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Biology Notes
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CHAPTER 1: MOLECULES OF LIFE
(7 HRS)
1.0 Molecules Of Life (7 hrs)
1.1 Water (1)
1.2 Carbohydrates (1)
1.3 Lipids (1)
1.4 Proteins (2)
1.5 Nucleic Acids (1)
Learning outcomes
a) Explain the structure of water molecule
b) Describe the properties of water and its importance
Structure:
1 oxygen atom & 2 hydrogen atoms (H2O)
Joined together by sharing electrons ~ covalent bond
3 atoms ~ arranged to form a triangle
Angle ~ 104.5
Learning Outcomes : 1.1 (a) Explain the structure of water molecule
H H
O
Learning Outcomes : 1.1 (a) Explain the structure of water molecule
The sharing of electrons between O & H atoms are not equal
O atom ~ slightly negative charge (-)
H atoms ~ slightly positive charge (+)
Unequal charge distribution within a molecule ~ polar molecule
2-
+ +
O
H H
+ H atom of one water molecule is attracted to the - O atom of nearby water molecules
Water molecules are held together by hydrogen bonds
H bond is weak, represented by dotted lines
2-
+ +
2-
+
+
Hydrogen bond
Learning Outcomes : 1.1 (a) Explain the structure of water molecule
1 water molecule can form maximum of 4 hydrogen bonds with 4 water molecules
Learning Outcomes : 1.1 (a) Explain the structure of water molecule
Learning Outcomes : 1.1 (b) Describe the properties of water and its importance
Properties of water
1. Universal solvent
2. High specific heat capacity
3. High latent heat of vaporization
4. High surface tension
5. Maximum density at 4C
6. Low viscosity
mn
1. Universal Solvent Powerful solvent for ionic & polar substances (eg: NaCl)
NaCl are held together by ionic bonds between Na+ & Cl-
Learning Outcomes : 1.1 (b) Describe the properties of water and its importance
1. Universal Solvent Water is a polar molecule
The O atoms has a slightly negative charge & H atoms has a slightly positive charge
O atoms are attracted to the positively charged sodium ions
H atoms are attracted to the negatively charged chloride ions
Ionic bonds between NaCl molecules become weaker
Learning Outcomes : 1.1 (b) Describe the properties of water and its importance
1. Universal Solvent
Water molecules gather around the Na+ & Cl- to form a hydration shell, separating them from one another
Pulling these ions away from the salt crystal
Causes these ions to separate & dissolve
Learning Outcomes : 1.1 (b) Describe the properties of water and its importance
1. Universal Solvent
Importance:
Act as transport medium for solutes (eg: dissolved nutrients are carried throughout the body in blood plasma)
Water facilitates chemical reaction (solutes are more reactive when dissolved)
Learning Outcomes : 1.1 (b) Describe the properties of water and its importance
2. High specific heat capacity
Definition : amount of energy needed to increase the temperature of 1 g of a substance by 1C
Large amount of energy is needed to increase the temperature of 1 g of water by 1oC
Heat is absorbed to break the H bonds between water molecules
Value = 1 cal/g (most substances have lower value)
A large body of water (ocean/lakes) has a relatively constant temperature although its surrounding temperature changes (temperature rises & falls slowly)
Learning Outcomes : 1.1 (b) Describe the properties of water and its importance
2. High specific heat capacity
Importance:
Organisms can maintain their normal body temperature
Aquatic organisms can live in a relatively stable temperature (protected from rapid temperature changes)
Learning Outcomes : 1.1 (b) Describe the properties of water and its importance
3. High latent heat of vaporization
Definition : Amount of energy needed to change 1 g of a
substance from liquid phase to vapor
A lot of energy is needed to change 1 g of water from
liquid state to vapor
Heat is absorbed to break the H bonds between water
molecules before they can move faster & vaporized
Value = 540 cal/g
Learning Outcomes : 1.1 (b) Describe the properties of water and its importance
Importance:
Cooling effect in organisms due to sweating (animals) or transpiration (plants)
Explanation:
As water absorbs heat, its energy increases
When water evaporates, it takes a lot of heat energy away lowering the temperature of the organism
3. High latent heat of vaporization
Learning Outcomes : 1.1 (b) Describe the properties of water and its importance
4. High surface tension
H bonds make water molecules stick to each other cohesion
On the surface, water has greater attraction for each other than for molecules in the air
Learning Outcomes : 1.1 (b) Describe the properties of water and its importance
4. High surface tension
Water are also pulled downward by other water molecules beneath them
Produce a strong layer on the surface, hard to break the water surface create high surface tension
Water molecules can also stick to other substances adhesion
Learning Outcomes : 1.1 (b) Describe the properties of water and its importance
4. High surface tension
Importance:
Allow some organisms to move on water (eg: water strider)
Learning Outcomes : 1.1 (b) Describe the properties of water and its importance
As water cools, the molecules get closer together
Reach maximum density at 4C
At temperature below 4C, water molecules expand until it freezes/solidifies (at 0C)
5. Maximum density at 4C
Learning Outcomes : 1.1 (b) Describe the properties of water and its importance
5. Maximum density at 4C
H bonds in ice space the water molecules far apart & become stable
Ice is less dense than cold water floats
Learning Outcomes : 1.1 (b) Describe the properties of water and its importance
5. Maximum density at 4C
Importance:
Allow aquatic life to live under the frozen surface of water in cold climate region
Explanation:
The floating layer of ice insulates the water below, prevent them from losing heat & from freezing
Learning Outcomes : 1.1 (b) Describe the properties of water and its importance
6. Low viscosity
Weak H bonds between water molecules are constantly breaking & reforming.
