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Water potential Ψ

Water potential Ψ. Ψ = Ψp + Ψs Ψp = pressure potential Ψs = solute potential

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Page 1: Water potential Ψ. Ψ = Ψp + Ψs Ψp = pressure potential Ψs = solute potential

Water potential

Ψ

Page 2: Water potential Ψ. Ψ = Ψp + Ψs Ψp = pressure potential Ψs = solute potential

Ψ = Ψp + Ψs

Ψp = pressure potential Ψs = solute potential

Page 3: Water potential Ψ. Ψ = Ψp + Ψs Ψp = pressure potential Ψs = solute potential

A cell is in equilibrium with its surroundings. The molarity of the surrounding solution is 0.5M

To convert molarity to solute potential in MPa (bars), use the formula: ΨS = - ( i CRT ) wherei = ionization constant (assume that is 1)

C=molar concentration (given above)R = pressure constant (R = 0.00831 liter bars/mole K) T = temp. in Kelvin (room temp is about 273 K° + 20 C°)

Calculate the solute potential of the surrounding solution.

Find the water potential of the surrounding solution. What is the water potential of the cytoplasm of the cell?

Page 4: Water potential Ψ. Ψ = Ψp + Ψs Ψp = pressure potential Ψs = solute potential

Two identical cells are place in two different environments. The cells both have a Ψ = -.7. One in distilled water the other .4M. What happens?

ΨS = - ( i CRT ) wherei = ionization constant (assume that is 1)

C=molar concentration (given above)

R = pressure constant (R=0.00831 liter bars/mole K )

T = temp. in Kelvin (room temp is about 293 °K )

What we know… - Deer Valley Unified School District ... we can give that value/variable: Pressure = Ψp Higher Ψp =water moves away from the pressure. (Gives a + value) Lower Ψp=

What we know… - Deer Valley Unified School District ... we can give that value/variable: Pressure = Ψp Higher Ψp =water moves away from the pressure. (Gives a + value) Lower Ψp=

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