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: CHAPTER 1: MOLECULES OF LIFE (7 HRS)

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  • :

    CHAPTER 1: MOLECULES OF LIFE

    (7 HRS)

  • 1.0 Molecules Of Life (7 hrs)

    1.1 Water (1)

    1.2 Carbohydrates (1)

    1.3 Lipids (1)

    1.4 Proteins (2)

    1.5 Nucleic Acids (1)

  • Learning outcomes

    a) Explain the structure of water molecule

    b) Describe the properties of water and its importance

  • Structure:

    1 oxygen atom & 2 hydrogen atoms (H2O)

    Joined together by sharing electrons ~ covalent bond

    3 atoms ~ arranged to form a triangle

    Angle ~ 104.5

    Learning Outcomes : 1.1 (a) Explain the structure of water molecule

    H H

    O

  • Learning Outcomes : 1.1 (a) Explain the structure of water molecule

    The sharing of electrons between O & H atoms are not equal

    O atom ~ slightly negative charge (-)

    H atoms ~ slightly positive charge (+)

    Unequal charge distribution within a molecule ~ polar molecule

    2-

    + +

    O

    H H

  • + H atom of one water molecule is attracted to the - O atom of nearby water molecules

    Water molecules are held together by hydrogen bonds

    H bond is weak, represented by dotted lines

    2-

    + +

    2-

    +

    +

    Hydrogen bond

    Learning Outcomes : 1.1 (a) Explain the structure of water molecule

  • 1 water molecule can form maximum of 4 hydrogen bonds with 4 water molecules

    Learning Outcomes : 1.1 (a) Explain the structure of water molecule

  • Learning Outcomes : 1.1 (b) Describe the properties of water and its importance

    Properties of water

    1. Universal solvent

    2. High specific heat capacity

    3. High latent heat of vaporization

    4. High surface tension

    5. Maximum density at 4C

    6. Low viscosity

    mn

  • 1. Universal Solvent Powerful solvent for ionic & polar substances (eg: NaCl)

    NaCl are held together by ionic bonds between Na+ & Cl-

    Learning Outcomes : 1.1 (b) Describe the properties of water and its importance

  • 1. Universal Solvent Water is a polar molecule

    The O atoms has a slightly negative charge & H atoms has a slightly positive charge

    O atoms are attracted to the positively charged sodium ions

    H atoms are attracted to the negatively charged chloride ions

    Ionic bonds between NaCl molecules become weaker

    Learning Outcomes : 1.1 (b) Describe the properties of water and its importance

  • 1. Universal Solvent

    Water molecules gather around the Na+ & Cl- to form a hydration shell, separating them from one another

    Pulling these ions away from the salt crystal

    Causes these ions to separate & dissolve

    Learning Outcomes : 1.1 (b) Describe the properties of water and its importance

  • 1. Universal Solvent

    Importance:

    Act as transport medium for solutes (eg: dissolved nutrients are carried throughout the body in blood plasma)

    Water facilitates chemical reaction (solutes are more reactive when dissolved)

    Learning Outcomes : 1.1 (b) Describe the properties of water and its importance

  • 2. High specific heat capacity

    Definition : amount of energy needed to increase the temperature of 1 g of a substance by 1C

    Large amount of energy is needed to increase the temperature of 1 g of water by 1oC

    Heat is absorbed to break the H bonds between water molecules

    Value = 1 cal/g (most substances have lower value)

    A large body of water (ocean/lakes) has a relatively constant temperature although its surrounding temperature changes (temperature rises & falls slowly)

    Learning Outcomes : 1.1 (b) Describe the properties of water and its importance

  • 2. High specific heat capacity

    Importance:

    Organisms can maintain their normal body temperature

    Aquatic organisms can live in a relatively stable temperature (protected from rapid temperature changes)

    Learning Outcomes : 1.1 (b) Describe the properties of water and its importance

  • 3. High latent heat of vaporization

    Definition : Amount of energy needed to change 1 g of a

    substance from liquid phase to vapor

    A lot of energy is needed to change 1 g of water from

    liquid state to vapor

    Heat is absorbed to break the H bonds between water

    molecules before they can move faster & vaporized

    Value = 540 cal/g

    Learning Outcomes : 1.1 (b) Describe the properties of water and its importance

  • Importance:

    Cooling effect in organisms due to sweating (animals) or transpiration (plants)

    Explanation:

    As water absorbs heat, its energy increases

    When water evaporates, it takes a lot of heat energy away lowering the temperature of the organism

    3. High latent heat of vaporization

    Learning Outcomes : 1.1 (b) Describe the properties of water and its importance

  • 4. High surface tension

    H bonds make water molecules stick to each other cohesion

    On the surface, water has greater attraction for each other than for molecules in the air

    Learning Outcomes : 1.1 (b) Describe the properties of water and its importance

  • 4. High surface tension

    Water are also pulled downward by other water molecules beneath them

    Produce a strong layer on the surface, hard to break the water surface create high surface tension

