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Basic Pharmacokinetics REV. 99.4.25 9-1Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
CHAPTER 9 Clearance
OBJECTIVES
1. Given patient information regarding organ function, the student will calculate (III) changes in clearance and other pharmacokinetic parameters inherent in compro-mised patients.
2. Determine the total clearance based on Dose and AUC.
3. Determine clearance of an organ based on dose, AUC, and fraction of drug elimi-nated by the organ
4. Determine change in clearance due to functional changes in an organ.
5. Determine change in clearance due to change in blood flow through an organ.
6. Prepare a professional consult (V) and justify (VI) modifications in drug therapy based on clearance of a drug.
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-2Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
9.1 Equations
(EQ 9-1)
(EQ 9-2)
(EQ 9-3)
(EQ 9-4)
(EQ 9-5)
(EQ 9-6)
(EQ 9-7)
(EQ 9-8)
(EQ 9-9)
(EQ 9-10)
(EQ 9-11)
(EQ 9-12)
(EQ 9-13)
(EQ 9-14)
(EQ 9-15)
Cl Rate of EliminationSerum Concentration---------------------------------------------------=
Cltotf D⋅ osAUC
----------------=
Clr Cltot Fraction of drug that is renally eliminated( )⋅=
ClH Cltot Fraction of drug that is hepatically eliminated( )⋅=
Qr 0.0191 Lmin kg⋅-------------------- renal blood perfusion 70kg 60min
hr---------⋅ ⋅ 80 L
hr-----blood≈=
QH 0.0238 Lmin kg⋅-------------------- hepatic blood perfusion 70kg 60min
hr---------⋅ ⋅ 100 L
hr-----blood≈=
Er Clr( ) Qr⁄=
EH ClH( ) QH⁄=
fu Clint⋅ Q Cl⋅Q Cl–----------------=
Clint
Q Cl⋅Q Cl–----------------
fu
----------------=
Fi
fu∗ Cl∗int⋅fu Clint⋅
--------------------------=
FRQ∗Q-------=
FCl
Fi FR⋅FR Er Fi FR–( )+-----------------------------------------=
FCltot
Cl∗tot
Cltot
-------------- k∗ V∗⋅k V⋅
----------------Cl∗H Cl∗r+
ClH Clr+-----------------------------= = =
0.80 FClto t≤ 1.20≤
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-3Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
9.2 Definitions and Terms
Clearance: The hypothetical volume of a fluid from which a substance istotally and irreversibly removed per unit time.
Dimensions:
Examples of fluids: blood, serum, plasma, bile, gut contents, CSF.
Systemic or Total Body Clearance: Removal process is elimination
(excretion and metabolism). Fluid is usually plasma or serum (rarely blood).
Renal Clearance: Removal process is urinary excretion of
unchanged drug. Fluid is usually plasma or serum (rarely blood).
Metabolic Clearance: Removal process is metabolism. Fluid is usu-
ally blood (rarely plasma or serum).
Hepatic Clearance: This is when the liver is the metabolic
organ.
Creatinine Clearance: This is applied to endogenous creatinine.
It is used to monitor renal function, and thus is a valuable parameter for calculatingdosage regimens in elderly patients or those suffering from renal dysfunction. Cre-atinine
Value for normal males: 117 ± 20 ml/minValue for normal females: 108 ± 20 ml/min
Inulin Clearance: This is for inulin, and yields the glomerularfiltration rate.
Value for normal males: 124.5 ± 9.7 ml/minValue for normal females: 108.8 ± 13.5 ml/min
L3
T⁄
Cl( ), Cltot( )
Clr( )
Clm( )
ClH( ) Clm
Clcr( ) Clr
t1 2⁄ 231min=
Clinulin Clr
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-4Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
9.3 Measurement of Creatinine Clearance
The mass of endogenous creatinine excreted into the urine collected over a given
time interval is determined. The mean serum creatinine concentration over that interval is calculated from sample determinations; this should be the con-
centration halfway through the interval. In practice, and, as is rela-tively constant, the serum sample is taken at any convenient time.
Let “a” be a volume of serum having a creatinine concentration of . The mass
of creatinine in the serum will be . If this creatinine is totally and irrevers-ibly removed from the serum to the urine in the time interval, , then
(EQ 9-16)
Thus, (EQ 9-17)
The volume of serum from which this creatinine is removed in unit time is ;this is the definition of clearance. Hence,
(EQ 9-18)
Siersbaek-Neilson et al. report a value of 11.1 for in 149 males (aged20-99). The value of decreased with age from 16.53 per Kg body
weight (age 20-29) to 6.53 per Kg body weight (age 90-99). For a 25 year
old 70Kg male, equation 9-18 yields
∆t( ) Cs( )cr
∆t 24hr= Cs( )cr
Cs( )cr
a Cs( )cr⋅
∆t
a Cs( )cr⋅ ∆Xu=
a∆Xu
Cs( )cr
---------------=
a ∆t⁄
Clcra∆t-----
∆Xu ∆t⁄( )T
Cs( )cr
---------------------------= =
µg ml⁄ Cs( )cr
∆Xu ∆t⁄( )T
µg min⁄
µg min⁄
Clcr 104.2 mlmin---------=
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-5Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
9.4 Model Correlations
Although intrinsically model independent, clearance can also be related to com-partmental models.
9.4.1 RENAL CLEARANCE
The plasma renal clearance of a drug may be measured analogously to creatinineclearance:
(EQ 9-19)
The practical versions of and states:
(EQ 9-20)
Comparing equation 9-19 and equation 9-20,
(EQ 9-21)
This relates clearance to model parameters. What is the slope of a plot of
against ?
Note that if (males), it may indicate active secretion of the druginto the kidney tubules. If (females), it may indicate reabsorp-
tion of the drug from the kidney tubules.
9.4.2 SYSTEMIC CLEARANCE AND METABOLIC CLEARANCE
How could you measure ? and
By analogy,
(EQ 9-22)
and , so .
Consequently, fractional changes in clearance,
Clr
∆Xu ∆t⁄( )T
Cp
---------------------------=
∆Xu ∆t⁄( )T
kuX kuVCp= =
Clr kuV=
∆Xu ∆t⁄( )T
Cp
Clr 117 20ml min⁄±>
Clr 108 20ml min⁄±<
Cl Clm
Cltot KV 0.693Vt1 2⁄
-----------------= =
K ku km+= Cltot Clr Clm+=
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-6Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
(EQ 9-23)
where is new or altered variable. Hepatic function and renal function are not apriori connected, although some physiological functional changes might result insimilar changes in clearance of both organs. We can see from equation 9-12 thatchanges in total body clearance can result in changes in either K, V, or both. Theconsequences of that will be discussed in the section on dosage regimens.
