Dieu Khien Tu Dong - Ngan Hang de Thi

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  • 7/31/2019 Dieu Khien Tu Dong - Ngan Hang de Thi

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 1

    NGN HNG THIMn: CSIU KHIN TNG

    Dng cho hHTX, ngnhin t- Vin thngS tn ch: 3

    CHNG 1. M T TON HC H THNG IU KHIN TNG /Chohthngiukhincskhinhhnhv,tnhiu l

    Tnhiuvo Tnhiura Tnhiuphnhi Tnhiuiukhin /Chohthngiukhincskhinhhnhv,khiCsthhin:

    itngiukhin Biukhin Thitbo Khngcvaitrrrng /Hthngtuyntnhlhthngm: Chaikhultuyntnh Cmtkhultuyntnh Ttccctnhiutronghthngltuyntnh Ttccckhutronghthngultuyntnh /Sailchtnhlsailchcahthngtrngthixclp,nghaysai? ng sai /trngthixclp,sailchtnhl: Sailchgiatnhiuchovtnhiuiukhin Sailchgiatnhiuovtnhiucho

    HC VIN CNG NGH BU CHNH VIN THNG

    Km10 ng Nguyn Tri, H ng-H Ty

    Tel: (04).5541221; Fax: (04).5540587Website: http://www.e-ptit.edu.vn; E-mail: [email protected]

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 2

    Sailchgiatnhiuovtnhiuiukhin Sailchgiatnhiuchovtnhiuo /NghimathctscaPTTcgilccimkhng(zero)? ng Sai

    /NghimathcmuscaPTTcgil? Ccimun Ccimcc Ccimcctr Ccimkhng

    /Hthngcmtnhhnhvtngngvitrnghp 1D = khimtntrongkhnggiantrngthi?

    ng Sai /Hmtruyntcahthngtronghnhtrn?

    ( )( )

    ( )1h

    kh

    W pW p

    W p=

    +

    ( )( )

    1

    1k

    h

    W pW p

    =+

    ( )( )

    ( )21h

    k

    h

    W pW p

    W p=

    +

    ( ) ( )( )1

    hkh

    W pW pW p

    =

    /Hthngphituyncthpdngnguynlxpchng? ng Sai

    /ctnhbintnlogarithmcxcnhtheocngthcnosauyvi ( )A lctnhbintn?

    ( ) ( )30lgL A =

    ( ) ( )lgL A =

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 3

    ( ) ( )20lgL A =

    ( ) ( )10lgL A =

    /Tmhmtruynttngngcagraphtronghnhtrn?

    1 2.W W

    1 2W W

    1 2W W

    1 2W W+

    /athcctrngcahthngl: Milinhgiatnhiuravtnhiuvocahthng Lmuscahmtruyntcaitngiukhin Muscahmtruynt Tscahmtruynt

    /BiniLaplacecahm ( )1 t ? p

    21 p

    1

    1 p

    /BiniLaplacecahm ( )t ?

    21 p

    1 p 1

    p

    /Hthngcmttrongkhnggiantrngthidng:

    Ax Bu

    y Cx Du

    = +

    = +

    trong ,x x l: Ccvectorbintrngthi uvo Ccmatrnbintrngthi ura

    /Mththngiukhintnggmnhngthnhphncbnno? itngiukhin,thitbiukhinvthitbolng Thitbiukhin,thitbolng itngiukhin,thitbiukhin

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 4

    itngiukhin,thitbolng /Tnhiuiukhincamththngiukhintngcphnhiml: Gitrmongmun Gitroc Sailchgiagitrmongmunvgitroc

    Tnggiagitrmongmunvgitroc /Hmtruyntcahthngl: TsgiatnhiuravtnhiuvocahthngbiudintheobiniLaplaceviiukinukhngi Tsgiatnhiuravtnhiuvocahthng Tsgiatnhiuravtnhiuvocahthngbiudintheothigian TsgiatnhiuravtnhiuvocahthngbiudintheobiniLaplaceviiukinutrittiu /Scutrctrngthicahlintctronghnhtrncdngbiudinh

    thngcmttheophngtrnhtrngthitheodngnosauy?

    Ax Bu

    y Cx Du= += +

    Ax Bu

    y Dx Cu

    = +

    = +

    Dx Bu

    y Cx Au

    = +

    = +

    Bx Au

    y Cx Du

    = +

    = +

    /Graphtnhiunhhnhtrnbiuthhmtruynt ijWbngbaonhiu?

    ij i jW X X= +

    ij j iW X X=

    ij i jW X X=

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 5

    ij i jW X X=

    /Tmhmtruynttngngcagraphtronghnhtrn?

    1 2

    1 2

    .

    1 .

    W W

    W W+

    1

    1 21 .

    W

    W W+

    1 2

    1 21 .

    W W

    W W

    +

    +

    2

    1 21 .

    W

    W W+ /Du?tronghnhtrnchmtruynt?

