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Questions 1) Two numbers are in the ratio 3 : 2 . After adding 2 and 4 to them respectively the ratio become 3 : 4 . Find the bigger number? a) 2 b) 3 c) 4 d) 1 2) The present age of Ram and Shyam are in the ratio 2 : 5 . After 3 years ratio of their age’s become 3 : 7 . If Aayam who is 10 years older than Ram then find Aayam’s age before 5 years? a) 29 b) 31 c) 40 d) 35 3) A college had ratio of 3 : 7 (Boy : Girl ) . 30% girls and 10% boys were absent. Find the girls present if the total students were 200? a) 120 b) 125 c) 98 d) 100 4) CP and SP of an article are in the ratio 5 : 7 . While MP and Discount of an article are in the ratio 20 : 6 . If the profit on an article is Rs. 100 then find the S.P of the article? a) Rs. 350 b) Rs. 400 c) Rs. 325 d) Rs. 300 5) The ratio of the speeds of car and bus is 5 : 3 . If the car covers 200 kms in 4 hour then find time taken by the bus to cover the distance of 270 kms? a) 6 hours b) 9 hours c) 10 hours d) 12 hours


6) Speeds of three cars are C1, C2, C3 are in the ratio of 2 : 4 : 5 .Find the time taken by Car’s to cover the same distance ? a) 10 : 5 : 3 b) 10 : 5 : 4 c) 2 : 4 : 5 d) 5 : 2 : 3 7) The profit percent of an article is 12.5%. Discount given on the article was 16.66%.If the difference between CP and MP is Rs.70. Find the selling price? a) 225 b) 250 c) 300 d) 350 8) If A : B = 8 : 7 and A is 21 more than B then find he sum of A and B. a) 325 b) 315 c) 285 d) 295 9) A person has some rupee notes in his pockets of 10, 20, 50 in the ratio of 5 : 6 : 8.Later he distributed whole amount to his two daughters in the ratio of 3:2. Find the amount received by both the daughters if younger received 4600? a) Rs. 11400 b) Rs. 12000 c) Rs. 13050 d) Rs. 15000 10) Income of A is 120% of B. Income of B is 150% of C. Income of D is 50% of the sum of A and C. Find the income of A if the difference between income of B and D is Rs. 250? a) Rs. 4500 b) Rs. 4000 c) Rs. 5000 d) Rs. 6500 11) A person regularly buys 2 litres of milk in the ratio of milk to water is 4 : 1, Find the amount of water, if he reduced half litre of milk consumed actually. a) 0.2 litre b) 0.5 litre c) 0.8 litre d) 0.3 litre 12) A person want to distribute his will to his two sons A and B in the ratio of 2 : 3. After some days person changes his mind and re- distribute his will with the new ratio of 3 : 5. In this process B got 2 lakh rupees less than before. Find the actual will of the person? a) 60 lakh b) 80 lakh c) 70 lakh d) 50 lakh 13) If A/2 = B/3 = C/7 then find the value of (A + B) : (B+C) : (C+A) = ? a) 5 : 10 : 9 b) 9 : 5 : 10


c) 2 : 3 : 7 d) 1 : 3 : 5 14) In a school pass to fail ratio of students being 11 : 5. If the number of students being 62 less than the ratio of fail to pass becomes 3:7.Find the pass students initially? a) 77 b) 100 c) 190 d) 200 15) A completion between two shopkeepers each other during festivals session. Initial prices of their article was in the ratio of 5 : 8. If the price of article is increased by x% and 50% such that the new ratio of their product becomes 7 : 10. Find X? a) 68% b) 70% c) 65% d) 60% 16) A company has certain employees with the ratio of men to women is 7:8. Due to covid-19 pandemic, there is some lay-off in the company due to which ratio of working men to removed men becomes 5 : 2 while ratio of working women to removed women becomes 5:3. If the difference between working men to removed men is 150. Find total employees of the company. a) 750 b) 570 c) 500 d) 400 17) Ratio of circumference of circle to the perimeter of rectangle is 11 : 3. Sum of length and breadth of rectangle is 6 cm. Find the circumference of circle? a) 44 b) 48 c) 52 d) 28 18) The age of Amit is 3 times of Ramit and age of Ramit is 2 times of Sumit and Sumit is 10 years younger to Amit. Find the present age of Ramit? a) 4 b) 6 c) 8 d) 2 19) A and B entered into partnership with ratio 3 : 5. A invested his money for 15 months while B invested for 18 months .Find the total profit earned by both if the difference Between their profit is Rs. 1500 a) Rs. 6000 b) Rs. 4500 c) Rs. 3000 d) Rs. 4000 20) A sum of money Rs.400 divided among A,B,C in such a way that B gets Rs.40 more than A and C get 80 more than B .Then, ratio of their shares is a) 2:5:3 b) 2:3:5 c) 3:2:5


d) 5:2:3 21) An office having 5/9 of the male employees and the rest were female. 3/8 of female were post-graduate and remaining were under graduates. Similarly 6/25 of men were under graduates and remaining was PG. Find the total number of employees of the office? (Given Men who were under graduate 240) a) 1800 b) 2000 c) 1700 d) 1500 22) Sumit has apples, oranges and banana in the ratio of 2 : 5 : 8.The number of oranges is more than apples by a number which is multiple of both 6 and 8. Find the minimum number of fruit in sumit’s shop? a) 120 b) 150 c) 90 d) 180 23) The ratio of Curved surface area of cylinder to the area of circle is 22 : 7. If the difference between height and radius is 4 cm then what is the volume of cylinder? a) 1694 cm3 b) 1532 cm3 c) 1331 cm3 d) 1428 cm3

24) Two Container A and B, having two liquids water and alcohol. Container A contains mixture in the ratio of 3 : 4 while container B contains mixture in the ratio of 5 : 8. Both the container is having same alcohol concentration and mixture in B is 182L. Find water concentration in Container A? a) 84 b) 96 c) 112 d) 88 25) Sanket decided to row a boat between points A and B situated at 120 kms apart. While going upstream he takes 12 hrs and while going downstream he takes 10 hours. Find the speed of stream is what percentage of boat speed? a) 9(1/11)% b) 11(1/9)% c) 13(7/9)% d) 12.5% 26) To pass an examination 40 % marks are required. Amit scores 20% more than passing marks while Sumit scores 62.5% less than Amit. Find how much marks needs to be scored by Ramit more than the average of Sumit and Amit to score minimum marks? a) 20 % b) 21 % c) 23 % d) 25 % 27) Three friends namely Arun, Barak and Clara decided to start a venture with the ratio of investments being 3 : 5 : 3. After 6 months Arun and Barak double their investment while C lara left the business. Find the profit of Clara is how much percent less than that of Barak?


a) 80% b) 75% c) 60% d) 50% 28) A school has the ratio of 8:5 (Boys : Girls) out of boys 60 % goes to picnic and 70% of Total student is the girls who go to trip. Find the percentage of student who doesn’t goes to trip? a) 44% b) 47% c) 50% d) 43% 29) If the radius of the cylinder is increased by 11(1/9) % and the height of the cylinder is decreased by 16(2/3) % then find the percentage change in volume of cylinder? a) 2.88% b) 4.5% c) 3.33% d) 11.11% 30) Four years hence, sum of ages of A and B will be 16 years more than the sum of present age of B and C. Four years ago, Sum of ages of A and C is 32 years what is the present age of C? a )16 b) 20 c) 12 d) 15 31) The ratio of third proportion to 12 and 30 and the mean proportion between 16 and 25 is? a) 15 : 4 b) 25 : 4 c) 50 : 51 d) 25 : 26 32) If a Bag contains three color balls i.e red, blue and white in the ratio 3 : 4 : 5. If a man paints 3 white balls into red and then one red ball into blue, after this process number of blue balls becomes 15 in the bag then find the number of balls initially? a) 36 b) 30 c) 39 d) 40 33) Age of Ravi is 200% more than Kavi. Age of Kavi is 150% of Lavi. If the average age of all Is 27 years. Find the age of Kavi before 3 years? a) 18 b) 12 c) 15 d) 16 34) Ram and Shyam started a business with an initial investment of 3 : 5. After one year, Ram takes break from business while Raju joins with the investment double that of Ram. After second year they distributed their profit as per investment in which difference of Ram and Raju is Rs. 4500. Find Initial investment of Raju (in rupees)? a) 9000 b) 6000 c) 10000


d) 5000 35) Six years ago ratio of the ages of the two persons Pavi and Saravana was 3:2.Four years hence the ratio of their ages will be 8:7,what is Saravana age? a) 8 b) 14 c) 12 d) 10 36) The ratio of speed of bus to car is 3 : 5. If the speed of the bus is increased by 25% then the Bus will take 4 hrs to travel 300km. Find the speed of the car? a) 75kmph b) 50kmph c) 100kmph d) 120 kmph 37) If the ratio of simple interest earned in two years to the principle is 3:10. Keeping the rate and time same find the ratio between principles to CI? a) 3225 : 10000 b) 3225 : 1000 c) 1225 : 1000 d) 1331 : 1000 38) A village has 7:9 ratio of population of female to male. If 45% of the population is married couple and 75% couple has one child then find the ratio of unmarried men to the couple having no child? a) 77 : 36 b) 36 : 77 c) Can’t be determined d) 55 : 49 39) Two number’s are in the ratio 3 : 5.If 2 is subtracted from each new number are in the ratio of 1 : 5. If 4 is added to the original number find the ratio of new number? a) 4 : 5 b) 5 : 4 c) 3 : 5 d) 5 : 7 40) Three numbers are in the ratio of 1 : 2 : 3 and the sum of their squares is 126. Find the Smallest number? a) 1 b) 2 c) 3 d) 4 41) A school has 2000 students. 1/25th of the students didn’t appear for the exams. 1/100th of the total students were not allowed to write in exams due to application mismatching. If the difference between pass and fail in the exam is 300 students. Find the number of students who were passed in the examination? a) 1100 b) 1200 c) 800 d) 1000


42) If the ratio of the present age of A, B, C, D are 3 : 2 : 6 : 4 and the average of their age’s after 5 years is 25 years. Find the sum of present age of B and C? a) 30 years b) 40 years c) 35 years d) 45 years 43) Anil brought a gold ring of 10gms in which concentration of impurity is 10%. After one year rust occurs which is 6% of the pure gold. Find the ratio of pure gold to the pure gold(except rest), after one year? a) 450 : 423 b) 450 : 441 c) 441 : 529 d) None of these 44) Two person A and B ratio of their age’s be 3:5.If after Three year’s they have a brother and now the ratio becomes 5:8:2.Find the age of new born after 5 years? a) 10 years b) 12 years c) Can’t be determined d) None of these 45) A person markup his article by 20 % above CP and on selling he faces loss of 6.25%. Find the value of Markup price if the loss incurred was Rs. 19. a) Rs. 228 b) Rs. 200 c) Rs. 250 d) Rs. 221 46) A container consists a mixture of water and milk in the ratio of 3 : 7 . After adding 12 litres of water ratio becomes 9 : 14 . Find initial value of water in the solution? a) 24 litres b) 30 litres c) 27 litres d) 24 litres 47) Three towns A, B and C having population in the ratio of 5:8:6. If 10% of the population in town A is not having Aadhar card, while town B and C have 94% and 70% of the population having aadhar card then find the ratio of people not having aadhar card? a) 25 : 24 : 90 b) 25 : 24 : 180 c) 24 : 25 : 80 d) 30 : 39: 41 48) Three person A, B and C having income in the ratio 5:4:6.If the company gives increment to them by 10%,18% and 16% respectively. In the next year company given decrement of 16%, 18% and 10%.Find the ratio of their new income? a) 23100 : 19352 : 31320 b) 31320 : 19352 : 23100 c) Can’t be determined d) None of these 49) Three numbers are in the ratio 3 : 4. If 5 is added to first number and 5 is subtracted from last number ratio becomes 4 : 5. Find the actual numbers?


a) 135 and 180 b) 135 and 150 c) 180 and 150 d) None of these 50) A bag contains 25 P coins 50 P coins and 1 rupee coins in the ratio 10: 5: 2, amounting to Rs. 224. Find the total number of coins in the bag. a) 544 b) 464 c) 272 d) 232 51) If (a + b) : c = 5/3 and (b + c) : a = 4/3 then find the value of (c + a) : b ? a) 45/11 b) 56/11 c) 65/11 d) 46/11 52) If 4A = 5B = 2C then find the value of A : B : C ? a) 5 : 4 : 10 b) 4 : 5 : 10 c) 10 : 5 : 4 d) None of these 53) What number must be added to 12, 15, 57 and 69 to get the result in proportion? a) 6 b) 2 c) 3 d) 8 54) The flight fare from Bhopal to Erode was increased by 25% due to which the sale of tickets was decreased by 33(1/3)% if the initial revenue was 15000 then find the increased revenue? A.5000 B.1250 C.3000 D.2500 55) If 25% of 3/8 of P = 33.33% of 2/8 of Q = 50% of 2/8 of R then find the value of (P + Q) : (Q + R) ? a) 17 : 15 b) 15 : 17 c) 16 : 17 d) 14 : 17 56) Rs. 83000 is to be divided between three friends namely as A, B and C in which A receives 2/7 of B who receives 3/8 of C then find the amount received by B? a) 30,000 b) 15,000 c) 12,000 d) 21,000 57) Income of Sanket and Sumit is in the ratio of 7 : 5 , their expenditure is in the ratio of 4 : 3 and savings of them is 5000 and 3000 then find their total income ? a) 36,000


b) 30,000 c) 25,000 d) 15,000 58) The ratio of present age of Sanket and Sumit is 6 : 5 and after 6 years the ratio becomes 8 : 7 then find the age of Charu who is 6 years older to Sanket ? a) 24 years b) 25 years c) 23 years d) 20 years 59) In an examination the ratio of success to failure is 11 : 8 if 80 candidates have applied more and 30 less got fail then ratio becomes 12 : 5 find the number of total applicants? a) 12,000 b) 15,000 c) 14,440 d) 13,000 60) The price of two articles A and B were in the ratio of 3 : 5 if the CP of these articles is increased by ‘x’% and 25% then the ratio becomes 21 : 25 then find the value of ‘x’ ? a) 75% b) 50% c) 100% d) 25% 61) A Sum of rupees is to be divided between A, B and C such that A receives 2/9 of B who receives ¾ of C. If the difference between Amount received by A and C is 1000 then find the total amount? a) 2000 b) 1500 c) 2300 d) None of these 62) A person saves 30% of his salary after few years his salary increases by 20% and savings remains same then find the change in expenditure? a) 28.57% b) 29.37% c) 27.37% d) 30% 63) Rs. 300 is to be divided between three friends such that A receives 30 rupees less than B who receives 30 rupees more than C then find the amount received by B ? a) 100 b) 120 c) 200 d) 180 64) A village has ‘N’ population in which male to female population is 3 : 5. If 1/25 persons are not registered for votes and if men who registered are 5000 and women who are registered are 3000 then find the number of women in the village? a) Cannot be determined b) 5000 c) 3000 d) 2000


65) A school has 60% male population and remaining is female. If 3/25 of the total population is registered for convocation ceremony are boys and 25% of the population is registered for convocation is female then find the ratio of non - registered male to female? a) 24 : 17 b) 15 : 24 c) 24 : 25 d) 24 : 15 66) If two numbers are in the ratio of 12 : 17 and the sum of their squares in 15588 then find greater number? a) 34 b) 85 c) 170 d) 102 67) Find the ratio of mean proportion of 81 and 169 to the third proportion of 12 and 17? a) 1404 : 289 b) 289 : 1404 c) 144 : 289 d) None of these 68) What is the fourth proportion of 18, 20 and 23 ? a) 230/9 b) 200/9 c) 100/9 d) 115/9 69) If a man rides his bike at 5/6 of its initial speed then he will be late by 15 minutes. Find the actual speed? a) 65 minutes b) 75 minutes c) 90 minutes d) None of these 70) If a : b = c : d = 5 : 2 then find the value of (a2 +c2) : (b2 + d2) = ? a) 50 : 4 b) 25 : 4 c) 100 : 8 d) Cannot be determined 71) Sumit appeared for the test of Quant and English and he awarded marks in the ratio of 3 : 2. If he had score 30 marks more in quants and 12 marks less in English then the score would be in the ratio of 5 : 3. Find the marks scored by him in Quant? a) 300 b) 450 c) 150 d) 250 72) One year ago the ratio of age of Sumit and Sujeet was 8 : 5 and two years hence this ratio becomes 3 : 2 then find the age of Sumit after 5 years? a) 30 years b) 25 years c) 20 years


d) 15 years 73) A father wants to distribute his cash between his three sons i.e Abhay, Nirbhay and Gajbhay in the ratio 3 : 6 : 7 but his file rejected this distribution and re-arrange the distribution in the ratio of (1/8) : (3/8) : 6 due to which Abhay loses 40,000 rupees find the amount Abhay was getting initially? a) 50,000 b) 40,000 c) 20,000 d) 60,000 74) In a bag A there are two colored balls red and white in the ratio of 5 : 3 and in bag B having same color balls if we take 10 white balls from bag A and put them in Bag B the ratio of bag B becomes 3 : 2 then find white balls in bag A? a) 60 b) 90 c) 30 d) Cannot be determined 75) The ratio of two numbers is 12 : 13 if 30 is added to numerator and 10 is subtracted from denominator then the ratio becomes 9 : 7 then find the greater number? a) 1300/11 b) 1400/11 c) 1500/11 d) 1600/11 76) If the battalion has the ratio of soldier to inspector is 13 : 4. If during a coward attack by terrorist 150 soldiers and 21 inspectors were killed then the ratio of them becomes 9 : 2. Find the initial numbers of soldier? a) 145 b) 140 c) 150 d) 130 77) A College having 3000 people in which the ratio of male students : female students : Faculty is 6 : 8 : 1. If in a new academics session 120 male students and 200 female students and some faculties joined the college so that new ratio becomes 61 : 90 : 12.Find the number of new faculty joined ? a) 80 b) 60 c) 40 d) 50 78) If the investment of A is 60% of B and the time of B was 30% of A if the difference of their profit is 1500 then find the initial investment of A? a) 1500 b) 3500 c) 3000 d) 6000 79) The sum of age of Ayush and Anil three years back was 50 years and after two years the ratio of their age becomes 7 : 5 then find the age of Ayush 5 years ago ? a) 20 years b) 25 years