    Water molecules can also stick to other substances adhesion

    Learning Outcomes : 1.1 (b) Describe the properties of water and its importance

  • 4. High surface tension

    Importance:

    Allow some organisms to move on water (eg: water strider)

    Learning Outcomes : 1.1 (b) Describe the properties of water and its importance

  • As water cools, the molecules get closer together

    Reach maximum density at 4C

    At temperature below 4C, water molecules expand until it freezes/solidifies (at 0C)

    5. Maximum density at 4C

    Learning Outcomes : 1.1 (b) Describe the properties of water and its importance

  • 5. Maximum density at 4C

    H bonds in ice space the water molecules far apart & become stable

    Ice is less dense than cold water floats

    Learning Outcomes : 1.1 (b) Describe the properties of water and its importance

  • 5. Maximum density at 4C

    Importance:

    Allow aquatic life to live under the frozen surface of water in cold climate region

    Explanation:

    The floating layer of ice insulates the water below, prevent them from losing heat & from freezing

    Learning Outcomes : 1.1 (b) Describe the properties of water and its importance

  • 6. Low viscosity

    Weak H bonds between water molecules are constantly breaking & reforming.

    Water molecules can slide easily over each other

    It flows with less friction through narrow vessels.

    Importance:

    Act as medium of transportation in living organisms (eg: blood easily flow in the circulatory system)

    Act as a good lubricant to reduce friction within body (eg: mucus facilitates movement of feces through the bowel)

    Learning Outcomes : 1.1 (b) Describe the properties of water and its importance

  • 1.0 Molecules Of Life (7 hrs)

    1.1 Water (1)

    1.2 Carbohydrates (1)

    1.3 Lipids (1)

    1.4 Proteins (2)

    1.5 Nucleic Acids (1)

  • Learning outcomes

    a) Describe various forms & classes of carbohydrates

    b) Describe the formation & breakdown of maltose

    c) Describe the structures & functions of starch, glycogen and cellulose

  • Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates

    Composed of carbon, hydrogen & oxygen atoms

    Ratio of C, H & O ~ approximately 1:2:1 (CH2O)n

    n = number of C atoms

    Introduction

  • Classification

    Monosaccharide Polysaccharide Disaccharide

    1 sugar unit 2 sugar units Many sugar units

    Classes of carbohydrates:

    Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates

  • MONOSACCHARIDES

    1. Small

    2. Sweet

    3. Soluble in water

    4. Can crystallized

    5. White / colourless

    6. Reducing sugar

    1 sugar molecule; simple sugar (3-7 carbon atoms)

    Characteristics:

    Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates

  • Based on the position of functional group

    Aldose Ketose Triose 3C Pentose 5C Hexose 6C

    Classification

    Based on no. of C atom

    Classes of monosaccharide:

    Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates

  • Functional group ~ carbonyl group (C=O)

    1. Aldose sugar

    Carbonyl group is located at the end of carbon chain

    Eg: glucose

    2. Ketose sugar

    Carbonyl group is located in the middle of carbon chain

    Eg: fructose

    Numbering of carbon chain begins with the carbon nearest to carbonyl group

    Classes of monosaccharide: based on the position of functional group

    Learning Outcomes : (a) Describe various forms and classes of carbohydrates

    Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates

  • Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates

  • 3 classes:

    1. Triose sugar (3 C atoms)

    Eg: glyceraldehyde & dihidroxyacetone; C3H6O3

    2. Pentose sugar (5 C atoms) will be discussed in nucleic acid

    Eg: ribose, ribulose; C5H10O5, & deoxyribose; C5H10O4

    3. Hexose sugar (6 C atoms)

    Eg: glucose, galactose, fructose; C6H12O6

    When dissolved in water, pentose & hexose form ring structure; which is more stable

    Classes of monosaccharide: based on the number of carbon atom

    Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates

  • Same molecular formulas but different arrangements of atoms ~ isomers

    Glucose ~ blood sugar, moderate sweetness, found in fruits & vegetables

    Galactose ~ less sweet, found in milk & yoghurt

    Fructose ~ fruit sugar, sweetest, found in fruits & honey

    Hexose sugar (6 C atoms)

    Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates

  • Linear and ring forms of glucose. To form the glucose ring, carbon 1 bonds to the oxygen attached to carbon 5.