Water molecules can slide easily over each other
It flows with less friction through narrow vessels.
Importance:
Act as medium of transportation in living organisms (eg: blood easily flow in the circulatory system)
Act as a good lubricant to reduce friction within body (eg: mucus facilitates movement of feces through the bowel)
Learning Outcomes : 1.1 (b) Describe the properties of water and its importance
1.0 Molecules Of Life (7 hrs)
1.1 Water (1)
1.2 Carbohydrates (1)
1.3 Lipids (1)
1.4 Proteins (2)
1.5 Nucleic Acids (1)
Learning outcomes
a) Describe various forms & classes of carbohydrates
b) Describe the formation & breakdown of maltose
c) Describe the structures & functions of starch, glycogen and cellulose
Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates
Composed of carbon, hydrogen & oxygen atoms
Ratio of C, H & O ~ approximately 1:2:1 (CH2O)n
n = number of C atoms
Introduction
Classification
Monosaccharide Polysaccharide Disaccharide
1 sugar unit 2 sugar units Many sugar units
Classes of carbohydrates:
Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates
MONOSACCHARIDES
1. Small
2. Sweet
3. Soluble in water
4. Can crystallized
5. White / colourless
6. Reducing sugar
1 sugar molecule; simple sugar (3-7 carbon atoms)
Characteristics:
Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates
Based on the position of functional group
Aldose Ketose Triose 3C Pentose 5C Hexose 6C
Classification
Based on no. of C atom
Classes of monosaccharide:
Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates
Functional group ~ carbonyl group (C=O)
1. Aldose sugar
Carbonyl group is located at the end of carbon chain
Eg: glucose
2. Ketose sugar
Carbonyl group is located in the middle of carbon chain
Eg: fructose
Numbering of carbon chain begins with the carbon nearest to carbonyl group
Classes of monosaccharide: based on the position of functional group
Learning Outcomes : (a) Describe various forms and classes of carbohydrates
Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates
Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates
3 classes:
1. Triose sugar (3 C atoms)
Eg: glyceraldehyde & dihidroxyacetone; C3H6O3
2. Pentose sugar (5 C atoms) will be discussed in nucleic acid
Eg: ribose, ribulose; C5H10O5, & deoxyribose; C5H10O4
3. Hexose sugar (6 C atoms)
Eg: glucose, galactose, fructose; C6H12O6
When dissolved in water, pentose & hexose form ring structure; which is more stable
Classes of monosaccharide: based on the number of carbon atom
Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates
Same molecular formulas but different arrangements of atoms ~ isomers
Glucose ~ blood sugar, moderate sweetness, found in fruits & vegetables
Galactose ~ less sweet, found in milk & yoghurt
Fructose ~ fruit sugar, sweetest, found in fruits & honey
Hexose sugar (6 C atoms)
Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates
Linear and ring forms of glucose. To form the glucose ring, carbon 1 bonds to the oxygen attached to carbon 5.