c) 28 years d) 15 years 80) Due to Covid - 19 If the price of movie ticket before and after increment is in the ratio of 12 : 17 and also the sale of the ticket before and after is 7 : 4.If the change in revenue is 80,000 rupees then find the initial revenue ? a) 420000 b) 840000 c) 620000 d) 350000 81) A sum of 46,000 rupees is to be distributed between four persons (A, B ,C, D) in such a way that they received (5/7) : (3/7) : (1/7) : (2).Find the difference between the amount received by B and C? a) 12000 b) 8000 c) 4000 d) 16000 82) If the ratio of radius of circle to the height of cylinder is 2 : 5 and the ratio of radius of cylinder to the radius of circle is 4 : 9.If the difference between their radius is 10 cm then find the volume of cylinder? a) 20365 cm3 b) 20256 cm3 c) 18054 cm3 d) None of these 83) If two friends Arun and Karan invested in the ratio of 3 : 5 for the time period of 1 : 3 then at the end of their investment Karan received 7200 more than Arun find the initial investment Arun? a) 1800 b) 9000 c) 3600 d) 7200 84) Sanjay and Ajay invested in the ratio of (7/2) :(9/8) for the period of 8 and 11 months respectively. If Sanjay received 2500 rupees more than Ajay find the initial investment of Ajay? a) 1800 b) 2000 c) 2500 d) 1980 85) If the speed of boat to the speed of stream is in the ratio 5 : 1 and the distance travelled in downstream is 120 km in 4 hrs then find the upstream speed of boat? a) 20 kmph b) 10 kmph c) 15 kmph d) 25 kmph 86) If two container having milk and water in the ratio of 3 : 2 and that in the second container it is 2 : 5 respectively. In what ratio must liquid of these two container must be mixed such that the final ratio of these liquid be 1 : 1 ? a) 31 : 39 b) 39 : 31


c) 1 : 1 d) 30 : 31 87) A mobile plan costs Rs 256 for 64 days. What is the approximate cost in Rupees, for 96 days? a) 424 b) 286 c) 384 d) 512 88) If a + b + c = 120 and a : b : c = 2 : 3 : 5 then find the value of a2 + b2 + c2 = ? a) 5462 b) 5472 c) 4728 d) 6000 89) If ( A + B + C ) : (A + B + 2C ) : ( A + 2B + C ) = 8 : 12 : 11 then find the value of (1/A) : (1/B) : (1/C) ? a) 12 : 4 : 3 b) 4 : 12 : 3 c) 3 : 4 : 12 d) Cannot be determined 90) If ( P - Q + R ) : ( Q-P+ 2R ) : ( Q + 3R ) = 3 : 3 : 5 then find the value of P*Q*R ? a) 0 b) 1 c) 2 d) 3 91) Rupees 62000 is to be divided between A, B and C such that A received 2/11 of B and C received 5/22 of B then find the amount received by B? a) 33000 b) 22000 c) 11000 d) 44000 92) In an office the ratio of male to female is 4 : 5. 25% of the female population is post graduated and 60% of the remaining is graduated while the remaining is uneducated whose number is 320. Find the male post graduated population who are 75% of total female population? a) 900 b) 600 c) 750 d) 500 93) If the average weight of three persons say A,B and C is 36 kg and ratio of their weight is 2 : 3 : 4 but it was later found that machine has some technical glitches and the actual weight ratio was 3 : 5 : 2. Find the change in weight of B? a) 24 kg b) 30 kg c) 60 kg d) 36 kg 94) If a : b = 5 : 2 , b : c = 3 : 5 and a : d = 3 : 8 then find the value of (a2 + d2) : (b2 + c2) ?


a) Cannot be determined b) 185 : 136 c) 185 : 136 d) 1825 : 136 95) If the ratio of three numbers a, b and c is 2 : 3 : 4 and the product of them is 5184 then find the sum of these three numbers? a) 54 b) 36 c) 28 d) 12 96) If ‘V’ is the vacancy of SSC-CPO 2020 in which the ratio of open to reserved vacancy is 13 : 1.If 20 vacancy still not filled in reserved seats when 216 candidates were allotted their preferred posts then find the number of vacancy ‘V’ ? a) 3000 b) 3304 c) 2500 d) 3500 97) If the age of Rahul and Sonia is in the ratio of 2 : 5.After two years their ratio becomes 3:5.Priyanka who is younger to Rahul is same young to Rahul as Sonia is young to Rajiv.Find the ratio of age of Rahul to Priyanka? a) Cannot be determined b) 2 : 5 c) 5 : 2 d) 8 : 7 98) If a : b : c = 3 : 2 : 1 and a2 + b2 + c2 = 504 then find the value of ( a2 + 2a ) : ( b2 + 2b ) = ? a) 5 : 6 b) 7 : 15 c) 15 : 7 d) 2 : 5 99) Rupees 18900 is to be distributed such as A got 2/5 times of (B + C) while B got 2/7 time of (A + C) then find the amount received by A? a) 5400/- b) 6000/- c) 5000/- d) Cannot be determined 100) If the profit % of an article is 12.5% while the Discount % of the article is 20% and the difference between MP and CP is rupees 260 then find the Profit of an article in rupees? a) 100/- b) 120/- c) 200/- d) 80/- 101) If a: b = 3 : 2, b : c = 6 : 5 and c : d = 2 : 9 find the ratio of a : d? a) 2 : 5 b) 5 : 2 c) 2 : 3 d) 4 : 5


102) The sum of two number’s A and B is 30.If A is 5 more than B .Find the ratio of A and B? a) 3 : 2 b) 2 : 3 c) 5 : 2 d) 4 : 5 103) Two numbers are in ratio 3 : 7. If both being the multiple of 5 and 3 then find the numbers respectively? a) 45 and 105 b) 105 and 45 c) 123 and 111 d) Can’t be determined 104) The two number’s are in ratio of 7:9.If both the numbers are increased and decreased by 20% respectively then find the ratio of new numbers? a) 6 : 7 b) 7 : 6 c) 5 : 7 d) 3 : 4 105) A number when divided into two parts in the ratio of 12 : 17. Due to which the greatest number becomes 15 more than the smaller. Find the original number? a) 87 b) 96 c) 88s d) 97 106) If A : B = 2 : 3, B : C = 9 : 8 , C : D = 2 : 5 . If the difference between A and D is 7 then find the sum of A and D? a) 39 b) 26 c) 52 d) 48 107) If A is 50% of B.B is 100% more than C and C is 75% of D then what is the ratio of A and D? a) 3 : 4 b) 4 : 3 c) 5 : 2 d) 5 : 7 108) Three numbers are in the ratio of 2 : 5 : 7. If the average of first and third number is 27 then find the ratio of sum to the product of numbers? a) 1 : 180 b) 180 : 1 c) 27 : 92 d) 95 : 112 109) What is the third proportion of 10 and 30? a) 90 b) 45 c) 25 d) 35 110) Two numbers say a and b are in the ratio of 5 : 4. If a is first increased by 25% then


decreased by 20% while b is first decreased by 25% and increased by 20% then find the new ratio? a) 5 : 4 b) 4 : 5 c) 1 : 3 d) 2 : 3 111) The age of A and B is in the ratio 5:6.Before 38 years ratio was 6:11.Find the present age of A? a) 50 years b) 45 years c) 47 years d) 78 years 112) A is thrice of B who is twice of C. If the difference of A and C is 20 years then find the age of B after 7 years? a) 15 years b) 20 years c) 10 years d) 12 years 113) In a beaker, Solution A consists of water and wine in the ratio of 3 : 8. On adding 8 litres of wine it becomes 5 : 16? a) 40 litres b) 35 litres c) 45 litres d) 30 litres 114) Container A has 25% water in it and remaining is sanitizer. On adding 16 Litre of water ratio gets reversed. Find the initial Quantity of Solution? a) 8 litres b) 10 litres c) 6 litres d) 12 litres 115) The ratio of radius of circle to the side of square is 7 : 5. The circumference of circle is 308 cm. Find the perimeter of square? a) 140 cm b) 70 cm c) 280 cm d) 150 cm 116) Two circle say C1 and C2 with radius in the ratio of 4 : 3. If the perimeter of the bigger circle is 176cm then find the perimeter of smaller circle? a) 132cm b) 156cm c) 121cm d) 120 cm 117) The weight of the two person A and B is in the ratio 5 : 8. The average of their weight is 39 kg. Find the difference of their weight? a) 18 kg b) 24 kg c) 12 kg


d) 16 kg 118) In a school, the ratio of girls and boys is 4:5. When 100 boys leave the school, the ratio becomes 6:7. How many girls are there in the school? a) 1200 b) 1500 c) 1800 d) 1600 119) A fraction bears the same ratio to 1/3 as 8/7 does to 8/11. What is the fraction? a) 11/21 b) 21/11 c) 11/3 d) 3/11 20) If A : B : C = 9 : 8 : 6.Find the value of (1/A) : (1/B) : (1/C) ? a) 9 : 8 : 12 b) 8 : 9 : 12 c) 9 : 8 : 7 d) 8 : 7 : 9 121) If (A + B) : (B + C ) : ( C + A ) = 8 : 7 : 6 .Find A:B:C ? a) 4 : 4 : 3 b) 3 : 4 : 4 c) 4 : 3 : 4 d) 1 : 2 : 4 122) If ‘X’ is subtracted from each of the numbers 22, 46, 18 and 34 then they will be in proportion find value of ‘X’? a) 10 b) 8 c) 15 d) 17 123] LNCT, Bhopal is having seats of civil, mechanical and electrical branch in the ratio of 3 : 4 : 7. If there is an increment of 30%, 40%, 50% respectively in it then find the new ratio of seats? a) 52 : 42 : 105 b) 105 : 42 : 52 c) 40 : 30 : 70 d) 20 : 30 : 50 124) There are two numbers a and b. If 40% of 3/8 of a is equal to 62.5% of 3/11 of b is equal then find the ratio between a and b? a) 25 : 22 b) 22 : 25 c) 100 : 23 d) 24 : 25 125) In a city the ratio of male to female is in the ratio of 5 : 8. 40% of the city females are employed and 60% of the city people are male. Find Ratio of unemployed male to female? a) 5 : 12 b) 1 2 :5 c) 5 : 13 d) 6 : 17


126) A is 8 more than B who is 16 more than C and ratio of A : C = 4 : 1. Find the value of A + B + C? a) 64 b) 32 c) 128 d) 57 127) If a number ‘X’ is added to 42, 140, 50 and 164 they will be in proportion then find the value of X? a) 7 b) 1 c) 3 d) 4 128) If a building having ‘N’ number of flats, ratio of broadband users to non broad band users is 10 : 7. If the ratio of AIRTEL to BSNL user is in the ratio of 7 : 3. If the difference between non-user to BSNL is 100 then find the value of ‘N’? a) 425 b) 400 c) 500 d) 900 129) Marks scored by Sumit in Maths, Science, English is in the ratio of 9 : 8 : 7. If the average marks is 80 then find the marks scored in maths? a) 90 b) 70 c) 80 d) 60 130) Find the ratio of mean proportion of 81 & 64 to the third proportion of 20 & 30? a) 8 : 5 b) 5 : 8 c) 5 : 6 d) 4 : 7 131) Indian Army has tank to missile is in the ratio of 5: 6. If due to some terrorist activity 40 tanks were destroyed and 32 missile were launched such that the new ratio becomes 3:4 then find the number of initial tanks ? a) 160 b) 320 c) 140 d) 170 132) In a notification of SSC stated vacancy in the ratio of 18 : 5 which means on every 18 vacancy there is 5 vacancy reserved for ex-service men. If the number of application by ex-service men was 5000 and 4350 were rejected till final round then find the total vacancy? a) 2340 b) 2400 c) 2380 d) 2540 133) (A + C) : (B + C ) : C = 7 : 9 : 5. Find the value of C - A if A is greater than by B by value 8? a) 12


b) 21 c) 8 d) 6 134) An article with MP : CP = 9 : 5 and also profit = 26%. Given is the MP is 540 more than SP. Find the CP? a) 1000 b) 800 c) 900 d) 1200 135) The Speed of boat to the stream is in ratio of 8 : 1. If boat speed is increased by 25% then it will cover downstream distance in 10 hours. (Distance of 220 kms).Find the Actual speed of boat a) 16 kmph b) 20 kmph c) 12 kmph d) 18 kmph 136) A village has population of ‘P’ in which voter to non-voter ratio is 8 : 9. In which male voters to female voters ratio is 2 : 3. If the difference of non - voters to female voters is 1800 then find the total population ‘P’? a) 5100 b) 2700 c) 6800 d) 5900 137) A sum of money s divided among A,B,C in such a way that 5 times A’s share, 3 times of B’s share and 2 times C’s share are equal .The ratio between the share of A,B,C is. a) 5:3:2 b) 2:3:5 c) 6:10:15 d) 15:10:6 138) A bag contains some eggs in it. After 10 minutes he buys some mangoes and now the ratio of egg to mangoes becomes 4 : 7 after some time he buys a dozen of orange and now the ratio becomes 8 : 11 : 6.Find the number of eggs in the bag? a) 16 b) 20 c) 12 d) 19 139) A container has 37.5% of water in it and rest is pure milk. If Anil puts 20 litre of pure milk in it then water will be 25% in it then find the initial quantity of water? a) 15 litres b) 9 litres c) 10 litres d) 12 litres 140) Two number’s say A and B are in the ratio 3:8. If A is 24 then find the value of B? a) 64 b) 36 c) 81 d) 58


141) Income of A and B is in the ratio 4: 3 and that of saving is 3 : 2. If the expenditure of A is 2500 then find the income of B? a) 7500 b) 5000 c) 10000 d) 1200 142) If ( A + B ) : ( A - B ) = 7 : 5 then find the ratio of 2A : 3B ? a) 4 : 1 b) 1 : 4 c) 3 : 4 d) 3 : 5 143) Two person A and B entered into partnership with the initial investment of 8 : 9 and that of time being is 8 : 5.if the profit of A is 16000.Find the initial investment of B? a) 11250 b) 12250 c) 12500 d) 13500 144) The prices of a Mobile and a refrigerator are in the ratio of 6:7.If a refrigerator costs 3000 more than a Mobile, then find out the price of Mobile a) 18000 b) 21000 c) 24000 d) 20000 145) If (a/d) = (b/e) = (c/f) = 5 : 1 then find (a + b + c) : (d + e + f ) = ?? a) 15 : 1 b) 1 : 15 c) 5 : 1 d) 5: 8 146) What value must be decreased from 6 : 7 to obtain 7 : 6? a) 13 b) 10 c) 2 d) 9 147) The price of a petrol is decreased by 6.66% due to which sale was increased by 10%.If initial price was 64/- then find the new revenue? a) 660 b) 640 c) 650 d) 655 148) If the ratio of income of P and Q is 3 : 1.The ratio of their expenditure is in ratio of 8 : 3 and the ratio of their saving is 4:1. The sum of their saving is 5000.Find the income of P? a) 12000 b) 9000 c) 15000 d) 16000


149) A : B : C = 3 : 4 : 2.If C is increased by 50% while B is decreased by the same due to which C becomes 120. Find the value of A? a) 90 b) 120 c) 150 d) 170 150) The ratio of a article’s cost price and selling is 8 : 9. The CP of the article is increased by 50 rupees and that of SP is increased by 200 rupees the ratio becomes 11 : 13. Find the increased SP of the article? a) 2990 b) 2790 c) 2870 d) 2345 151) Find the mean proportion of 81 and 9 a) 18 b) 17 c) 23 d) 27 152) If x+2, x – 1, 4 and 3 are in proportion then find the mean proportional to x and 4x2 a) 15 b) 20 c) 10 d) 12 153) The ratio of men and women in a group is 5:2.If 6 men and 6 women left the group then the ratio becomes 8:3.Find the total number of people in the group initially? a) 220 b) 230 c) 210 d) None of the above 154) Income of A is 40% less than the income of B and expenditure of A is 40% of B’s expenditure. If income of A is 70% of expenditure of B then find the ratio between the saving of A and B. a) 8 : 15 b) 9 : 5 c) 9 : 25 d) 7 : 13 155) Some amount Rs. x was divided among A, B, C and D in the ratio 1/5 : ½ : 1/3 : 1/4. If the difference between the shares of A and C is Rs.560 then find the total amount x (in rupees) a) 6000 b) 5480 c) 5390 d) 5400 156) Three numbers are in ratio 2 : 3 : 5. If the sum of the squares of those three numbers is 342 then find the sum of the three numbers a) 50 b) 40 c) 30S


d) 60 157) If A : B = 4 : 5 and C : B = 7 : 6 then find the ratio between A : B : C a) 24 : 5 : 30 b) 24 : 30 : 35 c) 24 : 35 : 30 d) 30 : 35 : 24 158) The total number of 3 different colored pens in a box is 91. If the ratio between red colored and green colored pen is 5 : 2 and the number of green pen is 33 1/3% of blue pens then find the difference between the red colored and green colored pen. a) 28 b) 35 c) 21 d) 14 159) If the ratio of three sides of a triangle is 3 : 4 : 5 then find the difference between the smallest and largest angle. (in degrees) a) 30° b) 15° c) 45° d) 50° 160) If 4A = 5B = 6C then find the ratio of A : B : C a) 12 : 15 : 10 b) 10 : 12 : 15 c) 15 : 10 : 12 d) 15 : 12 : 10 161) If A is twice of B and C is twice of B then find the ratio of A:B:C is: a) 1 : 2 : 2 b) 2 : 1: 2 c) 2 : 3 : 4 d) 1: 2 : 3 162) If A : B = 5 : 4 and A is 19 more than B then find the sum of A and B. a) 175 b) 171 c) 185 d) 186 163) The ratio of marks obtained by Suresh in half yearly examination to Annual examination is 9/10. If he got 50 marks more in half yearly examination then the ratio would have been become 1 : 1. Find the total marks for which he wrote the half yearly exam if the mark obtained in the same exam is 45% of the total marks. a) 600 b) 750 c) 1000 d) 950 164) If A : B = 5 : 4 and C : B = 8 : 7 then find the value of A + B : B + C : C + A a) 63 : 60 : 67 b) 60 : 51 : 53 c) 63 : 54 : 52


d) None of the above 165) The ratio of number of boys and girls in a school is 2 : 3. If 30% of girls is 6 more than the 30% of boys then find the total number of students in the school. a) 80 b) 60S c) 70 d) 100 166) A bag contains 25 P coins 50 P coins and 1 rupee coins in the ratio 10: 5: 2, amounting to Rs. 112. Find the total number of coins in the bag. a) 242 b) 172 c) 272 d) 232 167) Find the third proportion to 16,64 a) 246 b) 236 c) 256 d) 634 168) If a/(b + c) = 1 : 2 then find the ratio between a/(a + b + c) a) 2/3 b) 3/4 c) 5/6 d) 1/3 169) If a/(b – c) = 3 : 2 then find the value of (a – b + c)/(a + b – c) a) 1/5 b) 2/5 c) 5/1 d) 5/7 170) The ratio between the passed to fail student in an exam is 3:4.If 10 more students passed the ratio would have been 23:19.Out of the students passed 1/3rd are boys then find the total number of girls who passed in exam. a) 44 b) 56 c) 36 d) 24 171) The ratio between the valid and invalid vote is 4 : 1. If 70% of valid vote is equal to 6300 then find the difference between the valid and invalid votes. a) 7450 b) 7250 c) 6650 d) 6750 172) The ratio between the prices of two articles is 5:6. If the price of first article is increased by 20% and the price of second by 33 1/3% then find the new ratio. a) 3:4 b) 4:3 c) 2:3