    2 3U U

    2U

    2U

    3 2U U

    /Hmtruyntcahnhhnhtrn?

    1 2 3. .W W W W =

    1 2 3W W W W = + +

    2

    1 2 3

    WW

    W W W=

    + +

    1

    2 3

    WW

    W W=

    +

    /Hmtruyntcahnhhnhtrn?

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 6

    2

    1 2 3

    WW

    W W W=

    + +

    1

    2 3

    WW

    W W=

    +

    1 2 3. .W W W W =

    1 2 3

    W W W W = + +

    /Du?tronghnhtrnlgchngtngngnhau?

    1 W

    2W

    2W

    W /ctnhbintn(BT)cahthngcxcnhtheocngthcnodiyvi:

    ( ) ( ),R I

    lnltlphnthc,phnocahmtruyntnscah?

    ( ) ( ) ( )A R I = +

    ( ) ( ) ( )2 2A R I =

    ( ) ( ) ( )A R I =

    ( ) ( ) ( )2 2A R I = +

    /ctnhphatn(PT)cahthngcxcnhtheocngthcnodiyvi:

    ( ) ( ),R I

    lnltlphnthc,phnocahmtruyntnscah?

    ( ) ( )

    ( )arg R

    I

    =

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 7

    ( )( )( )

    argI

    R

    =

    ( )( )( )

    argI

    R

    =

    ( ) ( )

    ( )arg R

    I

    =

    /Du?tronghnhtrnlgchngtngngnhau?

    2

    W 2W

    W

    1 W /Du?tronghnhtrnlgchngtngngnhau?

    1 W

    W

    2W

    2

    W /Du?tronghnhtrnlgchngtngngnhau?

    2W

    2

    W

    1 W

    W

    /Tmhmtruyntcahthngtronghnhtrn?

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 8

    3 1 313

    1 21

    X W WWX W

    = =

    3 1 313

    1 21

    X W WW

    X W

    += =

    3 1 313

    1 21

    X W WW

    X W= =

    3 1 313

    1 21

    X W WW

    X W= =

    +

    /BiniLaplaceca ( )1 1p p + ?

    1t

    e

    1te+

    1t

    e

    1te

    /Hmtruyntcahthngtronghnhtrn?

    2 3 4

    1 2 5 1 2 3 4

    . .

    1 . . . . .

    W W W

    W W W W W W W + +

    1 2 3

    1 2 5 1 2 3 4

    . .

    1 . . . . .

    W W W

    W W W W W W W + +

    1 3 4

    1 2 5 1 2 3 4

    . .

    1 . . . . .

    W W W

    W W W W W W W + +

    1 2 3 4

    1 2 5 1 2 3 4

    . . .

    1 . . . . .

    W W W W

    W W W W W W W + + /Theonhltihn(nutnti)trongbiniLaplace,iunosauylng?

    ( ) ( )0 lim .

    p

    x t p X p

    = =

    ( ) ( )0 limp

    x t X p

    = =

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 9

    ( ) ( )20 lim .p

    x t p X p

    = =

    ( ) ( )0

    0 lim .p

    x t p X p

    = =

    /Theonhltihn(nutnti)trongbiniLaplace,iunosauylng?

    ( ) ( )0

    limp

    x t X p

    = =

    ( ) ( )0

    lim .p

    x t p X p

    = =

    ( ) ( )lim .p

    x t p X p

    = =

    ( ) ( )2

    0

    lim .p

    x t p X p

    = =

    /Hmtruyntcahthngtronghnhtrn?

    ( ) 1 32 3 1 21

    W WW p

    W W W W =

    + +

    ( ) 1 2 3

    2 3 1 21W W WW p

    W W W W = + +

    ( ) 2 32 3 1 21

    W WW p

    W W W W =

    + +

    ( ) 1 22 3 1 21

    W WW p

    W W W W =

    + +

    / 3 1X X

    tronghnhtrnbngbaonhiu?

    3 113

    1 21

    X WW

    X W= =

    3 1 313

    1 21

    X W WW

    X W= =

    +

    3 313

    1 21

    X WW

    X W

    = =

    3 1 313

    1 21

    X W WW

    X W= =

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 11

    CHNG 2. C TNH NG HC CA CC KHU CBN

    /ctnhtnhcaphntlmiquanhgiatnhiuravtnhiuvocaphnttrngthixclp? Sai ng

    /PhngtrnhviphnbiudinkhunguynhmviKlhstruyncaphnt?

    y K x=

    y x K=

    y Kx=

    1y Kx=

    /Phngtrnhviphnbiudinkhutchphnvi iT lhngsthigiantchphn?

    iy T dx=

    .iy T x dt=

    1

    i

    y dxT

    =

    1.

    i

    y x dtT

    =

    /Phngtrnhviphnbiudinkhuviphnvi dT lhngsthigianviphn?