9.4.3 USE IN PHARMACOKINETIC EQUATIONS
Systemic Clearance (Cl) can be used in many equations where the drug is removedby elimination (renal excretion and metabolism). If renal excretion is the onlyremoval process, use l if metabolism, use . Some examples:
Intravenous infusion:
Oral and Intravenous Bolus:
This equation becomes a means of calculating Cl from plasma data.
Dosage Regimen:
These examples are all model-independent expressions, which are very useful incalculating dosage regimens. The importance of clearance terms rests on their abil-ity to account for variations in both and / or V simultaneously, as both these
parameters can change in disease states and with age.
FCl tot
Clh°
Clr°
+
Clh Clr+------------------------- K
°V
°⋅K V⋅
----------------= =
X°
Clr Clm
Cp( )ss
QCl------=
Clf Xa( )
0
Cp td
0
∞
∫--------------- fD
Cp td
0
∞
∫--------------- fD
AUC------------== =
Cp( )ssfD
τ Cl⋅-------------=
t1 2⁄
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-7Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
9.5 Physiological Factors Affecting Clearance
9.5.1 INTRINSIC CLEARANCE
Intuitively, it may be recognized that two factors will affect the clearance of a drug:
1. The rate at which blood is presented to the eliminating organ.2. The intrinsic ability of the eliminating organ to clear the drug.
Mathematically, a hyperbolic equation has been derived to illustrate the relativeeffect of these factors. (Note: this is one model of clearance. There are several oth-ers which also illustrate the effect of these factors.)
Liver Drug Metabolism
(EQ 9-24)
Where is the rate of blood flow through the liver (assumed 23.8 ml/min/Kgbody weight in normal adult),
fu is the fraction unbound of the drug, and
is the intrinsic hepatic clearance of the drug.
If there were no physiological limits to the rate of blood flow , hence equa-tion 9-24 becomes
(EQ 9-25)
This equation provides a definition for intrinsic clearance, namely the clearance ofa drug were there to be no physiological limits on the rate of blood flow throughthe clearing organ.
Cl int( )
ClH
QH fu⋅ ClH( )⋅ int
QH fu ClH( )⋅ int+------------------------------------------=
QH
ClH( )int
QH ∞→( )
ClH ClH( )int
=
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-8Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Kidney drug excretion By analogy for excretion of unchanged drug by the kidney:
(EQ 9-26)
Where is the rate of blood flow through the kidney (assumed 19.1 ml/min per
Kg body weight in normal adults), and
is the intrinsic renal clearance of the drug.
Note that the value of (assumed 1.75 ml.min per Kg body weight in normaladults) is about 9% of .
9.5.2 EXTRACTION RATIO (E)
This is defined as “the ratio of the clearance of a drug compared to the rate of blood flow through the clearing organ.” As such, it indicates what fraction of the drug in the blood is cleared (extracted) on each passage through the clearing organ. Note: when using clearance to calculate extraction ratio, blood flow must be used.
Drug metabolism by the liver
(EQ 9-27)
Where is the steady-state hepatic extraction ratio.
By comparison with equation 9-24,
(EQ 9-28)
Thus, the range of values of is from zero, when , to one, when
or . For example, propanolol has , yielding
and in normal adult males.
Clr
Qr fu Clr( )int
⋅ ⋅
Qr fu Clr( )⋅ int+---------------------------------------=
Qr
Clr( )int
Clcr
Qr
EH
ClH
QH
---------=
EH
EH
fu ClH( )⋅ int
QH fu ClH( )⋅ int+------------------------------------------=
EH ClH( )int
0=
QH 0= ClH( )int
QH» EH 0.75=
ClH17.9ml
min Kg body weight⋅-----------------------------------------------------= ClH( )
int71.4ml
min Kg body weight⋅-----------------------------------------------------=
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-9Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Kidney excretion of unchanged drug
(EQ 9-29)
(EQ 9-30)
where is the steady-state renal extraction ratio.
Thus the range of values is from zero, when , to one, when or
. For example, digoxin has , yielding
and in normal adult males. In this case, note that
Er
Clr
Qr
--------=
Er
fu Clr( )⋅int
Qr fu Clr( )⋅ int+---------------------------------------=
Er
Clr( )int
0= Qr 0=
Clr( )int
Qr» Er 0.09= Clr1.72ml
min Kg body weight⋅-----------------------------------------------------=
Clr( )int
1.89mlmin Kg body weight⋅-----------------------------------------------------=
Clr Clcr≈
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-10Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
9.6 Hepatic Function and Clearance
9.6.1 ALTERATIONS IN HEPATIC BLOOD FLOW
For a given drug, equation 9-24 predicts that alterations in the hepatic blood perfu-sion rate will cause a change in drug clearance, assuming the intrinsic hepatic clearance is unaltered. A general equation may be derived relating the ratio of hepatic clearances at two blood perfusion rates to the fractional change in perfu-sion rate and the extraction ratio of the drug.
(EQ 9-31)
where denotes normal hepatic clearance,
denotes altered hepatic clearance
is the new flow rate over the old flow rate, the fractional change in blood
perfusion rate, and
is the hepatic extraction ratio under normal conditions.
The equation predicts that, for any given decrease in blood perfusion rate, drugshaving a large normal extraction ratio will experience a proportionally greaterreduction in clearance than drugs having a small normal extraction ratio.
Liver blood flow can be reduced by congestive heart failure, for example. Theintrinsic hepatic clearance can be represented by the inherent activity of theenzymes responsible for drug metabolism.
9.6.2 ALTERATIONS IN HEPATIC INTRINSIC CLEARANCE
For any given drug, equation 9-24 predicts that alterations in the intrinsic hepatic clearance will cause a change in drug clearance, assuming the blood flow rate is unchanged. A general equation may be derived relating the ratio of hepatic clear-ance at two intrinsic hepatic clearances to the fractional change in intrinsic hepatic and the extraction ratio of the drug.
Cl∗H
ClH
------------FR
FR EH 1 FR–( )+-----------------------------------------=
ClH
Cl∗H
FR
QH∗
QH----------=
EH
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-11Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
(EQ 9-32)
where is the fractional change in fraction unbound times the frac-
tional change in intrinsic hepatic clearance.
The equation predicts that, for any given decrease in intrinsic hepatic clearance,drugs having a small normal extraction ratio will experience a proportionatelygreater reduction in clearance than drugs having a large normal extraction ratio.
The intrinsic hepatic clearance of a drug can be reduced by cirrhosis or increasedby enzyme inducers, such as phenobarbitol.
