28
1 Lecture 8 Daily temperature Vapor pressure Saturation vapor pressure Dew point temperature Relative Humidity

Lecture8 sep30-bb (1)

Embed Size (px)

Citation preview

Page 1: Lecture8 sep30-bb (1)

1

Lecture 8Daily temperatureVapor pressure

Saturation vapor pressureDew point temperature

Relative Humidity

Page 2: Lecture8 sep30-bb (1)

2

Daily temperature

Page 3: Lecture8 sep30-bb (1)

Daily Temperature VariationsQ: When is the minimum

temperature during a day?

Q: When is the maximum temperature during a day?

E=sT4

because Stefan-Boltzmann law

Outgoing LW radiation emitted by the earth should be similar to the daily temperature, why?

Page 4: Lecture8 sep30-bb (1)

Net radiation

Whylag?

Q: Why there is a lag between maximum incoming SR and

temperature? Q: What determines

temperature variations?

Net radiation Net R

Net R=Incoming SW- Outgoing LWif Net R >0,

surface is warmingif Net R <0,

surface is cooling

+Net R

-Net R

-Net R

Similar reason for why the warmest period of a year is in July/August and not on June 21 (summer solstice)

Page 5: Lecture8 sep30-bb (1)

Pressure = Force per unit area

Page 6: Lecture8 sep30-bb (1)

the weight of the column of air will be about 14.7 lbs.

Sea-level pressure is also given in other units:14.7 lbs/inch2 =1013.25 millibars (mb)

Hence, the pressure at sea level is = force/area = 14.7 lbs/inch2

Page 7: Lecture8 sep30-bb (1)

Lecture 1 - 7

Air pressure = total air weight per unit area of the atmospheric column above z

High pressure

Low

pre

ssur

e

Page 8: Lecture8 sep30-bb (1)

Dalton's law

Total pressure exerted by a gaseous mixture is equal to the sum of the partial pressures of each individual component in a gas mixture

2 2 2...H O CO Np p p p

2

2

2

2

2

2

total pressure of the gas mixture

partial pressure of water vapor (H O)

partial pressure of carbon dioxide (CO )

partial pressure of nitrogen (N )

H O

CO

N

p

p

p

p

Page 9: Lecture8 sep30-bb (1)

P = P1 + P2 +P3

For example

Gas mixture

P

=

Per unit area

Gas 1P1

Gas 3P3

Gas 2P2

Per unit area Per unit areaPer unit area

Page 10: Lecture8 sep30-bb (1)

Example Given a parcel of air comprised of only nitrogen, oxygen, and water vapor

N2 78%O2 21%H2O1%

PTotal = PN2+ PO2 + PH2O1000 mb = 780 mb + 210 mb + 10 mb

Page 11: Lecture8 sep30-bb (1)

Fig. 11-9, p. 306

No water condensationNo weather

Under what conditions does condensation occur?

Temperature = Dew point temperature

Relative humidity = 100%

Page 12: Lecture8 sep30-bb (1)

Relative Humidity

Page 13: Lecture8 sep30-bb (1)

NYC daily Weather

Temperaturedew point temperature

Relative humidity

Wind

Rain

Page 14: Lecture8 sep30-bb (1)

Temperature = 43oF Dew point = 31oF

Relative humidity

Page 15: Lecture8 sep30-bb (1)

How much water vapor can be held in

the air?

What determines the capacity?

Page 16: Lecture8 sep30-bb (1)

0 5 10 15 20 25 30 35 40 45 500

10

20

30

40

50

60

70

80

90

100

110

120

Temperature (oC)

Vap

or p

ress

ure

PH

2O

(m

b)

Vapor Pressure 2H Op

Water

Dry Air

T=30°C

Total weight of water vapor per unit area

20H OP

Saturation Vapor Pressure P*H2O

Page 17: Lecture8 sep30-bb (1)

0 5 10 15 20 25 30 35 40 45 500

10

20

30

40

50

60

70

80

90

100

110

120

Temperature (oC)

Vap

or p

ress

ure

(m

b)

Vapor Pressure 2H Op

20H OP Water

Moist Air

H2Ovapor

T=30°C

evaporation

Total weight of water vapor per unit area

Saturation Vapor Pressure P*H2O

Page 18: Lecture8 sep30-bb (1)

0 5 10 15 20 25 30 35 40 45 500

10

20

30

40

50

60

70

80

90

100

110

120

Temperature (oC)

Vap

or p

ress

ure

(m

b)

2

*H OP

2

*H OP

Saturation Vapor Pressure 2

*H oP

Total weight of water vapor per unit area

T=30 oCSaturation: balance between the number of water molecules entering and leaving the water surface.