    2d

    dxy T

    dt=

    1

    d

    dxy

    T dt=

    d

    dxy T

    dt=

    2d

    dxy T

    dt=

    /Muntmhmtruynttnscahthnghocphnt,tathaybin p bngbaonhiuvohmtruyntcan?

    j

    je

    j /Khitnhtheodecibel,ctnhbintnlogarithm(BTL)cxcnhtheocngthcno?

    ( ) ( )10lgL A =

    ( ) ( )lgL A =

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 12

    ( ) ( )2lgL A =

    ( ) ( )20lgL A =

    /Cckhunghccbnctnhchtnosauy? Cnhiutnhiuvovnhiutnhiura

    Cnhiutnhiuvovmttnhiura Cmttnhiuvovnhiutnhiura Chcmttnhiuvovmttnhiura /Nuhmqucakhukhuchi:

    ( ) ( ).1h t k t =

    thhmtrnglng ( )k t bngbaonhiu? k

    ( ) ( ).k t k t =

    ( ) .k t k t =

    ( ) ( ).1k t k t =

    /Tnhiubcthangnvcthcbiudinnhhnhtrn?

    Sai ng /Tnhiuxungnv(xungDiract)cthcbiudinnhhnhtrncngkhng?

    ng Sai /Vctnhbintnlogarithmbngcchtuyntnhhatngon? ng Sai /Trongkhutchphn,ctnhphatncgitrbngbaonhiu?

    2

    4

    2

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 13

    /Hm( )t

    ?

    Lhmxungnvcphttithiim t = Lhmbcthangnvcphttithiim t = Lhmbcthangnvcphttithiim t =

    Lhmxungnvcphttithiimt =

    /Khutchphnccimg? Ctnhchtnh

    Tnhiurasmphahntnhiuvomtgc 2 Cbacimtrn Khuchitnhiuvolnkln

    /Nukhudaongbc2chscndu 1 > thnsthhintnhchtgcakhudaong?

    Khudaongdaongvibinkhngi Daongrtmnhvbnhthnghsnythng

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 14

    /Hmtrnglnglphnngcaphntkhitnhiutcnguvol ( )t ,

    nuhmtruyntcaphntl ( )W p thhmquctnhtheocngthcno?

    ( )

    ( )

    2

    1L h t

    W p=

    ( )

    ( )W pL h t

    p=

    ( ) ( )L h t W p=

    ( )( )1

    L h tW p

    =

    /Trongkhukhuchi,miquanhvphagiatnhiuvovtnhiural? Haitnhiuvovralngphavinhau Tnhiuvosmphahnsovitnhiuramtgcl

    Tnhiuvochmphahnsovitnhiuramtgcl 2 Tnhiuvosmphahnsovitnhiu /Trongkhutchphn,miquanhvphagiatnhiuvovtnhiural? Tnhiuvosmphahnsovitnhiuramtgcl

    Tnhiuvochmphahnsovitnhiuramtgcl 2

    Tnhiuvosmphahnsovitnhiuramtgcl 2 Haitnhiuvovralngphavinhau

    /Trongkhuviphn,miquanhvphagiatnhiuvovtnhiural?

    Tnhiuvosmphahnsovitnhiuramtgcl 2 Tnhiuvosmphahnsovitnhiuramtgcl

    Tnhiuvochmphahnsovitnhiuramtgcl 2 Haitnhiuvovralngphavinhau /Khivctnhbintnlogarithm,tnsctcxcnhtheocngthcno?

    1c T =

    21

    cT =

    cT =

    20.logc T =

    /ctnhbintnlogarithmcamtkhu ( ) 0L < khino?

    ( ) 0A

    ( )A =

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 16

    ( )3 2

    10 4

    8 5h

    pW p

    p p

    +=

    + Chobithhgmnhngkhucbnno? Mtkhutchphn,haikhuquntnhbc1vmtkhuviphn Haikhutchphn,haikhuquntnhbc1vmtkhuviphn Haikhutchphn,mtkhuquntnhbc1vhaikhuviphn Haikhutchphn,mtkhuquntnhbc1vmtkhuviphnbc1 /Viiukingthmtkhuquntnhbcnhtlmvicnhmtkhunguynhm?

    Tnslmvic c < Tnslmvic 0>

    Tnslmvic c >

    Tnslmvic c = /Miquanhgiahmquvhmtrnglng? Hmqulcnbc2cahmtrnglng Hmtrnglnglohmcahmqu Hmqulohmcahmtrnglng Hmtrnglnglcnbc2cahmqu

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 17

    CHNG 3. KHO ST TNH N NH CA H THNG /HTKTcgilnnhnusaukhibphvtrngthicnbngdotcngcanhiuthhthngsc: Tnhiuradaongvibinkhngi Tnhiuradaongvibintngdn

    Tnhiurastiuchnhtrlitrngthicnbng Tnhiuratintivcng

    /HTKTskhngnnhnusailch ( )e t thamn:

    ( )lim

    te t

    ( )lim

    te t

    hngs

    ( )lim

    te t

    daongcbinkhngi

    ( )lim 0t e t /HTKTcmtbngphngtrnhviphnbc n ,nghimtngqutcaphngtrnhviphnsctrngchoqutrnhnocahthng? Qutrnhhotngcahthng Khngthktlun Qutrnhqu Qutrnhxclp /HTKTcmtbngphngtrnhviphnbc n ,nghimringcaphng

    trnhviphnsctrngchoqutrnhxclpcahthng? Sai ng /MunxttnhnnhcamtHTKT,tachphixtqutrnhxclp,nghaysai? ng Sai /Vnggchchotronghnhtrnctrngchovngnocahthng?

