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Generator Protection for Rotor
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The year of Profitable Growth
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Rotor-Ground-Fault Protection
Power Automation 2
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Presenter: Dr. Hans-Joachim Herrmann PTD PA13Phone +49 911 433 8266E-Mail: [email protected]
Generator ProtectionRotor-Ground-Fault Protection
Power Automation 3
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Requirement for Rotor Ground Fault Protection
? in case of a ground fault, only small currents flow due to the galvanic isolation
Problem:Double ground faults and interturn faults as a consequence of an ground fault cause:• magnetically unbalance (unbalanced forces; violent vibration)• high currents at the fault location
Task: Detection a ground fault already when it starts to build up
? Destruction of the Rotor (Generator)
Ground fault in the rotor
RECE
Rotor
Excitationsystem
+
-Stator
Power Automation 4
Power Transmission and Distribution
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Protection Principle
Excitationsystem
+
-
Voltage Source
„Grounding brush “
CouplingUnit
Measuring
- Incoupling of an AC voltage (50 Hz or 60 Hz)- Measuring of the ground fault current- Measuring of the ground fault resistance
- Incoupling of low frequency square wave voltage
Principles:
HigherSensitivity
Power Automation 5
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Ground Current CriterionPrinciple (50 Hz/60Hz - Voltage Injection)
Coordinatedresonant circuit to fN
>40V
If disturbance influence from the excitation is too large
IE
Protection
Pick-up limit:IG,Fault > IG,Dist...
L1 L2 L3
IG,Distr.
IG,Fault
4?F105?
0,75H
Connectionon the groundingbrush
Power Automation 6
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Ground Current MeasurementConnection
Also IEE2
at 7UM62is possible
IEE1J7J8
1B11B3
1A11A3
+
-
4A1
4B1
3PP1336Err.
2B1
7UM6
Connection on the phase to phase voltage
7XR61
100 V - 125 V AC
105?
105?
AC VoltageSourceappr. 42V or65V
Documentation for Coupling Device in the Internetwww.siprotec.com
External resistorsat excitation voltages> 150 V (circulating current >0,2A)
Power Automation 7
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Gain Characteristic of the R, C, L-Circuit
Z 50( ) 169.65? Z 60( ) 69.531?
0 50 100 150 200 250 3000
500
1000
1500
2000Filterverhalten Bandpaß
Frequenz in Hz
Impe
danz
in O
hm
Z f( )
f
mA27k 1,5 170
V 45 I
R ZV
I
fCoupling
????
?
??
Imax approx. 300 mA
Frequency in Hz
Impe
danc
e in
Ohm
Power Automation 8
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Ground Current CriterionProtection Settings
Protection with two stages:Measuring circuit supervision
mA23k 1,5 400
V 45 I
R ZV
I
fCoupling
????
?
??
ZCouplingl(50Hz) = 400?
ZCouplingl(60Hz) = 335?
Imax approx. 100 mA
(voltage source decreases a little bit )
Note: Coupling impedance only with R and CFinally setting during commissioning
Power Automation 9
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Ground Current Criterion Logic
Power Automation 10
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Calculation of the Ground Resistance RE
(50Hz/60Hz- Voltage Injection)
100V 42V u
Digitalprotection(7UM62)calculationof RE
RE CE
RV CK
RV CK
L1 L2 L3
iL1)
1) Recommendedat static excitationwith inject harmonics(3rd harm.; 6th harm.)
Power Automation 11
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Calculation Formula of the Ground Resistance RE
(1) (2)
(3)
(4)
combining (3) and (4):
Note: RV* and XK* are measured during commissioning
Model:
Zers ZMess Z
X*K R*V
XERE
? ? VE2
E2
E
2EE *R -
, ZR
XR
XRR ?
?
??
? ? ? ?ZZRZ j meMess I????
?
?
??
?
?
??
???
2E
2E
E2
EK2
EE
2EE
V
- - j
2
ersXR
XR*X
XR
XR*RZ
? ? Km2E
2E
E2
E -
, *XZXRXR
X I???
?
? ?? ?? ? ? ? V
Ve
2Km
2
E - e - - -
, ,,
*RZR*RZR*XZ
RRX
R ????I
Power Automation 12
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Ground Fault Resistance CalculationLogic
Power Automation 13
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Ground Fault Resistance CalculationSettings
Measured during commissioning
Measuring circuit supervision
Measured current can be influenced by disturbancesCorrection during primary test,(in most case the alarm stage is concerned)
Power Automation 14
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Injection of Square Wave Voltage with Low FrequencyBasic Diagram
Excitation
+
-CE
RE
Digital Protection (7UM62)
VH
RV
RV
Vcontrol
Vmeas.RM
7XR6004
Controlling device(7XT71)IE
Measuring transducer
RE Fault resistanceRV Coupling resistorVH Auxiliary supply ( ? 50V)RM Measuring shunt resistorCE Rotor capacitance
Typical frequency:1 - 3 Hz
Power Automation 15
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Injection of Square Wave Voltage Connection Diagram (7UM62)
Connection on the phase to phase voltage
Exc.17
15
11
25
+
-
27
7XR600425
27
7UM62
7XT71
TD1K14K13 +
TD2K16
K15 +
40 k?
