2 kademeli redüktör

8/18/2019 2 kademeli redüktör

1/38

PAMUKKALE ÜNİVERSİTESİMAKİNE MÜHENDİSLİĞİ BÖLÜMÜ

DERS : MAKİNE ELEMANLARIKONU : 2 KADEMELİ REDÜKTÖR

TASARIMI

ÖĞR. ADI : MUHAMMEDBOZKURTÖĞR. NUMARASI :08244014 İ.Ö.ÖĞR. ADI : DOÇ.DR. TEZ AN!EKER İOĞLU


2/38

V"#$%"& B$%'$%"#

($#$) (*+* , Pg - / ($#$) D" $# S3 565 , n1 - 1700 d /d

T 9%3 Ç" #$ O#3&5 , iT - 14K3;" " S3 565 2

1.K3;" " D$)%$ T$9$ H"%$62.K3;" " D$)%$ T$9$ H"%$61. Kademe ; i 12 4 2. Kademe ; i 34 = 3.5

1.ÖN HESAPLAMALAR VE MEKANİZMA ÖZELLİKLERİ


3/38

z1 : ($#$) $%$ 9$& & 5#. z4 : Ç5 5) $%$ *?"#$&;" $ ;@&;*#*%"& 5#.

β : H"# $ $ 3;" " $ $& 3>63 565 S 1./ 3%5& 5)>5#.

D$)%$ C>C6C&C& >35#5%3+3 >5#.

D$)%$%"# 3?;5# 3 @&>" $ %" $ 3% ";$% $) " ;$)%"#$ 93#%3>5% 5)>

M$%%"# $ $ 3>3 %3& 5) " 6"

B*>*& " 3&$? 3;3 "#$ 1 3%5& 5)>5#.

M$% D@&;*# " M "&>%"#$ " D" $# S3 5%3#5

1 numaralıgiriş mili için; M d 1 =9550 ∗ P

n1 F//0 G5

1300 7= 70. = N

n1 = 1400 d /d


4/38

2 numaralıaramili için; M d 2 = M d 1∗i12 7= 70. = G 4 14=F27.04

N n2 = n1 /4 72/ d /d3 numaralıçıkış miliiçin ; M d 3 = M d 2∗i34 14=F27.04G7./ /14270.=4

N n3 = n2 /3.5 F2.8/ d /d

1-HELİS Dİ!LİLER İÇİN MODÜL HESABI 3-D$) ;$ $ C 3 " ">$&" '@#" &># %:

H"%$6 ;$)%$ '#C C $ $& 1 #N$M = 6" "&>36 & "%$ $6" $%;$.

mn 1 ≥ 3√2∗ M d 1∗ K f ∗ K i∗ K v∗ K m∗ K ε∗cos βφ m∗ z1∗σ em

M ;*% ;" "#$ mn 1 2./ 3 C% ";$%;$.

M d 1 7= 70. = N

K f 2.F , ze 1 = 19.282 J 0 $ $& # 3 >@#*-

K i 1.20 ,D*?'*& 3%5)3& "%" >#$ > #C " #"& $ $& $)%"> "3 >@#*-

K v 1.0/42∗π ∗1300 ∗¿

60 ∗2

2.5 ∗16

2= 2.72 msve y ksek kali!e az y k gelendişli için"ız fak!#r

v1 = ¿¿

K m= 1.2 , φ∗mn 1 = 12∗2.5 = 30iyi ya!aklanmışaz se"imli mil için y k da$ılım fak!#r -


5/38

K ε 0.== ,H"%$6 ;$)%$ " ;$) ;$ $&;"& 5#5% 3 3 '@#" &># % $ $& 3 #3 3

3 >@#* K ε 0.2/0.75

ε an¿

H"%$6 ;$)%$%"#;" 3 #3 3 #3&5

K ε 0.2/0.75

ε an

εanε

acos β%

2 = 1.611

cos18.742 = 1.796

tan β% β∗¿cos a ! = tan 20 ∗cos 21.172 β%= 18.74 °

tan ¿

ε= εa +ε β

εa =√ r a 1

2 − r %12 +√ r a 2

2 − r %22 − a d 1∗sin a !

π ∗mn 1∗cos a !

r a 1d 1 +2∗" a

2 d 1 = z1∗mn 1

cos β

16 ∗2.5

cos 20 42./=" a = mn1 2./

r a 1 = 23.78 mm

r %1d 1∗cos a!

