Write an equation in slope-intercept form:

1. Given slope -6 and y-intercept is 9.

2. Given slope ⅓ and passes through (2,-1)

y= -6x + 9

y+1= ⅓(x – 2) distributey+1 = ⅓x - ⅔ subtract 1y = ⅓x – 1⅔

Write the equation of the line in slope-intercept form (y = mx+b):

3. Passing through (-1,2) and (4,5)

4. Passing through (3,-5) and (-4,2)

y+5= -1(x - 3) distributey+5 = -1x + 3 subtract 5 y = -1x - 2

m= 5-24+1

= 3 5

m= 2+5-4-3

= 7 =-1 -7

y-2= 3/5(x + 1) distributey-2 = 3/5x + 3/5 add 2y = 3/5x + 2 3/5

5. Write equation of the line perpendicular to 2y + 3x = 8 and passes (3,4).

6. Write equation of the line parallel to 4y - 3x = 16 and passes (2,-1).

y-4= ⅔(x - 3) distributey-4 = ⅔x - 2 add 4y = ⅔x + 2

m = ⅔2y = -3x + 8 y = -3/2x + 4

4y = 3x + 16 y = ¾x + 4

y + 1= ¾(x - 2) distributey+ 1 = ¾x - 1½ subtract 1y = ¾x - 2½

m = ¾

7. Passing through (7,4) and (8,-3)m= -3-4

8-7 = -7 =-7 1

y-4= -7(x - 7) distributey-4 = -7x + 49 add 4 y = -7x + 53

Write the equation of the line in standard form (Ax + By = C):

7x + y = 53

Write the equation of the line in standard form (Ax + By = C):

8. Passing through (-3,4) and (2,6)

m= 6-42+3

= 2 5

y-4= 2/5(x + 3) distributey-4 = 2/5x + 6/5 add 4y = 2/5x + 5 1/5( )5 multiply all by 5

5y = 2x + 26

-2x + 5y = 26

HOMEWORKText book page 95

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