    Khngcthngtin Khngnnh nnh Bingiinnh /iukincnthitmtHTKTnnhlcchscaphngtrnhctrng? >0

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 18

    Cmthsdng =0

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 19

    Hkhngnnh /Munxtnnhcahthng,trchttaxt: LpnhthcHurwitz iukinhnnh LpbngRouth

    iukincnhnnh /TiuchunRouthcsdngxtnnhcho: Chchohthngcphnhim Hhvhkn Chchohkn Chchohh /TiuchunHurwitzthngcsdngxtnnhchocchthngcphngtrnhctrng: Bcrtcao

    Bcthp ( )4n < Chomihthng Bccao /QutrnhqucamtHTKTcmtnhhnhtrn,vyhthngl:

    nnh,daong bingiinnh nnh,khngdaong Khngnnh /QutrnhqucamtHTKTcmtnhhnhtrn,ngs4mththngctnhchtg?

    nnh,daong bingiinnh Khngnnh,khngdaong Khngnnh,daong

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 20

    /TheotiuchunNyquist,nuhhnnhhaybingiinnh( 0k = ),lch

    knsnnhnuctnhTBPcahhcquanhnhthnoviim ( )1, 0j Khngbaoquanh iqua Khngcquanhg

    Baoquanh /BngRouthcxydngnhsau:

    Hs 2b trongbngRouthctnhtheocngthcnosauy?

    0 42

    1 5

    a ab

    a a=

    0 42

    1 5

    a aba a

    =

    0 22

    1 3

    a ab

    a a=

    1 32

    0 2

    a ab

    b b=

    /PhtbiunosauylngvtnhchtcabngRouth?

    CthnhnhocchiaccshngtrncngmtctcabngRouthvimtsdngthktqutnhtonvnkhngthayi CthnhnhocchiaccshngtrncngmthngcabngRouthvimtsdngthktqutnhtonvnkhngthayi CththmmtsdngvomthngbtkcabngRouththktqutnhtonvnkhngthayi CthnhnhocchiaccshngtrncngmthngcabngRouthvimtsmthktqutnhtonvnkhngthayi

    /Nu ip nmbntritrconhhnhtrnthgcquaycanquanhgctactnhnhthno?

    ( )-

    arg j ip

    =

    ( )-

    arg j ip

    =

    ( )-

    arg j 2ip

    =

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 21

    ( )-

    arg j 2ip

    =

    /TheotiuchunMikhailope,nubiuvectorathcctnhnhhnhtrnthhthngnysnnhnuPTTcancbc:

    3 2 5 4 /NungcongbaoimM1nhhnhtrnthtaningcongbaoimM1

    mtgcbng?

    2

    2

    /dtrnnhl? Gitrphnocanghimsgntrconhtsoviccnghimkhc Gitrphnthccanghimsgntrcthcnhtsoviccnghimkhc Gitrphnocanghimsgntrcthcnhtsoviccnghimkhc Gitrphnthccanghimsgntrconhtsoviccnghimkhc /PhtbiunosauylngvtnhchtcabngRouth? SlniducaccshngtrongctutincabngRouthbngsnghimcaphngtrnhctrngcphnthcbng0

    SlniducaccshngtrongctutincabngRouthbngsnghimcaphngtrnhctrngcphnthcm SlniducaccshngtrongctutincabngRouthbngsnghimcaphngtrnhctrngcphnthcdng Khngnilniug /TheotiuchunHurwit,mththngcphngtrnhctnhbc2vicchsdngs: Lunbingiinnh Lunkhngnnh Lunnnh nnhtrongastrnghp

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 23

    /TheotiuchunNyquist,nuhthnghcctnhtn-bin-phanhhnhtrnthhthngkntngngcnnhkhng?

    C Khng

    /Nubiuvector ( )J j baotmtamtgcbng k thbiuvectorca

    ( )1 J j+

    sbaoimnomtgcbng k?

    ( )0, 0

    ( )1, 0j

    ( )1, 1j

    ( )1, 0j

    /Chohthnghchmtruynt:

    ( )2

    1

    1hW p

    Tp p=

    + + .Vi 2T = thhkntngngcnnhkhng? Khng C /nhthcHurwitzbc n ctnhtheocngthcnodiy?

