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Using Similar Figures Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day Lesson Quizzes Lesson Quizzes

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Warm Up. Problem of the Day. Lesson Presentation. Lesson Quizzes. JN. KO. Warm Up. Solve each proportion. 24 x. 6 19. k 4. 75 25. x = 76. k = 12. 2. 1. =. =. - PowerPoint PPT Presentation

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Using Similar Figures

Warm UpWarm Up

Lesson PresentationLesson Presentation

Problem of the DayProblem of the Day

Lesson QuizzesLesson Quizzes

Using Similar Figures

Warm UpSolve each proportion.

1. k4

= 7525

2. 619

= 24x

3.

Triangles JNZ and KOA are similar. Identify the side that corresponds to the given side of the similar triangles.

J

N Z K O

A

JN KO

k = 12 x = 76

Using Similar Figures

Problem of the Day

Harvey starts to fill a 3-gallon tank from a hose that delivers 1 gallon per minute. However, the tanks leaks 1 quart per minute. In how many minutes will the tank begin to overflow?4

Using Similar Figures

Learn to use similar figures to find unknown lengths.

Using Similar Figures

Vocabulary

indirect measurement

Using Similar Figures

Indirect measurement is a method of using proportions to find an unknown length or distance in similar figures.

Using Similar Figures

Find the unknown measures in the similar figures.

Additional Example 1: Finding Unknown Lengths in Similar Figures

ABJG

= BCHG Write a proportion using corresponding sides.

105

= 6x

Substitute lengths of the sides.

10 · x = 5 · 6 Find the cross product.10x = 30 Multiply.

10x10

= 3010

x = 3

HG is 3 centimeters.

Divide each side by 12 to isolate the variable.

HB A

CGJ

10 cm

6 cm 116 cm

5.8 cmx

5 cm

31°

59°

y

Using Similar Figures

Find the unknown measures in the similar figures.

Additional Example 1 Continued

Step 2 Find y.

Corresponding angles of similar triangles have equal angle measures.

H corresponds to C

y = 59

HB A

CGJ

10 cm

6 cm 116 cm

5.8 cmx

5 cm

31°

59°

y

Using Similar Figures

Find the unknown measures in the similar figures.

Check It Out: Example 1

ABFE

= BCDE Write a proportion using corresponding sides.

147

= 9x

Substitute lengths of the sides.

14 · x = 9 · 7 Find the cross product.14x = 63 Multiply.

14x14

= 6314

x = 4.5

HG is 4.5 centimeters.

Divide each side by 12 to isolate the variable.

DB A

CEF

14 cm

9 cm 116 cm

5.8 cmx

7 cm

27°

63°

y

Using Similar Figures

Find the unknown measures in the similar figures.

Check It Out: Example 1 Continued

Step 2 Find y.

Corresponding angles of similar triangles have equal angle measures.

D corresponds to C

y = 63

DB A

CEF

10 cm

6 cm 116 cm

5.8 cmx

5 cm

27°

63°

y

Using Similar Figures

The inside triangle is similar in shape to the outside triangle. Find the length of the base of the inside triangle.

Let x = the base of the inside triangle.

82

=12x

8 · x = 2 · 128x = 24

8x8

= 248

x = 3The base of the inside triangle is 3 inches.

Write a proportion using corresponding sidelengths.

Find the cross products.Multiply.

Divide each side by 8 to isolate the variable.

Additional Example 2: Measurement Application

Using Similar Figures

Check It Out: Example 2

The rectangle on the left is similar in shape to the rectangle on the right. Find the width of the right rectangle.

3 cm

6 cm12 cm

Let w = the width of the right rectangle.

612

= 3w

6 ·w = 12 · 3

6w = 36

6w6

= 366

w = 6

The right rectangle is 6 cm wide.

Write a proportion using correspondingside lengths.

Find the cross products.Multiply.

Divide each side by 6 to isolate the variable.

?

Using Similar Figures

Additional Example 3: Estimating with Indirect Measurement

City officials want to know the height of a traffic light. Estimate the height of the traffic light.

27.2515

= 48.75h

Write a proportion.

Use compatible numbers to estimate.

53

≈ 50h

Simplify.

5h ≈ 150

The traffic light is about 30 feet tall.

27.25 ft

48.75 ft

h ft 2515

≈ 50h

Cross multiply.

h ≈ 30 Divide each side by 5 to isolate the variable.

Using Similar Figures

Check It Out: Example 3

The inside triangle is similar in shape to the outside triangle. Find the height of the outside triangle.

514.75

= h30.25

Write a proportion.

Use compatible numbers to estimate.

13

≈ h30

Simplify.

1 • 30 ≈ 3 • h

The outside triangle is about 10 feet tall.

14.75 ft

30.25 ft

h ft

515

≈ h30

30 ≈ 3h Divide each side by 3 to isolate the variable.

5 ft

Cross multiply.

10 ≈ h

Using Similar Figures

Standard Lesson Quiz

Lesson Quizzes

Lesson Quiz for Student Response Systems

Using Similar Figures

Lesson Quiz: Part I

Find the unknown length in each pair of similar figures.

1.

2.

x = 120 cmy = 98◦

t = 150 cms = 120◦

33°49°

98° y

s

19°

120° 41°

Using Similar Figures

Lesson Quiz: Part II

Find the unknown length in each pair of similar figures.

3. The width of the smaller rectangular cake is 5.75 in. The width of a larger rectangular cake is 9.25 in. Estimate the length of the larger rectangular cake.

about 15 inches

Using Similar Figures

1. Identify the unknown length in the given pair of similar figures.

A. x = 174 cm

B. x = 182 cm

C. x = 196 cm

D. x = 204 cm

Lesson Quiz for Student Response Systems

Using Similar Figures

2. Identify the unknown length in the given pair of similar figures.

A. t = 166 cm

B. t = 198 cm

C. t = 206 cm

D. t = 248 cm

Lesson Quiz for Student Response Systems

Using Similar Figures

3. The width of the smaller rectangular box is 6.25 inches. The width of a similar larger rectangular box is 8.75 inches. Estimate the length of the larger rectangular box.

A. about 16 in.

B. about 17 in.

C. about 18 in.

D. about 19 in.

Lesson Quiz for Student Response Systems