d) 3:2 173) Find the ratio of A, B and C if A is 30% more than B and B is 20% more than C. a) 39 : 34 : 25 b) 39 : 30 : 25 c) 29 : 30 : 25 d) 39 : 30 : 28 174) The number of people in a village is 6400. If the ratio between then male to female population is (x + 2) : (x + 4) then find the value of x a) 3199 b) 3201 c) 3197 d) 3204 175) If the ratio between A, B and C is 5 : 7 : 9 then find the ratio between 1/A, 1/B and 1/C. a) 63 : 47 : 35 b) 63 : 45 : 37 c) 63 : 45 : 35 d) 64 : 45 : 35 176) If a/7 = b/3 = c/5 then find the ratio between a,b and c a) 3 : 4 : 5 b) 3 : 6 : 7 c) 7 : 3 : 5 d) 5 : 7 : 3 177) Three persons A, B and C went to hotel and paid the bill amount of Rs. 600 in the following way. A paid half of the amount paid by both B and C , B paid 1/5th of the amount paid by both A and C then find the amount paid by C. a) 200 b) 300 c) 100 d) 400 178) The ratio between the number of pen and pencils is 5 : 6 and the ratio of cost of per pen and pencil is 4 : 3 then find the percentage by which total cost of pen is greater than the total cost of pencil. a) 12.23% b) 11.11% c) 13.15% d) 14.56% 179) If A : B + C = 2 : 5, B : A + C = 1 : 2 then find C : A + B? a) 8 : 13 b) 5 : 13 c) 13 : 8 d) 13 : 5 180) Total income of A and B is Rs.5000 if A save 20% and B saves 30% and their savings are in the ratio 4:9. Find their individual income. a) 1500, 3500 b) 1700, 3300 c) 1000, 4000


d) 2000, 3000 181) Ravi’s expenditure and savings is in the ratio 3 : 1 if the income increases by 50% and expenses increases by 20% then find the percentage increase in savings a) 75% b) 50% c) 100% d) 125% 182) If A and B is in the ratio 3:2 and the difference between them is 8 then find the difference between their squares a) 160 b) 280 c) 320 d) 480 183) The ratio between cost of two idly and one dosa is 2 : 5 and the ratio between cost of one idly and two dosa is 1 : 10 then find the ratio between three idly and two dosa. a) 2 : 15 b) 3 : 10 c) 3 : 20 d) 4 : 13 184) Some amount was divided among A, B and C in the ratio 4 : 6 : 9. If the share of A is 50 less than share of C then find the 1/5th of total amount (in Rs). a) 48 b) 38 c) 45 d) 35 185) Income of A and B is in the ratio 6 : 7, their expenses is in the ratio 4 : 3 if their savings are Rs.2000 and Rs.4000 then find the sum of their incomes (in Rs.) a) 12000 b) 14000 c) 13000 d) 13500 186) If the ratio of income of Raj and Raghu is y2/x2 and the ratio of their saving is y/x then find the ratio of expenditures a) y(y – 1)/x(x + 1) b) y(1 – y)/x(1 – x) c) y(y + 1)/x(x + 1) d) y(y + 1)/x(x – 1) 187) Rs. 1500 was divided among A and B such that if Rs.50 and Rs.25 is deducted from the shares of A and B respectively then the ratio becomes 34:23. Find the difference between their shares a) 350 b) 450 c) 300 d) 900 188) The ratio of number of hen to goat is 2 : 3 and the ratio of number of legs of hen and goat is 1 : 3. If the difference between the total legs of hen and total legs of goat is 80 then find the total


number of hens. a) 30 b) 12 c) 20 d) 24 189) If the ratio between the squares of A and B is 9 : 25 if the difference between their squares is 144 then find the value of A3. a) 64 b) 729 c) 1000 d) 512 190) The ratio of marks obtained by Ram and Raghu in an entrance examination is 4 : 5. Raghu score is 5 more than the cut off score and Ram score is 3 less than the cut off score then find the cutoff score. a) 32 b) 34 c) 35 d) 38 191) Sita and Geetha had some number of stones initially in the ratio 9 : 11. Sita gave some number of stones to Geetha then the ratio becomes 7 : 13 then find what fraction of stones are given to Geetha by Sita against her initial value. a) 6/7 b) 8/9 c) 2/9 d) 3/5 192) A and B contest in an election, if the ratio between the valid votes and the vote got by A is 5:3 and the ratio of invalid votes and vote got by B is 1:2 and the ratio between the valid and invalid votes is 5:1 then find the ratio between the votes got by A and B. a) 2:3 b) 2:1 c) 3:2 d) 1:2 193) A and B participated in an election. If the ratio between the valid and invalid votes is 6 : 1 and out of the valid votes if A got 20% of vote more than B then find the fraction of vote got by A out of total votes(including invalid votes) a) 5/11 b) 4/11 c) 36/77 d) 37/77 194) If the area of rectangle is 168 sq units and ratio between the length and breadth is in the ratio 14 : 3 then find the difference between the length and breadth. a) 24 b) 22 c) 14 d) 16 195) If A : B : C : D = 4 : 6 : 7 : 9 and A + C = 3454 then find the sum of A and B. a) 3250


b) 3140 c) 3540 d) 3658 196) If A : B = 4 : 5 , B : C = 8 : 9 and C : D = 6 : 7 then find the value of A : B : C : D a) 64 : 80 : 90 : 107 b) 65 : 80 : 90 : 105 c) 64 : 80 : 90 : 105 d) 64 : 81 : 90 : 105 197) Find the fourth proportion of 14, 18, 28 a) 26 b) 24 c) 36 d) 38 198) x varies inversely as square of y and given that y=4 for x=4.Find the value of x for y=8 a) 4 b) 6 c) 2 d) 1 199) The ratio of number of students in class A,B and C is 7:9:11.If the students increased by 10%,15% and 25% respectively in classes A,B and C then find the new ratio of students after increment. a) 144:207:275 b) 154:217:275 c) 154:207:275 d) 154:207:276 200) If the ratio between A and B is 7 : 13 and A increased by 24% and B decreased by 25% then find the revised ratio a) 168 : 329 b) 168 : 325 c) 168 : 345 d) 168 : 327 201) If (a + b)/c = 5/3 and (b + c)/a = 7/4 then find the value of (a + c)/b = ? a) 23/65 b) 65/23 c) 66/25 d) 56/25 20) The ratio of income of Arun and Varun is in the ratio of 7 : 9 while saving of them was 4000 and 6000 respectively. If the expenditure ratio of A is 83.3% of B then what is the total salary of both of them? a) 144000 b) 160000 c) 128000 d) 120000 203) In a school, 1600 students were there in which the ratio of boys to girls is 3 : 5.In a new academics session Some boys left and same number of girls took admission due to which the new ratio of boys becomes 87.5% of girls in which girls were 300 more than boys. Find the


number of girls in the new session? a) 900 b) 853 c) 870 d) 820 204) The Ratio of angles of a triangle is 3 : 4 : 5 while the ratio of radius of circle to the sum of two smaller angle is 1 : 7. Find the area of circle (approx)? a) 707 b) 700 c) 800 d) 807 205) If the sides of the cube are a, b and c. If we change its sides with increase 10%, increase 15% and decrease 10% respectively then find the percentage change in its volume? a) +13.8% b) -13.85% c) 20% d) 18% 206) Find how many people applied for the job if the ratio of selected to rejected candidate is 19 : 17. If 1200 less candidate applied and 800 less got selected then ratio becomes 1 : 1 ? a) 817 b) 880 c) 847 d) 820 207) If the ratio of present age of Ram to the age of Shyam is 3 : 2.The ratio of present age of Shyam to Kumar is 5 : 3.The average age (present) of all three of them is 31 years. Find the age of Ram four years back? a) 41 years b) 40 years c) 45 years d) 42 years 208) If the age of Ravi and Sohan is in ratio of 3 : 5.After ten years ratio of ages of Ravi, Sohan and Sujeet becomes 7 : 8 : 5 and average of their present age is 30 years then find the present age of Sujeet? a) 25 years b) 30 years c) 20 years d) 15 years 209) If the ratio of radius to the height of cone is 5 : 3 and ratio of volume of cylinder to the cone is 2 : 3. .If the radius of both shapes is being same and the radius of cone being 25 cms then find the volume of cylinder? a) 6547 cm3 b) 6580 cm3 c) 5901 cm3 d) 6501 cm3 210) Three numbers are in the ratio of 13 : 14 :9.When all of them were increased by 50% then the difference between first and last number is 120. Find the original numbers? a) 260,280,180


b) 280,180,260 c) 180,260,280 d) Cannot be determined 211) A square sheet of paper is divided into three equal sections and filled with two colors red and black in some ratio. If the ratio of red and black in the complete sheet is 5 : 7. Upper part of the sheet is having the ratio of 4 : 3 while the lower part is having the ratio of 2 : 5 then find the ratio of color in the mid-section if the red color in this section is equal to the total color in the lower part? a) 7 : 13 b) 10 : 7 c) 7 : 10 d) Cannot be determined 212) Arun, Varun and Karan invested in a business in the ratio of 3 : 5 : 2 for six months after which Karan left the business while Arun increases investment by 66 (2/3)% and after another 8 months they distributed their profit depending upon their investment ratio. Given is that Karan’s initial investment was 30000. If Arun pays 10% TDS then find the amount he left with him? a) 128500 b) 145000 c) 130500 d) Data insufficient 213) Two friends Amar, Bimar invested in business with initial investment 6 : 5 and after 8 months Bimar doubles his investment while Amar made his investment as Bimar’s initial investment and Kamar joins them with the initial investment 66(2/3)% of A’s initial investment and after another 10 months they distribute their profit in which Kamar received 15000 more than Bimar Find the profit of Amar ? a) 14,700/- b) 12,700/- c) 17,200/- d) 13,500/- 214) If the present age of Amit and Sumit is in the ratio of 5 : 8 after eight years ratio becomes 3 : 4. Ratio of Age of Sumit after two years to the age of son at present is in the ratio of 9:2. Find the present age of son? a) 4 years b) 6 years c) 2 years d) 8 years 215) If the ratio of milk to water in container A is 3 : 2 and that of in container B is 4 : 1 and the mixture in container A was half to that of final mixture of container B. Find the milk amount in container A if 10 litres of water is added to container B then new ratio becomes 2 : 3 ? a) 2 litres b) 4 litres c) 3 litres d) 6 litres 216) There are two bags A and B with balls of three different colors i.e red, blue and green. In bag A the ratio of these balls is 2 : 3 : 4 respectively while in bag B the ratio of the balls is 3 : 4 : 1. If 2 more balls were added to bag A then the ratio of balls in bag A to B becomes 5 : 2 and if 1 ball is added to bag B ratio becomes 2 : 1 Find total blue balls ?


a) 8 Balls b) 3 Balls c) 2 Balls d) 10 Balls 217) If (a – b + c ) : ( b – c + 2w ) : (2a + c – w ) = 3 : 4 :7 then find the value of (4a + 4c -2w) : w ? a) 10 : 1 b) 1 : 10 c) 5 : 2 d) 10 : 9 218) There are some passengers at Bhopal airport about to board for Mumbai and Delhi. If the ratio of passengers to board is 9 : 11 respectively. It is observed as in Mumbai flight the ratio of occupied to vacant seats is 2 : 3 while in Delhi flight the ratio was 13:9. If fare of one passenger was 5000 and Delhi flight has a loss of 90,000 due to vacant seats then find the total passengers at Bhopal airport ready to board? a) 80 b) 44 c) 66 d) 77 219) If the radius of the circle is increased by 40% then the new area will be 100 units more than the previous area. If the height of the cylinder is increased by 10% and radius by 25% then find the ratio of percentage change of area of circle to the percentage change of volume cylinder? a) 96 : 71.88 b) 96 : 79 c) 71.88 : 96 d) Cannot be determined 220) A sum of rupees 50000 was rewarded for lottery to three friend Amal, Bimal and Kamal. The ticket was purchased by Amal so Bimal and Kamal will pay sum of Rs.2000 from their winnings to Amal. The prize distribution in between them was in the ratio of 12 : 7 : 6. Find the total amount received by Amal? a) 24000 b) 26000 c) 25000 d) 27000 221) The cost of laptop to desktop is in the ratio of 5 : 4 and during the sale quantity sold of laptop to desktop were in the ratio of 3 : 5 also the sold to unsold desktop was 7 : 5. If the company had 100 desktops left and 20 desktops were returned due to defect then find the cost of one desktop? a) Cannot be determined b) 5000 c) 2900 d) 4000 222) A sum was divided between four friends Anu,Kanu, Ranu and Banu. If Anu gets 37.5% that of Kanu and Kanu gets twice that of Banu while Banu gets 33.3% less than that of Ranu. In the end when then check their amount it was observed that difference in amount of Anu and Ranu was 600. Find the Amount received by Kanu? a) 600 b) 800


c) 1600 d) 1500 223) In SSB selection, selection percentage of candidate was 60%. If 50 more applied and 20 less selected then percentage of rejected candidate will be 60%. How many candidate has applied for it? a) 150 b) 100 c) 200 d) Cannot be determined 224) Rs.12000 is divided among A, B and C such that A gets 3/4 of (B+C) and B gets 5/6 of (A+C) then find the approx amount given to B ? a) 5454 b) 5000 c) 5400 d) 5600 225) Three persons P, Q, R spend 75%, 70%, 80%of their income. Their saving ratio is 20 : 9 : 8. Find the total amount of their income is 45,000 then find their incomes. a) 24000, 9000, 12000 b) 9000, 24000, 12000 c) 24000, 15000, 10000 d) 15000, 15000, 15000 226) If the compound ratio of [(3a + 2b): 3] and [1:(3a+ b)] is 2:5,then find the ratio between a : b.? a) 1 : 2 b) 3 : 4 c) 4 : 3 d) 2 : 1 227) The ratio of a two-digit natural number to a number formed by reversing its digits is 7 : 4. Which of the following is the sum of all the numbers of reverse pairs? a) 94 b) 320 c) 188 d) 120 228) Ram, Shyam and Sundar sitting on dining table. Ram has 7 eggs and Shyam has 8 eggs. Sundar requested them to share their food and he gave money. Three of them share their eggs equally and Sundar paid other two a total of rupees 50 find the amount received by Ram and Shyam respectively? a) 20 and 30 b) 15 and 35 c) 30 and 20 d) 35 and 15 229) Four buckets having capacity of 200 ml, 350 ml, 470 ml and 650 ml. 2505 ml of water is poured into them so that same fraction of each bucket will be filled. The volume field in small bucket will be? a) 300 b) 500 c) 400


d) 450 230) The manufacturing cost of television is fixed and partly variable. If the expenditure were Rs. 13400 for 150 TV and Rs. 15000 for 180 TV what would be ratio of 240 TV to 270 TV? a) 81 : 91 b) 91 : 93 c) 91 : 99 d) 19 : 21 231) Student got an aggregate of 40% marks in five subjects in ratio of 10 : 9 : 8 : 7 : 6. If passing marks are 35% of maximum marks and each subject has same mark. In how many subject did he pass the exam? a) 2 b) 3 c) 4 d) 5 232) Two men are climbing up on moving escalators which have 240 steps. Ratio of first person to first escalator is 2 : 3 and ratio of second person to second escalator is 3 : 5 find total numbers of steps they both have taken? a) 158 b) 186 c) 196 d) 165 233) In a zoo there are lion, elephant and dog in the ratio 5 : 7 : 3 if number of elephant was more than number of dog by a multiple of both 3 X 21, then what is minimum number of animals in zoo? a) 835 b) 744 c) 925 d) 945 234) The ratio of a and b money is same as ratio of X and Y money. The ratio of difference of money of a and b to X and Y is 3 : 2. What is the sum of money of x + y to a + b? a) 4 : 3 b) 2 : 1 c) 2 : 3 d) 1 : 2 235) If ratio of men and women in a factory is M and ratio of women to men is N. Then find the value of 7(M+N)? a) Equal to 4 b) More than 14 c) Less than 8 d) Less than 12 236) If a : (b + c) = 3 : 4, and c : (a + b) = 8 : 13 then find out the value of b : (c + a) = ? a) 4 : 17 b) 10 : 1 c) 1 : 10 d) 13 : 10 237) If a, b and c are real number 9a2 + 8b2 + 9c2 = 12*b (a + c) then find a : b : c ?


a) 1 : 2 : 3 b) 6 : 3 : 1 c) 2 : 3 : 2 d) 3 : 1 : 2 238) Due to covid-19 Netflix increases the price of plans. Gold plan increases 25%, silver plan increase 12.5% and Platinum plan increases 40% if the collection of one month subscription is 218983 then find the collection of Platinum, given that the ratio of price of silver gold and Platinum is 5 : 9 : 12 (increased price). a) 109665 b) 44800 c) 14400 d) Data insufficient 239) The duration of railway journey varies as the distance and inversely as a velocity. The velocity varies directly as the square root of the quantity of coal used and inversely as the number of carriages in the train. In a journey of 60 km in 2 hour with 20 carriages 169 kg of coal is required. How much coal will be consumed in a journey of 42 km in 78 minutes with 10 carriages? a) 60 b) 65 c) 49 d) 70 240) A man left a sum of rupees 39000 to be distributed after his death among his widow, five sons and four daughters. If each son receives three times as much as a daughter receive and each daughter receives twice as much as their mother receives, then what is the widow's share? a) 1000 b) 2000 c) 3000 d) 4000 241) The cost of gold varies with square of its weight. Gold is broken into 3 parts whose weight are in the ratio 3:4:5 if gold had been broken into three parts whose weight are in the ratio 9: 5 : 2 then there would have been a father profit of 152000 what is the actual cost of gold? a) 2225600 b) 3125000 c) 1176340 d) 1843200 242) A virus inside a human organ can triple itself at every second. Then the ratio of the number of viruses at 31 seconds and 34 seconds is - a) 2 : 11 b) 1 : 17 c) 1 : 27 d) 2 : 17 243) The ratio of number of 2 rupees coins and 5 rupees coins that Moni has is 6 : 11. If the number of 5 rupees coins is halved, then she will have an amount of Rs. 790. How many 2 rupees coins does Moni have? a) 80 b) 120 c) 125 d) 110