  • Glucose

    Each of these structure is glucose (C6H12O6)

    a. All carbon atoms are clearly shown

    b. The carbon atoms are omitted

    c. The hydrogen atoms are omitted

    Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates

  • Glucose

    2 isomeric forms, according to the position of OH group at C1

    above the ring plane = -glucose

    below the ring plane = -glucose

    Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates

  • Function of Monosaccharides

    Energy source

    Glucose ~ major respiratory substrate, primary energy source

    Basic building units or monomers for disaccharide & polysaccharide

    Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates

  • DISACCHARIDES

    1. Sweet

    2. Soluble in water

    3. Can crystallized

    4. White / colourless

    2 sugar molecules or two monosaccharides

    Joined together by a condensation process (removal of a water molecule)

    Form covalent bond glycosidic bond

    Can be broken down into monomers by hydrolysis process (addition of water molecule)

    Characteristics:

    Disaccharide

    Maltose Sucrose Lactose

    Learning Outcomes : 1.2 (b) Describe the formation and breakdown of maltose

  • Condensation

    Hydrolysis

    CONDENSATION PROCESS

    HYDROLYSIS PROCESS

    Learning Outcomes : 1.2 (b) Describe the formation and breakdown of maltose

  • MALTOSE

    Malt sugar

    Monomers : -glucose + -glucose

    Joined together by -1,4 glycosidic bond (between C1 of one glucose molecule and C4 of another molecule)

    condensation

    hydrolysis

    -glucose (C6H12O6)

    -glucose (C6H12O6)

    Maltose (C12H22O11)

    -1,4 glycosidic

    bond

    +

    condensation

    hydrolysis

    Learning Outcomes : 1.2 (b) Describe the formation and breakdown of maltose

  • POLYSACCHARIDES

    1. Large molecule

    2. Not sweet

    3. Insoluble in water (form colloid)

    Many sugar molecules; polymer (vary in length)

    Joined together by condensation process (removal of a water molecules)

    Form covalent bond glycosidic bond

    Formation of polymer (large molecules made up of repeating units of monomers) polymerization

    Can be broken down into monomers by hydrolysis process (addition of water molecules)

    Characteristics:

    Polysaccharide

    Starch Glycogen Cellulose

    Amylose Amylopectin

    Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose

  • Energy storage in plants

    Plants convert excess glucose into starch for storage in chloroplast

    Monomers: -glucose molecules

    Broken down by hydrolysis process with the help of amylase enzyme

    Starch is a mixture of:

    Amylose

    Amylopectin

    STARCH

    Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose

  • Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose

    Monomers: -glucose molecules

    Joined together by -1,4 glycosidic bond

    Helical, due to the formation of H bonds

    Unbranched chain (variable length of monomers)

    Folded ~ very compact (ideal for storage)

    AMYLOSE

    O O

    -1,4 glycosidic bond

    O O O

    OH

    OH

    CH2OH

    1 4

    2 3

    5

    6

    OH

    CH2OH

    1 4

    2 3

    5

    6

    OH

    OH

    CH2OH

    4 1

    6

    2 3

    5

    OH

    OH

    CH2OH

    4 1

    6

    2 3

    5

    OH

    -glucose -glucose -glucose -glucose

  • Monomers: -glucose molecules

    Joined together by -1,4 glycosidic bond & -1,6 glycosidic bond

    Helical, branched chain (variable length of monomers)

    Branches occur within 30 units

    Folded & branched ~ very compact (ideal for storage)

    AMYLOPECTIN

    Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose

  • AMYLOPECTIN

    O O O O O

    OH

    OH

    CH2OH

    1 4

    2 3

    5

    6

    OH

    CH2OH

    1 4

    2 3

    5

    6

    OH

    OH 4 1

    6

    2 3

    5

    OH

    OH

    CH2OH

    4 1

    6

    2 3

    5

    OH

    -glucose -glucose -glucose -glucose

    OH

    OH

    CH2OH

    4 1

    6

    2 3

    5

    OH

    OH

    CH2OH

    4 1

    6

    2 3

    5

    O O

    C H H

    -1,4 glycosidic bond

    -1,6 glycosidic bond

    O

    Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose

  • DIFFERENCES BETWEEN AMYLOSE &

    AMYLOPECTIN

    Features Amylose Amylopectin

    Monomers -glucose -glucose

    Bond

    -1,4 glycosidic bond -1,4 glycosidic bond

    -1,6 glycosidic bond

    Shape Helical, unbranched Helical, branched (within

    30 units)

    Function

    Ideal for energy storage

    (insoluble, coiled, compact)

    Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose

  • Energy storage in animals (in liver & muscle)

    Structure ~ similar to amylopectin

    More branched than amylopectin

    GLYCOGEN

    Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose

  • Major component of plant cell wall

    Monomers: -glucose

    Bond: -1,4 glycosidic bond

    Broken down by hydrolysis with the help of cellulase enzyme

    Unbranched, long straight chain

    CELLULOSE

    O O

    -1,4 glycosidic bond

    O

    OH

    OH

    CH2OH

    1 4

    2 3

    5

    6

    OH

    CH2OH

    1 4

    2 3

    5

    6

    OH

    OH

    CH2OH

    4 1

    6

    2 3

    5

    OH

    OH

    CH2OH

    4 1

    6

    2 3

    5

    OH

    -glucose -glucose -glucose -glucose

    Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose

  • CELLULOSE

    -1,4 glycosidic bond

    Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose

  • Straight chains are arranged parallel to one another

    Linked together by hydrogen bonds (form microfibril)

