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+. -. +. -. +. -. +. -. +. +. +. +. e-. e-. +. +. +. e-. +. +. +. Types of Primary Chemical Bonds. Isotropic, filled outer shells. Metallic Electropositive: give up electrons Ionic Electronegative/Electropositive Colavent Electronegative: want electrons - PowerPoint PPT Presentation
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• Metallic– Electropositive: give up electrons
• Ionic– Electronegative/Electropositive
• Colavent– Electronegative: want electrons
– Shared electrons along
bond direction
Types of Primary Chemical BondsIsotropic, filled outer shells
+ - +
- + -
+ - +
+ + +
+ + +
+ + +
e-
e-
e-
Close-packed structures
Review: Common Metal Structureshcp ccp (fcc) bcc
ABABABABCABC not close-packed
Features• Filled outer shells spherical atom cores, isotropic bonding• Maximize number of bonds high coordination number• High density
Metals• single element, fairly electropositive• elements similar in electronegativity
cation
anion
Ionic Compounds• elements differing
in electronegativity
CERAMICS
Ionic Bonding & Structures
• Isotropic bonding• Maximize packing density• Maximize # of bonds, subject to constraints
– Like atoms should not touch– Maintain stoichiometry– Alternate anions and cations
Ionic Bonding & Structures
+ –
–
––
–
–
+ –
–
––
–
–
Isotropic bonding; alternate anions and cations
––
–
– –
–+
Just barely stable
Radius Ratio “Rules”
Cubic Coordination: CN = 8
2RA
2(rc + RA)
2 AR a
3c A
A
r RR
3 1 0.732c
A
rR
a
2( ) 3A cR r a
Cuboctahedral: CN = 12
rc + RA = 2RA
rc = RA rc/RA = 1
2RA
rc + RA
Radius Ratio RulesCN (cation) Geometry min rc/RA
2 none(linear)
3 0.155(trigonal planar)
4 0.225(tetrahedral)
CN Geometry min rc/RA
6 0.414(octahedral)
8 0.732(cubic)
12 1(cuboctahedral)
Ionic Bonding & Structures• Isotropic bonding• Maximize # of bonds, subject to constraints
– Like atoms should not touch• ‘Radius Ratio Rules’ – rather, guidelines• Develop assuming rc < RA
• But inverse considerations also apply• n-fold coordinated atom must be at least some size
– Maintain stoichiometry• Simple AaBb compound: CN(A) = (b/a)*CN(B)
– Alternate anions and cations
Radius Ratio Rules
CN (cation) Geometry min rc/RA (f)2 linear none
3 trigonal planar 0.155
4 tetrahedral 0.225
6 octahedral 0.414
8 cubic 0.732
12 cubo-octahedral 1
if rc is smaller than fRA, then the space is too big and the structure is unstable
common in ionic compounds
sites occur within close-packed arrays
Local Coordination Structures• Build up ionic structures from close-
packed metallic structures• Given range of ionic radii: CN = 4, 6, 8
occur in close-packed structurestetrahedral
octahedral
HCP: tetrahedral sites
4 sites/unit cell2 sites/close-packed atom
HCP: octahedral sites
2 sites/unit cell1 site/close-packed atom
Sites in cubic close-packed
8 tetrahedral sites/unit cell2 tetrahedral sites/close-packed atom
4 octahedral sites/unit cell1 octahedral site/close-packed atom
Summary: Sites in HCP & CCP
2 tetrahedral sites / close-packed atom1 octahedral site / close-packed atom
sites are located between layers: number of sites/atom same for ABAB & ABCABC
Common Ionic Structure Types• Rock salt (NaCl) sometimes also ‘Halite’
– Derive from cubic-close packed array of Cl-
• Zinc blende (ZnS)– Derive from cubic-close packed array of S=
• Fluorite (CaF2)– Derive from cubic-close packed array of Ca2+
• Cesium chloride (CsCl)– Not derived from a close-packed array
• Complex oxides– Multiple cations
Example: NaCl (rock salt)
• Cl- ~ 1.81 Å; Na+ ~ 0.98 Å; rc/RA = 0.54
• Na+ is big enough for CN = 6– also big enough for CN = 4,
but adopts highest CN possible
• Cl- in cubic close-packed array
• Na+ in octahedral sites
• Na:Cl = 1:1 all sites filled
CN f
4 0.225
6 0.414
8 0.732
Rock Salt Structure
Cl
Na
CN(Cl-) also = 6RA/rc > 1 Cl- certainly large enough for 6-fold coordination
ccp array with sites shown
Lattice Constant Evaluationccp metal
4R = 2 a
a
R
a
R
a = 2(RA + rc) > ( 4/2)RA
rock salt
Example: ZnS• S2- ~ 1.84 Å; Zn2+ ~ 0.60 – 0.57 Å;
– rc/RA = 0.326 – 0.408• Zn2+ is big enough for CN = 4 • S2- in close-packed array• Zn2+ in tetrahedral sites• Zn:S = 1:1 ½ tetrahedral sites filled• Which close-packed arrangement?