Glucose
Each of these structure is glucose (C6H12O6)
a. All carbon atoms are clearly shown
b. The carbon atoms are omitted
c. The hydrogen atoms are omitted
Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates
Glucose
2 isomeric forms, according to the position of OH group at C1
above the ring plane = -glucose
below the ring plane = -glucose
Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates
Function of Monosaccharides
Energy source
Glucose ~ major respiratory substrate, primary energy source
Basic building units or monomers for disaccharide & polysaccharide
Learning Outcomes : 1.2 (a) Describe various forms and classes of carbohydrates
DISACCHARIDES
1. Sweet
2. Soluble in water
3. Can crystallized
4. White / colourless
2 sugar molecules or two monosaccharides
Joined together by a condensation process (removal of a water molecule)
Form covalent bond glycosidic bond
Can be broken down into monomers by hydrolysis process (addition of water molecule)
Characteristics:
Disaccharide
Maltose Sucrose Lactose
Learning Outcomes : 1.2 (b) Describe the formation and breakdown of maltose
Condensation
Hydrolysis
CONDENSATION PROCESS
HYDROLYSIS PROCESS
Learning Outcomes : 1.2 (b) Describe the formation and breakdown of maltose
MALTOSE
Malt sugar
Monomers : -glucose + -glucose
Joined together by -1,4 glycosidic bond (between C1 of one glucose molecule and C4 of another molecule)
condensation
hydrolysis
-glucose (C6H12O6)
-glucose (C6H12O6)
Maltose (C12H22O11)
-1,4 glycosidic
bond
+
condensation
hydrolysis
Learning Outcomes : 1.2 (b) Describe the formation and breakdown of maltose
POLYSACCHARIDES
1. Large molecule
2. Not sweet
3. Insoluble in water (form colloid)
Many sugar molecules; polymer (vary in length)
Joined together by condensation process (removal of a water molecules)
Form covalent bond glycosidic bond
Formation of polymer (large molecules made up of repeating units of monomers) polymerization
Can be broken down into monomers by hydrolysis process (addition of water molecules)
Characteristics:
Polysaccharide
Starch Glycogen Cellulose
Amylose Amylopectin
Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose
Energy storage in plants
Plants convert excess glucose into starch for storage in chloroplast
Monomers: -glucose molecules
Broken down by hydrolysis process with the help of amylase enzyme
Starch is a mixture of:
Amylose
Amylopectin
STARCH
Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose
Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose
Monomers: -glucose molecules
Joined together by -1,4 glycosidic bond
Helical, due to the formation of H bonds
Unbranched chain (variable length of monomers)
Folded ~ very compact (ideal for storage)
AMYLOSE
O O
-1,4 glycosidic bond
O O O
OH
OH
CH2OH
1 4
2 3
5
6
OH
CH2OH
1 4
2 3
5
6
OH
OH
CH2OH
4 1
6
2 3
5
OH
OH
CH2OH
4 1
6
2 3
5
OH
-glucose -glucose -glucose -glucose
Monomers: -glucose molecules
Joined together by -1,4 glycosidic bond & -1,6 glycosidic bond
Helical, branched chain (variable length of monomers)
Branches occur within 30 units
Folded & branched ~ very compact (ideal for storage)
AMYLOPECTIN
Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose
AMYLOPECTIN
O O O O O
OH
OH
CH2OH
1 4
2 3
5
6
OH
CH2OH
1 4
2 3
5
6
OH
OH 4 1
6
2 3
5
OH
OH
CH2OH
4 1
6
2 3
5
OH
-glucose -glucose -glucose -glucose
OH
OH
CH2OH
4 1
6
2 3
5
OH
OH
CH2OH
4 1
6
2 3
5
O O
C H H
-1,4 glycosidic bond
-1,6 glycosidic bond
O
Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose
DIFFERENCES BETWEEN AMYLOSE &
AMYLOPECTIN
Features Amylose Amylopectin
Monomers -glucose -glucose
Bond
-1,4 glycosidic bond -1,4 glycosidic bond
-1,6 glycosidic bond
Shape Helical, unbranched Helical, branched (within
30 units)
Function
Ideal for energy storage
(insoluble, coiled, compact)
Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose
Energy storage in animals (in liver & muscle)
Structure ~ similar to amylopectin
More branched than amylopectin
GLYCOGEN
Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose
Major component of plant cell wall
Monomers: -glucose