    Very stable & tough structure ~ provide support to plant cell

    CELLULOSE

    Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose

  • Functions of Polysaccharides

    Energy Storage ~ eg: starch (in plant) & glycogen (in animals)

    Major component of cell walls ~ provide structural support to

    plant cell ~ eg: cellulose

    Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose

  • 1.0 Molecules Of Life (7 hrs)

    1.1 Water (1)

    1.2 Carbohydrates (1)

    1.3 Lipids (1)

    1.4 Proteins (2)

    1.5 Nucleic Acids (1)

  • Learning outcomes

    a) State the types of lipid

    b) Describe the structure of glycerol & fatty acids

    c) Describe the formation & breakdown of triglycerides

  • Learning Outcomes : 1.3 (a) State the types of lipid: fats, phospholipids and steroids

    LIPIDS

    Fats Steroids Phospholipids

    Consist of mainly carbon & hydrogen atoms; few oxygen atom

    Group of hydrophobic molecules ~ insoluble in water

    3 major types:

    LIPIDS

    Eg: oil, butter Eg: lecithin Eg: cholesterol

  • Learning Outcomes : 1.3 (a) State the types of lipid: fats, phospholipids and steroids

    Building block

    1 Glycerol 3 Fatty acids

    Saturated Unsaturated

    Most abundant

    Also known as (a.k.a) : Triglyceride / Triacylglycerol

    FATS

  • a) Structure of glycerol and b) general structure of fatty acids

  • Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids

    .

    A.k.a : glycerine

    3C alcohol with 3 OH groups (soluble in water)

    C

    C

    C

    OH

    OH

    OH

    H

    H

    H

    H

    H

    Glycerol

  • .

    Fatty Acids

    Has 2 regions:

    Hydrophilic head (a carboxyl group, COOH at 1 end ) ~ acid

    Hydrophobic tail ~ long unbranched hydrocarbon chain (known as side chain, R)

    HO C1

    O

    C2 C3 C4 C5 C6 C7 C8 C9 C10 C11 C12 C13 C14

    H H H H H H H H H H H H H

    H H H H H H H H H H H H H

    H

    Carboxyl group Hydrocarbon chain

    R

    Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids

  • . Hydrophobic tail vary in length

    Different fatty acids has different number of C atoms (usually 16 or 18)

    C2 HO C3 C4 C5 C6 C7 C8 C9 C1

    H H H H H H H O

    H H H H H H H H

    C10

    H H

    C11 C12 C13 C15 C14

    H H H H H

    H H H H

    C16 C18 C17

    H H H

    H H H

    H

    H H

    Eg: Stearic acid (stearate) C18H36O2

    Fatty Acids

    Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids

  • . Based on the presence of double bonds within hydrocarbon

    chain:

    Saturated fatty acids

    ~ no double bond between C atoms; eg: stearic acid

    Unsaturated fatty acids

    ~ has double bonds between C atoms; eg: oleic acid

    C2 HO C3 C4 C5 C6 C7 C8 C9 C1

    H H H H H H H O

    H H H H H H H H

    C10

    H H

    C11 C12 C13 C15 C14

    H H H H H

    H H H H

    C16 C18 C17

    H H H

    H H H

    H

    H H

    Eg: Stearic acid (stearate) C18H36O2

    Classification of Fatty Acids

    Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids

  • . Has maximum number

    of H atoms

    Straight chain, fatty acids can be closely packed

    Solid at room temperature

    SATURATED FATTY ACID

    Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids

  • .

    SATURATED FATTY ACID

    Fats that consist of saturated fatty acids ~ saturated fat

    Mostly animal fats (eg: butter, lard)

    Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids

  • SATURATED FATTY ACID

    Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids

  • Double bond causes

    bending in

    unsaturated fatty

    acids

    Fatty acids cannot be

    closely packed

    Liquid at room

    temperature

    UNSATURATED FATTY ACID

    Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids

  • UNSATURATED FATTY ACID

    Fats that consist of unsaturated fatty acids ~ unsaturated fat

    Mostly plant & fishes fats (eg: oil)

    Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids

  • Fatty acids stearic acid (saturated fat) and oleic acid (unsaturated fat).

