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Unit 3. Acids and Bases. Hydrogen ions and pH. Ion product constant of water (K w ) H 2 O H + + OH - In pure water : [H + ] = [OH - ] * [ ] are used to indicate concentration in mol/L K w = [H + ] [OH - ] = 1.0x10 -14 - PowerPoint PPT Presentation
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Hydrogen ions and pHIon product constant of water (Kw)
H2O H+ + OH-
In pure water : [H+ ] = [OH- ] * [ ] are used to indicate concentration in mol/L
Kw = [H+ ] [OH- ] = 1.0x10 -14 If [H+ ] > 1.0 x10-7 the solution is ACIDICIf [OH- ] > 1.0 x10-7 the solution is BASICIf [H+ ] or [OH- ] = 1.0 x10-7 the solution is
NEUTRAL
pH and pOHValues for concentrations of H+ and OH- are
small so scientist use a scale based on common logarithms.
pH= - log [H+] * [H+] : concentration hydrogen ions (related to acids)
[H+] = 10-pH
pOH= -log [OH-] * [OH-] : concentration hydroxide ions (related to bases)
[OH-] = 10-pOH
pH +pOH=14
A pH scale from 0 to 14 is used. (It has no units)
If pH< 7: solution is acidic ; if pH=7: solution is neutral; if pH>7: solution is basic
If pOH<7: solution is basic; if pOH=7: solution is neutral; if pOH>7 : solution is acidic
pH and pOH
pH of Common Substances
Timberlake, Chemistry 7th Edition, page 335
1.0 MHCl0
gastricjuice1.6
vinegar2.8
carbonated beverage3.0
orange3.5
apple juice3.8
tomato4.2
lemonjuice2.2 coffee
5.0
bread5.5
soil5.5
potato5.8
urine6.0
milk6.4
water (pure)7.0
drinking water7.2
blood7.4
detergents8.0 - 9.0
bile8.0
seawater8.5
milk of magnesia10.5
ammonia11.0
bleach12.0
1.0 MNaOH(lye)14.0
8 9 10 11 12 14133 4 5 621 70
acidic neutral basic[H+] = [OH-]
Example 1What is the pH of a solution with [H+]=1.00x10-
4 M? Is it acidic, basic, or neutral?
Given : [H+]=1.00x10-4 MUnknown: pH
pH = -log[H+]
pH = -log[1.00x10-4]
pH = 4.00 (acidic)
Example 2What is the pH and pOH of a solution with
[ H+]= 0.00350mol /L?
Given : [ H+]= 0.00350mol /L?Unknown: pH and pOH
pH = -log[H+]
pH = -log[0.00350]
pH = 2.46
pH + pOH = 14
pOH = 14 – pH= 14 - 2.46 = 11.54
Example 3What is the [H+ ] and [OH- ] of a solution if
pOH=4.40Given: pOH= 4.40 Unknown: [H+ ] and [OH- ]
[OH-] = 10-pOH
[OH-] = 10-4.40
[OH-] = 3.98x10-5 M
[H+] [OH-] = 1 x10-14
[H+] = 1 x10-14 = 1 x10-14 = 2.51x10-10M
[OH-] 3.98x10-5
classworkRead p650-655Do problems p651#22 p653 #24-26 p655
#30-31
Strengths of acids and basesStrong acids and bases : ionize completely in
aqueous solution.Examples: HCl, HNO3, H2SO4, KOH, NaOH
Weak acids and bases: ionize slightly in aqueous solution.
Examples: HClO, H3PO4 , NH3
Reactions between acids and basesWhen and acid and a base react with each other it is called neutralization reaction.
ACID + BASE → SALT + WATER
HHCl + NaOHOH → NaCl + H2O
H-OHSalt: ionic compound made up of cation of base and anion from acid.
Ex. Write the neutralization reaction between hydroiodic acid and potassium hydroxide.
TitrationTitration: adding a known amount of a
solution of known concentration to determine the concentration of another solution.
Equivalence point: when number of moles of hydrogen ions equals the number of moles of hydroxide ions.
Standard solution: solution of known concentration
End point: point at which the indicator changes color
Point of neutralization is the end point of the titration.
M1V1= M2V2
Ex. 1 How many milliliters of 0.45M HCl will neutralize 25.0 mL of 1.00M KOH?
mL HCl= 25.0mL x 1.00M KOH 0.45 M HCl
mL HCl= 55.6mL HCl
M1V1= M2V2
Ex. 2 What is the molarity of a NaOH solution if 20.0 mL of the solution is neutralized by 28.0mL of 1.00 M HCl?
M NaOH= 1.00 M HCl x 28.0 mL 20.0 mL
M NaOH = 1.40 M
Classwork: p 989 #22-25
M1V1= M2V2