    2 3 5

    0 2 4

    1 3

    0

    0

    0 0

    0 0 0

    n

    n

    a a a

    a a a

    a a

    a

    =

    1 1 5

    0 2 4

    3 3

    1

    1

    0 1

    0 0 0

    n

    n

    a a a

    a a a

    a a

    a

    =

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 24

    1 3 5

    0 2 4

    1 3

    0

    0

    0 0

    0 0 0

    n

    n

    a a a

    a a a

    a a

    a

    =

    0 3 5

    0 2 4

    1 3

    0

    0

    0 0

    0 0 0

    n

    n

    a a a

    a a a

    a a

    a

    =

    /Hmtruyntcahhcdng:

    ( )2 1

    hk

    W p

    p p=

    + + .

    Viiukinnoca kthhkntngngnnh?

    1k <

    2k >

    1k >

    2k < /HTKTchmtruyntdng:

    ( ) ( )k 4 3 2

    3 1W

    3 4 2 6 2 1

    pp

    p p p p p

    +=

    + + + +

    Hthngl: nnh Khngnnh Khngthxtnnhc bingiinnh /HTKTchmtruyntdng:

    ( )( )2

    k2

    2 9 19W

    6 8

    p pp

    p p

    + +=

    + + Xcnhccimcc,imkhngcahthng?

    imkhng: 1 25.62; 2z z= = ,imcc: 1 24; 3.38p p= =

    imkhng: 1 22; 4z z= = ,imcc: 1 25.62; 3.38p p= =

    imkhng: 1 25.62; 4z z= = ,imcc: 1 22; 3.38p p= =

    imkhng: 1 25.62; 3.38z z= = ,imcc: 1 22; 4p p= = /Chohthngcitngiukhin:

    0 3 2

    1

    W ( ) 5 8 4p p p p= + + +

    vbiukhin CW ( ) P Dp K K p= + (BPD)

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 25

    Tmphngtrnhctrngcahthngkn?

    3 2( ) 5 (8 ) (4 ) 0D PA p p p K p K= + + + + =

    3 2( ) 5 (8 ) (4 ) 0D PA p p p K K= + + + + + =

    3 2( ) 5 (8 ) (4 ) 0D PA p p p K p K= + + + + + =

    3 2( ) 5 (8 ) (4 ) 0D PA p p p K p K= + + + + =

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 26

    CHNG 4. NH GI CHT LNG H THNG IU KHIN TNG

    /Saistrngthixclpctnhtheocngthcno( ( )e t lsailchngcntntitrongqutrnhiukhin)?

    ( ) ( )0lim limt pe t pE p = =

    ( ) ( )

    0lim lim

    t pe t pE p

    = =

    ( ) ( )2

    0lim lim

    t pe t p E p

    = =

    ( ) ( )

    0lim lim

    t pe t E p

    = =

    /quiuchnhcaiukhincxcnhtheocngthcno?

    max 0% 100y yy

    =

    max% 100y y

    y

    =

    max% 100y y

    y

    =

    % 100y y

    y

    =

    /BiniLaplacecahm ( )u t kt = ?

    k p

    kp

    2k p

    2kp

    /Muntmmcnnh,tathaybiuthcnosauyvophngtrnhctrngcahthng?

    p j = +

    p j = +

    p j =

    p j =

    /NuHTKTcmtnhhnhtrnthmiquanhgia ( )E p v ( )Y p l?

    ( ) ( ) ( )hY p W p E p= +

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 27

    ( ) ( ) ( ).hE p W p Y p=

    ( ) ( ) ( ).hY p W p E p=

    ( ) ( ) ( )hE p W p Y p= +

    /Muntrittiusailchtnhcahthng,thngthngngitasdngthmkhucbnnodiy? Tchphn Viphn Khuchi Khutr

    /NunghimcaPTTnmtrongvnggchchonhhnhtrnthcgilg?

    dtrnnh Hsnnh dtrdaong Hsdaong

    /Vitnhiuvo ( ) ( )1u t t=

    ,saisxclpctnhtheocngthcno?

    ( )( )0

    1lim

    1p hp W p =

    +

    ( )0

    1lim

    1p hW p =

    +

    ( )0

    lim1p h

    p

    W p =

    +

    ( )( )

    1lim

    1p hp W p

    =

    +

    /Thigianqu qdtcxcnhbngcchno?

    Lthiimmhmqutgitrcci Lthiimmlnutinhmquttrsxclp Lthiimmhthngdaongnhiunht

    Lthiimmhmqu ( )y t khngvtrakhibingiicamingiihn quanhtrsxclp /Nuhmtruynthcdng:

    ( ) 10 11

    0 1

    ... 1

    ... 1

    m mh r n r n r

    b p b pkW pp a p a p

    + + +=+ + +

    th rcgilg?

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 29

    Thigiancquiuchnh Thigianpng /Nuhlkhuquntnhcdng

    ( )

    1

    kW p

    Tp=

    +

    thsailchtnhbngbaonhiu,vitnhiuvo ( ) ( )1u t t= ?