Bond: -1,4 glycosidic bond
Broken down by hydrolysis with the help of cellulase enzyme
Unbranched, long straight chain
CELLULOSE
O O
-1,4 glycosidic bond
O
OH
OH
CH2OH
1 4
2 3
5
6
OH
CH2OH
1 4
2 3
5
6
OH
OH
CH2OH
4 1
6
2 3
5
OH
OH
CH2OH
4 1
6
2 3
5
OH
-glucose -glucose -glucose -glucose
Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose
CELLULOSE
-1,4 glycosidic bond
Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose
Straight chains are arranged parallel to one another
Linked together by hydrogen bonds (form microfibril)
Very stable & tough structure ~ provide support to plant cell
CELLULOSE
Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose
Functions of Polysaccharides
Energy Storage ~ eg: starch (in plant) & glycogen (in animals)
Major component of cell walls ~ provide structural support to
plant cell ~ eg: cellulose
Learning Outcomes : 1.2 (c) Describe the structures and functions of starch, glycogen and cellulose
1.0 Molecules Of Life (7 hrs)
1.1 Water (1)
1.2 Carbohydrates (1)
1.3 Lipids (1)
1.4 Proteins (2)
1.5 Nucleic Acids (1)
Learning outcomes
a) State the types of lipid
b) Describe the structure of glycerol & fatty acids
c) Describe the formation & breakdown of triglycerides
Learning Outcomes : 1.3 (a) State the types of lipid: fats, phospholipids and steroids
LIPIDS
Fats Steroids Phospholipids
Consist of mainly carbon & hydrogen atoms; few oxygen atom
Group of hydrophobic molecules ~ insoluble in water
3 major types:
LIPIDS
Eg: oil, butter Eg: lecithin Eg: cholesterol
Learning Outcomes : 1.3 (a) State the types of lipid: fats, phospholipids and steroids
Building block
1 Glycerol 3 Fatty acids
Saturated Unsaturated
Most abundant
Also known as (a.k.a) : Triglyceride / Triacylglycerol
FATS
a) Structure of glycerol and b) general structure of fatty acids
Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids
.
A.k.a : glycerine
3C alcohol with 3 OH groups (soluble in water)
C
C
C
OH
OH
OH
H
H
H
H
H
Glycerol
.
Fatty Acids
Has 2 regions:
Hydrophilic head (a carboxyl group, COOH at 1 end ) ~ acid
Hydrophobic tail ~ long unbranched hydrocarbon chain (known as side chain, R)
HO C1
O
C2 C3 C4 C5 C6 C7 C8 C9 C10 C11 C12 C13 C14
H H H H H H H H H H H H H
H H H H H H H H H H H H H
H
Carboxyl group Hydrocarbon chain
R
Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids
. Hydrophobic tail vary in length
Different fatty acids has different number of C atoms (usually 16 or 18)
C2 HO C3 C4 C5 C6 C7 C8 C9 C1
H H H H H H H O
H H H H H H H H
C10
H H
C11 C12 C13 C15 C14
H H H H H
H H H H
C16 C18 C17
H H H
H H H
H
H H
Eg: Stearic acid (stearate) C18H36O2
Fatty Acids
Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids
. Based on the presence of double bonds within hydrocarbon
chain:
Saturated fatty acids
~ no double bond between C atoms; eg: stearic acid
Unsaturated fatty acids
~ has double bonds between C atoms; eg: oleic acid
C2 HO C3 C4 C5 C6 C7 C8 C9 C1
H H H H H H H O
H H H H H H H H
C10
H H
C11 C12 C13 C15 C14
H H H H H
H H H H
C16 C18 C17
H H H
H H H
H
H H
Eg: Stearic acid (stearate) C18H36O2
Classification of Fatty Acids
Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids
. Has maximum number
of H atoms
Straight chain, fatty acids can be closely packed
Solid at room temperature
SATURATED FATTY ACID
Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids
.
SATURATED FATTY ACID
Fats that consist of saturated fatty acids ~ saturated fat
Mostly animal fats (eg: butter, lard)
Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids
SATURATED FATTY ACID
Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids
Double bond causes
bending in
unsaturated fatty
acids
Fatty acids cannot be
closely packed
Liquid at room
temperature
UNSATURATED FATTY ACID
Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids
UNSATURATED FATTY ACID
Fats that consist of unsaturated fatty acids ~ unsaturated fat
Mostly plant & fishes fats (eg: oil)
Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids
Fatty acids stearic acid (saturated fat) and oleic acid (unsaturated fat).