– Either! “Polytypism”– CCP: Zinc blende or Sphaelerite structure– HCP: Wurtzite structure
CN f
4 0.225
6 0.414
8 0.732
ZnS: Zinc Blende
x
yz = 0 z = ½
x
yz = 1 z = ½
x
S2-
x
x
x
CCPanions as CP atomsfill 4/8 tetr sites
ZnS: Zinc Blende
CN(S2-) also = 4RA/rc > 1 S2- certainly large enough for 4-fold coordination
S2-
Zn2+
Example: CaF2 (Fluorite)• F- ~ 1.3 Å; Ca2+ ~ 1.0 Å;
– rc/RA = 0.77
• Ca2+ is big enough for CN = 8 – But there are no 8-fold sites in close-packed arrays
• Consider structure as CCP cations– F- in tetrahedral sites– RA / rc> 1 fluorine could have higher CN than 4
• Ca:F = 1:2 all tetrahedral sites filled• Places Ca2+ in site of CN = 8• Why CCP not HCP? - same reason as NaCl
CN f
4 0.225
6 0.414
8 0.732
Fluorite
CN(F-) = 4CN(Ca2+) = 8 [target]
F-
Ca2+
CsCl• Cl- ~ 1.8 Å; Cs+ ~ 1.7 Å;
– rc/RA = 0.94• Cs+ is big enough for CN = 8
– But there are no 8-fold sites in close-packed arrays• CsCl unrelated to close-packed structures
– Simple cubic array of anions– Cs+ in cuboctahedral sites– RA / rc> 1 chlorine ideally also has large CN
• Ca:Cl = 1:1 all sites filled
Cesium Chloride
Cl-
Cs+1 Cs+/unit cell1 Cl-/unit cellCN(Cs) = 8
Why do ionic solids stay bonded?2
1 2
4electrostaicpair
o
Z Z eEr
• Solid: repulsion between like charges• Net effect? Compute sum for overall all possible pairs
• Pair: attraction only
2
12 4
i jelectrostaticsolid cluster
i j o ij
Z Z eE
r
Sum over a cluster beyond which energy is unchanged
Madelung Energy
Can show 2
0( )
4electrostaticsolid
o
ZeE Nr
For simple structures Single rij
|Z1| = |Z2| = Madelung constant
Structures of Complex Oxides
• Multiple cations– Perovskite
• Capacitors• Related to high Tc superconductors
– Spinel• Magnetic properties
• Covalency– Zinc blende
• Semiconductors– Diamond
• Semiconductors– Silicates
• Minerals
Perovskite– Perovskite: ABO3 [B boron]
• A2+B4+O3 A3+B3+O3 A1+B5+O3
• CaTiO3 LaAlO3 KNbO3
• Occurs when RA ~ RO and RA > RB
• Coordination numbers– CN(B) = 6; CN(A) =– CN(O) = 2B + 4A
• CN’s make sense? e.g. SrTiO3
– RTi = 0.61 Å
– RSr = 1.44 Å
– RO = 1.36 Å http://abulafia.mt.ic.ac.uk/shannon/ptable.php
12
above/below
RTi/RO = 0.45
RSr/RO = 1.06
A
BO
Tolerance factorclose-packed directions
A
B