244) A box of chocolates containing 16 chocolates was given to each of the children A, B, C and D. When asked about the ratio of 'no. of chocolates eaten' to the 'no. of chocolates not eaten', they gave the following answers 1)5 : 3 2) 1 : 2 3) 1 : 4 4) 3 : 4 One of them was lying. Who is he? (here, eaten means completely eaten) a) 1 b) 2 c) 3 d) 4 245) Ram, Shyam and Raman get their salary in the ratio 3 : 5: 7. If Ram and Shyam get Rs.2000 after 25% canteen expenses cut from their salary. How much money Raman will get if he don't takes canteen food? a) 2333.3 b) 2000 c) 2500 d) 2111.1 246) If a + b + c = 1 and ab + bc + ca = 1/3 then the value a:b:c will be ? a) 1 : 2 : 2 b) 1 : 1 : 1 c) 1 : 2 : 1 d) 1 : 2 : 3 247) The angles in a quadrilateral PQRS are such that angle S is fourth proportional of angles P, Q and R. If the ratio of angles Q and P is 5 : 4, and angle S is 125°, find the measure of angle R? a) 70 b) 80 c) 90 d) 100 248) A sum of money is to be divided equally among Hamid, Jamal, Karan and Vinay in the respective ratio of 2 : 5 : 7 : 9 and another sum of money is to be divided between Priya and Garima equally. If Priya got Rs. 1800 less than Hamid, then how much amount did Karan receive? a) 1200 b) 1300 c) 1400 d) Cannot be determined 249) If (sin x + cos x)/ (sin x - cos x) = (10 + 131/2)/(10-131/2) then find the value of tan x ? a) 0 b) 1 c) 2 d) None of these 250) In a cricket match, team A scored 232 runs without losing wicket. The score consisted of byes wide and runs scored by 2 opening batsman Monu and Sonu. The runs scored by two batsman are 26 times wide. There are 8 more byes than wide. If the ratio of runs scored by


Monu and Sonu is 6 : 7 then the run scored by by Sonu Is - a) 78 b) 96 c) 112 d) 110

Answers

1) Answer: A Solution: Let the two number’s be 3x and 2x. According to the given question we will make equation. (3x+2)/(2x+4) = ¾ 12x + 8 = 6x + 12 12x – 6x = 12 – 8 6x = 4 x = 2/3 So, the bigger number will be 3x = 3(2/3) = 2 2x = 2 (2/3) = 4/3 = 1 1/3 Hence the biggest number is 2 2) Answer: A Solution: Let the ratio of the present age of Ram and Shyam = 2 : 5…………(1) Ratio of their age’s after 3 years will be = 3 : 7……………….(2) As we know that difference between their age will always remains constant. So from eq(1) We can see difference is 3 while from eq (2) we can see difference of 4. So we need to make them same so by multiplying eq (1) by 4 and eq (2) by 3. Present age ratio become 8 : 20 After 10 years ratio 9 : 21 Now we can say that 1 unit = 3 years Present age of Ram = 8 * 3 = 24 years. Aayam who is 10 years older, his present age will be 34 years. So age of Aayam 5 years back will be 29 years. 3) Answer: C Solution: Given the ratio of Boy and Girl is 3 : 7 Total students = 200 Boys = 60 and Girls = 140 So from above we can say that if there are 100 students then 70 will be girls and 30 will be boys.

Girls : Boy 140 : 60

Absent 42 : 6 Present 98 : 54 Hence the girls present in the class are 98. 4) Answer: A Solution: The ratio of CP and SP is 5 : 7 ----------- (1)


The ratio of MP and Discount is 20 : 6 ---------- (2) So from eq (2) we can say that if MP is 20 and Discount is 6 then SP will be 14 but from eq (1) we can see that SP is 7. So now we need to balance this value. We will multiply eq (1) by 2. So the new ratio we be as, CP : SP : MP : D = 10 : 14 :20 : 6 ----------- (3) So the difference of SP and CP is profit which is of 4 units and this is equal to profit 100 4 unit = 100 1 unit = 25 SP = 14 units SP = 14 * 25 = 350 5) Answer: B Solution: Ratio of speed of car to bus = 5 : 3 Since bus covers 200km in 4 hrs then it’s speed is 50 kmph. Car (5x) → 50 kmph Bus (3x) → 30 kmph Time = Distance / Speed Time = 270km/ 30kmph = 9 hours 6) Answer: B Solution: Speed of three car’s say C1, C2, C3 are in the ratio of 2 : 4: 5 As we know that if the distance is same then time ratio will be inversely proportional to that of speed. So first we will take LCM of (2, 4, 5) = 20 units This 20 units we be treated as a common distance. So now we have speed of all three car’s and distance. So by dividing Distance by their speeds we will get time ratio’s. Time ratio will be 10 : 5 : 4 7) Answer: A Solution: Profit percent = 12.5% = 1/8 ……………………..(1) So from this we can say that there is profit of 1 unit, CP of 8 units and SP = 9 units. Discount percent = 16.66% = 1/6………………………..(2) So from this we can say that MP = 6 units, Discount = 1 unit and SP 5 units So again we have two value of SP, multiply eq (1) by 5 and eq (2) by 9 We get the ratios as follows- CP : SP : MP : P : D = 40 : 45 : 54 : 5 : 9 So the difference between the MP and CP is 14 units which is equal to 70 value. So 1 unit = 5 value SP = 45 units * 5 = 225/- 8) Answer: B Solution: A : B = 8 : 7 Let x be the common multiplier then A : B = 8x : 7x A = B + 21 8x = 7x + 21 X = 21


A + B = 8x + 7x = 15x =15(21) = 315 9) Answer: A Solution: A person has some rupee notes in his pockets of 10, 20, 50 in the ratio of 5 : 6 : 8., Let’s find the total amount = ( 10*5 + 20*6 + 50*8 ) = 570 units This money will be distributed between two daughters as 3 : 2 (younger receives less) 2*570/5 = 230 units Elder receives = 340 units Given 230 units = 4600 So 1 unit = 20 So total 570 units = 570 * 20 = Rs. 11,400 10) Answer: A Solution: So we will be taking ratio as given, A : B = 6 : 5 ………………(1) B : C = 3 : 2 ……………(2) So again we will balance the ratio by multiplying eq (1) by 3 and eq (2) by 5 we get A : B : C = 18 : 15 : 10 D will get 50% of (A + C) So D will get 14 units. Difference of B and D is 1 unit and this will be equal to 250 Hence income of A is 18 units, so actual value will be 18*250 = 4500 11) Answer: D Solution: So the initial quantity was 2 litre I.e 2000ml Ratio of pure milk to water is 4 : 1 So we can see that milk will be 1600ml and water will be 400ml. If he consumes only 1500ml of it then Milk – 1200 ml; Water – 300 ml 12) Answer: B Solution: Initial distribution of his will between two son’s = 2 : 3 …(1) New distribution of his will between two son’s = 3 : 5 …….(2) So from eq (1) we can say that total property will be 5 units and that of from eq (2) will be of 8 units. So we will take LCM (5, 8) = 40 units. So initial ratio on the basis of 40 units will be 16 : 24 Final ratio on the basis of 40 units will be 15 : 25 So the reduction will be of 1 unit which is equal to 2 lakh. Hence the actual property which is 40 units will be 40 * 2 = 80 lakh 13) Answer: A Solution: A/2 = B/3 = C/7 (Given) Taking two terms at a time and making ratio’s we get, A : B = 2 : 3 B: C = 3 : 7 So the ratio’s become A : B : C = 2 : 3 : 7 To find, (A + B) : (B + C) : (C + A) , we will put value’s in it as this will not affect the actual ratio


because it is in ratio. 5 : 10 : 9 14) Answer: A Solution: Initial ratio of pass to fail 11 : 5 ……………(1) Final ratio of final to pass 3 : 7 ……………..(2) This ratio is changed because 62 students less than becomes pass but we can see that there must be no change of fail. So we will balance fail unit in both equations. New ratio(s) Initial 77 : 35 Final 15 : 35 (77-15) units = 62 value So 1 unit = 1 value. So initial pass students will be 77 students. 15) Answer: A Solution: Initial prices of their article (A and B) was in the ratio 5 : 8. Initial price of Product A = 5x Initial price of Product B = 8x After Increment the new prices will be 5x * (100+ x)% = 7 8x * (150/100) = 10 {5x (100+x)/100}/ {8x(150/100)} = 7 / 10 100+x=21*8 On solving above equation We will get X = 68% 16) Answer: A Solution: Given the ratio of male to female is 7 : 8

Male : Female 7: 8

Work : Remove Work : remove 5 : 2 5 : 3 So the difference between working men and removed men will be of 3 units which is equal to 150. Then 1 unit = 50 value Total employees are 15 unit = 15 * 50 = 750 employees 17) Answer: A Solution: Ratio of circumference of circle to perimeter of rectangle = 11/3 ( 2πr) : {2(l+b)} = 11 : 3 On solving above we get , l+b=6 2πr/2*6=11/3 22*r/7*6=11/3 R=7 Circumference of circle =2πr=44 18) Answer: A Solution:


Ratio of age of Amit and Ramit is 3 : 1 …………………..eq (1) Ratio of age of Ramit and Sumit is 2 : 1 …………….eq(2) So balancing Ramit age by multiplying eq (1) by 2 and eq (2) by 1 we get ratio as Amit : Ramit : Sumit = 6 : 2 : 1 Given is the difference of Amit and Sumit age which 10 years. So 5 unit = 10 years 1 unit = 2 years. Present age of Ramit = 2 *2 = 4 years. 19) Answer: B Solution: Ratio of investment of A and B = 3 : 5 Time Ratio of their investment = 15 : 18 Total investment = investment * time Total investment of A and B = 1 : 2 Difference of their profit is 1 unit which is equal to 1500/- . So total profit is 3 units Total profit = 4500 20) Answer: B Solution: Let share of A=x Then B share=x+40 And C share=x+40+80=x+120 A+B+C=400 X+x+40+x+120=400 3X=240 X=80 Required ratio=80:120:200 =2:3:5 21) Answer: A Solution: Let’s take the ratio of male to female = 50 : 40 Male Female 50 : 40 UG : PG UG : PG 12 : 28 25 : 15 Given is the boys who are graduate is 240. Here from ratio, we can see that boys who are under graduates are 12 units. So we can say that 12 units = 240 1 unit = 20 Total students = 90 units Total students = 90 * 20 = 1800 22) Answer: A Solution: The given ratio of apples, oranges and banana in the ratio of 2 : 5 : 8. So the total fruits will be 15 units. Difference between orange and apple is 3 units and this must be a multiple of 6 and 8 (minimum) Taking LCM of (6, 8) we get 24 no’s So this 3 units will be equals to 24 no’s 1 unit = 8 no’s Total fruits = 15 * 8 =120 fruits (minimum)


23) Answer: A Solution: The ratio of Curved surface area of cylinder to the area of circle is 22 : 7. (2πrh) : (πr2) = 22 / 7 h : r = 11 / 7 So the difference of h and r is 4 units which is equal to 4 cm. So 1 unit = 1 cm Volume of cylinder = πr2h = 22*11*7*7/7 = 1694 cm3 24) Answer: A Solution: Container A contains mixture in the ratio of 3 : 4. Container B contains mixture in the ratio of 5 : 8. Mixture in B is 182L Alcohol in Mixture B =8/13*182=112 Since it is given that both the container having is same alcohol concentration Alcohol concentration in Mixture A=112 . Total Mixture in A is 4/7*x=112 Mixture in A =196 Water concentration in Container A=196-112=84 25) Answer: A Solution: Distance AB = 120 kms Time taken in upstream = 12 hours Time taken in downstream = 10 hours Since Distance is same so we can take ratio of time,

Us : Ds Time 12 : 10 Speed 10 : 12 Upstream = 10x Downstream = 12x Speed of boat = (10x + 12x)/2 = 11x/2 Current speed = (12x – 10x)/2= x/2 Percentage = {(x/2)/ (11x/2)}= 1 / 11 = 9(1/11)% 26) Answer B Solution: Minimum score to pass the exam = 40% Amit score 20% more than passing marks = 48% Sumit score 62.5% less marks than Amit = 18% Ramit score average marks of Amit and Sumit = (48 +18)/ 2 Marks scored by Ramit = 33% Now to score minimum passing marks Ramit needs to score 7% more marks on 33% So the required percentage = 7 / 33 Required marks = 21% (approx) 27) Answer: A Solution:

Arun : Barak : Clara


Investment 3 : 5 : 3 Time 6 : 6 : 6 After 6 months 6 : 10 : Left Time 6 : 6 : 6 After taking above ratio’s into consideration, we will form total investment ratio’s Final ratio’s 3 : 5 : 1 Since it is clearly seen that investment of C is 4 units less than B so , Percentage less profit = 4 /5*100 = 80% 28) Answer: B Solution: Boys : Girls 8 : 13 60% boys goes to school trip = 60% of 8 = 4.8 boys 30% girls of total students goes to school trip = 6.3 girls Boys who doesn’t go to trip = 3.2 Girls who doesn’t goes to trip = 6.7 Total students who doesn’t goes to trip = 9.9 Percentage = 9.9/21 = 47% 29) Answer: A Solution: Volume of cylinder = πr2h

Old New Radius 9 : 10 (Radius)2 81 : 100 Height 6 : 5 Since from formula we can see that volume is independent of pi and radius varies with square while height varies directly. Old volume = 81*6 = 486 unit3 New volume = 500 unit3 Change = 14 unit3 Percentage change = (14/486)*100 = 2.88% 30) Answer: A Solution: Let the present age’s are A, B and C According to the first statement, A + 4 + B + 4 = B + C + 16 A - C = 8 …………………..eq (1) According to the second statement, A - 4 + C - 4 = 32 A + C = 40……………….eq (2) On solving above equations we get A = 24 and C = 16 years. 31) Answer: A Solution: Third proportion is calculated as - 12 / 30 = 30 / X X = 75 Mean proportion is calculated as – Mean proportion= √16*25 Mean proportion = 20 So the ratio between third proportion and mean proportion is 15 : 4


32) Answer: A Solution: Given ratio of balls is 3 : 4 : 5 Let’s assume total balls are 12 units. Step: 1. when three white balls are painted into red. Red balls becomes 6 and white becomes 2, blue remains same. Step: 2. Now one red ball is painted into blue. Such that the new ratio of balls becomes, 5 : 5 : 2 So the blue balls were 15 in number which is equal to 5 units 1 unit = 3 balls 12 units = 36 balls. 33) Answer: C Solution: Deducing the language into ratio’s R : K = 3 : 1 K : L = 3 : 2 Balancing the ratio’s we get R : K : L = 9 : 3 : 2 Average age of all = 28 years Sum = 84 years 14 units = 84 years 1 unit = 6 years Present age of Kavi = 18 years Age 3 years back = 15 years. 34) Answer: A Solution: Ram : Shyam: Raju Initial investment 3 : 5 : 6 Total time 12 : 24 : 12 Final investment 3 : 10 : 6 Difference in the investment of Ram and Raju is 3 units which is equal to 4500/- So 1 unit = 1500/- Investment of Raju was 6 units = 6 * 1500 = 9000/- 35) Answer: D Solution: Six year ago saravana’s age=2x Six year ago pavi’s age =3x 3x+10/2x+10=8/7 5x=10 X=2 Present Saravana age =2x+6=10 36) Answer: C Solution: From question we can calculate speed of Bus = 75kmph Now this 75kmph is not actual speed it is incremented speed by 25%. So actual speed = 75*100/125 Actual speed = 60kmph From ratio we can conclude if 3 unit = 60kmph so 5 unit = 100 kmph


37) Answer A Solution: Given is the ratio of principle to the S.I of two years - 10 : 3 So Rate for two years can be calculated as 3 *100 / 10 = 30% Since we can say that Rate is 15% per year. CI for two years on rate being 15% is calculated by successive as 15 + 15 + 15*15/100 CI for two years = 32.25% Ratio of CI to principle 32.25 : 100

3225 : 10000 38) Answer: A Solution: Male to female population ratio 7 : 9 Unmarried male population will be 55% of 7…………….(1) Married couple who don’t have any child will be 45% of 25% of 16……………..(2) Taking ratio’s of eq (1) and eq (2) ( 55 * 7 /100 ) = (45 * 25 * 16) /(100*100) Required ratio will be 77 : 36 39) Answer: A Solution: Let the original number’s be 3x and 5x. (3x - 2)/(5x - 2) = 1/5 On solving above we get x = 4/5 Such that number’s will be 12/5 and 4. Now if 4 is added to the original number. So we get 32/5 and 8 Ratio of new number will be= 32/5 : 8= 4 : 5 40) Answer: C Solution: Let the number in the ratio be x , 2x , 3x Sum of their square’s be = 126 x2 + 4x2 + 9x2 = 126 14x2 = 126 X = 3 41) Answer A Solution: Given total students = 2000 1/25 didn’t appear for the exam = 1*2000/25 = 80 Eligible for the examination = 1920 1/100 not allowed to sit in examination = 20 Appeared for examination (Pass + fail ) =1900…………………(1) Difference of pass and fail = 300…………………(2) On solving both we get pass = 1100 and fail = 800 42) Answer: B Solution: Given the ratio of present age of A : B : C : D = 3 : 2 : 6 :5 After 5 years average will become 25 years which means sum will be 100 years. Sum of their age in present = 80 years


16 units = 80 years 1 unit = 5 years Present age of B = 10 and C = 30 Sum = 40 years. 43) Answer: A Solution: Given is total gold of 1000 mg or 10 gm This consist of 10% impurity and rest is Pure gold such 900 mg is pure and 100 mg is impurity. After 1 year there is rust on it’s surface which is 6% of pure gold I.e 54mg Pure gold on 1st year = 900 mg Pure Gold except rust on 2nd year 846 mg Ratio = 450 : 423 44) Answer: C Solution: Let the present age of A and B be 3x and 5x. After 3 years a new baby was born so the ratio becomes 5 : 8 : 2 Since from the above two equations we can conclude that there is no actual value is given. So we cannot find the actual value by any method hence the answer will be cannot be determined. 45) Answer: A Solution: CP : MP = 5 : 6 CP : SP = 10 : 9 Balancing ratios we get CP : MP : SP = 10 : 12 : 9 Loss = 19 = 1 unit Markup price = Rs. 228 46) Answer: A Solution: Initial ratio of water : milk = 3 : 7 After adding 12 l of water ratio becomes 9 : 14. Since we can see that only water is added. So milk must remain same. Hence we will balance milk by multiplying initial ratio with 2. Initial mixture 6 : 14 Final mixture 9 : 14 So ratio difference is 3 which is equal to 12. So from here we can conclude 1 unit = 4 litre. Initial water 6*4 = 24L Alternative method 3x+12/7x=9/14 X=8 Initial water =3x=3*8 = 24L 47) Answer A Solution: Population in the ratio of 50 : 80 : 60 Having Aadhar 45 : 75.2 : 42 Not having Aadhar 5 : 4.8 : 18 Not having Aadhar 25 : 24 : 90