40 k?
Control voltage
Measuring voltage
100 V110 V
120 V
9
7
Power Automation 16
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Injection of Square Wave Voltage with Low FrequencyBasic Principle
RV2
RECEVH
VMRM
VH
VM
VM
50V
- 50V
1,88V
- 1,88V
0,75V
- 0,75V
t
t
t
iE
50V
375
20k 2
H
M
V
????
??
U
R
REMM iRU ??
?? ER
?? 5k ER
0 M ?? UE
V 2
CR
???
EM
1 ~ R
U?
Equivalent circuit:
Power Automation 17
Power Transmission and Distribution
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Sources of Error and Error Compensation
Influence of field voltage and ground fault location
a) Ground fault location
Shifting of measuring voltage witha positive or negative dc voltage
b) Jumps in the field voltage
a change in the field voltage takesto jumps in the dc-voltage shifting
Vdc = dc voltage shifting
Solution:Calculation of the difference voltage
? V = |VM1 - VM2|
? V1 = |VM1 - VM2| ? V3 = |VM3 - VM4|? V2 = |VM2 - VM3|
Solution:Block of measuring at jumps (e.g. ? V1 = ? V2)
VM
VdcVdc1
VM1
VM2
VM3VM4
VM1 VM2 Vdc2
VM
Power Automation 18
Power Transmission and Distribution
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Calculation Formulas
RECEVH
VMRM
RV
2
VM V1
V2
Algorithm
Voltage divider:
Filtering:
Amplitude-log frequency curve: fA = 800 Hz; N = 64
2- 1 -
2 V
MM
HE
M
MEV
M
H RR
VV
RR
RRR
VV
???
????
??
???
????
??NN
vN
VvN
V1 i
i2,2
1 ii1,1
1 ;
1
2 -
: : 21M
VVV ??? V
1KK I I ???? VV
??
???8
1 k k
81
VV0 30 60 90 120150180210240 270 300
0.001
0.01
0.1
1
f in Hz
G(f)
Continuity supervision:
Validity requirement
otherwise
Power Automation 19
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Logic Diagram Rotor Ground Fault Protection (1-3Hz)
Power Automation 20
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Rotor Ground Fault Protection (1-3Hz) Setting Values
Measuring circuit supervision
If the integrated test function is used,pick-up value of test resistor
Advanced parameteronly visible in DIGSI
Power Automation 21
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Connection of the Rotor Ground Fault Protection
GRW RE
CE
EM
EX-TL+
RWUG
RE CE
L-
(50/60 Hz)
(1 - 3 Hz)
(50/60 Hz)
(1 - 3 Hz)
40k?
4µF
4µF
a) rotating diodes
b) separate Exciter(static excitation)
40k?
Power Automation 22
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Generator with Rotating ExcitationFault Free Condition (Square Wave Principle)
Chance of charge ofrotor ground capacitance
Disturbances by the excitation generator
Power Automation 23
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Generator with Rotating ExcitationTest Condition with a Fault Resistor
Fault resistor is inverse proportional to the difference voltage
Power Automation 24
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Parallel Operation of Rotor Ground Fault Protections
100V 42V
CK;4µF
CK;4µF
RK;105?
RK;105?RV;40k?
RV;40k?
RE
7UM62 7UM62VControl
VMeas.
iREF
uREF
7UM61
nuriREF
or
1- 3 Hz principle 50 Hz principle
Power Automation 25
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
Parallel Operation of Rotor Ground Fault ProtectionsMeasurement with the 50/60 Hz Principle
( )?20k 2
RV
*KR *KC
ER
2 ll : * V
EER
RR ?
???
??
20k 2
*
VE
E
RR
R
????
4k *
5k
E
E
R
R
Measurement 7UM61 or 7UM62(RV is grounded for an AC voltage)
Equivalent circuit:
seen from the 7UM6, RV alreadyis interpreted as a rotor-to-groundresistance
Measurement:
measured as a fault resistance
Case 1:
Case 2:
alarm stage becomes less sensitive
? open brushes can not be find out
Power Automation 26
Power Transmission and Distribution
Power AutomationProgress. It‘s that simple.
RV
2
RERM2CK(8µF)
Vmeas
? V2
Measurement 7UM62 (1- 3 Hz)(CK is grounded for a DC voltage)
Equivalent circuit:
? seen from the 7UM6:high rotor capacitance
? capacitors will not becompletely loaded
? ? V ~ RE-1
under no-ground-fault conditions a fault resistance is already measured
? alarm stage becomes less sensitive (approx. 50k? )
? longer measuring time
Parallel Operation of Rotor Ground Fault ProtectionsMeasurement with the Square Wave Principle