  • . Based on the ability to be synthesized in the body:

    Essential fatty acids

    ~ cannot be synthesized in the body

    ~ must be present in the diet

    ~ eg: linoleic, linolenic and arachidonic acids

    Non-essential fatty acids

    ~ can be synthesized in the body

    ~ eg: stearic acid & others

    Classification of Fatty Acids

    Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids

  • PHOSPHOLIPIDS

    Building block

    1 Glycerol 2 Fatty acids Phosphate group

    Major component of cell membrane; eg: lecithin

    Amphipathic molecule

    i.e one end hydrophilic polar, another end hydrophobic non-polar

    Learning Outcomes : 1.3 (a) State the types of lipid: fats, phospholipids and steroids

  • Learning Outcomes : 1.3 (a) State the types of lipid: fats, phospholipids and steroids

    PHOSPHOLIPIDS

  • Composed of 3 fatty acids & 1 glycerol backbone

    Fats are formed when 3 condensation reaction occurs ~ also

    known as esterification

    Water is removed by extracting the OH from the carboxyl

    group (of fatty acid) and H from the glycerols hydroxyl group

    Triglyceride can be broken down by hydrolysis

    TRIGLYCERIDE

    Learning Outcomes : 1.3 (c) Describe the formation & breakdown of triglycerides

  • Learning Outcomes : 1.3 (c) Describe the formation & breakdown of triglycerides

    Formation of Triglycerides

    C OH H

    H

    H

    R HO

    O

    C

    C OH H

    C OH H

    R HO

    O

    C

    R HO

    O

    C

    C O H

    H

    H

    R

    O

    C

    C O H

    C O H

    R

    O

    C

    R

    O

    C

    1 glycerol 3 fatty acids

    Condensation

    Triglyceride

    + 3H2O

    Hydrolysis

    Ester bond

    Ester bond

    Ester bond

  • Importance of Lipids

    Main energy storage in animals (due to higher number of

    hydrogen atom)

    1 g of fat has > twice energy than same weight of starch

    Lighter ~ hydrophobic nature, doesnt associates with

    water

    Improve buoyancy in aquatic animals

    Provide better thermal insulation of mammals

    Act as padding for internal organs

    Phospholipid ~ major component of plasma membrane

    Steroid ~ some are hormones that regulates metabolism

    Learning Outcomes : 1.3 (c) Describe the formation & breakdown of triglycerides

  • 1.0 Molecules Of Life (7 hrs)

    1.1 Water (1)

    1.2 Carbohydrates (1)

    1.3 Lipids (1)

    1.4 Proteins (2)

    1.5 Nucleic Acids (1)

  • Learning outcomes

    a) Describe the basic structure of amino acids

    b) Explain how amino acids are grouped

    c) Describe the formation and breakdown of dipeptide

    d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved

    e) Classify proteins according to their structure

    f) Explain the effect of pH & temperature on the structure of protein

  • Learning Outcomes : 1.4 (a) Describe the basic structure of amino acids

    PROTEIN

    Polymer

    Building blocks ~ amino acids

    Joined together to form a long chain ~ polypeptide

    Protein consist of 1 or more polypeptide chains which folded & coiled into specific conformation

    Mostly composed of C, H, O, N & sometimes S

  • BASIC STRUCTURE OF AMINO ACIDS

    C H2N COOH

    R

    H

    Amino acids consist of 4 components attached to a central carbon

    These components include:

    a. a hydrogen atom

    b. a carboxyl group

    c. an amino group

    d. a variable R group (or side chain).

    amino group carboxyl group

    Learning Outcomes : 1.4 (a) Describe the basic structure of amino acids

  • BASIC STRUCTURE OF AMINO ACIDS

    i. COOH (carboxyl group)

    ii. NH2 (amino group) : basic

    : acidic

    C H2N COOH

    R

    H

    2 functional groups:

    amino group carboxyl group

    Amino acids are amphoteric; have both acidic & basic properties

    Learning Outcomes : 1.4 (a) Describe the basic structure of amino acids

  • Learning Outcomes : 1.4 (b) Explain how amino acids are grouped

    20 types of amino acids commonly found in proteins

    All have the same basic structure but differ in the side chain, R

    Amino acids are grouped based on the properties of R group

    GROUP OF AMINO ACIDS

    C H2N COOH

    R

    H

    amino group carboxyl group

  • Serine (ser)

    Aspartic acid (asp)

    Lysine (Lys)

    Glycine (gly)

    4 groups

    Non-polar Basic Polar Acidic

    Hydrophilic Has COOH group Has NH2 group Hydrophobic

    Learning Outcomes : 1.4 (b) Explain how amino acids are grouped

  • i. Essential amino acids (for human)

    Cannot be synthesized in sufficient amount, must be

    obtained through food or supplement intake

    8 amino acids; eg: isoleucine, leucine, lysine, methionine,

    phenylalanine, threonine, tryptophan, valine

    For infants : histidine

    ii. Non-essential amino acids

    Can be synthesized in the body

    Eg: alanine, arginine, asparagine, aspartic acid, cysteine,

    glutamic acid, glycine, proline, serine, tyrosine, glutamine

    GROUP OF AMINO ACIDS

    Learning Outcomes : 1.4 (b) Explain how amino acids are grouped

  • Learning Outcomes : 1.4 (c) Describe the formation and breakdown of dipeptide

    2 amino acids are joined by condensation process to form a dipeptide

    By removal of a hydroxyl group from the carboxyl end of one amino acid and a hydrogen from the amino group of another amino acid.