48) Answer A Solution: Let Income of person A, B, C are in the ratio 50 : 40: 60 Increment to them by 10%, 18% and 16% respectively. New Ratio of their income will be in the ratio 55 : 47.2 : 69.6 The above ratio can also be written as 550 : 472 : 696 Next year company Given decrement of 16%, 18% and 10%. Final income of person’s will be 462 : 387.04 : 626.4 This can also be written as 23100 : 19352 : 31320 49) Answer A Solution: Let the two numbers be 3 : 4 So according to the given condition, (3x + 5)/(4x - 5) = 4/5 On solving above equation we get x = 45 So that the numbers will be 135 and 180 50) Answer: A Solution: Let ratio be x. Hence no. of coins be 10x ,5x , 2x respectively Now given total amount = Rs.224 => (10x)/4 + (5x)/2 +(2x) = 224 We get x = 32 The total number of coins=10*32+5*32+2*32=544 51) Answer: A Solution: (a + b) : c = 5/3 …………….(1) (b + c) : a = 4/3……………(2) Multiplying eq (1) by 7 and eq (2) by 8 we get, (a + b) : c = 35/21 (b + c) : a = 32/24 From above we can say that c = 21, a = 24 and b = 11 Value of (c + a) : b = 45/11 52) Answer: A Solution: 4A = 5B = 2C …………….(1) A : B = 5 : 4 and B : C = 2 : 5 Now we need to balance the above two ratio and on balancing we get, A : B : C = 5 : 4 : 10 53) Answer: C Solution: So the numbers are 12, 15, 57 and 69. We can write them as, (12 + x ) / (15 + x ) = ( 57 + x ) / ( 69 + x ) …………..(1) In these types of questions we will go by options. So we will pick first option. X=3 (15)/(18) = (60)/(72) = (5)/(6)


Hence option C satisfy the condition. 54) Answer: D Solution:

Old : New Fare 4 : 5 Sale 3 : 2 Revenue = Fare * Sale Revenue 12 : 10 So 12 units = 15000 1 unit = 1250 Change was 2 units which is equals to 2 * 1250 = 2500 Increased revenue=2500 55) Answer: A Solution: 25% of 3/8 of P = 33.33% of 2/8 of Q = 50% of 2/8 of R (1/4) * (3/8) * P = (1/3) * (2/8) * Q = (1/2) * (1/4) * R On solving above we get, P : Q : R = 8 : 9 : 6…………….(1) Value of (P + Q) : (Q + R) = 17 : 15 56) Answer: D Solution: A receives 2/7 of B who receives 3/8 of C. The above statement can be written as, A : B = 2 : 7 ………….(1) B : C = 3 : 8 …………..(2) Making common ratio’s from eq(1) and eq(2) we get, A : B : C = 6 : 21 : 56 ……………(3) Amount received by B = (21/83) * 83,000 Amount received by B = 21,000 57) Answer: A Solution:

Sanket : Sumit Income 7 : 5 Expenditure 4 : 3 Savings 5000 : 3000 1 unit = 3000 Total income = 12 units Total income = 12 * 3000 = 36000 Alternative method Monthly income of Sanket =7x Monthly income of Sumit =5x Monthly expenditures of Sanket = 4y Monthly expenditures of Sumit = 3y Savings of Sanket and Sumit is 5000 and 3000 7x-4y=5000---- eq (1) 5x-3y=3000-----eq(2) Solving above eq (1) and (2) We get x=3000 Total income = 12 * 3000 = 36000


58) Answer: A Solution: (Sanket)0 : (Sumit)0 = 6 : 5………………..(1) (Sanket)+6 : (Sumit)+6 = 8 : 7 ………………..(2) So from above equation we can say that 2 units = 6 years. 1 unit = 3 years. Present age of Sanket and Sumit is 18 and 15 years. Given Charu is 6 years older than Sanket so her age will be 24 years. Alternative method 6x+6/5x+6=8/7 42x+42=40x+48 2x=6 X=3 Present age of Sanket=6x=18 years Present age of Sumit=5x=15 years Given Charu is 6 years older than Sanket so her age will be 24 years. 59) Answer: C Solution: The ratio of success to failure is 11 : 8 So the applied candidates were 19 units. (19x + 80 ) / ( 8x - 30 ) = 12/5……………..(1) On solving eq (1) we get, x = 760 numbers Total applicants = 19 * 760 = 14,440 60) Answer: A Solution: Price of two articles A and B were in the ratio of 3 : 5 Let the price of Article A and B is 300 and 500 respectively On increasing the value of B we get, 625. The ratio becomes 21 : 25 Now we can say that 625 is written as 25 which means, 25 units = 625 1 unit = 25 So first term = 21 Actual value of first term = 21 * 25 = 525 So we can say that in first term there is an increase of 225 on 300 x = (225/300) * 100 = 75% 61) Answer: C Solution: A : B = 2 : 9 ………………(1) B : C = 3 : 4 ………………(2) Making common ratio’s we get, A : B : C = 2 : 9 : 12……………..(3) It is given that the difference of A and C is 1000 10 units = 1000 1 units = 100 Total amount = 23 unit * 100 = 2300 62) Answer: A Solution: Current New


Income 10 : 12 Savings 3 : 3 Expenditure 7 : 9 Percentage change = (2/7)*100 = 28.57% 63) Answer: B Solution: A = B - 30 ………….. (1) B = C + 30 ……………. (2) A + B + C = 300 …………… (3) Putting value of eq (1) and eq (2) in eq (3) we get, B = 120 64) Answer: A Solution: Male: Female = 3 : 5 …………(1) 1/25 persons are not registered for votes But we can see that ratio of men or women were not given who are register and non-registers. So we cannot find the value of women and men. 65) Answer: D Solution: Male : Female 60% : 40% 300 : 200 So Total population = 500 numbers. 3/25 of 500 = 60 numbers = Boys. 25% of 200 = 50 numbers = Girls. Non - register boys = 240 numbers Non - register Girls = 150 numbers Ratio Boys: Girls = 24: 15 66) Answer: D Solution: Ratio of a : b = 12 : 17 ………………(1) Sum of their squares = 144x2 + 289x2 = 433x2 units 433x2 = 36 * 433 x = 6 Greatest number = 6 * 17 = 102 67) Answer: A Solution: Mean proportion of 81 and 169 b =√ (81 * 169) b = 9 * 13 = 117…………… (1) Third Proportion of 12 and 17 - (12)/(17) = (17)/(c) C = 289/12………….. (2) Taking ratio of (1) and (2) we get, 117: 289/12 1404 : 289 68) Answer: A Solution:


We know the formula to find the fourth proportion - a : b = c : d we get, 18 : 20 :: 23 : d d = 230/9 69) Answer: B Solution: Speed ratio is 6 : 5 Time ratio is 5 : 6 Difference will be 1 unit and this equals to 15 minutes. Actual time=5*15 Actual time 75 minutes 70) Answer: B Solution: a : b = c : d = 5 : 2……………(1) We can write as, a : b = 5x : 2x and also, c : d = 5x : 2x . Assuming all the value’s in unit we can directly put value in it, The value of (a2 + c2) : (b2 + d2) = (50x2) : (8x2) The value of (a2 + c2) : (b2 + d2) = 25 : 4 71) Answer: B Solution: Quant : English = 3x : 2x ……………(1) If he had score 30 marks more and 12 marks less in Quant and English respectively. (3x + 30)/(2x - 12) = 5/3 …………..(2) From eq (2) we will find the value of x, We get x = 150 Marks scored by him in Quant = 3x = 450. 72) Answer: A Solution: (Sumit)-1 : (Sujeet)-1 = 8 : 5 ………………(1) (Sumit)+2 : (Sujeet)+2 = 3 : 2 ………………(2) From eq (1) we have difference of 3 units and from eq (2) we have difference of 1 unit. Multiplying eq (1) by 1 and eq (2) by 3 units we get, (Sumit)-1 : (Sujeet)-1 = 8 : 5 ………………(1) (Sumit)+2 : (Sujeet)+2 = 9 : 6 ………………(2) So from above we can say that 1 unit = 3 years. Age of Sumit and Sujeet one year ago was 24 and 15.So present age of them will be 25 years and 16 years. Age of Sumit after 5 years will be 30 years. 73) Answer: D Solution: Initial distribution between Abhay, Nirbhay and Gajbhay in the ratio 3 : 6 : 7 ……………….(1) Final distribution will be (1/8) : (3/8) : 6 this can also be written as, Final distribution will be (1) : (3) : (48) ………………….(2) So loss of Abhay will be 2 units which is equals to 40,000 1 unit=20,000 3 unit = 60,000


74) Answer: B Solution: Bag A there are two colored balls red and white in the ratio of 5 : 3……….(1) If 10 white ball is taken from bag A and putted in Bag B then ratio becomes 3 : 2 ……….(2) So now we will frame equation based on the above condition we get, (5x)/(3x + 10 ) = 3/2 …………..(3) s On solving above we get, x = 30 White balls in bag A was 90 balls. 75) Answer: A Solution: The ratio of a and b is 12x : 13x……………..(1) According to the condition we can frame the equation, (12x + 30)/ (13x - 10) = 9 / 7 x = 100/11 Greatest number = 13 * 100/11 = 1300/11 76) Answer: A Solution: The ratio of soldier to inspector is 13x : 4x. According to the given condition we can frame the equation as, (13x -150)/(4x - 21 ) = 9/2 On solving above equation we get, x = 111/10 (Ignoring negative sign) Initial number of soldiers = 111*13/10 = 145 approx. 77) Answer: C Solution: The ratio of male students: female students: Faculty is 6 : 8 : 1. Distributing 3000 people in the given ratio we get, Male students = 1200 Female students = 1600 Faculty = 200 In the new academics session changed students, Male students = 1320 Female Students = 1800 New ratio becomes 61 : 90 : 12 If we multiply by 20 in the above ratio we can get the desired ratio’s. 12 * 20 = 240 will be new professors. New faculty = 40. 78) Answer: C Solution:

A : B Investment 3 : 5 Time 10 : 3 Total investment 2 : 3 So the difference between their profits is 1 unit and this is equals to 1500. So Investment of A = 3000 79) Answer: C Solution: (Ayush - 3) + (Anil - 3) = 50 years.


Ayush0 + Anil0 = 56 years……………….(1) Eq (1) is for the present age and sum of their age after two years will be, Ayush+2 + Anil+2 = 60 years…………(2) Ratio of their age after two years 7 : 5 …………..(3) 12x = 60 x = 5 years Age of Ayush after two years will be 35 years Present age of Ayush will be 33 years. Age of Ayush 5 years back will be 28 years. 80) Answer: A Solution:

Previous : New Price 12 : 17 Sale 7 : 4 Revenue = price * Sale Revenue 84 : 68 Change in revenue = 16 units 16 unit = 80,000 1 unit = 5,000 Initial revenue = 84 * 5 * 1000 = 420000 81) Answer: C Solution: Ratio of amount received by A : B : C : D = (5/7) : (3/7) : (1/7) : (2) Ratio of amount received by A : B : C : D = (5) : (3) : (1) : (14)…………….(1) 23x = 46000 x = 2000 ……………. (2) Difference of B and C is 2 units = 2 * 2000 = 4000 82) Answer: A Solution: The ratio of radius of circle to the height of cylinder is 2 : 5…………(1) The ratio of radius of Cylinder to the radius of circle is 4 : 9 ……………….(2) Making the ratio common from eq(1) and eq(2) Rcircle : hcylinder : rcylinder = 4 : 10 : 9 …………………(3) Difference between differences of their radius is 5 units 5 units = 10 cm 1 unit = 2 cm Volume of cylinder = πr2h Volume of cylinder = 20365 cm3 83) Answer: A Solution: Arun and Karan invested in the ratio of 3 : 5…………….(1) Time period of Arun and Karan is 1 : 3 ……………..(2) Multiplying eq (1) by eq (2) we get, Total investment =Arun : Karan = 1 : 5 ……………..(3) Karan received 7200 more than Arun which is equals to 4 units. 4 units = 7200 rupees 1 unit = 1800 rupees Initial Investment of Arun = 1800


84) Answer: D Solution: Sanjay and Ajay invested in the ratio of (7/2) : (9/8) Sanjay: Ajay = 28: 9 ………….. (1) Time ratio of Sanjay: Ajay = 8: 11……… (2) Multiplying eq (1) and eq (2) we get Total investment =Sanjay: Ajay = 224: 99……………(3) Difference of Sanjay and Ajay is 125 units which is equals to 2500 So 1 unit = 20 rupees Initial investment of Ajay = 1980. 85) Answer: A Solution: Speed of boat to the speed of stream is in the ratio 5 : 1 i.e Bs : Cs = 5 : 1 …………….(1) Downstream speed = 6 units Upstream speed = 4 units 6 units = 120/4 = 30 kmph 1 unit = 5 kmph Upstream speed = 20 kmph 86) Answer: A Solution: The above question can be solved allegation method - Taking milk- A B 3/5 2/7

X 1 : 1 On Solving above we get , x = 31/70 So the ratio of milk to water will be 31 : 39 87) Answer: C Solution: Applying chain rule 256: x:: 64:96 256/x=64/96 X=256*96/64 X=384 Rs.384 for 96 days 88) Answer: B Solution: a + b + c = 120 …………..(1) a : b : c = 2 : 3 : 5………………(2) From eq (1) and eq (2) we get, 10x = 120 x = 12 The value of a2 + b2 + c2 = 38x2 = 38 * 12 * 12 = 5472 89) Answer: A Solution: ( A + B + C ) : ( A + B + 2C ) : ( A + 2B + C ) = 8 : 12 : 11 …………….(1) Subtracting first section from third section we get, B = 3


Subtracting first section from second section we get, C = 4 Putting all value in any of the segment we get A = 1 Value of (1/A) : (1/B) : (1/C) = 12 : 4 : 3 90) Answer: A Solution: ( P - Q + R ) : ( Q -P+ 2R ) : ( Q + 3R ) = 3 : 3 : 5……………(1) Adding first and second part, we get 3R = 6 R = 2 Subtracting second part from third part we get, R + P = 2 P = 0 Value of P*Q*R = 0 91) Answer: D Solution: A : B = 2 : 11 ……………..(1) C : B = 5 : 22 …………..(2) Balancing the ratio we get, A : B : C = 4 : 22 : 5 ……………..(3) According to the condition we will frame condition, 31x = 62 * 1000 x = 2000 Amount received by B = 44000 92) Answer: C Solution: Let the ratio of Male to Female be 400 : 500. If the number of female be 500 then as per the condition we have, 25% of female population is PG = 125 numbers. 60% of the remaining will be Graduate = 215 numbers. Remaining will be 160 numbers will be uneducated. This 160 number is equals to 320 1 unit = 2 The above relation shows that in every value we have to multiply by 2. Male population which is post graduated = 75% of Female Male population which is post graduated = 375 * 2 = 750 93) Answer: A Solution: The average weight of three persons say A, B and C is 36 kg. Sum = 108 kg False ratio of their weight = 2 : 3 : 4………..(1) 9x = 108 x = 12 kg Weight of B = 36 kg Actual ratio of their weight = 3 : 5 : 1………..(2) 9x = 108 kg x = 12 kg Weight of B = 60 kg Difference = 24 kg


94) Answer: D Solution: a : b = 5 : 2 , b : c = 3 : 5 and a : d = 3 : 8 ………….(1) From eq (1) we will balance ratio’s we get, a : b : c : d = 15 : 6 : 10 : 40 ……………(2) Value of (a2 + d2) : (b2 + c2) = 1825 : 136 95) Answer: A Solution: The ratio of three numbers a, b and c is 2: 3: 4 …………… (1) According to the question we can frame equation, 24x3 = 6 * 6 * 6 * 4 * 3 * 2 x3 = 216 x = 6 ………………(2) Sum of their units be = 9x=9 * 6 = 54 96) Answer: B Solution: ‘V’ is the vacancy of SSC-CPO 2020 in which the ratio of open to reserved vacancy is 13 : 1. Open vacancy : Reserved seats 13 : 1 So 20 vacancies is still not filled when 216 were filled. So total vacancy in reserved was 236. So 1 unit = 236 vacancy. Total vacancy = 14 units. 14 * 236 = 3304 numbers. 97) Answer: A Solution: (Rahul)0 : (Sonia)0 = 2 : 5 …………………(1) (Rahul)+2 : (Sonia)+2 = 3 : 5 …………………(2) From eq(1) the difference is 3 units and from eq(2) the difference is 2 units. (Rahul)0 : (Sonia)0 = 4 : 10 …………………(3) (Rahul)+5 : (Sonia)+5 = 9 : 15 …………………(4) 5 units = 5 years 1 unit = 1 years Present age of rahul is 4 and Sonia is 10 years. According to the condition , Rahul - Priyanka = Rajiv - Sonia From above equation we can see that we have only two values and two are unknown.So the answer will be cannot be determined. 98) Answer: C Solution: a : b : c = 3 : 2 : 1 …………..(1) a2 + b2 + c2 = 504…………..(2) Putting value of eq(1) in eq(2) we get, 9x2 + 4x2 + x2 = 14 * 36 14x2 = 14 * 36 x = 6 A = 18 , b = 12 and c = 6 Putting value in the evaluating section we get, ( a2 + 2a ) : ( b2 + 2b ) = ( 360 ) : ( 168 ) ( a2 + 2a ) : ( b2 + 2b ) = 15 : 7