2 tan a ! =tan 20

cos20 0.78 a ! 1 = 21.172 °

r %1 = 19.84 mm


6/38

d 2 = z2∗mn 1

cos β z2 = z1∗i12 1=G4 =4

d 2 = 170.26 mm

r a 2d 2 +2∗" a

2 8 .=7

r %2d 2∗cos a!

2 F.78

a d 1 = mn 1∗( z1 + z2 )2∗cos β

2.5 ∗(16 +64 )2∗cos20 10=.418

εa =13.109 +37.119 − 38.43

7.320 1.=11

ε β=%∗sin β

Pn

30 ∗sin 20

2.5 ∗π 1.70

ε 2.F11 K ε 0.==

D$) ;$ $&;"& "6$% " " '@#" " &$ ">%$ '"#$% "

σ em K %∗ K y∗σ &&

K ç∗'

K %= 1 , mn 1 2.5


7/38

σ && 1000N mm2 ,1 #N$M = 6" "&>36 & "%$ $ "σ )* = σ && $ $& $%'$%$ $?"%'";"& C&3& C 3 " "> ;" "#$

-

K ç= 1 ++∗( K ! − 1 )

0.8/ ,# 0.78G2./ 0.F/ " R 1200 N mm2

$ $& "&>$


8/38

K a= 2.36 , β= 20 " J 0 $ $& 3 #3 3 3 565 3 >@#*-

K i= 1.20 ,D*?'*& 3%5)3& "%" >#$ > #C " #"& $ $&$)%"> " 3 >@#*-

K v 1.0/42∗π ∗1300 ∗¿

60 ∗2

2.5 ∗16

2= 2.72 msve y ksek kali!e az y k gelendişli için "ız fak!#r

v1 = ¿¿

K m= 1.2 , φm∗2.5 = 30ve iyi ya!aklanmışaz se"imlimil için y kda$ılım fak!#r -

K ε 0.787 ,H"%$6 ;$)%$ *?" 365&+5&3 '@#" &># % "ε β= 1.30 >1 $ $& $%'$%$

$?"%'";"& 3%5&3& 3 #3 3 3 >@#* # *%*&;"&1 /¿√ ε , = 0.787

K ε= √ ¿ -

E 2.1G 105

N mm2

i12 = 4

Pem=σ -lim∗ K #

'

σ -lim = ¿ 1/10 N mm2

K #= 1 , 107 y k !ekrarıiçin -

Pem=1510 ∗1

1.5= 1006.66 . /mm2


9/38

mn 1 ≥ 0.7 ∗cos 203√36730.76 ∗2.36 2∗1.2 ∗1.054 ∗1.2 ∗0.787 ∗2.1 ∗10 5∗512 ∗16 2∗1006.66 2∗4

mn 1 ≥

1.8071.807 1.7/1 %;C C $ $& $# *6> ;" "#" C 3#%3>>5 5 5?;3 ;*%;" "#$ $?" C%3)5#5?. mn 1 = 2 ./

2-HELİS Dİ!LİLER İÇİN MODÜL HESABI3-D$) ;$ $ C 3 " ">$&" '@#" &># %:

H"%$6 ;$)%$ '#C C $ $& 1 #N$M = 6" "&>36 & "%$ $ 6" $%;$.

mn ≥ 3√2∗ M d 2∗ K f ∗ K i∗ K v∗ K m∗ K ∈∗cos βφm∗ z3∗σ em

M d 2 14=F27.04 N

M ;*% ;" "#$ mn 2 2 3 C% ";$%;$.

i34 =/ 4/ 3 / 4 /= / 3 1= i34 =

3.5

/e 3 = / 3

(cos β

)3= 19.282 0 20 ;$)

K f = 2.87 ( 1= 0 ; /e 3 = 20 )

K i= 1.25 ( & zg nçalışanelek!rik m(!(ru;kren )

K v= 1.01 , * 6" 3%$>";" 3? * '"%"& v=π ∗325

60∗2∗10

− 3∗16 0./44 6


10/38

K m= 1.2 , φm∗2 = 24 ve iyi ya!aklanmışaz se"imlimil için y k da$ılım fak!#r -

εa =√ r a 3

2 − r %32 +√ r a 4

2 − r %42 − a d 3∗sin a !