=

Air is “saturated”

2H OP

2

17.27* 273.3( ) 0.6108

T

TH OP T e

Q: what does this red curve tell us?

Page 19: Lecture8 sep30-bb (1)

0 5 10 15 20 25 30 35 40 45 500102030405060708090100110120

Temperature (oC)

Satu

rati

on

vap

or

pre

ssu

re (

mb

)

T=30 oC

T=44 oC

T=10 oC

This curve indicates how much water vapor can be held in the air at a given temperature

2

*H OP

Temperature determines the capacity of holding water vapor in the air

2

17.27* 273.3( ) 0.6108

T

TH OP T e

Page 20: Lecture8 sep30-bb (1)

20

Why does Hurricane always generate in

these areas?

Hurricane = Typhoon = Tropical CycloneAtlantic and eastern Pacific: hurricaneWestern Pacific: typhoonIndian Ocean & Australia: tropical cyclone

Page 21: Lecture8 sep30-bb (1)

0 5 10 15 20 25 30 35 40 45 500

10

20

30

40

50

60

70

80

90

100

110

120

Temperature (oC)

Satu

rati

on

vap

or

pre

ssu

re (

mb

)

2

*H OP

Relative Humidity

Total weight of water vapor per unit area

T=30 oCSaturation: balance between the number of water molecules entering and leaving the water surface.

=

Air is “saturated”2

*H OP

2H OP

2

2

*100%H O

H O

PRH

P

Page 22: Lecture8 sep30-bb (1)

0 5 10 15 20 25 30 35 40 45 500

10

20

30

40

50

60

70

80

90

100

110

120

Temperature (oC)

Satu

rati

on

vap

or

pre

ssu

re (

mb

)

2

*H OP

Saturation Vapor Pressure 2

*H oP

Total weight of water vapor per unit area

T=30 oCSaturation: balance between the number of water molecules entering and leaving the water surface.

2

2

*100%H O

H O

PRH

P =

Air is cooled toT=20 oC2H OP

Dew point

2

*H OP

Page 23: Lecture8 sep30-bb (1)

Dew point temperature

Temperature to which a given parcel of air must be cooled for water vapor to condense into water.

Page 24: Lecture8 sep30-bb (1)

0 10 20 30 40 500

10

20

30

40

50

60

70

80

90

100

110

120

Satu

rati

on v

apo

r pr

essu

re (

mb

)2

2

*100%H O

H O

PRH

P

2

1H OP

2

*H OP

Tdew Dew point

o10 C

2

2H OP

o26 C o34 C

2

3H OP

Page 25: Lecture8 sep30-bb (1)

NYC daily Weather

Temperature indicates the capacity of holding water vapor in the air

Dew point temperature indicates how much water vapor is in the airRelative humidity

Page 26: Lecture8 sep30-bb (1)

0 5 10 15 20 25 30 35 40 45 500102030405060708090100110120

Temperature (oC)

Satu

ratio

n va

por p

ress

ure

(mb)

This curve indicates how much water vapor can be held in the air at a given temperature

( )se T17.625

( ) 6.1exp243.04s

Te T

T

T=10 oCT=30 oC

T=44 oC

Hot weatherHot weather The atmosphere can hold more water vapor.

The atmosphere can hold more water vapor.

Page 27: Lecture8 sep30-bb (1)

The water-holding capacity of the atmosphereThe water-holding capacity of the atmosphere

Increased flooding

Increased flooding

Global warmingGlobal warming

It takes longer to recharge

It takes longer to recharge

It releases more latent heat

It releases more latent heat

It produces heavier rainsIt produces

heavier rains

More violentMore

violentIncreased

droughtIncreased

drought

Extreme weatherExtreme weather

increased

Page 28: Lecture8 sep30-bb (1)

The water-holding capacity of the

atmosphere

The water-holding capacity of the

atmosphereincreased

The carbon-storage capacity of the

terrestrial biosphere

The carbon-storage capacity of the

terrestrial biosphere

Global warming

Global warming

Extreme weather

Extreme weather

increased

altering

Feedback by changing atmospheric CO2

How ?