9.6.3 TABULATED OR GRAPHICAL ALTERATIONS
A table or graph of clearance changes when the hepatic blood flow (but not the intrinsic hepatic clearance) is altered shows that drugs having a low extraction ratio need little adjustment in dosage. Even if the hepatic blood flow were halved , the hepatic clearance is still 91% of its normal value. Con-
versely, dosage adjustment is necessary for drugs having a high extraction ratio and predominantly eliminated by hepatic metabolism (e.g., propanolol).
A table or graph of clearance changes when the intrinsic hepatic clearance (but notthe hepatic blood flow) is altered shows that drugs having a high extraction ratio
need little adjustment in dosage. Even if the intrinsic hepatic clearance
were halved , the hepatic clearance is still 91% of its normal value. Con-versely, dosage adjustment is necessary for drugs having a low extraction ratio andpredominately eliminated by hepatic metabolism (e.g., phenylbutazone).
Cl∗H
ClH
------------Fi
1 EH Fi 1–( )+-----------------------------------=
Fi
fu∗ Clint( )∗⋅fu Clint( )⋅
-------------------------------=
EH 0.1=( )
FR 0.5=( )
EH 0.9=( )
Fi 0.5=( )
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-12Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
9.7 Renal Function and Clearance
Approximately 25% of cardiac output goes to the kidneys or approximately 735 ml/min of plasma is presented to the kidneys of a 70 kg man (19.1 mL/min/kg x 70 kg). Approximately 125 ml/min (1.8 mL/min/kg) of that goes to the glomeruli for filtration (Glomerular Filtration Rate, GFR). Unbound drug is filtered into the proximal renal tubule at this point. The remaining plasma (as blood) is shunted around the tubule in the arterioles adjascent to the proximal tubule where drug may be actively secreted from the arteriol into the proximal tubule or actively reabsorbed in the opposite direction. As the blood flows down the vessels adjas-cent to the loop of Henle, the drug may be also passively reabsorbed into the blood vessel as the water in the urine is being reabsorbed and the urine is being concen-trated.
This leads to some interesting possibilities:
1. . It is likely that the drug is filtered only, in this case, . It is also possible that
secretion and reabsortion balance and cancel each orther out but are still occurring. The actual clearance of the drug may be low as the drug may be bound to plasma protiens or red blood cells.
11. . Net active secretion is infered in this case. These active mechanisms are non-
specific and consequently, drugs actively secreted compete with each other. Secretion, if it occurs, occurs on the unbound drug and thus is also effected by changes in free fraction. In cases where secretion is very rapid and as a consequence, virtually all of the drug is removed by the single pass through the kidney (Er ~1), the disssociation of the drug from the protien or out of the red blood cells is not a hinderance. Some reabsorption may occur but it is less than secre-tion.
12. . Net active reabsorbtion is infered in this case. Active reabsorption occurs for
many exogenous compounds, including glucose and vitamins. For many compounds, reabsorp-tion is passive, occurring only as a consequence of the concentration gradient produced as water is removed from the urine as is proceeds down the renal tubule. Since the membrane is lipoidal in nature, polar compounds, ionized acids and ionized bases are less likely to be reabsorbed. Thus changing the pH of the urine would result in changing the reabsorption characteristics of weakly acidic or basic drugs.
For low molecular weight drugs (<2,000 dalton) , filtration always occurs. Active secretion, active reabsorption and passive reabsorption may occur.
It has been found that renal blood flow is little affected by changes in blood flow elsewhere. However, in chronic renal dysfunction there are two effects which exhibit a parallel decline. One is a decrease in glomerular filtration rate (GFR), as measured by , and the other is the net secretion of drugs into the kidney
tubules. Note that p-amino hippurate (PAH) clearance measures the sum of both effects.
Clr fu GFR⋅=
Clr fu GFR⋅>
Clr fu GFR⋅<
Clcr
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-13Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
For any given drug, equation 9-26 predicts that alterations in both the renal bloodperfusion rate (as manifest by the GFR) and the intrinsic renal clearance will causea change in drug clearance. A general equation may be derived relating the ratio ofrenal clearances at two different blood flow rates and two different intrinsic renalclearances.
(EQ 9-33)
where is the fractional change in drug unbound times the fractional change inintrinsic renal clearance.
In this case,
(EQ 9-34)
where is the fractional change in blood flow rate (or GFR).
Thus, equation 9-33 shows that the renal clearance of a drug is reduced by a con-stant fraction, independent of the renal extraction ratio . This fractionaldecrease can be estimated by changes in creatinine clearance:
(EQ 9-35)
where is the altered creatinine clearance
Substituting, equation 9-33 through equation 9-35, we get:
(EQ 9-36)
This equation shows why, in cases of chronic renal dysfunction, a change in themeasured creatinine clearance indicated a likely change in drug renal clearance.Hence, dosage adjustments are made on this basis, particularly for drugs predomi-nantly eliminated by renal filtration (e.g., gentamicin, digoxin).
Cl∗r
Clr
----------- Fi=
Fi
Fi
fu∗
fu
------- F⋅R
=
FR
Er( )
FRCl∗cr
Clcr
-------------=
Cl∗cr
Cl∗r
Clr
-----------Cl∗cr
Clcr
-------------=
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-14Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
9.8 General Equations for Changes in Clearance
For each clearing organ,
(EQ 9-37)
When a drug has a high extraction ratio, , then equation 9-26 becomes
(EQ 9-38)
and when a drug has a low extraction ratio, , then equation 9-26 becomes
(EQ 9-39)
Thus, the clearance of drugs with a high extraction ratio are more effected by phys-iological changes in flow of blood to the clearing organ, while drugs with a lowextraction ratio are more effected by physiological changes in the function of theorgan.
9.8.1 PLASMA/BLOOD RATIO
Calculation of Extraction Ratio requires measurement in whole blood by defini-tion. Since most clinical measurements are done in plasma, knowledge of the plasma/blood ratio is necessary. Blood in made up of plasma and red blood cells (RBCs). Thus the amount of drug in the blood is made up of the amount of drug in the plasma and the amount of drug in the RBCs.