99) Answer: A Solution: A : ( B + C ) = 2 : 5 …………….(1) B : ( A + C ) = 2 : 7 ………….(2) Multiplying eq(1) by 9 and eq(2) by 7 we get, A : B : C = 18 : 14 : 31 …………..(3) Amount received by A = (18/63) * 18,900 Amount received by A = 5400/- 100) Answer: D Solution: Profit % = 12.5% = 1/8 So we can say that P = 1 unit and CP = 8 units then SP = 9 units……………(1) Discount% = 20% = 1/5 So we can say that MP = 5 and D = 1 then SP = 4 units………..(2) From eq (1) and eq (2) we have to balance SP, We get SP : CP : MP : D : P = 36 : 32 : 45 : 9 : 4 ……………(3) As we have given Difference of MP and CP is 260 which is equals to 13 units. 13 units = 260 1 unit = 20 rupees Profit of an Article = 4 units = 4 * 20 = 80/- 101) Answer: A Solution: a : b = 3 : 2 …………(1) b : c = 6 : 5 …………(2) c : d = 2 : 9 …………(3) From above equations we will find a : d, a:b:c:d= 36 : 24 :20 :90 a : d = 36 : 90 a : d = 2 : 5 102) Answer: A Solution: Given, sum of two numbers A and B is 30 A + B = 30…………… (1) A – B = 6………… (2) On solving both the equations we get, A = 18 B = 12 103) Answer: A Solution: Let the two numbers be A and B in the ratio 3 : 7 If both the numbers are multiple of 3 and 5 then it must be a multiple of 15. Hence we can say that A and b will be 45 and 105. 104) Answer: B Solution: Let the given numbers be A and B in the ratio of 70 and 90 It is given that both the numbers are increased by 20% and then decreased by 20% respectively. New value of A = 120% of 70 New value of B = 80% of 90


A : B=120% of 70: 80% of 90 A : B = 7 : 6 105) Answer: A Solution: Let the number be x. If this number is further break in the ratio of 12 : 17 then the bigger number say 17 units will be 15 values greater than 12 units. 5 units = 15 value 1 unit = 3 value Since the number is breaking into 12 and 17 unit so the sum will be 29 units which is equal to x. So the number will be 29*3 = 87 Alternative method 17x-12x=15 X=3 12x+17x=12*3+17*3=87 106) Answer: A Solution: A : B = 2 : 3………………..(1) B : C = 9 : 8……………….(2) C : D = 2 : 5……………..(3) A : D = 36 : 120 A : D = 3 : 10 Difference between A and D is 7 units which is equals to 21 value. So 1 unit = 3 value Sum of A and D is 13 units. So by multiplying 13*3 = 39 Alternative method Difference between A and D is 7 10x-3x=21 7x=21 X=3 Sum of A and D is 10x+3x=13x=39 107) Answer: A Solution: A : B = 1 : 2………..(1) B : C = 2 : 1…………(2) C : D = 3 : 4………….(3) From above equations we can find A : D = 3 : 4 108) Answer: A Solution: Let the number be 2x, 5x and 7x. So the sum of first and last number will be 9x and the average of these numbers will 27. Hence, 9x = 54 x = 6 The ratio of sum to the product of numbers will be, =14 * 6 : 70 * 6 * 6 * 6 = 1 : 180 109) Answer: A Solution: Third proportion can be calculated as,


10:30:: 30:x X=30*30/10 X = 90 110) Answer: A Solution: Let the numbers be 50 and 40. Applying procedure on first term a, Using successive formula; a + b + a*b/100……………………(1) +25% + -20% + (25)*(-20)/100 Net change = 0 Applying procedure on first term b, -25% + 20% + (+25)*(20)/100 Net change = 0 So the ratio will be remained unchanged. 111) Answer: A Solution: Age of A and B is in ratio 5 : 6…………..(1) Age of A and B before 38 years will be 6 :11……………..(2) As we know that the difference between their ages will be same. Difference in eq (1) is 1 and eq (2) is 5 so we will multiply by 5 in eq (1) and we will get A : B = 25 : 30 Before 38 years, A : B = 6 : 11 So difference will be 19 unit = 38 years 1 unit = 2 years Present age of A= 25*2 = 50 years. 112) Answer: A Solution: Deducing the first statement we get, A : B = 3 : 1 B : C = 2 : 1 Balancing the ratio we get, A : B : C = 6 : 2 : 1 Here the difference is 5 units which is equal to 20 years. So 1 unit = 4 years Present age of B is 8 years and age of B After 7 years will be 15 years. 13) Answer: A Solution: Ratio of water and wine is in ratio 3 : 8 After adding 8 litres of wine it becomes 5 : 16 We can see that we have only added wine so the concentration of water must be same in both the equations. Balancing both the equations by multiplying 3 and 5 to make it 15. Ratio of water and wine is in ratio 15 : 40 After adding 8 litres of wine it becomes 15 : 48 So 8 units will be equals to 8 litre 1 unit = 1 litre Initial wine = 40 litre Alternative Method


Ratio of water and wine is in ratio 3 : 8 After adding 8 litres of wine it becomes 5 : 16 3x/8X+8=5/16 48x=40x+40 X=5 Initial wine =8X= 40 litre 114) Answer A Solution: Initial ratio of mixture 25% : 75% 1 : 3 (water : sanitizer )……………..eq (1) Final ratio of mixture 3 : 1 (water : sanitizer) ……eq (2) Since only 16 litre of water is added so that sanitizer should be balanced. So multiply equation (2) by 3 we get, 1 : 3…….eq (1) 9 : 3…….eq (2) 8 units = 16 litres 1 unit = 2 litres So initial quantity was 4 unit * 2 = 8 litres Alternative Method Initial ratio of mixture 25% : 75% 1 : 3 (water : sanitizer )……………..eq (1) Final ratio of mixture 3 : 1 (water : sanitizer) ……eq (2) x/3x+16=3/1 x=2 So initial quantity=4x=8 litres 115) Answer A Solution: Ratio of radius of circle to the side of square is 7 : 5 Circumference = 308 = 2πr Radius(r) = 49 cm So side of square will becomes 35 cm Perimeter of square = 4 * side = 140 cm 116) Answer A Solution: Two circle say C1 and C2 with radius in the ratio of 4 : 3 Perimeter of the bigger circle is 176cms = 2πr… Eq (1) On solving above we get r1 = 28 On comparing with the ratio’s we get radius of smaller circle = 21cm So perimeter of smaller circle = 132 cm 117) Answer: A Solution: Weight of the two person’s A and B is in the ratio 5 : 8 The average of their weight is 39 i.e (A + B ) = 78 kg Sum of their weight is 13 units = 78 kg 1 unit = 6kg Difference of their weight in units = 3 units 3 units * 6 kg = 18 kg Alternative Method


5x+8x/2=39 13x=78 X=6 Difference of their weight=8x-5x=3x=18 kg 118) Answer: A Solution: Let number of girls=4x Number of boys=5x 4x/5x-100=6/7 2x=600 X=300 Number of girls=4x=1200 119) Answer: A Solution: According to the question X:1/3=8/7:8/11 X=11/21 120) Answer: B Solution: If A : B : C = 9 : 8 : 6 Taking LCM of them we get 72 Now dividing 72 by unit’s of A, B, C we can get our respected ratios. Value of (1/A) : (1/B) : (1/C) = 8 : 9 : 12 121) Answer: A Solution: (A + B) : (B + C ) : ( C + A ) = 8 : 7 : 7 …………(1) Let A + B = 8 units………..(2) B + C = 7 units…………(3) C + A = 7 units………….(4) (A + B) + (B + C) + (C + A) = 22 units 2 (A + B + C) = 22 units A + B + C = 11 A + 7 = 11 ⇒ A = 4; B + 7 = 11 ⇒ B = 4 C + A + B = 11 C + 8 = 11 ⇒ C = 3 Taking ratios of A : B : C = 4 : 4 : 3 122) Answer: A Solution: This type of questions must always be approached with option, It is clear that 15 can never be because it will be reduced the first term very much. Let’s take X = 10 and subtract from each term We will get, 12 : 36 : : 8 : 24 1 : 3 : : 1 : 3 123) Answer: A Solution: Ratio of seats as given respectively 4: 3 : 7


Let’s take the values are 40 , 30 and 70 respectively Now there is an increment in it is 30%, 40% and 50% respectively. So we get New ratio will be 52 : 42 : 105 124) Answer: A Solution: Let the two numbers be a and b. Now according to the given condition, (40/100) * (3/8) * a = (5/8) * (3/11) * b a : b = 25 : 22 125) Answer: A Solution: Ratio of Male to female = 5 : 8 Let take the value of male and female = 50 and 80 Total female = 80 40% of female are employed Employed female = 80 *(40/100) = 32 Unemployed female = 80 – 32 = 48 Total Male = 50 Unemployed male = 50 * (40/100) = 20 Employed Male = 50 – 20 = 30 Ratio of unemployed male to female = 20 : 48 ⇒ 5 : 12 126) Answer: A Solution: A is 8 more than B means A - B = 8……………..(1) B who is 16 more than C means B - C = 16……….(2) Adding both the equations we get A - C = 24……..(3) Ratio of A : C = 4 : 1……..(4) So the difference in units will be 3 units = 24 value So 1 unit = 8 value. So A = 32, B = 24 and C = 8 A + B + C = 64 127) Answer: A Solution: This type of questions must always be approached with option, It is clear that 1 can never be the answer because it will be reduced the first term very much. 42 : 140:: 50: 164 Let’s take X = 7 and add from each term we will get, 49 : 147 :: 57 : 171 1 : 3 :: 1 : 3 128) Answer: A Solution: Total numbers of flats in a building = N Ratio of broadband users to non users is 10 : 7

N Broadband : Non broadband users

10 : 7


AIRTEL : BSNL 7 : 3

The difference between non broadband users to BSNL is 100 In term of units it is 4 units. So this 4 units will be equal to 100 1 unit = 25 value Total population = 17 units Total population = 17 * 25 = 425 129) Answer: A Solution: Marks in Maths, Science, English is in the ratio of 9 : 8 :7 Maths = 9x; Science = 8x; English = 7x Average = 80 So sum will be 80 * 3 = 240 Total = 9x + 8x + 7x = 24x 24 x = 240 x = 10 Marks in maths = 9 * 10 = 90 130) Answer: A Solution: Mean proportion of 81 & 64 = √ 81*64 = 72 Third proportion = a / b = b / c 20/30=30/x x= 45 Desired ratio will be = 72 : 45 = 8 : 5 131) Answer A Solution: Let the number of Tanks and missiles are in the ratio 5:6 Forming equation we get (5x - 40) / (6x - 32 ) = 3 / 4 On solving above equation we get x = 32 So initial tanks = 32 * 5 = 160 132) Answer: A Solution: Ratio of vacancy to reserved for ex-service men 18 : 5 Given: 5000 candidate applied and 4350 rejected so 650 were finally selected and this will also be the vacancy by SSC. We can say that 5 unit = 650 1 unit = 130 post 18 unit = 2340 vacancy. 133) Answer: A Solution: If ( A + C) : (B + C ) : C = 7 : 9 : 5 From above we can say that If we assume C = 5 then B = 4 and A = 2 units. Given is A is greater than B by 8.So B - A = 2 units = 8 value 1 unit = 4 C - A = 3 unit * 4 = 12


134) Answer: A Solution: MP : CP = 9 : 5……………..(1) profit = 26% = CP : P = 50 : 13……………(2) Making common ratios we get- CP : MP : P : SP : D = 50 : 90 : 13 : 63 :27……………….(3) It is given that MP is 540 more that SP which is equal to 27 units 1 unit = 20 value CP = 50 units * 20 = 1000/- 135) Answer: A Solution: The Speed of boat to the stream is in ratio of 8 : 1 If the speed is increased by 25% then it will becomes 10units Now downstream will be 11 units 11 units = 220 / 10 11 unit = 22 value 1 unit = 2 value Speed of stream is 2 kmph Increased speed of boat is 20 kmph So actual value must be 80% of 20 = 16 kmph 136) Answer: A Solution: Total population is ‘P’ Voters : Non-voters 8 : 9 Male : female 2 : 3 Difference of Non-voters and female is 1800 which is equal to 6 units So 1 unit = 300 value Total population = 17 units Total population = 17 units * 300 = 5100 137) Answer: C Solution: 5A=3B=2C 5A/30=3B/30=2C/30 A/6=B/10=C/15 A:B:C=6:10:15 138) Answer: A Solution: Final ratio becomes 8 : 11 : 6 after buying one dozen orange. 1 dozen =12 So 12 is denoted as 6 here. So multiplying completely by 2. We get 16 : 22 : 12 Hence we can say that egg in the bag was 16 in numbers. 139) Answer: A Solution:


37.5% = 3/8 means 3 is water then 5 is milk So the ratio of water to milk is 3 : 5…………..(1) Anil puts 20 litre of milk then water becomes 25% in it. So new ratio becomes 1 : 3………………(2) 3x/5x+20=1/3 9x=5x+20 X=5 So initial quantity of water = 3 x = 15 litres. 140) Answer: A Solution: Let the two be 3x and 8x. According to the condition, 3x / 8x = 24 / B B = 64 141) Answer: A Solution: Income of A and B is in the ratio 4 : 3 Saving of A and B is in the ratio 3 : 2 From above statement we can say that if income of A is 4 unit and Saving is 3 then expenditure of A will be 1 unit and this is equal to 2500/-. Income of B will be 3 units and it will be equals to 3 * 2500 = 7500/- 142) Answer: A Solution: Let’s assume them as equations, A + B = 7…………(1) A - B = 5…………(2) Solving equations we get, A = 6 and B = 1 The ratio of 2A : 3B

2 * 6 : 3 * 1 4 : 1

43) Answer: A Solution: Initial investment 8 : 9 Time Ratio 8 : 5 Total investment 64 : 45 Profit of A is 16000 64 unit = 16000 1 unit = 250 Initial investment of B = 45 units * 250 Initial investment of B = 11,250 144) Answer: A Solution: Let the price of refrigerator=7x Let the price of Mobile =6x According to the Question 7x-6x=3000 X=3000 Price of mobile =6x=18000


145) Answer: C Solution: Since the given expression is in proportion. So we can compare them term wise. We can observe that a = b = c = 5k (let) And, d = e = f = 1k (let) Putting all value’s in the equations, we get (a + b + c) : (d + e + f ) = 15 : 3 = 5:1 146) Answer: A Solution: Let the number to be decreased be x. So we will make equation as follows, (6 – x) / (7 – x) = 7 / 6 X = 13 147) Answer: A Solution: Price of petrol is decreased by 6.66% = 1 / 16 So initial price = 16 Final price = 15 Sale was increased by 10% = 1 /10 So initial value = 10 Final price = 11 Initial revenue = 160 Final revenue = 165 (All values are in units) 16 unit = 64 rupees 1 unit = 4 rupees. Final revenue = 660/- 148) Answer: A Solution: Ratio of Income of P and Q is 3 : 1 Ratio of expenditure of P and Q is 8 : 3 Ratio of saving is 4 : 1 Cross multiplying income * expenditure = expenditure * savings ( 3 * 3 ) - ( 8 * 1 ) = ( 4*3 ) - ( 8 * 1 ) 1 unit = 4000/- So income of P is 12,000/- Alternative Method Ratio of Income of P and Q is 3 : 1 Ratio of expenditure of P and Q is 8 : 3 Ratio of saving is 4 : 1 Sum of their saving is 5000 3x-4000/x-1000=8/3 9x-1200=8x-8000 X=4000 So income of P =3x= 12,000/- 149) Answer: B Solution: Given ratio is 3 : 4 : 2………(1) If C increased by 50% while B is decreased by 50% then ratio becomes, 3 : 2 : 3…………(2) Now C becomes 120.So 3 unit = 120 1 unit = 40


3unit = 120 A=120 150) Answer: A Solution: Let the CP and SP of the article be 8x and 9x.So according to the condition we will form equation, (8x + 50) / (9x + 200) = 11 / 13 On Solving above equation we get x = 310 Initial SP = 9 * 310 = 2790 Incremented SP = 2990 151) Answer: D Solution: Mean proportion of 81 and 9 =√(81*9)=27 152) Answer: B Solution: (x + 2)/(x – 1) = 4/3 3x + 6 = 4x – 4 X = 10 Mean proportional to x and 4x=√x*4x =2x =2(10) = 20 153) Answer: C Solution: Initially, M : W = 5x : 2x After some people left then the ratio of M : W = 8y : 3y 5x – 6 = 8y ---- (1) 2x – 6 = 3y --- (2) Solving (1) and (2) x = 30 Then total number of people in the group initially = 5x +2x = 7x = 7(30) = 210 Alternative Method 5x – 6 /2x – 6 = 8/3 X=30 Then total number of people in the group initially = 5x +2x = 7x = 7(30) = 210 154) Answer: B Solution: Let income of B is 100x Then income of A is 60x Let expenditure of B is 100y Then expenditure of A is 40y Given, income of A is 70% of expenditure of B 60x = (70/100)100y 6x = 7y Saving of A/Saving of B = (60x – 40y)/(100x – 100y) Put the value of x in above = (70y – 40y)/((700y/6) – 100y) =30y/(100y/6) =9/5 = 9 : 5 155) Answer: C Solution:


A:B:C:D=(1/5)y :(1/2)y:(1/3)y:(1/4)y Let consider y=60 which is least common multiple of all denominators A : B : C : D = 12 : 30 : 20 : 15 A – C = 20y – 12y = 8y 8y = 560 Y = 70 Total amount = 12y + 30y + 20y + 15y = 77y = 77(70) =5390 156) Answer: C Solution: A : B : C = 2x : 3x : 5x A2 + B2 + C2 = 4x2 + 9x2 + 25x2 = 38x2 38x2 = 342 X = 3 A + B + C=2x + 3x + 5x = 10x = 30 157) Answer: B Solution: A : B = 4 : 5 B : C = 6 : 7 Since B is common in both ratio, multiply A : B with 6 and B : C with 4 Then, A : B = 24 : 30 B : C = 30 : 35 Combining the above two ratios A : B: C = 24 : 30 : 35 158) Answer: C Solution: R: G =5x : 2x G=33 1/3% of B 2x = 33 1/3% of B 2x = (100/3)/100 of B B = 2x(300/100) B = 6x R : G : B = 5x : 2x : 6x R + G + B = 91 13x = 91 X = 7 R – G = 5x - 2x = 3x = 3(7) =21 159) Answer: A Solution: Ratio of three sides = 3x : 4x : 5x Sum of three sides = 3x + 4x + 5x = 180° 12x = 180° X = 15° Difference between smallest and largest angle = 5x – 3x= 2x =2(15) = 30° 160) Answer: D Solution: Consider 4A = 5B = 6C = k A = k/4, B = k/5, C = k/6 A : B : C = k/4 : k/5 : k/6