    1

    1k =

    2

    1

    1k =

    +

    1

    1k =

    +

    1k = +

    /Muntrittiusailchtnhtrongkhuquntnh( 0 = )thphimcnitipkhuquntnhvikhuchmtruyntnhthnotothnhhvsaicp1? p

    2p

    21 p

    1 p /Nhntnocnhhnglnnvicxcnhsailchtnhcahthng?

    Khutchphn dtrdaong dtrnnh Sailchtnh /DavonghimcaPTT,tacthnhgicphnnochtlngcaqutrnhqu.VynuttcccnghimcaPTTcphnbtrntrcthcthcthkhngnhqutrnhqucahthng: Chtlngqurtkm Cdaong Chtlngqurttt

    Khngdaong

    /Vitnhiuvo ( )u t kt = ,saisxclpctnhtheocngthcno?

    ( ) 20

    1lim .

    1p h

    k

    W p p =

    +

    ( )0

    1lim .

    1p h

    k

    W p p =

    +

    ( )

    20

    1lim .

    1ph

    k

    W pp

    =

    +

    ( )

    1lim .

    1p h

    k

    W p p =

    +

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 30

    /Saisxclpcahthngchmtruynth:

    ( )h 21

    W pp p k

    =+ +

    khiuvo ( ) ( )1u t t= lbaonhiu?

    ( )1k k+

    ( )1 k k+

    k

    1 k

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 31

    CHNG 5. TNG HP H THNG IU KHIN TNG

    /Biukhinviphn(D-Derivative)thngcdngtrongthct,nghaysai? Sai ng

    /Biukhintl(P-Proportional)ctcdngnhmtkhu Tchphn Viphn Khutr Khuchi /Thayihskhuchicthtrittiusailchtnh? Sai ng

    /Khixcnhcccthamstiucabiukhinmhthngiukhinvnkhngthamnccyucutra,chngtaphilmg? Chpnhnktqudkhngththamnyucutra Khngsdnghthngna Sdngbiukhinphctphn Thayicutrchthngiukhintng /Tnhiuiukhintheoquyluttlcxydngtheocngthcno,trongxltnhiura,eltnhiuvo?

    px K=

    .px K e=

    1. .i

    i

    x K e dt e dtT

    = =

    x e= /Trongquyluttchphn,tnhiuiukhincxcnhtheobiuthc:

    1. .i

    i

    x K e dt e dtT

    = =

    (trong 1i iT K= cgilhngsthigiantchphn).Vytisaouimcaquyluttchphnltrittiusailchtnh?

    Vkhi iTcgitrrtlnth 0x =

    Vgitriukhinx chtcgitrxclp(qutrnhiukhinktthc)khi 0e = Vgitriukhinx chtcgitrxclp(qutrnhiukhinktthc)khi e = Vgitriukhinx thayitheotchphncae

    /Trongkhuviphn,tnhiuralunlunsmphahntnhiuvomtgc 2 .iunynilnuimcakhuviphnlctcngnhanh,iunghaysai? ng Sai

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 32

    /BiukhinPDthngcdngchonhnghthngccimgnibt? Cnctcngnhanh Cnchnhxccao Khngcnhiutcng Cncnnhbnvng

    /NitcngcaquylutPInhanhhnquylutPnhngchmhnquylutIlnghaysai? ng Sai /Khithayit0n thctnhphatncabiukhinPDsthayinhthno?

    T 2 n0

    Bng 2 ,khngthayi

    T 2 n 2 T0n 2 /Trongcngnghip,quyluttl(P)thngcdngchonhnghthngccimg? Yucutcngrtnhanh Chophptntisailchtnh Khngnnh Yucuchnhxccaiukhinphicao

    /Nivtcng,quylutPIDcncthnhanhhncquyluttl,iunghaysai? Sai ng /ctnhcakhutchphnltnhiuracanlunchmphasovitnhiuvo

    mtgc 2 ,iunynghal: Quyluttchphnctcngnhanh Quyluttchphnctcngchm Quyluttchphnctcngnnh

    Khngcnghag /Hskhuychicabiukhintlcnglnthhthng Hthngstinnbingiinnh Cngnnhhn Khngnhhngntnhnnhcahthng Cngmtkhnngnnh /Tcdngcakhutchphntrongbiukhin? Lmtngtccabiukhin Rtngnqutrnhqucahthng Lmgimtccabiukhin Trittiusailchtnh

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 33

    /Chcnngcakhuviphntrongbiukhin(nuchnngthngschon)? Hnchtcdngcakhuviphn Lmtngtnhnnhcahthng Cithinqutrnhqu Trittiusailchtnh

    /Mcchcaphngphpbnhiuphtillmchohthng Lmtngnhhngcanhiu Btbinvitcng Lmgimnhhngcanhiu Khngcmcchnorrt /cimcahthngiukhinchngtrnh? Tnhiurathayilintc Tnhiuvocgicnh Tnhiuvothayilintc Tnhiuracgicnh