(EQ 9-40)
where
and b = blood, p = plasma, rbc = red blood cell
If we define the ratio of the concentration of the drug in the RBCs to the concentra-tion of the free drug in plasma as
(EQ 9-41)
and
(EQ 9-42)
FClClCl------
° FI FR⋅FR E+ FI FR–( )----------------------------------------= =
E 1≈
FCl FR≈
E 0≈
FCl FI≈
Cb Vb⋅ Cp Vp⋅ Crbc Vrbc⋅+=
Cx Vx⋅ AMOUNTx=
ρCrbc
fu Cp⋅---------------=
Vrbc H Vb⋅=
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-15Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
(EQ 9-43)
Pluging equation 9-41 thru equation 9-43 into equation 9-40 results in:
(EQ 9-44)
Rearranging and simplifying results in:
(EQ 9-45)
(EQ 9-46)
Thus equation 9-46 determines the affinity of the drug for the RBCs. Drugs with ahigh affinity for the RBCs should result in a smaller volume of distribution.
For drugs that are primarily filtered by the glomeruli, the renal extraction ratio is:
(EQ 9-47)
Putting equation 9-45 into equation 9-47 results in:
(EQ 9-48)
Thus:
1. If the the ratio of to calculated Erf from equation 9-48 is one, it is likely that the drug is
filtered only.
13. If the the ratio of to calculated Erf from equation 9-48 is greater than one, active secretion
is infered in this case.
14. If the the ratio of to calculated Erf from equation 9-48 is less than one, active reabsorb-
tion is infered in this case.
Vp 1 H–( ) Vb⋅=
Cb Vb⋅ 1 H–( ) Vb Cp⋅ fu ρ H Vb Cp⋅ ⋅ ⋅ ⋅+⋅=
Cb
Cp
------ 1 H fu ρ 1–⋅( )⋅+=
ρH 1– Cb Cp⁄( )+
fu H⋅-----------------------------------------=
ErfRate of filtration
Rate of presentation------------------------------------------------
GFR fu Cp⋅ ⋅Qr Cb⋅
--------------------------------==
Erf
GFR fu⋅Qr 1 H fu ρ 1–⋅( )⋅+( )⋅-----------------------------------------------------------=
Clr
Qr
--------
Clr
Qr--------
Clr
Qr--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-16Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
9.8.2 HALF LIFE AND ELIMINATION RATE CONSTANT IN RELATIONSHIP TO CLEARANCE
The elimination rate constant is related to the volume of distribution and the total body clearance by equation 9-22 above which when rewritten yields:
(EQ 9-49)
(EQ 9-50)
where b = blood and pwu = unbound plasma water. Clearance of drug from blood(Clb) is useful in considering drug extraction in the eliminating organs. Volumeand clearance terms based on unbound drug concentration are particularly usefulin therapeutics, because only the unbound drug is thought to cause the therapeuticaction.
9.8.3 EFFECTS OF ALTERATIONS IN PROTEIN BINDING ON CLEARANCE
Protein binding of drugs may be altered in disease states and by interferance bind-ing by other drugs on the protein. These changes in binding effect Fi , the frac-tional change in intrinsic clearance in both renal and hepatic clearances eventhough the actual intrinsic clearance, the indicator of organ function, may be unef-fected as shown in equation 9-11:
where . Thus, a change in protein binding will cause a proportionalchange in Fi of both clearances. There is more discussion in the chapter on proteinbinding.
K Rate of EliminationAmount in the body------------------------------------------------ Mass( ) Time( )⁄
Mass---------------------------------------- Cl
V------ Volume( ) Time( )⁄
Volume----------------------------------------------= = = =
K ClV------
Clb
Vb
--------Clpwu
Vpwu
-------------= = =
Fi
fu∗ Cl∗int⋅fu Clint⋅
--------------------------=
Cl∗int Clint=
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-17Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
9.9 Problems
For each of the problems, do questions A through R now and S through W after completing chapter 10. In doing questions S through W, please try to obtain a
plasma concentration of free drug within 120 % of normal and 80 % of
.
Cpss
maxfree
Cpss
minfree
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-18Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Acebutolol (Problem 9 - 1)
Piquette-Miller, M., et. al., “Effect of aging on the pharmacokinetics of acebutolol enantiomers”, Journal of Clinical Pharmacol-ogy, Vol. 32, (1992), p. 148 - 156. Kukes, VG; Gneushev ET; Mamedov TS; Gneusheva IA; “Acebutolol and diacetolol: thier bind-ing to plasma and erythrocytes and secretion with saliva.” Farmakol-Toksikol. 1991 Jan-Feb; 54(1) Acebutolol is a beta-adrenergic blocking agent which is often used in the treatment of hypertension.(Use Qr = 72 L/hr;
Qh = 90 L/hr)
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
PROBLEM TABLE 9 - 1. Acebutolol
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 200 400
B f 0.4
C fu 0.867
D 1.93
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 5.5
H %Clr 40
I %Clnr 60
J AUC (mg/L*hr) 3.97
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr) 12
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
maxfree
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-19Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 1. Answers for Acebutolol
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 200 400 BID 400 BID 400 BID 400 BID 200 QID
FRR 1 1 0.5 1 1 1
FIR 1 1 0.5 0.5 1 1
FRH 1 1 1 1 0.5 1
FIH 1 1 1 1 1 0.5
B f 0.4
C fu 0.867
D 1.93
E Vd (L) 160
F k (hr-1) 0.126 0.101 0.102 0.12 0.091
G T 1/2 (hr) 5.5 6.87 6.77 5.89 7.64
H %Clr 40 25 26.1 42.9 55.5
I %Clnr 60 75 73.9 57.1 44.6
J AUC (mg/L*hr) 3.97 9.93 9.78 8.51 5.5
K (L/hr) 20.2 16.1 16.4 18.8 14.5
L (L/hr) 12.1 12.1 12.1 10.7 6.5
M (L/hr) 8.1 4.03 4.27 8.1 8.1
L 0.126
O 0.112
P (L/hr) 16
Q (L/hr) 10.5
R FCL 1 0.8 0.81 0.93 0.72
S (hr) 12 12 12 12 6
T N 2.18 1.75 1.77 2.04 0.785
U
1.11 1.24 1.23 1.15 1.03
V 0.57 0.72 0.71 0.61 0.80
W 0.25 0.37 0.36 0.28 0.6
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
maxfree
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-20Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Bisoprolol (Problem 9 - 2)
Kirch, W., et. al., “Pharmacokinetics of bisoprolol during repeated oral administration to healthy volunteers and patients with kid-ney or liver disease”, Clinical Pharmacokinetics, Vol. 13, (1987), p. 110 - 117.Bisoprolol (comes as 5 and 10 mg tablets) is a - selective adrenergic antagonist. It is used in the treatment of hyperten-sion and angina pectoris.(Use Qr = 72 L/hr; Qh = 90 L/hr)
PROBLEM TABLE 9 - 2. Bisoprolol
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 10 10 TID
B f 0.7
C fu 1
D 1
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 10
H %Clr 50
I %Clnr 50
J AUC (mg/L*hr) 0.661
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
maxfree
