11.3
1AB=AD,BC=DCA,ABAD,ACAE,AE?
2 ACDACB AD=AB DC=BC CA=CA ACD ACBSSS CAD=CAB ACDAB
ONOMCE
AOC
1AOB
2OCCDCDAB 3
(1)AOB (2):.
OC AOB 1= 2 PD OAPE OB PDO= PEO PDOPEO PDO= PEO 1= 2 OP=OP PDO PEOAAS PD=PE OCAOBPOCPDOADPEOBE: PD=PE(3)
(4) ?()
OABEDOCAOB ,P OC,PE=PD??CPPD,PEOA,OB,,
ABCC=90 ADBACDEABEFACBD=DF CF=EB :CF=EB,,RtCDF RtEDB. BD=DF(),DC=DE () HL.
1()2 3
1.OCAOB PD=PEPDOAPEOB
2.,ABCACBCADBACDEABAB7AC3BEEDCBA
3.RtABCBDABC DEABEDEAB10BC8AC6BEAEAED