π ∗mn 2∗cos a !

r a 3d 3 +2∗" a

2 d 3 = z3∗mn 2

cos β

16∗2

cos20 74.0/

" a = mn 2 2

r a 3 = 19.025 mm

r %3d 3∗cos a!

2 tan a ! =tan 20

cos 20 0.78 a ! = 21.172 °

r %3 = 15.875 mm

d 4 = z4∗mn 2

cos β

z4 = z3∗i34 1=G7./ /=

d 4 = 119.187 mm

r a 4d 4 +2∗" a

2 =1./F7/

r %4d 4∗cos a!

2 //./ 0

a d 3 =mn2∗( z3 + z4 )

2∗cos β

2∗(72 )2∗cos 20 =.=20

εa =10.484 +26.56 − 27.672

π ∗2∗cos21.172 1.=007


11/38

ε%=%∗sin β

Pn

24 ∗sin20

2∗π 1.70

ε 2.F0 7 εanε a

cos β2 1.812

K ε 0.2/ 0.75

1.812= 0.663

D$) ;$ $&;"& "6$% " " '@#" " &$ ">%$ '"#$% "

σ em K %∗ K y∗σ && K ç∗'

K %= 1 , mn 2 2


12/38

σ em 1∗0.928 ∗1000

1.250 ∗1.5 4F4.F7 N mm2

mn 2 ≥ 3

√2∗146923.04 ∗2.87 ∗1.25 ∗1.2 ∗1.01 ∗0.663 ∗cos20

12∗16∗494.93 1.8F

2 ¿ 1.8F %;C C $ $& 3 C% ";$%"& ;*% ;$);$ $ C 3 " ">$&" '@#" " &$ ">%$;$#. *?" 365&+5&3'@#" ;" #$ > #C " #"& $ $& $)%"> " 3 >@#*-

K v= 1.01 , * 6" 3%$>";" 3? * '"%"& v=π ∗325

60 ∗2∗10−3

∗16 0./44 6

K m= 1.2 , φ∗2 = 24 ve iyi ya!aklanmışaz se"imlimil için y k da$ılım fak!#r-

K ε=√ 1εa =√ 11.6003 = 0.79


13/38

E 2.1G 105

N mm2

i34 = 3.5

Pem=σ -lim∗ K #

'

σ -lim = ¿ 1/10 N mm2 K #= 1 , 10 7 y k !ekrarıiçin -

Pem=1510 ∗1

1.5 = 1006.66 . /mm2

mn 2 ≥ 0.7 ∗cos203√146923.04 ∗2.36 2∗1.25 ∗1.2 ∗1.01 ∗0.79 ∗2.1 ∗10 5∗4.512∗16 2∗1006.66 2∗3.5 = 1.F

1.F 1.8F %;C C $ $& $# *6> ;" "#" C 3#%3>>5 5 5?;3;*% ;" "#$ $?" C%3)5#5?. mn 2 = 2

7-H"%$6 D$)%$%"#$& B C>%3&;5#5% 365

3-P$& & ;$)%$&$& C>%3&;5#5% 365 , / 1

-:mn 1 = 2 ./

m! 1 = mn 1cos 20

= 2.66

da 1 = 44.42


14/38

d 1 =16∗2.5

cos 20= 42.567

"a 1 mn 1 = 2 ./

"f 1 1.2/G2./ 7.12/

d f 1 d 1 Q 2 G "f 1 42./= Q 2./ G 7.12/ 74. /4

a ! 1 21.1 2

d %1 d 1∗cos a ! 1 7F.=F7

Pn 1 Pn 2 mn 1 G π 2./ G π .8/

P! 1 P! 2 = m! 1 G π 2.== G π 8.7/2

" 1 " 2 "a 1 "f 1 2./ 7.12/ /.=2/

%1 %2 = ¿ φ G mn 1 70

a d 1 mn 1

2∗cos β∗(/ 1 +/ 2 )= ¿ 10=.41

-Ç3# ;$)%$&$& C>%3&;5#5% 365 , / 2 -:

mn 1 mn 2 = ¿ 2./ / 2 = / 1∗i12 = 64

m! 2 = mn 2cos 20

= 2.66

d a 2 = d 2 +2∗" a 2 = 175.26 mm


15/38

d 2 =64 ∗2.5

cos 20= 170.26

" a 2 mn 2 = 2 ./

" f 2 1.2/G mn 2 7.12/

d f 2 d 2 Q 2 G " f 2 1 0.2= 2 G 7.12/ 1=4.01

a ! 1 a! 2 21.1 2

d %2 d 2∗cos a ! 2 = ¿ 1/8.