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-21Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 2. Answers for Bisoprolol
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 10 10 10 10 10 10
FRR 1 1 0.5 1 1 1
FIR 1 1 0.5 0.5 1 1
FRH 1 1 1 1 0.5 1
FIH 1 1 1 1 1 0.5
B f 0.9
C fu 0.7
D
E Vd (L) 152.8
F k (hr-1) 0.0693 0.052 0.0526 0.067 0.0525
G T 1/2 (hr) 10 13.3 13.2 10.3 13.2
H %Clr 50 33.3 34 51.3 66
I %Clnr 50 66.7 66 48.7 34
J AUC (mg/L*hr) 0.661 0.85 0.87 0.69 0.87
K (L/hr) 10.6 7.94 8.0 10.3 8.0
L (L/hr) 5.3 5.3 5.3 5.0 2.7
M (L/hr) 5.3 2.65 2.8 5.3 5.3
L 0.055
O 0.074
P (L/hr) 5.6
Q (L/hr) 5.7
R FCL 1 0.75 0.76 0.97 0.76
S (hr) 8 12 12 8 12
T N 0.8 0.9 0.9 0.78 0.91
U
0.108 0.099 0.098 0.11 0.098
V 0.083 0.073 0.073 0.085 0.073
W 0.062 0.052 0.052 0.064 0.052
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
maxfree
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-22Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Cefonicid (Problem 9 - 3)
Fillastre, J., et. al., “Pharmacokinetics of cefonicid in uraemic patients”, Journal of Antimicrobial Chemotherapy, Vol. 18, (1986), p. 203 - 211.Cefonicid is a beta-lactamase resistant cephalosporin which is useful in treating many infections caused by Gram-posi-tive and Gram-negative organisms. Cefonicid is 80% renally excreted.(Use Qr = 72 L/hr; Qh = 90 L/hr)
PROBLEM TABLE 9 - 3. Cefonicid
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 1000 1000 TID
B f 1
C fu 0.06
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 5.3
H %Clr 80
I %Clnr 20
J AUC (mg/L*hr) 654
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-23Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 3. Answers for Cefonicid
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 1000 1000 1000 1000 1000 1000
FRR 1 1 0.5 1 1 1
FIR 1 1 0.5 0.5 1 1
FRH 1 1 1 1 0.5 1
FIH 1 1 1 1 1 0.5
B f 1
C fu 0.06
D
E Vd (L) 11.7
F k (hr-1) 0.131 0.078 0.079 0.131 0.118
G T 1/2 (hr) 5.3 8.8 8.8 5.3 5.9
H %Clr 80 66.7 66.9 80 88.9
I %Clnr 20 33.3 33.1 20 11.1
J AUC (mg/L*hr) 654 1090 1083 654 727
K (L/hr) 1.53 0.917 0.93 1.5 1.4
L (L/hr) 0.3 0.31 0.31 0.3 0.15
M (L/hr) 1.22 0.612 0.62 1.22 1.22
L 0.0032
O 0.017
P (L/hr) 5.11
Q (L/hr) 20.7
R FCL 1 0.6 0.6 1 0.9
S (hr) 8 12 12 8 8
T N 1.51 1.4 1.4 1.51 1.36
U
7.9 8.4 8.4 7.9 8.4
V 4.9 5.5 5.4 4.9 5.4
W 2.8 3.3 3.3 2.8 3.3
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-24Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Cefpirome (Problem 9 - 4)
Lameire, N., et. al., “Single-dose pharmacokinetics of cefpirome in patients with renal impairment”, Clinical Pharmacology and Therapeutics, Vol. 52, (1992), p. 24 - 30.Cefpirome is a third-generation, broad-spectrum cephalosporin which is useful against many cephalosporin-resistantorganisms.
PROBLEM TABLE 9 - 4. Cefpirome
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 2000 IV 2000 TID
B f 1
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 2.6
H %Clr 85
I %Clnr 15
J AUC (mg/L*hr) 342
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-25Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 4. Answers for Cefpirome
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-26Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Cefprozil (Problem 9 - 5)
Shyu, W., et. al., “Pharmacokinetics of cefprozil in healthy subjects and patients with renal impairment”, Journal of Clinical Phar-macology, Vol. 31, (1991), p. 362 - 371.Cefprozil is a broad-spectrum oral cephalosporin.
PROBLEM TABLE 9 - 5. Cefprozil
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 1000
B f 0.95
C fu 0.7
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 1.2
H %Clr 75
I %Clnr 25
J AUC (mg/L*hr) 58.1
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-27Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 5. Answers for Cefprozil
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-28Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Chloramphenicol (Problem 9 - 6)
Ambrose, P., “Clinical pharmacokinetics of chloramphenicol and chloramphenicol succinate”, Clinical Pharmacokinetics, Vol. 9, (1984), p. 222 - 238.Chloramphenicol succinate is a prodrug which is converted in vivo to the active form, chloramphenicol.
PROBLEM TABLE 9 - 6. Chloramphenicol
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 1000
B f 1
C fu 0.4
D
E Vd (L/kg) 2.8
F k (hr-1)
G T 1/2 (hr) 0.6
H %Clr 30
I %Clnr 70
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-29Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 6. Answers for Chloramphenicol
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-30Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Enalapril (Problem 9 - 7)
Ohnishi, A., et. al., “Kinetics and dynamics of enalapril in patients with liver cirrhosis”, Clinical Pharmacology and Therapeutics, Vol. 45, (1989), p. 657 - 665.Enalapril is an ACE inhibitor which is a prodrug that is metabolized in the liver to the active metabolite, enalaprilat.
PROBLEM TABLE 9 - 7. Enalapril
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 10 mg po 10 BID1
B f 0.65
C fu 0.55
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 0.63
H %Clr 27
I %Clnr 73
J AUC (mg/L*hr) 0.123
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-31Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 7. Answers for Enalapril
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-32Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Enoxacin (Problem 9 - 8)
Somogyi, A., and Bochner, F., “The absorption and disposition of enoxacin in healthy subjects”, Journal of Clinical Pharmacol-ogy, Vol. 28, (1988), p. 707 - 713.Enoxacin is a fluorinated quinolone which is used to treat infections caused by gram-negative organisms andPseudomonoas aeruginosa.
PROBLEM TABLE 9 - 8. Enoxacin
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 400 200 bid
B f 0.9
C fu 0.8
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 7.75
H %Clr 60
I %Clnr 40
J AUC (mg/L*hr) 15.61
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr) 12
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-33Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 8. Answers for Enoxacin
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-34Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Enprofylline (Problem 9 - 9)
Nadai, M., et. al, “Dose-dependent pharmacokinetics of enprofylline and its renal handling in rats”, Journal of Pharmaceutical Sciences, Vol. 80, No. 7, (1991), p. 648 - 651 Enprogylline is a xanthine bronchodilator which is more potent than theophylline.