. Based on the ability to be synthesized in the body:
Essential fatty acids
~ cannot be synthesized in the body
~ must be present in the diet
~ eg: linoleic, linolenic and arachidonic acids
Non-essential fatty acids
~ can be synthesized in the body
~ eg: stearic acid & others
Classification of Fatty Acids
Learning Outcomes : 1.3 (b) Describe the structure of glycerols and fatty acids
PHOSPHOLIPIDS
Building block
1 Glycerol 2 Fatty acids Phosphate group
Major component of cell membrane; eg: lecithin
Amphipathic molecule
i.e one end hydrophilic polar, another end hydrophobic non-polar
Learning Outcomes : 1.3 (a) State the types of lipid: fats, phospholipids and steroids
Learning Outcomes : 1.3 (a) State the types of lipid: fats, phospholipids and steroids
PHOSPHOLIPIDS
Composed of 3 fatty acids & 1 glycerol backbone
Fats are formed when 3 condensation reaction occurs ~ also
known as esterification
Water is removed by extracting the OH from the carboxyl
group (of fatty acid) and H from the glycerols hydroxyl group
Triglyceride can be broken down by hydrolysis
TRIGLYCERIDE
Learning Outcomes : 1.3 (c) Describe the formation & breakdown of triglycerides
Learning Outcomes : 1.3 (c) Describe the formation & breakdown of triglycerides
Formation of Triglycerides
C OH H
H
H
R HO
O
C
C OH H
C OH H
R HO
O
C
R HO
O
C
C O H
H
H
R
O
C
C O H
C O H
R
O
C
R
O
C
1 glycerol 3 fatty acids
Condensation
Triglyceride
+ 3H2O
Hydrolysis
Ester bond
Ester bond
Ester bond
Importance of Lipids
Main energy storage in animals (due to higher number of
hydrogen atom)
1 g of fat has > twice energy than same weight of starch
Lighter ~ hydrophobic nature, doesnt associates with
water
Improve buoyancy in aquatic animals
Provide better thermal insulation of mammals
Act as padding for internal organs
Phospholipid ~ major component of plasma membrane
Steroid ~ some are hormones that regulates metabolism
Learning Outcomes : 1.3 (c) Describe the formation & breakdown of triglycerides
1.0 Molecules Of Life (7 hrs)
1.1 Water (1)
1.2 Carbohydrates (1)
1.3 Lipids (1)
1.4 Proteins (2)
1.5 Nucleic Acids (1)
Learning outcomes
a) Describe the basic structure of amino acids
b) Explain how amino acids are grouped
c) Describe the formation and breakdown of dipeptide
d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved
e) Classify proteins according to their structure
f) Explain the effect of pH & temperature on the structure of protein
Learning Outcomes : 1.4 (a) Describe the basic structure of amino acids
PROTEIN
Polymer
Building blocks ~ amino acids
Joined together to form a long chain ~ polypeptide
Protein consist of 1 or more polypeptide chains which folded & coiled into specific conformation
Mostly composed of C, H, O, N & sometimes S
BASIC STRUCTURE OF AMINO ACIDS
C H2N COOH
R
H
Amino acids consist of 4 components attached to a central carbon
These components include:
a. a hydrogen atom
b. a carboxyl group
c. an amino group
d. a variable R group (or side chain).
amino group carboxyl group
Learning Outcomes : 1.4 (a) Describe the basic structure of amino acids
BASIC STRUCTURE OF AMINO ACIDS
i. COOH (carboxyl group)
ii. NH2 (amino group) : basic
: acidic
C H2N COOH
R
H
2 functional groups:
amino group carboxyl group
Amino acids are amphoteric; have both acidic & basic properties
Learning Outcomes : 1.4 (a) Describe the basic structure of amino acids
Learning Outcomes : 1.4 (b) Explain how amino acids are grouped
20 types of amino acids commonly found in proteins
All have the same basic structure but differ in the side chain, R
Amino acids are grouped based on the properties of R group
GROUP OF AMINO ACIDS
C H2N COOH
R
H
amino group carboxyl group
Serine (ser)
Aspartic acid (asp)
Lysine (Lys)
Glycine (gly)
4 groups
Non-polar Basic Polar Acidic
Hydrophilic Has COOH group Has NH2 group Hydrophobic
Learning Outcomes : 1.4 (b) Explain how amino acids are grouped
i. Essential amino acids (for human)
Cannot be synthesized in sufficient amount, must be
obtained through food or supplement intake
8 amino acids; eg: isoleucine, leucine, lysine, methionine,
phenylalanine, threonine, tryptophan, valine
For infants : histidine
ii. Non-essential amino acids
Can be synthesized in the body
Eg: alanine, arginine, asparagine, aspartic acid, cysteine,
glutamic acid, glycine, proline, serine, tyrosine, glutamine
GROUP OF AMINO ACIDS
Learning Outcomes : 1.4 (b) Explain how amino acids are grouped
Learning Outcomes : 1.4 (c) Describe the formation and breakdown of dipeptide
2 amino acids are joined by condensation process to form a dipeptide
By removal of a hydroxyl group from the carboxyl end of one amino acid and a hydrogen from the amino group of another amino acid.