2.K3;" "


16/38

d %3 d 3∗cos a ! 3 71. /1

Pn 3 Pn 4 mn 3 G π 2 G π =.28

P! 3 m! 3 G π 2.128 G π =.=81

" 3 " 4 "a 3 " f 3 2 2./ 4./

%3 φ G mn 3 24

a d 2 m

n3

2∗cos β∗(/ 3 +/ 4 ) =.=20

;-Ç3# ;$)%$&$& C>%3&;5#5% 365 , / 4 -:

mn 3 2

m! 4 = mn 4cos 20

= 2.128 mm

da 4 = d 4 +2∗" a 4 = 110.41 mm

d 4 = 56∗2cos 20 = 106.41 mm

"a 4 mn 4 = 2 mm

" f 4 1.2/G2 2./

d f 4 d 4

Q 2 G " f 4

101.41


17/38

a ! 4 21.1 2

d %4 d 4 G + 6 a! 4 FF.22

4-MİLLERİN BO UTLANDIRILMASI3-($#$) $%$&$& C>%3&;5#5% 365:M3%?" " 1 #N$M = )" $%;$

) ! 1= M d 1

d 1∗2 2G 36730.7642.56 1 2=.0=F N

d 1 = z1

cos 20∗mn 1

16 ∗2.5

cos 20 42./=

) r 1= ) ! 1∗!an,

2(sβ 1 2=.0=F G tan20

cos20 ==8.// N

) a 1 = ) ! 1∗!anβ 1 2=.0=F G>3&20 =28.27 N


18/38

;*?%" $&;"

∑ M 0

) 3 y∗135 ) r 1∗35 − ) a 1∗(42.567

2)

) 3 y 4.282 N

∑ ) y 0 ) 4 y /F4.2=8 N

∑ ) 1= 0 ) 4a − ) a 1 = 0 ) 4a = 628.237 .

Z ;*?%" $&;"

∑ M 4 0 ) 3 z∗135 = ) ! 1∗35

) 3 z1726.069 ∗35

135 44 .4FF N

∑ )

z 0 ) 4 z ) ! 1− ) 3 z

12 8./ N


19/38

M e2= √ M e5 2 + M e /

2

M e2= √ 20.7992

+44.7492

= 49346.44 .mm M d2= 36736 .mm

D 70 3 C% ";$%;$.

σ ∗¿T&e¿

σ T&e∗ K %∗ K y K ç

σ T&e /80 N mm2


20/38

K % 0.88 ,; 7/ $ $& C> 3 >@#*-

K y 0.F8, 6 m= ¿ 1200 N mm2

" *?" $ 93#%3>5% 5) ;C#C

$ $& *?" 3>63 565- K ç 1.1/

77 7 σ ∗¿T&e

¿580 ∗0.88 ∗0.98

1.15 ¿ 474.F4F N mm2

;

σ ∗¿T&e M e2

¿¿

¿2 + 34∗( M d2 6 e )

2

¿¿

32 ∗sπ

∗√ ¿

≥ 3√ ¿

6 e= 780 . /mm2

; ≥ 3√32∗1.5π ∗√(49346.44434.949 )2 + 34 ∗(36736780 )2

; ≥ 12.2=0 77 7 D 70 3%5&5#.

A%5&3& 39 C%C&3& 39 ;" "#$&;"& * * %;C C $ $&" &$ ">%$;$#.


21/38

(İRİ! MİLİ İMALAT RESMİ

-A#3 $%$& C>%3&;5#5% 365:

d 3 z3∗mn3

cos β 16∗2

cos20 74. 0/

; ≅ ,1.2 1.4- dmil

) ! 2= M d 2d 2∗2 2G

146923.04

170.26 1 2=.0=F N

) r 2= ) ! 2∗!an,

2(sβ 1 2=.0=F G tan20

cos20 ==8.// N

) a 2 = ) ! 2∗tan20 =28.27 N

) ! 3= M d 2d 3∗2 2G

146923.04

34.05 8=2F.84 N

) r 3= )