PROBLEM TABLE 9 - 9. Enprofylline
TABLE 9 - 9. Answers for Enprofylline
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg/kg) 2.5 2.5 TID
B f 1
C fu 0.4
D
E Vd (L/kg)
F k (hr-1)
G T 1/2 (hr) 0.36
H %Clr 90
I %Clnr 10
J AUC (mg/L*hr) 3.6
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-35Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-36Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Erythromycin (Problem 9 - 10)
Welling and Creig (JPS 67, 1057-9,1978).Erythromycin is a macrolide antibiotic.(Use Qr = 72 L/hr; Qh = 90 L/hr)
PROBLEM TABLE 9 - 10. Erythromycin
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 300 300 TID
B f .8
C fu 0.06 0.06 0.12 0.06 0.18
D
E Vd (L) 57 57 100 57 150
F k (hr-1)
G T 1/2 (hr)
H %Clr 10
I %Clnr 90
J AUC (mg/L*hr)
K (L/hr) 16.5
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr) 8
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-37Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 10. Answers for Erythromycin
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 300 300 300 200 300 200
FRR 1 1 0.5 1 1 1
FIR 1 1 0.5 0.5 1 3
FRH 1 1 1 1 0.5 1
FIH 1 1 1 2 1 0.5
B f .8
C fu 0.06 0.06 0.12 0.06 0.18
D
E Vd (L) 57 57 100 57 150
F k (hr-1) 0.255 0.242 0.235 0.227 0.075
G T 1/2 (hr) 2.71 2.85 2.92 3.05 9.27
H %Clr 10 5.3 3.1 11.2 37
I %Clnr 90 94.7 96.9 88.8 63
J AUC (mg/L*hr) 14.5 17.4 6.7 18.5 14.2
K (L/hr) 16.5 13.8 23.7 13.0 11
L (L/hr) 13.1 13.1 23.4 11.5 7.02
M (L/hr) 1.45 0.73 0.73 1.45 4.19
L 0.136
O 0.020
P (L/hr) 252
Q (L/hr) 24.7
R FCL 1 0.95 1.63 0.89 0.77
S (hr) 8 8 8 8 24
T N 2.94 2.79 2.74 2.63 2.59
U
0.29 0.30 0.23 0.30 0.23
V 0.12 0.13 0.10 0.14 0.11
W 0.038 0.042 0.034 0.049 0.038
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-38Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Fleroxacin (Problem 9 - 11)
Singlas, E., et. al., “Disposition of fleroxacind, a new trifluoroquinolone, and its metabolites - pharmacokinetics in renal failure and influence of haemodialysis”, Clinical Pharmacokinetics, Vol. 19, No. 1, (1990), p. 67 - 79.Fleroxacin is a trifluorinated quinolone with activity against a variety of gram-negative and gram-positive organisms.
PROBLEM TABLE 9 - 11. Fleroxacin
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 400 200 tid
B f 0.95
C fu 0.5
D 1.45
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 14
H %Clr 65
I %Clnr 35
J AUC (mg/L*hr) 92
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-39Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 11. Answers for Fleroxacin
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-40Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Fosinopril (Problem 9 - 12)
Hui, K., et. al., “Pharmacokinetics of fosinopril in patients with various degrees of renal function”, Journal of Clinical Pharmacol-ogy and Therapeutics, Vol. 49, No. 4, (1991), p. 457 - 466.Fosinopril is an angiotensin converting enzyme inhibitor which is a prodrug that is metabolized to active form, fosino-prilat.
PROBLEM TABLE 9 - 12. Fosinopril
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 7.5 IV 20 po qd
B f 1 (Oral 0.36)
C fu 0.01
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 7
H %Clr 0
I %Clnr 100
J AUC (mg/L*hr) 5.1
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr) 24
T N
U
V
W
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-41Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 12. Answers for Fosinopril
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-42Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Glutathione (Problem 9 - 13)
Mulders, T., et. al., “Characterization of glutathione conjugation in humans: stereoselectivity in plasma elimination pharmacoki-netics and urinary excretion of (R)- and (S)-2-bromoisovalerylurea in healthy volunteers”, Clinical Pharmacology and Therapeu-tics, Vol. 53, (1993), p. 49 - 58.This study explored the pharmacokinetics of glutathione.
PROBLEM TABLE 9 - 13. Glutathione
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 600 500 tid
B f 1
C fu 1
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 4.4
H %Clr 35
I %Clnr 65
J AUC (mg/L*hr) 276
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-43Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 13. Answers for Glutathione
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-44Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Guanadrel (Problem 9 - 14)
Halstenson, C., et. al., “Disposition of guanadrel in subjects with normal and impaired renal function”, Journal of Clinical Phar-macology, Vol. 29, (1989), p. 128 - 132.Guanadrel is adrenergic blocker used in the treatment of hypertension.
PROBLEM TABLE 9 - 14. Guanadrel
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 25 mg po 25 BID
B f 1
C fu 0.8
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 3.7
H %Clr 40
I %Clnr 60
J AUC (mg/L*hr) 0.234
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr) 12
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-45Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 14. Answers for Guanadrel
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-46Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Monoxidine (Problem 9 - 15)
Kirch, W., Hutt, H., and Plänitz, V., “The influence of renal function on clinical pharmacokinetics of monoxidine”, Clinical Phar-macokinetics, Vol. 15, (1988), p. 245 - 253.Monoxidine is a centrally acting antihypertensive agent which stimulates -adrenergic receptors.
PROBLEM TABLE 9 - 15. Monoxidine
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
α2
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 0.25 IV 0.25 tid
B f 1
C fu 1
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 2.75
H %Clr 95
I %Clnr 5
J AUC (mg/L*hr) 0.05
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-47Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 15. Answers for Monoxidine
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-48Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Nalmefene (Problem 9 - 16)
Dixon, R., et. al., “Nalmefence: safety and kinetics after single and multiple oral doses of a new opiod antagonist”, Journal of Clinical Pharmacology, Vol. 27, (1987), p. 233 - 239.Nalmefene is a pure opiod antagonist which is currently being investigated for use.