    /Trongcutrccahthngiukhintngthngthngcmythitbiukhin? 3 2 5 4 /Kthpquyluttlviquyluttchphntoraquyluttl-tchphn.VybiukhinPIccimgnibt? Ctcngchmnhngtrittiucsailchd

    Ctcngnhanhnhngkhngtrittiucsailchd Vactcngnhanh,vatrittiucsailchd Ctcngchmvkhngtrittiucsailchd /Xcnhcchngsthigiantchphn,viphntrongbiukhinPIDctnhiuiukhindng:

    1. . . . .p I d P d

    i

    de dex K e K e dt K K e e dt T

    dt T dt

    = + + = + +

    d p iT K K=

    , p d pT K K=

    i p iT K K=

    , d d pT K K=

    i p iT K K=

    , d p dT K K=

    i i pT K K=

    , d d pT K K=

    /GclchphagiatnhiuravtnhiuvotrongbiukhinPID? 0

    2

    2

    Nmtrongkhongt2n

    2

    /Hmtruyntcaquyluttl-vitchphncdng?

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 34

    ( )1

    1 ..

    p di

    W p K T pT p

    = + +

    ( )1 1

    1 ..

    pi d

    W p K pT p T

    = + +

    ( ) 1 .ip dTW p K T p

    p = + +

    ( )1

    1 ..

    p id

    W p K T pT p

    = + +

    /Hthngbtbinvinhiuphticxydngnhhnhtrn.Xcnhhm

    truyntcakhu ( )bW p ?

    ( )( ) ( )

    ( )1 2

    3

    .b

    W p W pW p

    W p=

    ( )( )

    ( ) ( )3

    1 2.b

    W pW p

    W p W p=

    ( )( ) ( )

    ( )1 2

    3

    .b

    W p W pW p

    W p=

    ( )( )

    ( ) ( )3

    1 2.b

    W pW p

    W p W p=

    /Hthngiukhintngnhhnhtrn.itngiukhincathitbiukhin

    ( )1mW p phicxcnhtheocngthcno?

    ( )( )

    ( ) ( )2

    12 21 .

    md

    m

    W pW p

    W p W p=

    +

    ( )( ) ( )

    ( )2 1

    12

    .md

    W p W pW p

    W p=

    ( )( ) ( )

    ( ) ( )2 1

    12 2

    .

    1 .

    md

    m

    W p W pW p

    W p W p=

    +

    ( ) ( ) ( )( ) ( )

    2 11

    2 2

    .1 .

    md

    m

    W p W pW pW p W p

    =

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 36

    /Khitnghphthngiukhintngnhhnhtrn,vnctralmboqutrnhqu

    camchvngtrong ( ) ( )( )2 2mW p W p phixyranhthnosovimchvngngoi

    (mchvngchnhvithitbiukhin ( )1mW p )?

    Nhanhhnrtnhiu Bng Chmhnrtnhiu Khngbrngbuclnnhau /Hthngtuyntnhcmtbiphngtrnhtrngthicp2:

    [ ]

    1 2 1. .

    1 1

    1 0 .

    x x uk

    y x

    = +

    =

    Vigitrnoca kthhthngiukhinchonton? 2k

    3k

    4k

    5k /Hthngtuyntnhcmtbiphngtrnhtrngthicp2:

    [ ]

    1 2 1. .

    1 1

    1 0 .

    x x u

    k

    y x

    = +

    =

    Vigitrnoca kthhthngquanstchonton? 2k

    1k

    3k Mik

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 37

    CHNG 6. M T TON HC H RI RC /Nutimtmtxchno,tnhiukhngctruynilintcthhlginon,iunghaysai? ng Sai

    /Vicchuyntnhiutlintcthnhginoncgil Tuyntnhhatngon Lngtha Phituynhangcong Rirchatngon /Trongphngphplngthatheothigian,phplngtcthchintheo: Nhngkhongthigianbngnhau Nhngmcbngnhau Nhngkhongthigianthayi

    Nhngmcnhtnh,phthucvotnhiuvo /Trongcchthngrircthngthng,ngoiphntxung,ccphntkhccnlitronghthnglccphnt Rirctuyntnh Phituyn Lintctuyntnh Ty /Hnhtrnlphngphplngthatheo

    Hnhp Mc Bin Thigian

    /Skhicamththngrirccchratrnhnhtrn.Khu ( )LGW p ccimg?

    Lngthatnhiutheomc Lngthatnhiutheothigian

    LmchogitrhmrircthayitrongkhongthigianT TrongkhongthigianT,gitrhmrirccgikhngi

    /Saiphncp1ctnhtheocngthc?