! 3∗

!an,

2(sβ 8=2F.84 Gtan20

cos20 7742./8 N


22/38

) a 3 = ) ! 3∗tan20 7141 N

;*?%" $&;"

∑ M 0 ) 2 y∗135 = ) a 3∗17.025 + ) r 3∗100 − ) r 2∗35 − ) a 2∗85.13

) 8y∗135 = 3141 ∗17.025 +3342.58 ∗100 − 668.55 ∗35 − 628.237 ∗85.13

) 2 y 2702.=1 N

∑ ) y 0 ) & y 7742./8 2702.=1 Q ==8.// 7 1.42N

Z ;*?%" $

∑ M 0

) 2 z∗135 = ) ! 3∗100 + ) ! 2∗35

) 2 z∗135 = 8629.84 ∗100 +1726.069 ∗35


23/38

) 2 z =87F.F N

∑ ) z 0 ) & z 8629.84 +1726.069 Q=87F.F 7/1/.F7 N

M e)

= √ M 2e5

+ M 2e9

M e) = √ 80.592 +239.39 2 = 252.59 k.mm M %= 207.79 k.mm

σ ∗¿T&e¿


= 580 ∗0.88 ∗0.981.15

= 434.94 . /mm2


24/38

;

σ ∗¿T&e M e)

¿¿

¿2 + 34∗

( M %

6 e )2

¿¿

32 ∗sπ

∗√ ¿

¿ 3√ ¿

; ¿3√32∗1.5π ∗√(252590434.94 )2 + 34∗(207790780 )2 7777777d = 21.218 mm

; 40 3 C% ">>$ 40 ¿21.218 %;C C& $ $& " &$ ">%$

ARA MİL İMALAT RESMİ

+-Ç5 5) $%$& C>%3&;5#5% 365:

) ! 4 = M d 3d 4∗2 2G

514230.64

106.41 F==/.08 N

) r 4= ) ! 4∗!an,

2(s, F==/.08Gtan20

cos20 7 47./= N


25/38

) a 4= ) ! 4∗!an, F==/.08G tan 20 7/1 .8 N

;*?%" $

∑ M 0

) * y∗145 = 3743.56 ∗110 − 3517.8 ∗53.205 = 1549.15 .

∑ ) y 0

) - y= 3743.56 − 1549.15 = 2194.41 .

Z ;*?%" $

∑ M 0

) * z∗145 = ) ! 4∗110 F==/.08G110

) * z 772.21 N


26/38

∑ ) z 0

) - z ) ! 4 ) * z F==/.08 Q 772.21 2772.8 N

M e= √ M 2

: y❑+ M 2 : z❑

M e= 352.296 k.mm M %= 524.23 k.mm

σ ∗¿T&e¿



27/38

σ T&e /80 N mm2

K % 0.87 ,; /0 $ $& C> 3 >@#*-

K y 0.F8 , 6 m= ¿ 1200 N mm2

" *?" $ 93#%3>5% 5) ;C#C$ $& *?" 3>63 565-

K ç 2.2/ , # A " $% " ;C#C C " 6 m= ¿ 1200 N mm2

$ $&"&>$ 3>63 565-

D /0 3%5&;5

77 7 σ ∗¿T&e¿580 ∗0.83 ∗0.98

2.25 ¿ 20F.= N mm2

;

σ ∗¿T&e M e

¿¿

¿2 + 34∗

( M %

6 e )2

¿¿

32 ∗sπ

∗√ ¿

≥ 3√ ¿

6 e= 780 . /mm2

; ≥ 3√32∗1.5π ∗√(352296209.67 )2 + 34∗(524230780 )2

; ≥ 70.0= 77 7 D /0 3%5&5#.

A%5&3& 39 C%C&3& 39 ;" "#$&;"& * * %;C C $ $&" &$ ">%$;$#.


28/38

/-KAMA BAĞLANTISI APILAN Dİ!LİLERİN KAMAHESAPLARI1-A#3 $% *?"#$&;" $ 3 3%3#5& 565&5& 395%3+3 5 40 ;$#.

B3 %3&>5;3 %C)3+3 >" ">6"% C ">

) ! =2∗ M d 2

d = 2∗146923.04

40= 7346.15 .

D$)%$ $ $ 3;"> 3 3 $%" $%" &>3 395%3+3 >5#.BC *?;"&

) ! 1= ) !