LCM of 4, 5 and 6 is 60.Consider this as k A : B : C = 60/4 : 60/5 : 60/6 =15 : 12 : 10 161) Answer: B Solution: A = 2B A : B = 2 : 1 C = 2B C : B = 2 : 1 B : C = 1 : 2 A : B : C = 2 : 1 : 2 162) Answer: B Solution: A : B = 5 : 4 Let x be the common multiplier then A : B = 5x : 4x A = B + 19 5x = 4x + 19 X = 19 A + B = 5x + 4x = 9x =9(19) = 171 163) Answer: C Solution: H : A = 9 : 10 10H = 9A ------- (1) (H + 50) : A = 1 : 1 H + 50 = A --–-- (2) Put the value of A in (2) H + 50 = 10H/9 9H + 450 = 10H H = 450 Half yearly marks = 45% of total marks 450 = 45% of Total Total marks 100% = 100*450/45 = 1000 164) Answer: A Solution: A : B = 5 : 4 B : C = 7 : 8 A : B : C = 35 : 28 : 32 The terms are: A = 35x, B = 28x, C = 32x A + B : B + C : C + A = 63x : 60x : 67x A + B : B + C : C+ A = 63 : 60 : 67 165) Answer: D Solution: B : G = 2x : 3x 30% of G = (30% of B) + 6 30% of 3x = (30% of 2x) + 6 9x/10 = 6x/10 + 6 X = 20 B + G = 2x + 3x = 5(20) = 100


166) Answer: C Let ratio be x. Hence no. of coins be 10x ,5x , 2x respectively Now given total amount = Rs.112 => (10x)/4 + (5x)/2 +(2x) = 112 We get x = 16 The total number of coins=10*16+5*16+2*16=272 167) Answer: C Solution: 16:64::64:x Third proportion to 16 and 64 is given by = 64*64/16=256 168) Answer: D Solution: a/(b + c) = 1 : 2 ---(1) By componendo method (a + b + c)/(b + c) = (1 + 2)/2 = 3/2 ------- (2) (1) ÷ by (2) a/(a + b + c) = 1/(1 + 2) = 1/3 169) Answer: A Solution: a: (b – c) = 3 : 2 By componendo method (a + b – c)/(b – c) = 5/2 ---(1) By dividendo method (a – b + c)/(b – c) = 1/2 ---(2) (2) ÷ (1)=> (a – b + c)/(a + b – c) = 1/5 170) Answer: D Solution: Let P and F be the pass and failed students respectively P : F = 3 : 4 P = 3F/4 10 more students passed the exam Then the ratio becomes, (P + 10) : (F – 10) = 23 : 19 19P + 190 = 23F – 230 23F – 19P = 420 –----- (1) Put the value of P in (1) 23F – 19(3F/4) = 420 23F – 57F/4 = 420 (92F – 57F)/4 = 420 35F = 420*4 F = 48 P = 3(48)/4 = 36 (1/3)P = Boys who passed Boys who passed = 12 Girls who passed = Total passed – Boys who passed= 36 – 12 = 24 171) Answer: D Solution:


Valid : Invalid = 4 : 1 70% of valid vote = 6300 100% = 100*6300/70 = 9000 Valid – Invalid votes = 4x – x = 3x Since 4x = 9000 X=9000/4 3x = 3*9000/4 =3*2250=6750 Difference between the valid and invalid votes = 6750 172) Answer: A Solution: Article 1: Article 2 = 5 : 6 120% of article 1 : 133 1/3% of article 2 = 120%(5) : 133 1/3%(6) = (6/5)(5) : (4/3)(6) = 6 : 8 = 3 : 4 173) Answer: B Solution: A = 130% of B A/B = 13/10 B = 120% of C B/C = 6/5 A : B = 13 : 10 B : C = 6 : 5 A : B : C = 78 : 60 : 50 = 39 : 30 : 25 174) Answer: C Solution: Male : female = (x + 2) : (x + 4) Total population = 6400 X + 2 + x + 4 = 6400 2x + 6 = 6400 X + 3 = 3200 X = 3197 175) Answer: C Solution: A : B : C = 5 : 7 : 9 1/A : 1/B : 1/C = 1/5 : 1/7 : 1/9 = 63 : 45 : 35 176) Answer: C Solution: Let a/7 = b/3 = c/5 = k A = 7k, b = 3k, c = 5k a : b : c = 7k : 3k : 5k = 7 : 3 : 5 177) Answer: B Solution: Total bill amount: 600 A : (B + C) = 1/2


A + B + C = 600 3A = 600 A = 200 B : (A + C) = 1/5 A + B + C = 600 6B = 600 B = 100 C = 600 – 200 – 100 = 300 178) Answer: B Solution: Number => Pen : Pencil = 5x : 6x Cost => Pen : pencil = 4y : 3y Total cost => Pen : Pencil = 20xy : 18xy % greater= (20xy-18xy)*100/18xy = 100/9 = 11.11% 179) Answer: A Solution: A : (B + C) = 2 : 5 (Total 7) ------ (1) B : (A + C) = 1 : 2 (Total 3) ----- (2) As both sums should be same, multiply (1) by 3 and (2) by 7 (1) => A : (B + C) = 6 : 15 (2)=> B : (A + C) = 7 : 14 Since B = 7units, C = 15 – 7 = 8 units C/(A+B) = 8/(6+7) = 8 : 13 180) Answer: D Solution: Let the income of A and B is x and y X + y = 5000 -------- (1) 20%x : 30%y = 4 : 9 x/5 : 3y/10 = 4 : 9 2x : 3y = 4 : 9 x/y = 2/3 Put the value of x in (1) 2y/3 + y = 5000 5y/3 = 5000 Y = 3000 X = 5000 – 3000 = 2000 181) Answer: C Solution: Expenditure : Saving = 3 : 1 ------- (1) Income = 3 + 1 = 4 units Income increases by 50% = 150% of 4 units =6 units Expenditure increases by 20% = 120% of 3 units = 18/5 units Savings = Income – Expenditure = 6 – 18/5 = 12/5 Revised Expenditure : Saving = 18/5:12/5 = 3 : 2 –----- (2)


On comparing (1) and (2) Saving is incremented by 1 unit which is equivalent to 100% 182) Answer: C Solution: A : B = 3 : 2 A – B = 8 3 – 2 units = 8 1 unit = 8 A + B = 3 + 2 = 5 units A + B = 40 A2-B2 = (A + B)(A – B) = 40*8 = 320 Alternative method A : B = 3 : 2 a-b=8 3x-2x=8 X=8 A2-B2=(3x)2-(2x)2 =9x2-4x2=9*64-4*64 =64*5=320 183) Answer: B Solution: Let the I and D be the Idly and Dosa respectively 2I : D = 2 : 5 ------- (1) I : 2D = 1 : 10 –---- (2) Comparing (1) and (2) I : D = 1 : 5 So price of one idly is 1unit and one dosa is 5 unit 3I : 2D = 3(1) : 2(5) = 3 : 10 184) Answer: B Solution: A : B : C = 4 : 6 : 9 A : B : C = 4x : 6x : 9x A = C – 50 4x = 9x – 50 X = 10 A + B + C = 4x + 6x + 9x = 19x = 19*10 = 190 1/5th of (A + B + C) = 190/5 = 38 185) Answer: C Solution: Income A : B = 6x : 7x Expenses A : B = 4y : 3y Savings = 2000 : 4000 Income of A=> 6x = 4y + 2000 6x – 4y = 2000 –----- (1) Income of B=>7x = 3y + 4000 7x – 3y = 4000 ------ (2)


Solving (1) and (2) X = 1000 Sum of the incomes = 6x + 7x = 13x =13(1000) = 13000 186) Answer: B Solution: Ratio of income Raj : Raghu = y2/x2 Ratio of savings Raj : Raghu =y/x Ratio of expenditures = (y2-y)/(x2-x) = y(y-1)/x(x-1) = (-y)(1-y)/(-x)(1-x) = y(1-y)/x(1-x) 187) Answer: C Solution: Let the shares be A and B (A – 50) : (B – 25) = 34 : 23 23(A – 50) = 34(B – 25) 23A – 1150 = 34B – 850 23A – 34B = 300 --------- (1) A + B =1500 ------------- (2) Solving (1) and (2) A = 900 and B = 600 A – B = 900 – 600 = 300 188) Answer: C Solution: Number=> Hen : Goat = 2 : 3 Number of legs=> Hen : Goat = 1 : 3 Let hen be H and goat be G Then H : G = 2 : 3 2H : 4G = 1 : 3 {legs count} H : 2G = 1 : 3 Difference between the legs = 2 parts = 80 Then, 1 part = 40 Since H = 1 part then Total number of hens leg = 40 Number of hens = 40/2 =20 (As, 2 for 2 legs/hen) 189) Answer: B Solution: A2 : B2 = 9 : 25 B2 – A2 = 144 (Since B>A) Put the value of B2 in the above expression 25A2/9 – A2 = 144 16A2/9 = 144 A2 = 144*9/16 A = 12*3/4 = 9 A3 = 729 190) Answer: C Solution: Let marks obtained by Ram and Raghu is x and y respectively. X : y = 4 : 5


Let cut off score is z then X = z – 3 and y = z + 5 Equating the above two expression for z then X + 3 = y – 5 X – y = - 8 Put the value of y = 5x/4 in above expression then X – 5x/4 = - 8 -x/4 = - 8 X = 32 Since cut off score z = x + 3 Z = 32 + 3 = 35 191) Answer: C Solution: Initially S : G = 9x : 11x(Total 20x units) After exchange S : G = 7y : 13y (Total 20y uints) Irrespective of the exchange total units is same (i.e.) 20x= 20y The above expression is equal only when x = y So, fraction of stones given by Sita to Geetha against heroriginal = (9x – 7y)/9x Since x = y, put y = x in above expression, = (9x – 7x)/9x =2x/9x = 2 : 9 192) Answer: C Solution: Let A, B, V and IV be the votes got by A,B and valid and invalid votes respectively. V : A = 5 : 3 ----- (1) IV : B = 1 : 2 ---- (2) V : IV = 5 : 1 ---- (3) On comparing (2) and (3) V : IV : B = 5 : 1 : 2 ----- (4) On comparing (4) and (1) V : IV : A : B = 5 : 1 : 3 : 2 From the above, A : B = 3 : 2 193) Answer: C Solution: Valid : Invalid = 6x : 1x A : B = 6y : 5y (Since A = 120% of B) Since total votes =7x Votes got by A = 6y Votes got by A = (total valid votes*A’s part)/(Total parts of A and B) = (6x*6)/11 = 6y (Votes got by A) Votes by A: total votes = 6y : 7x = ((6x*6)/11)/7x = 36/77 194) Answer: B Solution: Let the length and breadth be l and b respectively L : b = 14 : 3 l*b = 168 --------- (1) Put the value of b in the above expression then 3l/14 *l = 168


l2 = 56*14 l = 28 Put l = 28 in (1) then b = 6 Difference l – b = 28 – 6 = 22 195) Answer: B Solution: A : B : C : D = 4 : 6 : 7 : 9 A + C = 4x + 7x = 11x 3454 = 11x X = 3454/11 = 314 A + B = 4x + 6x = 10x = 10(314) = 3140 196) Answer: C Solution: A : B = 4 : 5 -------- (1) B : C = 8 : 9 -------- (2) C : D = 6 : 7 ------– (3) From (1) and (2) Multiply (1) by 8 and (2) by 5 Then, (1)=>A : B = 32 : 40 (2)=> B : C = 40 : 45 Therefore A : B : C = 32 : 40 : 45 -------- (4) From (4) and (3) Multiply (4) by 2 and (3) by 15 Then(3) => C:D=90:105 (4)=>A : B : C = 64 : 80 : 90 Therefore, A : B : C : D = 64 : 80 : 90 : 105 197) Answer: C Solution: Since the given number are in proportion then, 14/18 = 28/x X = 28*18/14 X = 36 198) Answer: D Solution: X = k/y2 (K is proportionality constant) –----------- (1) Put the values of x and y 4 = k/16 K = 64 Put the value of y and k in (1) From equation (1) x = 64/82 = 1 199) Answer: C Solution: A : B : C = 7 : 9 : 11


After increment, A : B : C = 110(7)/100 : 115(9)/100 : 125(11)/100 = 77/10 : 207/20 : 55/4 = 154 : 207 : 275 200) Answer: B Solution: A : B = 7 : 13 After respective increment and decrement A : B = (24/100)(7) : (25/100)(13) = (6/25)(7) : (13/4) = 42/25 : 13/4 = 168 : 325 251) Answer: B Solution: If (a + b)/c = 5/3 ………………(1) (b + c)/a = 7/4 …………………(2) If we sum a + b + c in both the equations then eq (1) will give 8 units and eq (2) will give 11 units. Let’s take LCM of both which will be equals to 88 units. In eq (1) to obtain 88 we have to multiply by 11 in numerator and denominator while in eq (2) we have to multiply by 8.After following this procedure we can write the above equation as; (a + b)/c = 55/33 ………………(3) (b + c)/a = 56/32 …………………(4) So from eq (3) and eq (4) we can say that a = 32 and c = 33 then b = 23 We have to find (a + c)/b = 65/23 252) Answer: A Solution: Ratio of income of Arun and Varun 4 : 5 Ratio of expenditure of Arun and Varun 5 : 6 Saving of Arun and Varun 6000 : 4000 (5 * 5 ) – ( 4 * 6 ) units = ( 6 * 6000 ) – (5 * 4000 ) 1 units = 16000 rupees Total income of Arun and Varun is 9 units 9 units = 16000 * 9 = 144000 Alternative method 4x-6000/5x-4000=5/6 X=1600 Total income of Arun and Varun is 9x=9*16000=144000 253) Answer: B Solution: Total students were 1600 Ratio of boys to girls is 3 : 5 which means girls were 600 and that of boys were 1000 Now if ‘X’ boys left and ‘X’ girls were admitted then according to the question it can be reduced as equation and can be written as; (1000 – x ) / ( 600 + x ) = 7 / 8 ……………..(1) It is also stated that finally girls in the school is 300 more than the boys. So from eq(1) we can say that if 7 units is the boys and 8 units is representing girls and difference being 1 unit which is equal to 300. So 1 unit = 300 8 units = girls = 2400


7 units = boys = 2100 On solving eq (1) we get x = 253 (approx) If ‘X’ is the number of girls admitted in the new session and in the old session girls were 600 so total girls in the new session = 853 (approx) 254) Answer: A Solution: Ratio of angles of a triangle is 3 : 4 : 5 We know that the sum of angles of triangle is 180’.So we can write from above as, 3x + 4x + 5x = 180 12x = 180 X = 15 So the angles will be 45, 60 and 75 respectively. Now, the ratio of radius of circle to the sum of two smaller angle is 1 : 7 i.e R : (A1 + A2 ) = 1 : 7 R : (45 + 60 ) = 1 : 7 …………(1) From eq (1) we can calculate R and we get R = 15 units Area of circle = πr2 Area of circle = 22 × 15 × 15 / 7 Area of circle = 707 units2

255) Answer: A Solution: Cube: All the sides are equal which means a = b = c If we change its sides with +10%, +15% and -10% respectively. 10% = 1/10 and 15% = 3/20 As we can see the denominator of fraction values are different so we need to modulate them. Multiplying 1/10 by 2 it will becomes 2/20 now all fraction values will have same denominators. So from here we can say that side of cube is 20 units. Volume of cube = (side)3 Volume of cube = (20)3 = 8000 unit3 Cuboid: All three sides are different. So If we change its sides with +10%, +15% and -10% increment and decrement respectively then new shape will becomes cuboid with its sides as, a = 22, b = 23 and c = 18 units Volume of cuboid = length × breadth × height = abc Volume of cuboid = 22 × 18 × 23 = 9108 Units3

So the difference between their volume = 9108 – 8000 = 1108 cu. Units Percentage change = (1108) *100 / 8000 Percentage change = +13.85 % 256) Answer: C Solution: In this question we can directly solve by framing equation. The equation can be written as, If 19x is the selected candidate and 17x being rejected candidate then total applied candidate will be 36x. So equation can be written as, (36x – 1200)/(19x – 800) = 1/1 …………(1) On solving above equation we get, x = 400/17 units Applied candidates were 36x = 36 * 400 / 17 Applied candidates = 847 (approx)


257) Answer: A Solution: The ratio of present age of Ram to the age of Shyam is 3 : 2 R : S = 3 : 2 ……………….(1) The ratio of present age of Shyam to the age of Kumar is 5 : 3 S : K = 5 : 3 ……………….(2) From eq (1) and eq (2) we can see that age of Shyam in different in both the equations so we need to balance them. Multiplying eq(1) by 5 and eq(2) by 2 we get, R : S : K = 15 : 10 : 6 …………….(3) Average present age of all three of them = 31 years Sum of their present ages will be 93 years Since eq (3) is also the ratio of their present age so from this equation we can write as, 15x + 10x + 6x = 93 years 31x = 31 * 3 years x = 3 years So the present age of Ram, Shyam and Kumar is 45 , 30 and 18 years respectively. So the age of Ram four years back = 41 years 258) Answer: C Solution: Ratio of present age of Ravi and Sohan is 3 : 5 Ravi0 : Sohan0 = 3 : 5 ……………..(1) After ten years ratio of ages of Ravi, Sohan and Sujeet becomes 7 : 8 : 5 Ravi+10 : Sohan+10 : Sujeet+10 = 7 : 8 : 5………….(2) Average of their present age is 30 years so the sum will be 90 years and after 10 years sum will be 90 + 30 = 120 years…………..(3) So from eq (2) and eq (3) we can write as, 7x + 8x + 5x = 120 years 20x = 120 years X = 6 years Age of Sujeet 10 years later = 5 * 6 = 30 years So the present age = 20 years 259) Answer: A Solution: The ratio of radius to the height of cone is 5 : 3 R : h = 5 : 3 …………….(1) Ratio of volume of cylinder to the cone is 2 : 3. Vcy : Vcone = 2 : 3 ………………..(2) Eq (2) can also be written as, (πr2h ) / (πr2h/ 3 ) = 2 : 3 hcy : hcone = 2 : 9 ………….(3) From eq (1) we have ratio of radius to height of cone and also radius of both shape is equals to 25 which we can put here, from eq(1) 25 / hcone = 5 / 3 hcone = 15 Putting this value in eq (3) we get, hcy = 10/3 cms Volume of cylinder = πr2h Volume of cylinder = 6547 cm3 260) Answer: A Solution: Three numbers are in the ratio of 13 : 14 : 9 The above numbers can also be written as , 130 : 140 :90…………..(1)


