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1 Unit 2 : Magnetostatics

Unit 2 : Magnetostatics

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Page 1: Unit 2 : Magnetostatics

1

Unit 2 : Magnetostatics

Page 2: Unit 2 : Magnetostatics

TABLE OF CONTENTS

1. Magnetostatics

I. Biot- Savert Law

II. Magnetic Flux and force

III. Curl Opertor

2. Classification of vector fields

3. Magnetic vector potential

4. Stokes theorem

5. Ampere’s circuital law

6. Boundary condition on the tangential component of magnetic field

7. Future Scope and relevance to industry.

8. NPTEL/other online link

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Page 3: Unit 2 : Magnetostatics

If charges are moving with constant velocity, a static

magnetic (or magnetostatic) field is produced. Thus,

magnetostatic fields originate from currents (for instance,

direct currents in current-carrying wires).

Most of the equations we have derived for the electric fields

may be readily used to obtain corresponding equations for

magnetic fields if the equivalent analogous quantities are

substituted.

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Magnetostatics

Page 4: Unit 2 : Magnetostatics

Biot – Savart’s Law

The magnetic field intensity dH produced at a point P by the differential current element Idl is proportional to the product of Idl and the sine of the angle between the element and the line joining P to the element and is inversely proportional to the square of the distance R between P and the element.

IN SI units, , so

2R

sinIdlkdH

2R4

sinIdlkdH

4

1k

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Page 5: Unit 2 : Magnetostatics

Using the definition of cross product we can represent the previous equation in vector form as The direction of can be determined by the right-hand rule or by the right-handed screw rule. If the position of the field point is specified by and the position of the source point by where is the unit vector directed from the source point to the field point, and is the distance between these two points.

)esinABBA( nAB

32

r

R4

RdlI

R4

edlIHd

RR R

Rer

r

rre

rr

r

dH I(dl e

r r )

4 r r 2

I[dl (r r )]

4 r r 3

Hd

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Page 6: Unit 2 : Magnetostatics

Example. A current element is located at x=2 cm,y=0, and

z=0. The current has a magnitude of 150 mA and flows in

the +y direction. The length of the current element is 1mm.

Find the contribution of this element to the magnetic field

at x=0, y=3cm, z=0

r 3102e y x2e10*2r

r r 13 102

(r r ) (2e x 3e y) 102

dH I[dl (r r )]

4 r r 3

0.15(2 10-5 )e z

4( 13 102)3

5.09 10-3 e z A m

dl (r r ) 103e y (2e x 3e y ) 102

10-5 (2e z)

e y e x e z

e y e y 0

y3e10dl

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Page 7: Unit 2 : Magnetostatics

The field produced by a wire can be found adding up the fields produced by a large number of current elements placed head to tail along the wire (the principle of superposition).

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Page 8: Unit 2 : Magnetostatics

Consider an infinitely long straight wire located on the z axis

and carrying a current I in the +z direction. Let a field point

be located at z=0 at a radial distance R from the wire.

)ZR(4

esinIdz

rr4

)ee(Idz

rr4

)edl(IHd

22

)ZR(

R

2rrz

2rr

2/122

2/122 )ZR(rr

R2

I)11(

R4

I

222

z

2/3222/12222ZRR

Z

4

IRdz

)ZR(

1

)ZR(

R

)ZR(4

IdzH

z 0

ze

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Page 9: Unit 2 : Magnetostatics

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Page 10: Unit 2 : Magnetostatics

constbarr 22

addl

22

0

ba

a)90sin(cos

H Iad

4 (a2 b2)

a

(a2 b2)1/ 20

2

Ia2

4 (a2 b2)3 / 2 2

Ia2

2(a2 b2)3 / 2

H H e z

The horizontal components of (x-components and y-components add to zero

H

r're

dl(perpendicular to both

and )

dH I(dl e r'r )

4 r r 2

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Page 11: Unit 2 : Magnetostatics

Magnetic Flux Density

The magnetic flux density vector is related to the magnetic

field intensity by the following equation

T (tesla) or Wb/m2

where is the permeability of the medium. Except for

ferromagnetic materials ( such as cobalt, nickel, and iron),

most materials have values of very nearly equal to that for

vacuum,

H/m (henry per meter)

The magnetic flux through a given surface S is given by

Wb (weber)

H

,HB

7o 104

S

,sdB

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Page 12: Unit 2 : Magnetostatics

Magnetic Force

One can tell if a magnetostatic field is present because it

exerts forces on moving charges and on currents. If a current

element is located in a magnetic field , it experiences a

force

This force, acting on current element , is in a direction

perpendicular to the current element and also perpendicular

to . It is largest when and the wire are perpendicular.

The force acting on a charge q moving through a magnetic

field with velocity is given by

The force is perpendicular to the direction of charge motion,

and is also perpendicular to .

Idl B

dF Idl B

F q(v B )

B

Idl

B

v

B

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Page 13: Unit 2 : Magnetostatics

The Curl Operator

This operator acts on a vector field to produce another vector

field. Let be a vector field. Then the expression

for the curl of in rectangular coordinates is

where , , and are the rectangular components of

The curl operator can also be written in the form of a

determinant:

)z,y,x(B

z

xy

y

zx

x

yz ey

B

x

Be

x

B

z

Be

z

B

y

BB

B

xB

yB z

B

zyx

zyx

BBB

zyx

eee

B

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Page 14: Unit 2 : Magnetostatics

The physical significance of the curl operator is that it

describes the “rotation” or “vorticity” of the field at the point

in question. It may be regarded as a measure of how much

the field curls around that point.