2 7= 7.0 N

; 40 14 < F ! 1 /./

K3 3 3%?" "6$ E77/ '"&"% 395 "%$ $ 6" $%;$.

K3 3 $%" $% 3#365&;3 $ *?" 365&+5 &># %*


29/38

P ) ! 1! 1∗

< P em=ℜ

'

3673.07

5.5 ∗ <

335

1.57777

L ≥ 2.99 mm

K3 3 $%" '@ " 3#365&;3 *?" 365&+5 &># %*

L ≥ 2∗s∗ Md

d (" − ! 1 )∗ℜ∗ z ? 2 , $% *?"#$&;" $ 3 3

63 565-

L ≥ 2∗1.5 ∗146923.04

40 ∗(3.5 )∗355 ∗2 4.=F

K"6$% " &># %*

L ≥ 4∗s∗ Mdd∗%∗ℜ∗ z

L ≥ 4∗1.5 ∗146923.04

40 ∗14 ∗355 ∗2 2.74

K3 3 $%" '@ " 3#365&;3 %C)3& *?" 365&+5&3 '@#"395%3& &># % ;" 3 3 C?C&%C C 3J 5 5)>5#.K3 3

>*#* %3#3 A >$9$ C 'C 3 365 6" $% $)>$#.E);" "# 3 3C?C&%C C

eş= +% 4.=F 14 18.=F % 3%5;5#.

TS 14 F A 14GFG20 )" %$&;" 2 3;"> 3 3 6" $%$#.

2-Ç5 5) $%$ *?"#$&;" $ 3 3%3#5&


30/38

Ç5 5) $%$ *?"#$&;" 3 3 $%" $%" &>3 395%3+3 >5#.BC *?;"&

) ! 1= ) !

2 10284.=1 N

; /0 1= < 10 ! 1 =

K3 3 3%?" "6$ E77/ '"&"% 395 "%$ $ 6" $%;$.

K3 3 $%" $% 3#365&;3 $ *?" 365&+5 &># %*

P ) ! 1

! 1∗ < P em= ℜ'

10284.61

6∗ <

335

1.57777 L ≥7.675 mm

K3 3 $%" '@ " 3#365&;3 *?" 365&+5 &># %*

L ≥ 2∗s∗ Md

d (" − ! 1 )∗ℜ∗ z ? 2 , $% *?"#$&;" $ 3 3

63 565-

L ≥ 2∗1.5 ∗514230.64

50 ∗(4 )∗355 ∗2 11./12


31/38

K"6$% " &># %*

L ≥ 4∗s∗ Mdd∗%∗ℜ∗ z

L ≥ 4∗1.5 ∗514230.64

50 ∗16 ∗355 ∗2 /. /=

K3 3 $%" '@ " 3#365&;3 %C)3& *?" 365&+5&3 '@#"395%3& &># % ;" 3 3 C?C&%C C 3J 5 5)>5#.K3 3

>*#* %3#3 A >$9$ C 'C 3 365 6" $% $)>$#.E);" "# 3 3C?C&%C C

eş= +% 11./12 1= 2 ./12 % 3%5;5#.

TS 14 F A 1=G10G70 )" %$&;" 2 3;"> 3 3 6" $%$#.

=- ATAK SEÇİMİ3-($#$) $%$&;" $ 3>3 %3#5& 6" $ $

A 3>3 5:A 3>3 5&5 "> $%" "& $%") " #3; 3% C ">

) 4 r= √ ( ) 4 y )2 +( ) 4 z)

2 = √ 594.268 2 +1278.57 2 = 1409.92 .

A 3>3 5&5 "> $%" "& " 6"&"% C ">

) 4 a= 628.237 N

A 3>3 5 $ $& 6$%$&;$#$ 3 3#3%5 70 395&;3 NUP20=E P#C% 3&5 6" $%;$.

RC% 3& 3>3% 'C&;3& 6" $%"& 6>3&;3#> ;" "#%"#

44 N 44000 N

) 4 a )

4 r

=628.237

1409.92= 0.44 >e= 0.2 7 9 = 0.92 5 = 0.6


32/38


33/38

) &r= √ ( ) & y )2 +( ) & z )

2 = √ 371.42 2 +3515.93 2 = 3535.49 .

