Presented By:
Abhishek Wadhwa
3.2
DATA RATE LIMITS
A very important consideration in data communications ishow fast we can send data, in bits per second, over achannel. Data rate depends on three factors:
1. The bandwidth available2. The level of the signals we use3. The quality of the channel (the level of noise)
Noiseless Channel: Nyquist Bit Rate
Noisy Channel: Shannon Capacity
Topics discussed in this section:
Nyquist gives the upper bound for the bit
rate of a transmission system
Nyquist theorem states that for a noiseless channel:
C = 2 B log22n
Where :C= capacity in bpsB = bandwidth in Hz
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Consider a noiseless channel with a bandwidth of 3000Hz transmitting a signal with two signal levels. Themaximum bit rate can be calculated as
Example 1
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Consider the same noiseless channel transmitting a signalwith four signal levels (for each level, we send 2 bits). Themaximum bit rate can be calculated as
Example 1.1
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Increasing the levels of a signal
increases the probability of an error
occurring, in other words it reduces the
reliability of the system
Shannon’s theorem gives the capacity of a channel in the presence of noise
C = B log2(1 + SNR)
Where:
C=capacity
SNR=signal to noise ration
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Consider an extremely noisy channel in which the value
of the signal-to-noise ratio is almost zero. In other words,
the noise is so strong that the signal is faint. For this
channel the capacity C is calculated as
Example 1
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We can calculate the theoretical highest bit rate of aregular telephone line. A telephone line normally has abandwidth of 3000. The signal-to-noise ratio is usually3162. For this channel the capacity is calculated as
Example 2
It doesn’t take noise into consideration
Nyquist formula can be used to determine how many signal levels are required to achieve that limit based on how much bandwidth is available
Shannon's result takes the noise on a line into consideration
The Shannon limit gives a theoretical maximum limit based on the signal to noise ratio
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Any Questions?
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Thank You
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3.12