The curl of is defined as an axial ( or rotational) vector

whose magnitude is the maximum circulation of per unit

area as the area tends to zero and whose direction is the

normal direction of the area when the area is oriented so as

to make the circulation maximum.

where the area is bounded by the curve L, and is the

unit vector normal to the surface and is determined using

the right – hand rule.

n

max

L

0sa

s

dlB

limBBrotBcurl

BB

sn

as

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Page 15: Unit 2 : Magnetostatics

z

xy

y

zx

x

yz ey

B

x

Be

x

B

z

Be

z

B

y

BB

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Page 16: Unit 2 : Magnetostatics

Classification of Vector Fields

A vector field is uniquely characterized by its divergence

and curl (Helmholtz’s theorem). The divergence of a vector

field is a measure of the strength of its flow source and the

curl of the field is a measure of the strength of its vortex

source.

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Page 17: Unit 2 : Magnetostatics

If then is said to be solenoidal or divergenceless. Such a field has neither source nor sink of flux. Since (for any ), a solenoidal field can always be expressed in terms of another vector : If then is said to be irrotational (or potential, or conservative). The circulation of around a closed path is identically zero. Since (for any scalar V), an irrotational field can always be expressed in terms of a scalar field V:

0A A

0)F(

F

0A

FA

0V

VA

AA

A

A

F

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Page 18: Unit 2 : Magnetostatics

Magnetic Vector Potential

Some electrostatic field problems can be simplified by

relating the electric potential V to the electric field intensity

. Similarly, we can define a potential associated with

the magnetostatic field :

where is the magnetic vector potential.

Just as we defined in electrostatics

(electric scalar potential)

we can define

(for line current)

)VE(E

AB

'rr4

)'r(dq)r(V

L 'rr4

'dl)'r(I)r(A

B

A

m

Wb

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Page 19: Unit 2 : Magnetostatics

The contribution to of each differential current element

points in the same direction as the current element that

produces it.

The use of provides a powerful, elegant approach to

solving EM problems (it is more convenient to find by first

finding in antenna problems).

The Magnetostatic Curl Equation

Basic equation of magnetostatics, that allows one to find the

current when the magnetic field is known is

where is the magnetic field intensity, and is the current

density (current per unit area passing through a plane

perpendicular to the flow).

The magnetostatic curl equation is analogous to the electric

field source equation

A 'dlI

B

JH

D

A

A

H

J

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Page 20: Unit 2 : Magnetostatics

Stokes’ Theorem

This theorem will be used to derive Ampere’s circuital law

which is similar to Gauss’s law in electrostatics.

According to Stokes’ theorem, the circulation of around a

closed path L is equal to the surface integral of the curl of

over the open surface S bounded by L.

The direction of integration around L is related to the

direction of by the right-hand rule.

A

A

ds

A dl A dsS

L

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Page 21: Unit 2 : Magnetostatics

Stokes’ theorem converts a surface integral of the curl of a

vector to a line integral of the vector, and vice versa.

(The divergence theorem relates a volume integral of the

divergence of a vector to a surface integral of the vector, and

vice versa).

Sv

dsAdvA

Determining the sense of dl and dS involved in Stokes’s theorem

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Page 22: Unit 2 : Magnetostatics

S

dsAdlA

1

Surface S2 (circular)

22

L

Page 23: Unit 2 : Magnetostatics

Ampere’s Circuital Law

Choosing any surface S bounded by the border line L and

applying Stokes’ theorem to the magnetic field intensity

vector , we have

Substituting the magnetostatic curl equation

we obtain

which is Ampere’s Circuital Law. It states that the circulation

of around a closed path is equal to the current enclosed by

the path.

S

L

dlHsdH

H

JH

L

I

S

dlHsdJ

enc

H

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Page 24: Unit 2 : Magnetostatics

Ampere’s law is very useful in determining when there is a closed path L around the current I such that the magnitude of is constant over the path. H

H

(Amperian Path)

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Page 25: Unit 2 : Magnetostatics

Boundary conditions are the rules that relate fields on opposite sides of a boundary.

T= tangential components

N= normal components

We will make use of Gauss’s law for magnetic fields

and Ampere’s circuital law

BN1

BN 20dsB

1TH 2T

Henc

IdlH

for and

for and

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Page 26: Unit 2 : Magnetostatics

In the limit as

we have

where is the current on the boundary surface

(since the integration path in the limit is infinitely narrow).

When the conductivities of both media are finite,

Boundary condition on the tangential component of

0L2

0L4

H dlL

HT1l HT 2l Ienc

encI

2T1THH

H

The tangential component of is continuous across the boundary, while that of is discontinuous

H

B

0Ienc

and

22T11T/B/B

HT1

HT 2

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Page 27: Unit 2 : Magnetostatics

Gaussian surface (cylinder with its plane faces parallel to the boundary)

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Page 28: Unit 2 : Magnetostatics

Applying the divergence theorem to and noting that

(magnetic field is solenoidal) we have

In the limit as , the surface integral over the curved

surface of the cylinder vanishes. Thus we have

(the normal component of is continuous at the boundary)

(the normal component of is discontinuous at the boundary)

B 0B

VS

0BdsB

h 0

BN2A BN1A 0

BN1 BN 2

1HN1 2HN 2

B H

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Page 29: Unit 2 : Magnetostatics

Future Scope and relevance to industry

• https://pure.tue.nl/ws/portalfiles/portal/90464432/general_formulation_magnetostatic_15_.pdf

• https://lib.dr.iastate.edu/cgi/viewcontent.cgi?referer=https://www.google.co.in/&httpsredir=1&article=12115&context=rtd

• https://www.researchgate.net/publication/3096032_FEM_analysis_of_3D_magnetostatic_fields

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