Form a covalent bond ~ peptide bond
Formation of the dipeptide
Learning Outcomes : (c) describe the formation and breakdown of dipeptide
OH C N C
O R1
H
H
H
H C N C OH
O R2
H H
Peptide bond
C N C
O R1
H
H
H
C N C OH
O R2
H H
H2O
Condensation
H2O
Hydrolysis
C-terminal N-terminal
Formation & breakdown of the dipeptide
Learning Outcomes : 1.4 (c) Describe the formation and breakdown of dipeptide
Dipeptide is hydrolysed into 2 amino acids by hydrolysis process (addition of water).
Peptide bond is broken down and produces 2 amino acids.
Breakdown of dipeptide
Learning Outcomes : 1.4 (c) Describe the formation and breakdown of dipeptide
Many amino acids are joined by condensation process to form a polypeptide
Bond ~ peptide bonds
Polypeptide backbone ~ repeated sequence of (-N-C-C-)
Formation of polypeptide
OH H C N C
O R2
H H
H C N C OH
O R3
H H
Peptide bond
H OH C N C
O R1
H H
Peptide bond
Learning Outcomes : 1.4 (c) Describe the formation and breakdown of dipeptide
Formation of tripeptide
Learning Outcomes : 1.4 (c) Describe the formation and breakdown of dipeptide
Two ways based on:-
Level of protein structure
i. Primary
ii. Secondary
iii. Tertiary
iv. Quaternary
Structure
i. Fibrous
ii. Globular
iii. Conjugated
Classification of Protein
Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved
Learning Outcomes : (d) explain primary, secondary, tertiary and quaternary levels of proteins and the types of bonds involved
Learning Outcomes : (d) explain primary, secondary, tertiary and quaternary levels of proteins and the types of bonds involved Learning Outcomes :
1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved
Primary structure
Refers to the linear sequence of amino acids joined by peptide bonds within a polypeptide chain
Each protein has a unique sequence of amino acids, determined by specific DNA code
Different sequence results in the formation of different bonds between amino acids
Causes a polypeptide chain to fold & coil into a unique 3 dimensional shape of protein
Eg : lysozyme & all protein that has been sequenced
Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved
Primary structure
Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved
Secondary structure
Linear chain of amino acids will coil or fold spontaneously
Due to the formation of H bonds between the backbones (between H of the NH groups & O of the C=O groups of amino acids in the primary chain)
2 types
-helix
-pleated sheet
Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved
Secondary structure
Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved
-helix
Helical coil
H bonds is formed between 1 amino acid & the 4th amino acid away from it
Can stretch under tension ~ provide elasticity
Because the hydrogen bonds can be reformed
Eg: keratin in hair, nails & wool
| S |
S |
| S |
S |
Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved
-pleated sheet
Zig-zag pattern ~ provide strength & flexibility
Eg: silk, spider web
Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved
Tertiary structure
1 polypeptide chain in secondary structure may further coiled into a globular shape which is maintained by bonds and interactions among R groups
Globular shape unique to each polypeptide chain
Mantained by 4 interactions between R groups:-
Disulfide bonds (covalent bonds) between R groups with sulfhydryl groups
Ionic bonds between +ve & -ve charged R groups
Hydrogen bonds between + & - charged R groups
Hydrophobic / Van der Waals interaction between non-polar R groups
Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved
Tertiary structure
Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved
Features Primary Secondary Tertiary
Type of
bond exist
i. Peptide
bond
i. Peptide bond
ii. H bond (between
C=O & NH group of
backbone)
i. Peptide bond
ii. H bond (between C=O
& NH group of
backbone)
iii. Disulfide bond
iv. Ionic bond
v. H bond (between R
groups)
vi. Hydrophobic (van der
Waals) interaction
Tertiary structure
Eg: enzymes, hormones, antibodies
Type of bonds exist in different levels of protein:
Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved
Quaternary structure
Refers to a single protein that is formed when two or more polypeptide chain joins
Bonds exist ~ same as tertiary structure