D 3>3 5&5 "> $%" "& " 6"&"% C ">

) &a = ¿ =28.27 N

D 3>3 5 $ $& 6$%$&;$#$ 3 3#3%5 7/ 395&;3 NUP20 E#C% 3&5 6" $%;$.

RC% 3& 3>3% 'C&;3& 6" $%"& 6>3&;3#> ;" "#%"#

/0 N /0000 N

) &a ) &r

= 628.2373535.49 = 0.177 5 = 0

D$&3 $ ");" "# C ">

) &= 9 ∗ ) &r+5 ∗ ) &a = 1∗3535.49 +0∗628.237 = 7217.14 .

3>3 5& & $&3% @ #* "= 10

6

60∗n∗( 8 ) & )

=

n 2 = 325 dd

= 7.777 ,S$%$&;$#$ 3 3#3%5 #C% 3& $ $&-

"= 10

6

60∗325∗( 500003535.49 )

3.333

= 350469.19 >20000 "

3>3 5

3>3 5&5 "> $%" "& $%") " #3; 3% C "> ) 8 r= √ ( ) 8 y)

2 +( ) 8 z)2 = √ 2302.61 2 +6839.97 2 = 7217.14 .

3>3 5&5 "> $%" "& " 6"&"% C "> >C#.

3>3 5 $ $& 6$%$&;$#$ 3 3#3%5 40 395&;3 NUP208 E#C% 3&5 6" $%;$.

RC% 3& 3>3% 'C&;3& 6" $%"& 6>3&;3#> ;" "#%"#


34/38

/7 N /7000 N

D$&3 $ ");" "# C ">

) 8 r= 7217.14 .

3>3 5& & $&3% @ #*

"= 10

6

60∗n∗( 8 ) 8 )

=

n2 = 325 dd = 7.777 ,S$%$&;$#$ 3 3#3%5 #C% 3& $ $&-

"= 10

6

60∗325 ∗( 53000

7217.14 )3.333

=39449.89

>20000

"

+-Ç5 5) $%$&;" $ 3>3 %3#5& 6" $ $H 3>3 5:

H 3>3 5&5 "> $%" "& $%") " #3; 3% C ">

) - r= √ ( ) - y )2 +( ) - z)

2 = √ 2194.41 2 +2332.87 2 = 3202.76 .

H 3>3 5&5 "> $%" "& " 6"&"% C ">

) - a= ¿ 7141 N

H 3>3 5 $ $& 6$%$&;$#$ 3 3#3%5 40 395&;3 NUP208E TVP2#C% 3&5 6" $%;$.

RC% 3& 3>3% 'C&;3& 6" $%"& 6>3&;3#> ;" "#%"# /7 N /7000 N

) - a ) - r

= 31413202.76

= 0.98 >e= 0.2 7 9 = 0.92 5 = 0.40

D$&3 $ ");" "# C ">

) - = 9 ∗ ) - r+5 ∗ ) - a= 0.92 ∗3202.76 +0.40 ∗3141 = 4202.93 .


35/38

3>3 5& & $&3% @ #* "= 10

6

60∗n3∗( 8 ) - )

=

n3 = 92.85 dd

= 7.777 ,S$%$&;$#$ 3 3#3%5 #C% 3& $ $&

"= 10

6

60∗92.85∗( 530004202.93 )

3.333

= 837103.14 >20000 "

E 3>3 5

E 3>3 5&5 "> $%" "& $%") " #3; 3% C ">

) * r= √ ( ) * y )2 +( ) * z )

2 = √ 1549.15 2 +7332.21 2 = 7494.07 .

E 3>3 5&5 "> $%" "& " 6"&"% C "> >C#.

E 3>3 5 $ $& 6$%$&;$#$ 3 3#3%5 A( #C% 3& 3> % C&;3& 4/ 395&;3 NU100FM1 #C% 3&5 6" $%;$.

RC% 3& 3>3% 'C&;3& 6" $%"& 6>3&;3#> ;" "#%"#

74./ N 74/00 N

D$&3 $ ");" "# C ">

) ) r= 7494.07 .

3>3 5& & $&3% @ #*

"= 10

6

60∗n∗( 8 ) * )

=

n= 92.85 dd

== 3.333 (silindirik makaralırulman )

"= 10

6

60∗92.85∗( 345007494.07 )

3.333

= 29119.48 >20000 "


36/38


37/38


38/38

Documents

2 kademeli redüktör