So from eq (1) we have to increase every value by 50% and on increasing every value by 50% we get, 195 : 210 : 135 …………….(2) From eq (2) we can see the difference of first and last term is 60 units which is equals to 120 value. So we can say that 60 units = 120 values 1 unit = 2 values So the originals number will be obtained by multiplying the eq(1) by 2 Originals numbers = 260 , 280 and 180 211) Answer: C Solution: Given is the ratio of red and black color in the complete sheet is 5 : 7. Upper part is having the ratio of 4 : 3. Lower part is having the ratio of 2 : 5 Mid part is having red color equal to the total color in the lower part which is 7 units. Now see if we add each color then it must be equals to the complete part ratio. So we will try to frame an equation, Numerator will represent red and denominator will represent black. (13)/(8 + B) = 5/7 On solving above equation we get, B = 10 Approx So the ratio of red : black of the mid section = 7 : 10 212) Answer: C Solution: Initial investment ratio of Arun : Varun : Karan 5*8 + 3*6 : 5*14 : 2*6 On solving above we get investment ratios as; 29 : 35 : 6 ……………(1) Given is that Karan’s initial investment was 30000 /- which is equals to 6 units. Such that 1 unit = 5000 rupees Profit of Arun = 29 * 5000 = 1,45,000/- If Arun pays 10% TDS then he will left with 90% so the 90% of 1,45,000 = 1,30,500/- 213) Answer: A Solution: Initial Ratio of investment of these three friends, Amar : Bimar : Kamar 6*8 +5*10 : 5*8 + 10*10 : 4*10 Ratio’s can be written as; 49 : 70 : 20 ……………(1) Since the difference between Bimar and Kamar is 50 units which is equal to15000, i.e 1 unit = 300 rupees So the profit of Amar is 49 units = 49 * 300 = 14700 214) Answer : A Solution : Ratio of Present age of Amit to Sumit = 5 : 8…………….(1) Ratio of their age after eight years = 3 : 4…………….(2) In eq(1) we can see that age difference is 3 units while in eq(2) it is 1 unit so we need to balance this difference. We will multiply eq(1) by 1 and eq(2) by 3 Above equations can be also written as,


A0 : S0 = 5 : 8 A+8 : S+8 = 9 : 12 So from here we can say that 4 units = 8 years i.e 1 unit = 2 years Present age of Sumit = 16 years Sumit’s age after 2 years = 18 years Ratio of Age of Sumit after two year to the age of son at present is in the ratio of 9:2. From comparing here we can say that if 9 units = 18 years so 2 units = 4 years Present age of his son = 4 years 215) Answer: D Solution: Ratio of milk to water in container A is 3 : 2 Ratio of milk to water in container B is 4 : 1 In container A, if 10 litres of water is added to container B then new ratio becomes 2 : 3.So from here we can say that only water is added so milk must be same in both the cases. Now we have to balance milk in container A Ratio of milk to water in container B is 4 : 1……………(1) 10 litres of water is added to container B then new ratio becomes 2 : 3……………(2) Multiplying eq (1) by 1and eq (2) by 2 Above equations can be modified as, Ratio of milk to water in container B is 4 : 1……………(3) 10 litres of water is added to container B then new ratiobecomes 4 : 6……………(4) So from above equations we can say that 5 unit = 10litres 1 unit = 2 Litres Now we can see that final mixture in container B was 10units and 1 unit = 2 Litres so final mixture in container Bis 20 Litres in which water was 8 litre and milk was 12 litre. Container A is having half capacity of B i.e 10 Litres so milk will be 6 litres and water will be 4 litres. 216) Answer: D Solution:

Bag A Bag B Red 2x 3y Blue 3x 4y Green 4x y Condition 1: If 2 more balls were added to bag A then the ratio of balls in bag A to B becomes 5:2. It can be written as – (9x + 2)/8y = 5/2 On solving above equation we get, 18x + 4 = 40y……………..(1) Condition 2: If 1 ball is added to bag B ratio of balls in bag A to bag B becomes 2 : 1 It can be written as (9x)/(8y+1) = 2/1 On solving above we get, 9x - 16y = 2 ……………(2) On solving eq (1) and eq (2) We get x = 2 and y = 1 Total blue balls in bag A is 3x = 6 Balls Total blue balls in bag B is 4y = 4 Balls So total blue balls = 10 217) Answer: A Solution :


Given: (a – b + c ) : ( b – c + 2w ) : (2a + c – w ) = 3 : 4 : 7……………..(1) From eq (1) we can observe that sum of first two terms in the ratio is equals to the third ratio. So we can equate them. (a – b + c ) + ( b – c + 2w ) = (2a + c – w )…………….(2) On solving eq (2) we get, 3w = a + c ………….(4) In the evaluating part we can see that we ( a + c ) is four times. So we will multiply eq(4) by 4 and on multiplying we get, 12w = 4( a + c )………….(5) Putting above value in the evaluating section we get, (12w – 2w) / w 10 : 1 218) Answer: A Solution: The given ratio of passengers to Mumbai and Delhi is written as,

Mumbai Delhi Passengers : 18 : 22

Occupied : Vacant occupied : Vacant 2 : 3 13 : 9

If fare of one passenger was 5000 and Delhi flyte has a loss of 90,000 due to vacancy seats so from here we can say that 18 seats were vacant in Delhi flyte but in ratio we can see it is given as 9. We can say that to get the actual values we have to multiply all the ratio’s by 2 So total passengers were (18+22) * 2 = 80 219) Answer: A Solution: Circle: Radius is increased by 40% as we know that area depends upon square of radius. Area = πr2 Radius old New r 5 7 Area 25 49 So the change is 24 units on 25 units. Percentage change in area = (24/25) * 100 Percentage change in area = 96%....................(1) Cylinder: Volume = πr2h In cylinder Radius is increased by 25% and height is increased by 10% Radius old New r 4 5 r2 16 25 h 10 11 From above we can see that volume is independent of π. Old volume = 160 cu. Units New Volume = 275 cu. Units Percentage change = (115)*100/160 Percentage change = 71.88% ………………..(2) Taking Ratio of eq(1) and eq(2) we get, 96 : 71.88 220) Answer: B Solution:


Total winning amount was Rs. 50000 and this amount is distributed between Amal, Bimal and Kamal in the ratio of 12 : 7 : 6 On distributing the ratio in between them the amount received by Amal, Bimal and Kamal was 24000, 14000 and 12000 respectively. Now Bimal and Kamal will contribute 1000 each to Amal so total amount Amal has 26000 221) Answer: A Solution:

Laptop : Desktop Cost 50 : 40 Quantity 30 : 50

Sold : Unsold 7 : 5

If the company had 100 desktops left and 20 desktops were returned due to defect. In the above statement and from the ratio’s we can observe that there is no linkage of any quantity with the cost of laptop or desktop hence we can say that cost of product cannot be determined. 222) Answer: C Solution: Anu : Kanu = 3 : 8 …………..(1) Kanu : Banu = 2 : 1 …………..(2) Banu : Ranu = 2 : 3 …………..(3) From above three equations we will calculate general ratio’s of all four; Anu : Kanu : Banu : Ranu = 3 : 8 : 4 : 6 ……………..(4) Difference in amount of Anu and Ranu was 600 which is equals to 3 units. 3 units = 600 1 unit = 200 Kanu gets 3 units = 8 * 200 = 1600 223) Answer: C Solution: Selection Percentage was 60% so automatically rejected candidates percentage will be 40%. According to the question, (100% + 50)/(60%-20) = 100%/40%..................(1) On solving above eq(1) we get 100% = 200 So the total applied candidates were 200 Alternative method Selection Percentage was 60% so automatically rejected candidates percentage will be 40%. Let ->Total applied candidates=10X According to the question 10x+50/6x-20=10/4 X=20 Total applied candidates=10X=10*20=200 224) Answer: A Solution: The given ratios are A/(B+C) = 3/4……………(1) B/(C+A) = 5/6…………(2) In order to get the individual ratios let’s sum numerator and denominator of each equation individually. So from eq (1) we get 7 units and from eq (2) we get 11 units. Taking LCM of 7 and 11 = 77 units Multiplying eq (1) by 11 and eq (2) by 7 we get,


A/(B+C) = 33/44……………(3) B/(C+A) = 35/42……………(4) So from above equations we can say A = 33, B = 35 and C = 9 So amount given to B = (35/77)* 12000 So amount given to B = 5454 (approx) 225) Answer: A Solution: Three persons P, Q, R spend 75%, 70%, 80%of their income. So the savings of them will be ,

P : Q : R Expenditure 75% : 70% : 80% Saving 25% : 30% : 20% Savings ratio (given) 20 : 9 : 8 Multiplying above ratio by 10 we get Savings ratio (given) 200 : 90 : 80 From here we can say that 25% = 200 so 1% = 8 and so on so the income ratio can be written as, Income ratio 8 : 3 : 4 Let income ratio be 8x, 3x and 4x, 15x = 45000 x = 3000 Income of P, Q and R = 24000, 9000 , 12000 226) Answer: C Solution: As we know, the compound ratio for the ratios (a : d), (b : e), (c : f) is (a*b*c : d*e*f) Hence, for the given ratios, compound ratio is obtained as, [(3a + 2b)/3] x [1/(3a + b)] = 2/5 5 x (3a + 2b) = 6 × (3a + b) 15a + 10b = 18a + 6b 3a = 4b a/b = 4/3 227) Answer: D Solution: Let the two digit number be 10a + b and the number formed by reversing its digits be 10b + a. (10a + b)/(10b + a) = 7/4 40a + 4b = 70b + 7a 33a = 66b Therefore, a/b = 2/1 So, let us list down all possible values for a and b a b Number Reverse 2 1 21 12 4 2 42 24 6 3 63 36 8 4 84 48 Reverse pair – 12 + 24 + 36 + 48 = 120 228) Answer: A Solution: Ram and shyam has 7 and 8 eggs respectively (Total 15) So ram and shyam has to give 2 and 3 eggs to Sundar to make them equally. (5 eggs each) Sundar gave him Rs. 50 for these 5 eggs of ram and shyam


That means 5 eggs equals to Rs.50 1 egg equals to Rs.10 So ram gives 2 eggs of Rs. 20 and shyam gives 3 eggs of Rs. 30. 229) Answer: A Solution: 4 buckets filled of same fraction i.e a/200 = b/350 = c/470 = d/650 = k(let) a : b : c : d = 200 : 350 : 470 : 650 a : b : c : d = 20 : 35 : 47 : 65 ∴ 20 + 35 + 47 + 65 = 167 units 167 units tends to 2505 1 unit tends to 15 Smallest bucket contains 20 units i.e 20 × 15 = 300. 230) Answer: C Solution: Expenditure = Fixed cost + Variable cost Fixed cost is always same in manufacturing of television i.e. For 150 TV expenditure is 13400 and For 180 TV expenditure is 15000 30 units equals to 1600 150 units equals to 8000 That means 13400 – 8000 = 5400 is fixed cost Cost of 240 units = 12800 + 5400 = 18200 Similarly cost of 270 units = 14400 + 5400 = 19800 240TV : 270TV = 18200 : 19800 = 91 : 99 231) Answer: C Solution: Aggregate ratio of five subject 10 : 9 : 8 : 7 : 6 will be 8………………(1) Since the aggregate marks scored by the student is 8 units.So from here we can say that, 8 units equals to 40% Then 1 unit equals to 5% Maximum marks in each subjects is 100% which will be equals to 20 units. Passing marks in each subjects is given as 35% of maximum marks. Passing marks = 35% of 20 units. Passing marks = 7 units. From eq(1) we can directly observe that their is only one value which is less than 7 while other are greater than 7 so from here we can say that the following student is passed in four subjects. Alternative method Let the full marks of each subject is 100. So, Total Mark in five subjects = 500. Student gets 40% aggregate marks i.e. 40% of 500 = 200 marks. 10x+ 9x+ 8x + 7x +6x = 200 40x = 200 x = 200/40 = 5. Marks in first subject = 10x = 10 *5 = 50 Marks in second subject = 9x = 9 *5 = 45 Marks in third subject = 8x = 8 *5 = 40. Marks in fourth subject = 7x = 7 * 5 = 35 Marks in last subject = 6 *5 = 30. Thus, he passed in 4 subjects.


232) Answer: B Solution: When first person climb up 2 stairs escalator moves 5 stairs Means overall person moves 5 stairs So 5 stairs equals to 240 1units equals to 48 First Person climb up 2 stairs means 96 steps taken Similarly, second person climb up 3 stairs escalator moves 8 stairs 8 stairs equals to 240 1 stairs equals to 30 Second person climb up 3 stairs means 90 steps taken So total steps taken is 90 + 96= 186 Alternative method Ratio of first person to first escalator is 2: 3 Ratio of second person to second escalator is 3: 5 2/5*240+3/8*240 So total steps taken is 90 + 96= 186 233) Answer: D Solution: Let ‘x’ be the animals in zoo Lion: elephant: dog = 5x : 7x : 3x Elephant is 4x more than dog i.e. 4x tends to multiple of both 3×21 = 63 63 is not divisible by 4 and animals cannot be in fraction form, they should be a complete number with multiple of 3×21. 4x tends to 3 × 21 × 4 ‘x’ tends to 63 Total 15x = 15 × 63 = 945 234) Answer: C Solution: (A – B)/(X – Y) = 3 : 2 (given) (A/B) = (X/Y) (given) (A+B)/(A – B) = (X+Y)/(X – Y) ( by applying Componendo &Dividendo) (X+Y)/(A+B) = (X-Y)/(A-B) = 2 : 3 235) Answer: B Solution: M = Men/Women, N = Women/Men M×N =1 N = 1/M 7( M + 1/M)…………..(1) From eq (1) we can say that minimum value of M can be 1. So on putting value of M we get, 7×2 =14 236) Answer: A Solution: From 1st statement we have, a + b + c = 7-------- (1) From 2nd statement we have, a + b + c = 21------- (2) We have to multiple 3 with 1st eq. to get equal value of a


+ b + c so we get a = 9, c = 8 and b = 4 b : (c + a) = 4 : 17 237) Answer: C Solution: Given: 9a2 + 8b2 + 9c2 - 12ab -12bc = 0 --------- (1) (9a2 -12ab + 4b2) + (4b2 -12bc + 9c2) =0 (3a - 2b)2 + (2b - 3c)2 = 0 From here we will be equating both terms to zero and finding ratio’s, a/b = 2/3 and b/c = 3/2 The ratio of a : b : c = 2 : 3 : 2 238) Answer: D Solution: In the given question, we have increase in plan in percentage form while increased or actual price is not given. So we can say that it is not possible to find the actual value hence result will be cannot be determined. 239) Answer: C Solution: Duration (D) = distance(d)/velocity(v) Velocity = square root of quantity (q)/number of carriages (n) Put velocity in duration D= d×n/square root of q D1/D2 = d1/d2 × n1/n2 × square root of q2/q1 120/78 = 60/42 × 20/10 × square root of q2/ √ 169 Square root of q2 = 7 q2 = 49 Quantity of coal (q2) = 49 240) Answer: A Solution: Total sum to be distributed between them was 39,000/- Son = 3 * Daughter …………..(1) Daughter = 2 * Mother …………….(2) Making the common ratios, we get Son : Daughter : Mother = 6 : 2 : 1 ……………..(3) Son : Daughter : Mother = 5 : 4 : 1 …………..(4) Eq (3) denotes the share of single person while eq (4) denotes number of persons Multiplying eq (3) and eq (4) we get, Son : Daughter : Mother = 30 : 8 : 1 …………….(5) Adding all 30x + 8x + x = 39000 39x = 39000 x = 1000 241) Answer: D Solution: Price of gold depends on the weight of its square and divides in 3 parts in the ratio 3 : 4 : 5 then gold weight is to be 12 kg. If gold break into 9 : 5 : 2 then gold weight is to be 16 kg. But actually gold weight is same in both conditions.


So to make it equal we have to multiply with 4 in 12 kg of gold and multiply with 3 with 16 kg of gold then we get 12 : 16 : 20 and 27 : 15 : 6. Gold depends on weight of its square so previously gold weight 144 + 256 + 400 = 800 And now weights 729 + 225 + 36 = 990 means 190 190 units tends to 152000 1 unit tends to 800 Actual cost of gold is square of 48 × 800 i.e. 1843200 242) Answer: C Solution: Virus inside a human organ can triple itself at every second. So, if number of virus is 1 at the beginning Number of virus after 1 sec = 3 Number of virus after 2 sec = 3 raise to the power 2 Number of virus after 3 sec = 3 raise to the power 3 Number of virus after 4 sec = 3 raise to the power 4 Number of virus after 5 sec = 3 raise to the power 5 In the same way, Number of virus after 31 sec = 3 raise to the power 31 Number of virus after 34 sec = 3 raise to the power 33 Ratio of number of virus at 31 sec and 33 sec is 1:27 243) Answer: B Solution: Suppose the number of 2 rupees coins is 6x and number of 5 rupees coins is 11x. If the number of 5 rupees coins is halved, then she will have an amount of Rs. 790. 6x * 2 + (11x/2) x 5 = 790 39.5x= 790 x = 20 Number of 2 rupees coins that Moni has = 6x= 120 244) Answer: D Solution: For dividing 16 into two whole numbers, the sum of the ratio terms must be a factor of 16. 1) 5 : 3 = 5+3 = 8 (factor of 16) 2) 1 : 1 = 1+1 = 2(factor of 16) 3) 1 : 7 = 1+7 = 8(factor of 16) 4) 3 : 4 = 3 + 4 = 7( not factor of 16) Option (4) because 3 + 4 = 7 doesn't divide 16 into whole numbers. 245) Answer: A Solution: Let the salaries of Ram, Shyam and Raman be 3a, 5a and 7a respectively. Let the original sum of Ram's and Shyam's salary be b. b(1- 25/100) = 2000 0.75b = 2000 b = 2666.6 Also, 3a + 5a = 2666.6 8a = 2666.6 a = 333.3 Hence, the amount of money that Raman will get =7a = 7 x 333.3 = Rs. 2333.3 246) Answer: B Solution:


Given that, a + b + c = 1 and ab + bc + ca =1/ 3 ab + bc + ca/ a+b+c = 1 : 3 Заb + 3bc + 3ca = a + b + c a (3b - 1) + b(3C – 1) + с(За - 1) = 0 Since a, b, c are non-zero terms so, (3b – 1), (3c - 1) and (3a - 1) must be zero a = b = c =1/3 a : b : c = 1/3 : 1/3 : 1/3 a : b : c = 1 : 1 : 1 247) Answer: D Solution: Angle S is fourth proportional of angles P, Q and R then, P/Q = R/S Ratio of angles Q and P is 5 : 4, and angle S is 125° So P/Q = 4/5 4/5 = R/125 R = 4 x 25 = 100 Measure of angle R is 100°. 248) Answer: D Solution: Cannot be determined because sum of money is not given in either of the cases. 249) Answer: D Solution: (sin x + cos x)/(sin x - cos x) = (10 + 131/2)/(10- 131/2)……………(1) Applying Componendo and Dividendo, Sin x/ cos x = 10/ root 13 Tan x = 10/root 13 250) Answer: C Solution: Let wide be x Byes+ wide+ run (Monu and Sonu) = 232 x + x + 8 + 26x = 232 28x = 224 X = 8 Run scored by Monu and Sonu is 6:7 Means, 13 units tend to 26x 1 unit tends to 2x = 2×8 =16 Therefore run scored by Sonu is 16 × 7 = 112