Eg: hemoglobin (consist of 4 polypeptide chains, two chains and two chains)
Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved
4 Levels of Protein
Learning Outcomes : 1.4 (d) Explain primary, secondary, tertiary & quaternary levels of proteins & the types of bonds involved
Classification of Protein
FIBROUS
Mostly secondary structure
Form long parallel filaments or strands
Insoluble & stable
Function : mechanical & structural support
Eg:
Keratin, actin, myosin, collagen, silk
Fibrous Globular Conjugated
Based on Structure
Learning Outcomes : 1.4 (e) Classify proteins according to their structure
Globular Protein
Mostly tertiary/quaternary structure
Folded to form compact spherical shaped
Relatively unstable
Relatively soluble ~ colloid
Function : metabolic & chemical process
Eg:
Enzyme
Antibodies
Hormone
Hemoglobin
Learning Outcomes : 1.4 (e) Classify proteins according to their structure
Conjugated Proteins
Conjugated Protein Prosthetic group Location
Glycoprotein Polysaccharide Component of cell membrane
Mucin (in saliva)
Lipoprotein Lipid Component of cell membrane
Lipid transported in blood
plasma
Chromoprotein Pigment Myoglobin, hemoglobin
Nucleoprotein Nucleic acid Chromosome, ribosome
Protein that can function well if it joins with other compound
Non-protein compound ~ prosthetic group
Learning Outcomes : 1.4 (e) Classify proteins according to their structure
Effect of pH and Temperature
Structure of protein is affected by:-
1. pH
2. temperature
Globular protein is relatively unstable because it is maintained
by weak ionic bonds, hydrogen bonds & hydrophobic
interactions
When protein is heated or exposed to an extreme pH
changes, those bonds are broken
Causes it to uncoiled & change its conformation
Lose its biological function ~ denatured protein coagulate
Usually irreversible (sometimes, renaturation may occur)
Learning Outcomes : 1.4 (f) Explain the effect of pH and temperature on the structure of protein
Factor Effect to the protein structure
Heat or radiation Increased kinetic energy
Protein atoms vibrate
H & ionic bonds, van der Waals interaction break
Strong acids & alkali
H & ionic bonds, van der Waals interaction break
Breakdown of peptide bonds occur if exposed very long
Effect of pH and Temperature
Learning Outcomes : 1.4 (f) Explain the effect of pH and temperature on the structure of protein
1.0 Molecules Of Life (7 hrs)
1.1 Water (1)
1.2 Carbohydrates (1)
1.3 Lipids (1)
1.4 Proteins (2)
1.5 Nucleic Acids (1)
Learning outcomes
a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA & RNA)
b) Describe the structure of DNA based on the Watson & Crick Model
c) State the types & function of RNA
d) State the differences of DNA & RNA
Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)
Nucleic acid is polynucleotide ~ polymer of nucleotides
Building blocks ~ nucleotide
Mostly composed of C, H, O, P & N
Introduction
NUCLEIC ACIDS
2 types
Deoxyribonucleic Acid (DNA)
Ribonucleic Acid (RNA)
Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)
Structure of nucleotides
Each nucleotide has 3 components:-
Nucleotide
Pentose sugar Phosphate group Nitrogenous base
Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)
Ribose (in RNA)
Deoxyribose (in DNA)
Pentose Sugar (5 C sugars)
Ribose ~ component of RNA nucleotide
Deoxyribose ~ component of DNA nucleotide
At 2nd carbon atom ~ in deoxyribose; one H atom
~ in ribose; one OH group
C5H10O4 C5H10O5
Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)
Nitrogenous base
Based on the number of C ring
2 groups
Pyrimidine Purine
Cytosine (C) Uracil (U) Thymine (T) Adenine (A) Guanine (G)
Single ring Double rings
In RNA In DNA
Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)
Learning Outcomes : (a) Describe the structure of nucleotide as the basic composition of nucleic acid (DNA and RNA)
Nitrogenous base
Nitrogenous base in DNA:
i. Guanine
ii. Adenine
iii. Thymine
iv. Cytosine
Nitrogenous base in RNA:
i. Guanine
ii. Adenine
iii. Uracil
iv. Cytosine
Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)
Nitrogenous Base
CH2
H
O
H
OH H
H
H
OH
HO P O
O
Pentose Sugar ~ deoxyribose
Phosphate Group
1
2 3
4
5
Learning Outcomes : (a) Describe the structure of nucleotide as the basic composition of nucleic acid (DNA and RNA)
Nitrogenous Base
CH2