PROBLEM TABLE 9 - 16. Nalmefene
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 20 IV
B f 0.6 oral
C fu 1
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 9.8
H %Clr 70
I %Clnr 30
J AUC (mg/L*hr) 0.3
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-49Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 16. Answers for Nalmefene
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-50Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Nitrendipine (Problem 9 - 17)
Dylewicz, P, et. al, “Bioavailability and elimination of nitrendipine in liver disease”, European Journal of Clinical Pharmacology, Vol, 32, (1987), p. 563 - 568.Nitrendipine is a calcium antagonist
PROBLEM TABLE 9 - 17. Nitrendipine
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 5 IV 25 po BID
B f 1 (oral 0.2)
C fu 0.05
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 11.7
H %Clr 0.1
I %Clnr 99.9
J AUC (mg/L*hr)
K (L/hr) 90
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-51Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 17. Answers for Nitrendipine
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-52Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Ofloxacin (Problem 9 - 18)
Lamerire, N., et. al., “Ofloxacin pharmacokinetics in chronic renal failure and dialysis”, Clinical Pharmacokinetics, Vol. 21, No. 4, (1995), p. 357 - 371.
PROBLEM TABLE 9 - 18. Ofloxacin
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 300 300
B f 0.93
C fu 0.74
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 6
H %Clr 97
I %Clnr 3
J AUC (mg/L*hr) 28.47
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr) 12
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-53Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 18. Answers for Ofloxacin
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-54Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Omeprazole (Problem 9 - 19)
(Use Qr = 72 L/hr; Qh = 90 L/hr)
PROBLEM TABLE 9 - 19. Omeprazole
TABLE 9 - 19. Answers for Omeprazole
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 10 10 BID
B f 0.5 0.75
C fu 0.04 0.06 0.08
D
E Vd (L) 30
F k (hr-1)
G T 1/2 (hr) 2
H %Clr 0
I %Clnr 100
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr) 12
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 10 10 10 5 10 5
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-55Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
FRR 1 1 0.5 1 1 1
FIR 1 1 0.5 0.5 1 2
FRH 1 1 1 1 0.5 1
FIH 1 1 1 1.5 1 0.5
B f 0.5 0.75
C fu 0.04 0.06 0.08
D
E Vd (L) 30
F k (hr-1) 0.347 0.347 0.493 0.31 0.184
G T 1/2 (hr) 2 2 1.41 2.2 3.8
H %Clr 0
I %Clnr 100
J AUC (mg/L*hr) 0.48 0.48 0.338 0.53 0.68
K (L/hr) 10.4 10.4 14.8 9.38 5.5
L (L/hr) 10.4 10.4 14.8 9.38 5.5
M (L/hr) 0 0 0 0 0
L 0.108
O 0
P (L/hr) 291.5
Q (L/hr) 0
R FCL 1 1 1.42 0.90 0.53
S (hr) 6 6 8 6 12
T N 3 3 2.83 2.71 3.2
U
0.0076 0.0076 0.0051 0.0079 0.011
V 0.0032 0.0032 0.0025 0.0035 0.0045
W 0.00095 0.00095 0.00099 0.0012 0.0012
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-56Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Piperacillin (Problem 9 - 20)
Johnson, C., et. al., “Single-dose pharmacokinetics of piperacillin and tazobactam in patients with renal disease”, Clinical Phar-macology and Therapeutics, Vol. 51, (1992), p. 32 - 41.Piperacillin is a beta-lactam antibiotic.
PROBLEM TABLE 9 - 20. Piperacillin
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 3000 2000 qid
B f 1
C fu 0.82
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 0.95
H %Clr 75
I %Clnr 25
J AUC (mg/L*hr) 276
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr) 6
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-57Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 20. Answers for Piperacillin
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-58Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Piroxicam (Problem 9 - 21)
Boudinot, S., Funderburg, E., and Boudinot, F., “Effects of age on the pharmacokinetics of piroxicam in rats”, Journal of Pharma-ceutical Sciences, Vol. 82, No. 3, (1993), p. 254 - 257.Piroxicam is a nonsteroidal anti-inflammatory drug (NSAID) commonly used in the treatment of arthritis.
PROBLEM TABLE 9 - 21. Piroxicam
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 70 20 qd
B f 1
C fu 0.007
D
E Vd (L) 9
F k (hr-1)
G T 1/2 (hr) 50
H %Clr 5
I %Clnr 95
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-59Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 21. Answers for Piroxicam
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-60Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Quinidine (Problem 9 - 22)
Quinidine sulfate is used to treat ventricular and supraventricular arrythmias and is available in 200 and 300 mg tablets.It is known to bind to -acid glycoprotein (AAG), which is an acute phase reactant. AAG rises in trauma, inflamation,malignancy and stress and falls in hepatic disease, nephrotic syndrome and malneurtrition for example.(Use Qr = 72 L/hr; Qh = 90 L/hr)
PROBLEM TABLE 9 - 22. Quinidine
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
α
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg/kg) 10 10 TID
B f 0.7
C fu 0.2 0.10 0.25 0.15 0.3
D s 0.83
E Vd (L/kg) 2.6 2.0 2.75 2.2 3.0
F k (hr-1)
G T 1/2 (hr) 6.4
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr/kg)
L (L/hr/kg) 0.20
M (L/hr/kg) 0.056
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr) 8
T N
U
MTC
1.7
V
W MEC
0.37
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-61Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 22. Answers for Quinidine
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 10 10 10 10 10 5
FRR 1 1 0.5 1 1 1
FIR 1 1 0.25 0.5 0.75 1.5
FRH 1 1 1 1 0.5 1
FIH 1 1 0.5 1.25 0.75 0.5
B f 0.7
C fu 0.20 0.10 0.25 0.15 0.30
D s 0.83
E Vd (L) 2.6 2.0 2.75 2.2 3.0
F k (hr-1) 0.098 0.057 0.101 0.087 0.061
G T 1/2 (hr) 7 12.1 6.9 7.9 11.3
H %Clr 22 12.3 10 22 46
I %Clnr 78 87.7 90 78 54
J AUC (mg/L*hr) 27.3 61.3 20.6 36.5 19.0
K (L/hr) 0.256 0.114 0.28 0.19 0.18
L (L/hr) 0.20 0.10 0.25 0.15 0.1
M (L/hr) 0.056 0.014 0.028 0.04 0.08
L 0.0021
O 0.00078
P (L/hr) 1.0
Q (L/hr) 0.28
R FCL 1 0.45 1.1 0.75 0.72
S (hr) 8 8 8 8 8
T N 1.3 0.66 1.16 1.0 0.71
U
MTC
1.7
0.82 0.79 0.95 0.79 0.75
V 0.57 0.63 0.65 0.56 0.59
W MEC
0.3
0.37 0.5 0.44 0.39 0.46
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-62Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Tazobactam (Problem 9 - 23)
Johnson, C., et. al., “Single-dose pharmacokinetics of piperacillin and tazobactam in patients with renal disease”, Clinical Phar-macology and Therapeutics, Vol. 51, (1992), p. 32 - 41.Tazobactam is an irreversible beta-lactamase inhibitor.
