.com/https://tutormansor.wordpress.com/https://tutormansor.wordpress.com/


3/17







3

7. At -intercept, the value ofy= 0. / Pada pintasan-x, nilai = 0.4 2(0)= 12

4 = 12 = 3

8. Gradient /Kecerunan, =

= 312

=

14

9. (0, 4) =

44

= 1

= + 4

10._(a)(0, 4)(b) = 6


4/17







4

EXERCISE 2

1. Gradient = (, 0) Q(3, 5) =

53

35=0 5 3 3 = 5

53

=

253

=

253

+ 3 =

34

3

2. _(a)Put in the equation . /Letak dalam persamaan RS.

(4, )2 = 4 62 = 2

= 1

(b)(0, 5) (12,3) =

3 51 2 0

=

212

=

16


5/17







5

3. _(a)Gradient /Kecerunan =

= 2

(b)= = + 1 = 2(6) +

= 12 + = 12 + 1

= 11

Equation / Persamaan , = 2 11

4. _(a)(2,12) = 3

12 = 3(2) + = 6 +

= 12 6= 6

Equation / Persamaan = = 3 + 6

(b)= = 3 , (2, 0)

3 =

=

2

= 6

(,)


6/17







6

5. (, )=(3,9), (, )= (0, )(a)Gradient /Kecerunan,

=

1 = 90 (3)=

93

3 = 9

3 + 9 = =

(b)Formula for straight lines equation /Formula untuk persamaan garis lurus. = +

= 1, = = = 6

= + @ = +

6. ABCD is a parallelogram, so the gradient = and = .ABCD ialah satu segiempat selari, jadi kecerunan = dan = .

=23 + 4,=

23

(a)At x intercept, the value of = 0. , = 0

=23

+ 40 =

23

+ 42

3 = 4

= (x intercept, )

(b)Find the value of point A first,Cari nilai titik A dulu.

(0, ), =23

+ 4, (0, 4) (6, 0)

Gradient / Kecerunan

= =

46

=

23


7/17







7

7. Straight line PQ is parallel to straight line RSGaris lurus PQ selari dengan garis lurus RS.

(a)Gradient RS = Gradient PQKecerunan RS = Kecerunan PQ

(, )=(2, 0),(, )=(4, 8)

= =

=

8 04 2

=

8

2

=

(b)Point R / Titik R (,0)(, )=(10,2)=

0

4 =

2 01 0

4(1 0 )= 2

40 4 = 240 2 = 4

38 = 4 =

384

=

@ .

(x-intercept / pintasan-x)

8. =

, = 9

(a) = 9 =

13

=

13

(9)= 3, (3, 0)

(0, 9), (, )

(b)Gradient / Kecerunan(, )=(6, 9),

(, )=(3, 0)=

=

9 06 3

=

9

3

=


8/17







8

9. Straight line CD is parallel straight line EF / Garis lurus CD adalah selari dengan EFiEquation / Persamaan = 3 + 5

(a)x-intercept / x-intercept = 3 + 50 = 3 + 5 =

( )

(b)Gradient CD = Gradient EF (1,4), = 3 = +

4 = 3(1) + 4 = 3 +

= 4 + 3= 1

=

10.EFGH is a parallelogram, GradientEFis .

= , (, 0)=

5

2

=5 0

8

5(8 )= 5(2)40 5 = 1040 10 = 5

30 = 5 =

305

= 6

(,)


9/17







9

DIAGNOSTIC TEST

1. Gradient / Kecerunan MN =

=

6

8

=

2. 2 + 3 = 0, atx-intercept, the value of = 0/ pada pintasan-x, nilai = 0. 2(0) + 3 = 0

= ,

3. (0, 6)(2, 0)Gradient / KecerunanBC

= 62

= ,

4. (, )=(2, 8), (, )= (8, 2) =

=2 (8)8 (2)

=1010

= 1

= + 2 = 1(8) + = 2 8

= 6 = ,


10/17







10

5. (8, ) =

34

=

34

(8)= ,

6. Passing through (3,8)and parallel with =

+ 5.