H
O
H
OH OH
H
H
OH
HO P O
O
Pentose Sugar ~ ribose
Phosphate Group
1
2 3
4
5
deoxyribose ribose
DNA nucleotide RNA nucleotide
In a nucleotide :
nitrogenous base is joined to the 1st carbon of the pentose
phosphate group is joined to the 5th carbon of the pentose
Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)
2 nucleotides are combined by condensation process ~ dinucleotide
Between OH group in phosphate group (of 1 nucleotide) and the OH group at the 3rd carbon in pentose sugar (of the other nucleotide)
Joined together by phosphodiester bond
FORMATION OF DINUCLEOTIDE
Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)
FORMATION OF DINUCLEOTIDE
CH2
H
O
H
OH H
H
H
OH
HO P O
O 1
2 3
4
5
deoxyribose
CH2
H
O
H
OH H
H
H
OH
HO P O
O 1
2 3
4
5
deoxyribose
CH2
H
O
H
H
H
H
OH
HO P O
O 1
2 3
4
5
deoxyribose
CH2
H
O
H
OH H
H
H
O
HO P O
O 1
2 3
4
5
deoxyribose
phosphodiester bond
condensation
Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)
Many nucleotides joined together ~ polynucleotide
Elongation ~ from 5 to 3
Forming a backbone with repeating sugar-phosphate units
Breakdown by hydrolysis process
5
3
FORMATION OF POLYNUCLEOTIDE
Learning Outcomes : 1.5 (a) Describe the structure of nucleotide as the monomer of nucleic acid (DNA and RNA)
Based on Watson & Crick Model
DNA Structure
Learning Outcomes : 1.5 (b) Describe the structure of DNA based on the Watson & Crick Model
Consist of 2 polynucleotide chains
Both polynucleotide chains are twisted to form a double helix
Each polynucleotide chain is made up of nucleotide
Nucleotides are joined together by phosphodiester bond
Each full turn of a double helix has 10 base pairs
DNA Structure
Learning Outcomes : 1.5 (b) Describe the structure of DNA based on the Watson & Crick Model
2 polynucleotide chains are arranged in opposite direction (antiparallel)
One strand ends with a 3 hydroxyl group while the other strand ends with a 5 phosphate group
5 '
3 '
3 '
5 '
DNA Structure
Learning Outcomes : 1.5 (b) Describe the structure of DNA based on the Watson & Crick Model
Sugar-phosphate forms the backbone
The 2 backbones are on the outside, the nitrogenous bases are paired inside the helix
DNA Structure
Learning Outcomes : 1.5 (b) Describe the structure of DNA based on the Watson & Crick Model
Both chains are held together by hydrogen bonds between complementary base pair;
Adenine with Thymine, Cytosine with Guanine
Between Adenine & Thymine ~ 2 hydrogen bonds
Between Cytosine & Guanine ~ 3 hydrogen bonds
Specific base-pairing rule ~ the numbers of A=T, G=C
5 '
3 '
3 '
5 '
DNA Structure
Learning Outcomes : 1.5 (b) Describe the structure of DNA based on the Watson & Crick Model
Importance:
As genetic material which carries genetic information that control all activities of a cell
DNA
Learning Outcomes : 1.5 (b) Describe the structure of DNA based on the Watson & Crick Model
Single stranded polynucleotide
Pentose sugar ~ ribose
Nitrogenous bases ~ Guanine, Adenine, Cytosine, Uracil
3 types:
RNA
Messenger RNA (mRNA)
Transfer RNA (tRNA)
Ribosomal RNA (rRNA)
RNA
Learning Outcomes : 1.5 (c) State the types & function of RNA
Function :
Carries genetic information copied from DNA which act as a template for protein synthesis
mRNA
Learning Outcomes : 1.5 (c) State the types & function of RNA
Function :
Forms ribosomal subunits (together with proteins)
rRNA
Learning Outcomes : 1.5 (c) State the types & function of RNA
Function :
Transfer specific amino acids to ribosome during protein synthesis
tRNA
Learning Outcomes : 1.5 (c) State the types & function of RNA
RNA
Learning Outcomes : 1.5 (c) State the types & function of RNA
DNA RNA
2 polynucleotide chains 1 polynucleotide chain
pentose sugar ~ deoxyribose pentose sugar ~ ribose
nitrogenous base ~ G, A, T, C nitrogenous base ~ G, A, C, U
shape ~ double helix shape ~ linear (mRNA)
longer chain / larger molecular
mass
shorter chain / smaller molecular
mass
Only 1 type Has 3 types : mRNA, rRNA &
tRNA
Differences between DNA & RNA
Learning Outcomes : 1.5 (d) State the differences of DNA & RNA
Reference
Campbell N.A & Reece, J.B., Biology, 6th ed. (2002), Pearson Education, Inc.
Solomon E.P & Berg, L.R, Biology, 7th ed. (2005) Thomson Learning, Inc.
Mader, S.S Biology, 8th ed. (2004) McGraw-Hill Companies, Inc.