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23rd IYPT Problem : Steel Balls Wen-Chin Lin, Yu-Chen Lin, Wei-Shen Chen Department of Physics, National Taiwan Normal University Kaohsiung Senior High School Abstract Colliding two large steel balls with a thin sheet of material (e.g. paper) in between may "burn" a hole in the sheet. Investigate this effect for various materials. We tried different materials in this experiment in order to investigate the physical phenomenon during the steel ball collision. For thin papers, we can burn a hole by collision. For plastic materials, we can melt the sheet, but not necessarily create a hole. For metallic sheets, like copper and aluminum foils, interesting circular ripples were observed. The steel ball collision can be simplified as an adiabatic process, during which the work done by steel balls is transferred to heat. Therefore the temperature at collision area is significantly increased, resulting in the paper burning or the melting of thin sheets. Experimental Setup vertical collision Experimental Results Theory & Discussion Sheet Conclusion Height: Diameter of holes increases as height increases Collision Area: Melting or Burning Adiabatic Process is the main reason holes are burned because: Δt is small, Area is small, abd Pressure is high high is T Duration ∆t = ? 1. Our high speed video: 230 μs/frame ∆t < 230 μs 2. From reference our m ball =287 g R. Hessel, A. C. Perinotto, R. A. M. Alfaro, and A. A. Freschia, Am. J. Phys. 74 3, 176 (2006). We can conclude : ∆t < 230 μs Collision area A=? Al foil Estimate A from the melted Al foil . Diameter: 1.58± 0.08 mm Average pressure P = ? 1 F p P A t A m=287 g, H=50 cm, g=9.8 m/s 2 , A< π(0.8mm) 2 , ∆t < 230 μs 2 2 2 2 o o p m gH p m gH p ) ( 10 9 . 1 14 . 3 0008 . 0 1 10 3 . 2 5 . 0 8 . 9 2 287 . 0 2 9 2 4 m Nt P 4 1.9 10 P atm ) ( 10 9 . 3 ) ( 1 J d A P V P W Work ∆W=? Pressure P > 1.2 x 10 9 Nt/m 2 Collision Area A=πr 2 ~ 2x10 -6 m 2 Thickness of sheet ∆d= 10 -4 m ) ( 10 8 . 1 ~ 10 3 . 2 1000 ) 10 2 ( 401 4 4 6 J Q T A t Q Conducted heat ∆Q=? ∆T < 1000 A=πr 2 ~ 2 x 10 -6 m 2 Air 0.026 Al 237 Cu 401 Fe 80.4 Steel 46 Water 0.61 Wood 0.11 σ Adiabatic process!! Work done during collision ∆W > 3.9 ×10 -1 (J) Heat conducted during collision : Q < 2.9 ×10 -4 (J) ∆W >> ∆Q Adiabatic process T high T low 1. Paper (Burning point: 130 o ~232 o C) Reference:http://wiki.answers.com/Q/W hat_is_the_Burning_point_of_paper 5 mm Paper A thin piece of material left on the ball Greatly heated Burned Greatly heated Burned O 2 2. Plastic (Melting Point: 106~114) (Soften temperature: 80~98) 4 mm Cooled down Compressed Into thin layer Melted Wrinkles 6 mm 3. Aluminum foil (Melting point: 660 C) Concentric circles wrinkles Melted Compressed

23rd IYPT Problem : Steel Ballsarchive.iypt.org/enjoy_phy_ntnu_edu_tw/poster of problem 03 steel... · 23rd IYPT Problem : Steel Balls Wen-Chin Lin, Yu-Chen Lin, Wei-Shen Chen Department

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Page 1: 23rd IYPT Problem : Steel Ballsarchive.iypt.org/enjoy_phy_ntnu_edu_tw/poster of problem 03 steel... · 23rd IYPT Problem : Steel Balls Wen-Chin Lin, Yu-Chen Lin, Wei-Shen Chen Department

23rd IYPT Problem : Steel BallsWen-Chin Lin, Yu-Chen Lin, Wei-Shen Chen

Department of Physics, National Taiwan Normal University

Kaohsiung Senior High School

Abstract

Colliding two large steel balls with a thin sheet of material

(e.g. paper) in between may "burn" a hole in the sheet.

Investigate this effect for various materials.

We tried different materials in this experiment in order to

investigate the physical phenomenon during the steel ball

collision. For thin papers, we can burn a hole by collision. For

plastic materials, we can melt the sheet, but not necessarily

create a hole. For metallic sheets, like copper and aluminum foils,

interesting circular ripples were observed. The steel ball collision

can be simplified as an adiabatic process, during which the work

done by steel balls is transferred to heat. Therefore the

temperature at collision area is significantly increased, resulting

in the paper burning or the melting of thin sheets.

Experimental Setup vertical collision

Experimental Results

Theory & Discussion

Sheet

Conclusion

Height: Diameter of holes increases as height increases

Collision Area: Melting or Burning

Adiabatic Process is the main reason

holes are burned because:

Δt is small, Area is small, abd Pressure is high

high is T

Duration ∆t = ?

1. Our high speed video: 230 μs/frame

∆t < 230 μs

2. From referenceour mball=287 g

R. Hessel, A. C. Perinotto, R. A. M. Alfaro,

and A. A. Freschia, Am. J. Phys. 74 3, 176 (2006).

We can conclude : ∆t < 230 μs

Collision area A=?

Al foil

Estimate A from the melted Al foil .

Diameter: 1.58± 0.08 mm

Average pressure P = ?

1F pP

A t A

m=287 g, H=50 cm, g=9.8 m/s2, A< π(0.8mm) 2 , ∆t < 230 μs

2 2 2 2o op m gH p m gH p

)(109.114.30008.0

1

103.2

5.08.92287.02

9

24 m

NtP

41.9 10P atm

)(109.3)( 1 JdAPVPW

Work ∆W=?

Pressure P > 1.2 x 109 Nt/m2

Collision Area A=πr2 ~ 2x10-6 m2

Thickness of sheet ∆d= 10-4 m

)(108.1~103.21000)102(401 446 JQ

TAt

Q

Conducted heat ∆Q=?

∆T < 1000 ℃

A=πr2 ~ 2 x 10-6 m2

Air 0.026

Al 237

Cu 401

Fe 80.4

Steel 46

Water 0.61

Wood 0.11

σ

Adiabatic process!!

Work done during collision ∆W > 3.9 ×10-1 (J)

Heat conducted during collision : ∆Q < 2.9 ×10-4 (J)

∆W >> ∆Q Adiabatic process

ThighTlow

1. Paper (Burning point: 130o~232

oC)

Reference:http://wiki.answers.com/Q/W

hat_is_the_Burning_point_of_paper

5 mm

Paper

A thin piece of

material left on

the ball

Greatly heated

Burned

O2

Greatly heated

Burned

O2

2. Plastic (Melting Point: 106~114℃)

(Soften temperature: 80~98℃)

4 mm

Cooled down

Compressed

Into thin layer

Melted

Wrinkles

6 mm

3. Aluminum foil (Melting point: 660 C)

Concentric circles

wrinkles

Melted

Compressed