So, =

= + 8 =

23

(3) + = 2 +

= 8 + 2= 10

=23

+ 10 = + ,

7. = , 8. (, )=(3,6), (, )= (0,0)

Gradient / KecerunanOU

=

=

0 60 (3)

=

63

= ,

9. 4 = 3 2, aty-intercept, the value of = 04 = 3 2(0)4 = 3 =

,


11/17







11

10.(, )=(0, 8), (, )= (10,0) =

=

0 81 0 0

= 810=

45

= + =

+


12/17







12

Exercise 1

1. (, )=(1,0), (, )=(1, 4), (, )=(5, 7),(, )(a)Gradient /KecerunanPQ

=

= 4 01 (1)

=

42

=

(b)= = 2 = + 7 = 2(5) +

= 10 + = 7 10

= 3 =

(c)Atx-intercept the value of = 0/Pada pintasan-x, nilai = 0.

0 = 2 33 = 2 =

2. , equation / persamaan , + 3 + 3 = 0(a)Change the equation KL in the

gradient form / Tukar persamaan KL

kepada bentuk kecerunan.

= 3 3, so =

(b)= = 3 (5,0) = + 0 = 5(3) +

= 15 + = 15 = +

(c) y-intercept = =


13/17







13

3. = 2 (3, ), (7,10)

(a) = (b)= = 2

= + 10 = 2(7) +

= 14 + = 10 14

= 4 =

(c)(0, ),(3,10) =

2 =10

3 0

6 = 10 = 10 6

= 4

(,)

4. (5,20)(a)(5,0)(b)=

=20

5

= 4

=

4 = 5 = 20

(c) = + =

5. (2,1),(8,)Equation / Persamaan STUV2 = + 4(a)2 = 8 + 4

2 = 12 =

12

2

=

(b)2 = + 4 =

2

+ 2

So, y-intercept = 2

(c)= =

0 10 (2)

= 12

= 12

, (0,2)

=

+


14/17







14

Exercise 2

1. (3,10)EquationAB = 2 + 16

(a) = 10(b) = 0

0 = 2 + 16 =

162

= ,

(c)(8,0)(0, 10)= 108

=

54

=

+

2. (, )=(2,3), (, )=(8,2), (, )= (6, 5)(a)Gradient CD

=

=

2 38 (2)

=

510

=

(b)= = = + 5 =

12

(6) + 5 = 3 + = 8

= 12 + 8

(c) = 0

0 = 12

() + 812

= 8 =


15/17







15

3. (8,0), (, 3), (6,0)= 3(a)= 3

3 = 3 0 (8)

=

3

+ 8

3( + 8)= 33 + 24 = 3

3 = 21 =

(b)= 3=

3 =

8

= 8(3) =

(c)(6, 0)=

246

= 4

= + = +

4. (2, 3),(2,8)(a) = = 5

So, (,)

(b)Equation ofBC=

3

2

=32

+ 5

5. (a)=

= 124

= 3

= +

(b)= = 3, (3,0) = + 0 = 3(3) +

9 = = 3 9

(c)y-intercept = 9


16/17







16

DIAGNOSTIC TEST

1. = (a)= = (b)=

12

= 6

=

62

= 3

(,)

(c) = +

5 =

1

2 (6) +

= 3 + = 5 + 3

= 8

=

+

2. (0, 9), (5, 7),(0,5)(a)y-intercept = 9(b)Find gradient QR first

Cari kecerunan QR dulu.

=7 (5)

5 0

=12

5

=

(c) =

, (0, 9) =

+

3. (6, 0), (0, 8), (6,12)(a)(,)(b)GradientPM

=12 8

6 0 =

46

=

(c) =

+


17/17







17

4. CD = 2 + (a)(1,3)

3 = 2(1) + = 2 +

= 3 + 2 =

(b)= 1 = + 3 = 1(1) +

= 1 + = 3 1

= 2

= +

(c)(,0)0 = + 2 =

5. (3,6), (, ),(4,3)(a)=

= 34=6 =

6(4)3

=

(b)3 =

37

(4) + = 12

7 +

= 3 +127

=

337

=

+

Documents

Tutormansor Wordpress Com Latihan Matematik Tingkatan 4 05 Straight Line Answer