    Form a covalent bond ~ peptide bond

    Formation of the dipeptide

  • Learning Outcomes : (c) describe the formation and breakdown of dipeptide

    OH C N C

    O R1

    H

    H

    H

    H C N C OH

    O R2

    H H

    Peptide bond

    C N C

    O R1

    H

    H

    H

    C N C OH

    O R2

    H H

    H2O

    Condensation

    H2O

    Hydrolysis

    C-terminal N-terminal

    Formation & breakdown of the dipeptide

    Learning Outcomes : 1.4 (c) Describe the formation and breakdown of dipeptide

  • Dipeptide is hydrolysed into 2 amino acids by hydrolysis process (addition of water).

    Peptide bond is broken down and produces 2 amino acids.

    Breakdown of dipeptide

    Learning Outcomes : 1.4 (c) Describe the formation and breakdown of dipeptide

  • Many amino acids are joined by condensation process to form a polypeptide

    Bond ~ peptide bonds

    Polypeptide backbone ~ repeated sequence of (-N-C-C-)

    Formation of polypeptide

    OH H C N C

    O R2

    H H

    H C N C OH

    O R3

    H H

    Peptide bond

    H OH C N C

    O R1

    H H

    Peptide bond

    Learning Outcomes : 1.4 (c) Describe the formation and breakdown of dipeptide

  • Formation of tripeptide

    Learning Outcomes : 1.4 (c) Describe the formation and breakdown of dipeptide

  • Two ways based on:-

    Level of protein structure

    i. Primary

    ii. Secondary

    iii. Tertiary

    iv. Quaternary

    Structure

    i. Fibrous

    ii. Globular

    iii. Conjugated

    Classification of Protein

    Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved

  • Learning Outcomes : (d) explain primary, secondary, tertiary and quaternary levels of proteins and the types of bonds involved

    Learning Outcomes : (d) explain primary, secondary, tertiary and quaternary levels of proteins and the types of bonds involved Learning Outcomes :

    1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved

  • Primary structure

    Refers to the linear sequence of amino acids joined by peptide bonds within a polypeptide chain

    Each protein has a unique sequence of amino acids, determined by specific DNA code

    Different sequence results in the formation of different bonds between amino acids

    Causes a polypeptide chain to fold & coil into a unique 3 dimensional shape of protein

    Eg : lysozyme & all protein that has been sequenced

    Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved

  • Primary structure

    Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved

  • Secondary structure

    Linear chain of amino acids will coil or fold spontaneously

    Due to the formation of H bonds between the backbones (between H of the NH groups & O of the C=O groups of amino acids in the primary chain)

    2 types

    -helix

    -pleated sheet

    Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved

  • Secondary structure

    Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved

  • -helix

    Helical coil

    H bonds is formed between 1 amino acid & the 4th amino acid away from it

    Can stretch under tension ~ provide elasticity

    Because the hydrogen bonds can be reformed

    Eg: keratin in hair, nails & wool

    | S |

    S |

    | S |

    S |

    Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved

  • -pleated sheet

    Zig-zag pattern ~ provide strength & flexibility

    Eg: silk, spider web

    Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved

  • Tertiary structure

    1 polypeptide chain in secondary structure may further coiled into a globular shape which is maintained by bonds and interactions among R groups

    Globular shape unique to each polypeptide chain

    Mantained by 4 interactions between R groups:-

    Disulfide bonds (covalent bonds) between R groups with sulfhydryl groups

    Ionic bonds between +ve & -ve charged R groups

    Hydrogen bonds between + & - charged R groups

    Hydrophobic / Van der Waals interaction between non-polar R groups

    Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved

  • Tertiary structure

    Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved

  • Features Primary Secondary Tertiary

    Type of

    bond exist

    i. Peptide

    bond

    i. Peptide bond

    ii. H bond (between

    C=O & NH group of

    backbone)

    i. Peptide bond

    ii. H bond (between C=O

    & NH group of

    backbone)

    iii. Disulfide bond

    iv. Ionic bond

    v. H bond (between R

    groups)

    vi. Hydrophobic (van der

    Waals) interaction

    Tertiary structure

    Eg: enzymes, hormones, antibodies

    Type of bonds exist in different levels of protein:

    Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved

  • Quaternary structure

    Refers to a single protein that is formed when two or more polypeptide chain joins

    Bonds exist ~ same as tertiary structure

    Eg: hemoglobin (consist of 4 polypeptide chains, two chains and two chains)

    Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved

  • 4 Levels of Protein

    Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved

  • Classification of Protein

    FIBROUS

    Mostly secondary structure

    Form long parallel filaments or strands

    Insoluble & stable

    Function : mechanical & structural support

    Eg:

    Keratin, actin, myosin, collagen, silk

    Fibrous Globular Conjugated

    Based on Structure

    Learning Outcomes : 1.4 (e) Classify proteins according to their structure

  • Globular Protein

    Mostly tertiary/quaternary structure

    Folded to form compact spherical shaped

    Relatively unstable

    Relatively soluble ~ colloid

    Function : metabolic & chemical process

    Eg:

    Enzyme

    Antibodies

    Hormone

    Hemoglobin

    Learning Outcomes : 1.4 (e) Classify proteins according to their structure

  • Conjugated Proteins

    Conjugated Protein Prosthetic group Location

    Glycoprotein Polysaccharide Component of cell membrane

    Mucin (in saliva)

    Lipoprotein Lipid Component of cell membrane

    Lipid transported in blood

    plasma

    Chromoprotein Pigment Myoglobin, hemoglobin

    Nucleoprotein Nucleic acid Chromosome, ribosome

    Protein that can function well if it joins with other compound

    Non-protein compound ~ prosthetic group

    Learning Outcomes : 1.4 (e) Classify proteins according to their structure

  • Effect of pH and Temperature

    Structure of protein is affected by:-

    1. pH

    2. temperature

    Globular protein is relatively unstable because it is maintained

    by weak ionic bonds, hydrogen bonds & hydrophobic

    interactions

    When protein is heated or exposed to an extreme pH

    changes, those bonds are broken

    Causes it to uncoiled & change its conformation

    Lose its biological function ~ denatured protein coagulate

    Usually irreversible (sometimes, renaturation may occur)

    Learning Outcomes : 1.4 (f) Explain the effect of pH and temperature on the structure of protein

  • Factor Effect to the protein structure

    Heat or radiation Increased kinetic energy

    Protein atoms vibrate

    H & ionic bonds, van der Waals interaction break

    Strong acids & alkali

    H & ionic bonds, van der Waals interaction break

    Breakdown of peptide bonds occur if exposed very long

    Effect of pH and Temperature

    Learning Outcomes : 1.4 (f) Explain the effect of pH and temperature on the structure of protein

  • 1.0 Molecules Of Life (7 hrs)

    1.1 Water (1)

    1.2 Carbohydrates (1)

    1.3 Lipids (1)

    1.4 Proteins (2)

    1.5 Nucleic Acids (1)

  • Learning outcomes

    a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA & RNA)

    b) Describe the structure of DNA based on the Watson & Crick Model

    c) State the types & function of RNA

    d) State the differences of DNA & RNA

  • Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)

    Nucleic acid is polynucleotide ~ polymer of nucleotides

    Building blocks ~ nucleotide

    Mostly composed of C, H, O, P & N

    Introduction

  • NUCLEIC ACIDS

    2 types

    Deoxyribonucleic Acid (DNA)

    Ribonucleic Acid (RNA)

    Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)

  • Structure of nucleotides

    Each nucleotide has 3 components:-

    Nucleotide

    Pentose sugar Phosphate group Nitrogenous base

    Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)

    Ribose (in RNA)

    Deoxyribose (in DNA)

  • Pentose Sugar (5 C sugars)

    Ribose ~ component of RNA nucleotide

    Deoxyribose ~ component of DNA nucleotide

    At 2nd carbon atom ~ in deoxyribose; one H atom

    ~ in ribose; one OH group

    C5H10O4 C5H10O5

    Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)

  • Nitrogenous base

    Based on the number of C ring

    2 groups

    Pyrimidine Purine

    Cytosine (C) Uracil (U) Thymine (T) Adenine (A) Guanine (G)

    Single ring Double rings

    In RNA In DNA

    Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)

  • Learning Outcomes : (a) Describe the structure of nucleotide as the basic composition of nucleic acid (DNA and RNA)

    Nitrogenous base

    Nitrogenous base in DNA:

    i. Guanine

    ii. Adenine

    iii. Thymine

    iv. Cytosine

    Nitrogenous base in RNA:

    i. Guanine

    ii. Adenine

    iii. Uracil

    iv. Cytosine

    Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)

  • Nitrogenous Base

    CH2

    H

    O

    H

    OH H

    H

    H

    OH

    HO P O

    O

    Pentose Sugar ~ deoxyribose

    Phosphate Group

    1

    2 3

    4

    5

    Learning Outcomes : (a) Describe the structure of nucleotide as the basic composition of nucleic acid (DNA and RNA)

    Nitrogenous Base

    CH2

    H

    O

    H

    OH OH

    H

    H

    OH

    HO P O

    O

    Pentose Sugar ~ ribose

    Phosphate Group

    1

    2 3

    4

    5

    deoxyribose ribose

    DNA nucleotide RNA nucleotide

    In a nucleotide :

    nitrogenous base is joined to the 1st carbon of the pentose

    phosphate group is joined to the 5th carbon of the pentose

    Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)