PROBLEM TABLE 9 - 23. Tazobactam
TABLE 9 - 23. Answers for Tazobactam
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 375 IV 375 qid
B f 1
C fu 0.96
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 0.89
H %Clr 68
I %Clnr 32
J AUC (mg/L*hr) 30.3
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr) 6
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-63Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-64Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Theophylline (Problem 9 - 24)
Wagner, J., “Theophylline - pooled Michaelis-Menten parameters and implications”, Clinical Pharmacokinetics, Vol. 10, (1985), p. 432 - 442.
PROBLEM TABLE 9 - 24. Theophylline
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-65Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 24. Answers for Theophylline
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-66Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Tolrestat (Problem 9 - 25)
Troy, S., et. al., “The effect of renal disease on tolrestat pharmacokinetics”, Clinical Pharmacology and Therapeutics, Vol. 51, (1992), p. 271 - 277.Tolrestat is an aldose reductase inhibitor used in the treatment of diabetic neuropathy, diabetic nephropathy, and dia-betic retinopathy. (Use Qr = 72 L/hr; Qh = 90 L/hr)
PROBLEM TABLE 9 - 25. Tolrestat
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 200 200 tid
B f 0.8
C fu
D
E Vd (L)
F k (hr-1)
G T 1/2 (hr) 10.6
H %Clr 25
I %Clnr40 bile 35 metab.
J AUC (mg/L*hr) 86
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-67Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 25. Answers for Tolrestat
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 200 200 TID 200 TID 200 TID 200 TID 200 BID
FRR 1 1 0.5 1 1 1
FIR 1 1 0.5 0.5 1 1
FRH 1 1 1 1 0.5 1
FIH 1 1 1 1 1 0.5
B f 0.8
C fu 1
E Vd (L) 28.5
F k (hr-1) 0.0654 0.057 0.057 0.065 0.041
G T 1/2 (hr) 10.6 12.1 12.1 10.7 16.9
H %Clr 25 14.3 14.3 25.3 39.8
I %Clnr 75 85.7 85.7 74.7 60.2
J AUC (mg/L*hr) 86 98.3 98.2 87 137
K (L/hr) 1.86 1.63 1.63 1.84 1.17
L (L/hr) 1.4 1.4 1.4 1.4 0.7
M (L/hr) 0.46 0.23 0.47 0.47 0.47
L 0.0155
O 0.0065
P (L/hr) 1.42
Q (L/hr) 0.47
R FCL 1 0.88 0.88 0.99 0.63
S (hr) 8 8 8 8 12
T N 0.75 0.66 0.66 0.75 0.71
U
13.8 15.3 15.3 13.9 14.4
V 10.8 12.3 12.3 10.9 11.4
W 8.2 9.6 9.7 8.3 8.8
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-68Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Vancomycin (Problem 9 - 26)
Macais, W., Meuller, B., and Scarim, S., “Vancomycin pharmacokinetics in acute renal failure; preservation of nonrenal clear-ance”, Clinical Pharmacology and Therapeutics, Vol., 50, (1991), p. 688 - 694.Vancomycin is a glycopeptide antibiotic used in the treatment of infections caused by Gram-positive organisms.
PROBLEM TABLE 9 - 26. Vancomycin
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 1000 500 QID
B f 1
C fu
D 0.44
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr 70
I %Clnr 30
J AUC (mg/L*hr) 543
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
ρ
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-69Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 26. Answers for Vancomycin
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg)
B f
C fu
E Vd (L)
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr)
M (L/hr)
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-70Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
Xipamide (Problem 9 - 27)
Knauf, H, et. al., “Xipamide disposition in liver cirrhosis”, Clinical Pharmacology and Therapeutics, Vol. 48, No. 6, (1990), p. 328 - 632.Xipamide is a diuretic that has been used in the treatment of congestive heart failure, hypertension, advanced renal fail-ure, and hepatic edema.(Use Qr = 72 L/hr; Qh = 90 L/hr)
PROBLEM TABLE 9 - 27. Xipamide
Problem Submitted By: Maya Leicht AHFS 00:00.00Problem Reviewed By: Vicki Long GPI: 0000000000
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 40 40 QID
B f 0.8
C fu 0.01 0.01 0.02 0.01 0.025
E Vd (L) 21
F k (hr-1)
G T 1/2 (hr)
H %Clr
I %Clnr
J AUC (mg/L*hr)
K (L/hr)
L (L/hr) 1.38
M (L/hr) 0.72
L
O
P (L/hr)
Q (L/hr)
R FCL 1
S (hr)
T N
U
V
W
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------
Clearance
Basic Pharmacokinetics REV. 99.4.25 9-71Copyright © 1996-1999 Michael C. Makoid All Rights Reserved http://kiwi.creighton.edu/pkinbook/
TABLE 9 - 27. Answers for Xipamide
Patient Condition Normal Normal FRR=0.5 FIR=0.5 FRH=0.5 FIH=0.5
A Dose(mg) 40 40 QID 40 QID 20 QID 40 QID 20 QID
FRR 1 1 0.5 1 1 1
FIR 1 1 0.5 0.5 1 2.5
FRH 1 1 1 1 0.5 1
FIH 1 1 1 2 1 0.5
B f 0.8
C fu 0.01 0.01 0.02 0.01 0.025
E Vd (L) 21
F k (hr-1) 0.1 0.083 0.146 0.1 0.118
G T 1/2 (hr) 6.9 8.4 4.7 7.0 5.9
H %Clr 34 21 12 35 72
I %Clnr 66 79 88 65 28
J AUC (mg/L*hr) 15.2 18.4 7.8 15.4 6.5
K (L/hr) 2.1 1.74 3.1 2.1 2.5
L (L/hr) 1.38 1.38 2.71 1.36 0.7
M (L/hr) 0.72 0.36 0.36 0.72 1.8
L 0.0144
O 0.01
P (L/hr) 140
Q (L/hr) 73
R FCL 1 0.83 1.46 1 1.18
S (hr) 6 6 4 6 6
T N 0.87 0.71 0.847 0.86 1
U
0.034 0.039 0.034 0.034 0.038
V 0.025 0.031 0.026 0.025 0.027
W 0.019 0.024 0.019 0.019 0.019
Cltot
Clh
Clr
Eh
Er
Clhint
Clrint
τ
Cpss
max free
µgmL--------
Cpss
avgfree
µgmL--------
Cpss
minfree
µgmL--------