  • 2 nucleotides are combined by condensation process ~ dinucleotide

    Between OH group in phosphate group (of 1 nucleotide) and the OH group at the 3rd carbon in pentose sugar (of the other nucleotide)

    Joined together by phosphodiester bond

    FORMATION OF DINUCLEOTIDE

    Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)

  • FORMATION OF DINUCLEOTIDE

    CH2

    H

    O

    H

    OH H

    H

    H

    OH

    HO P O

    O 1

    2 3

    4

    5

    deoxyribose

    CH2

    H

    O

    H

    OH H

    H

    H

    OH

    HO P O

    O 1

    2 3

    4

    5

    deoxyribose

    CH2

    H

    O

    H

    H

    H

    H

    OH

    HO P O

    O 1

    2 3

    4

    5

    deoxyribose

    CH2

    H

    O

    H

    OH H

    H

    H

    O

    HO P O

    O 1

    2 3

    4

    5

    deoxyribose

    phosphodiester bond

    condensation

    Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)

  • Many nucleotides joined together ~ polynucleotide

    Elongation ~ from 5 to 3

    Forming a backbone with repeating sugar-phosphate units

    Breakdown by hydrolysis process

    5

    3

    FORMATION OF POLYNUCLEOTIDE

    Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)

  • Based on Watson & Crick Model

    DNA Structure

    Learning Outcomes : 1.5 (b) Describe the structure of DNA based on the Watson & Crick Model

  • Consist of 2 polynucleotide chains

    Both polynucleotide chains are twisted to form a double helix

    Each polynucleotide chain is made up of nucleotide

    Nucleotides are joined together by phosphodiester bond

    Each full turn of a double helix has 10 base pairs

    DNA Structure

    Learning Outcomes : 1.5 (b) Describe the structure of DNA based on the Watson & Crick Model

  • 2 polynucleotide chains are arranged in opposite direction (antiparallel)

    One strand ends with a 3 hydroxyl group while the other strand ends with a 5 phosphate group

    5 '

    3 '

    3 '

    5 '

    DNA Structure

    Learning Outcomes : 1.5 (b) Describe the structure of DNA based on the Watson & Crick Model

  • Sugar-phosphate forms the backbone

    The 2 backbones are on the outside, the nitrogenous bases are paired inside the helix

    DNA Structure

    Learning Outcomes : 1.5 (b) Describe the structure of DNA based on the Watson & Crick Model

  • Both chains are held together by hydrogen bonds between complementary base pair;

    Adenine with Thymine, Cytosine with Guanine

    Between Adenine & Thymine ~ 2 hydrogen bonds

    Between Cytosine & Guanine ~ 3 hydrogen bonds

    Specific base-pairing rule ~ the numbers of A=T, G=C

    5 '

    3 '

    3 '

    5 '

    DNA Structure

    Learning Outcomes : 1.5 (b) Describe the structure of DNA based on the Watson & Crick Model

  • Importance:

    As genetic material which carries genetic information that control all activities of a cell

    DNA

    Learning Outcomes : 1.5 (b) Describe the structure of DNA based on the Watson & Crick Model

  • Single stranded polynucleotide

    Pentose sugar ~ ribose

    Nitrogenous bases ~ Guanine, Adenine, Cytosine, Uracil

    3 types:

    RNA

    Messenger RNA (mRNA)

    Transfer RNA (tRNA)

    Ribosomal RNA (rRNA)

    RNA

    Learning Outcomes : 1.5 (c) State the types & function of RNA

  • Function :

    Carries genetic information copied from DNA which act as a template for protein synthesis

    mRNA

    Learning Outcomes : 1.5 (c) State the types & function of RNA

  • Function :

    Forms ribosomal subunits (together with proteins)

    rRNA

    Learning Outcomes : 1.5 (c) State the types & function of RNA

  • Function :

    Transfer specific amino acids to ribosome during protein synthesis

    tRNA

    Learning Outcomes : 1.5 (c) State the types & function of RNA

  • RNA

    Learning Outcomes : 1.5 (c) State the types & function of RNA

  • DNA RNA

    2 polynucleotide chains 1 polynucleotide chain

    pentose sugar ~ deoxyribose pentose sugar ~ ribose

    nitrogenous base ~ G, A, T, C nitrogenous base ~ G, A, C, U

    shape ~ double helix shape ~ linear (mRNA)

    longer chain / larger molecular

    mass

    shorter chain / smaller molecular

    mass

    Only 1 type Has 3 types : mRNA, rRNA &

    tRNA

    Differences between DNA & RNA

    Learning Outcomes : 1.5 (d) State the differences of DNA & RNA

  • Reference

    Campbell N.A & Reece, J.B., Biology, 6th ed. (2002), Pearson Education, Inc.

    Solomon E.P & Berg, L.R, Biology, 7th ed. (2005) Thomson Learning, Inc.

    Mader, S.S Biology, 8th ed. (2004) McGraw-Hill Companies, Inc.