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 38

    ( ) ( ) ( )1i x i x i = +

    ( ) ( ) ( )1i x i x i = + +

    ( ) ( ) ( )1 1x i x i x i = +

    ( ) ( ) ( )2i x i x i = +

    /Qutrnhnghccamththngrirccthcmtbiphngtrnhviphn,nghaysai? ng Sai /Hmtruynttronghrircltsgiatnhiuravtnhiuvocbiudintrongminno? TrongminZviiukinutrittiu TrongminLaplacerircviiukinutintivcng

    TrongminLaplaceviiukinutrittiu Trongminthigian

    /ViccgitrT (thigianctmu)khcnhauthktquchuynhthngtminlintcsangminrirctngngskhcnhau,nghaysai? ng Sai /iukingphngtrnhsaiphnsaucbcn ?

    ( ) ( ) ( ) ( ) ( )0 1 11 ... 1n na y i n a y i n a y i a y i u i+ + + + + + + =

    0na

    0, 0na a

    00, 0na a =

    00; 0na a=

    /Phngtrnhtrngthimthrirchnhtrncdng?

    ( ) ( ) ( )

    ( ) ( ) ( )

    1 d d

    d d

    i A x i B u i

    y i C x i D u i

    + = +

    = +

    ( ) ( ) ( )

    ( ) ( ) ( )

    1 d d

    d d

    i C x i B u i

    y i A x i D u i

    + = +

    = +

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 39

    ( ) ( ) ( )

    ( ) ( ) ( )

    1 d d

    d d

    i A x i B u i

    y i D x i C u i

    + = +

    = +

    ( ) ( ) ( )

    ( ) ( ) ( )

    1 d d

    d d

    i B x i A u i

    y i C x i D u i

    + = +

    = + /Cpcasaiphncaonhtluntrngvicpcaonhtcaphngtrnhsaiphnlnghaysai? Sai ng /Lngthatheomcl: Tnhiurallintc Tnhiuracchiathnhccmcbngnhauphthuctnhiuvo Tnhiuracchiathnhccmckhcnhauphthuctnhiuvo Tnhiurathayikhngngk /Hmtruyntcablugibc0(ZOH)?

    ( ) ( )-1 1 pLGW p e

    p

    = +

    ( ) ( )1 1 pLGW p e

    p

    = +

    ( ) ( )-1 1- pLGW p e

    p

    =

    ( ) ( )1

    1-p

    LGW p ep

    =

    /BiniZ cakhu1 p ?

    ( )1 1 z

    ( )11 1 z+

    ( )11 1 z

    ( )1

    1 1 z

    /Trong3phngphpchuynhthngtminlintcsangminrirc(dngbiniLaplace,tnhgnngohmcp1vphngphphnhthang),phngphpnochochnhxccaonht? Phngphphnhthang Tnhgnngohmcp1 Cbachochnhxcnhnhau DngbiniLaplace

    /Nutnhiuvocakhu1

    zl ( )2y i

    +thtnhiuracanlg?

    ( )3y i +

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 40

    ( )1y i +

    ( )2y i +

    ( )4y i +

    /Chohthngxungnhhnhtrn.ulbiuthcngbiudinmiquanhgiacctnhiutronghthng?

    ( ) ( ) ( ) ( ){ } ( ). .LG LT FHF z Z W p W p W p U z=

    ( ) ( ) ( ){ } ( ).LT FHF z Z W p W p E z=

    ( ) ( ) ( ) ( ){ } ( ). .LG LT FHF z Z W p W p W p Y z=

    ( ) ( ) ( ) ( ){ } ( ). .LG LT FHF z Z W p W p W p E z=

    /Hthngcmttrongkhnggiantrngthiviccmatrntrngthitngngl:

    0.5 3

    2 1

    kA

    = ;

    1

    0B

    =

    ; [ ]1 0C = .Vi kbngbaonhiuthhthngtrnliukhinchonton? 0k >

    0k <

    Migitrca k Khngtntigitrnoca khthngtrniukhinchonton /Miquanhgiaminz vminLaplace?

    Tz e=

    pz e=

    pTz e=

    pTz e= /Nuphngtrnhtrngthichchobit:

    ( ) ( ) ( )1 d dx i A x i B u i+ = +

    thtacthxtcctnhgcahthng? Tnhnnh Khngthngtinxtmttrongccctnhcahthng Tnhquanstc Tnhiukhinc

    /Nuphngtrnhtrngthichchobit:

    ( ) ( ) ( )d dy i C x i D u i= + thtacthxtcctnhgcahthng?

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 41

    Tnhnnh Khngthngtinxtmttrongccctnhcahthng Tnhquanstc Tnhiukhinc /Cchbiniththnglintcsanghthngrirctrongkhnggiantrngthi

    theophngphptnhgnngohmcp1?(TrongI lmatrnnv., , ,A B C D lccmatrntrngthitronghlintcv , , ,d d d d A B C D lccmatrn

    trngthitronghrirc)

    ; ; ;d d d d A I A B TB C C D D= + = = =

    ; ; ;d d d d A I TA B TB C C D D= = = =

    ; ; ;d d d d A I TA B TB C C D D= + = = =

    ; ; ;d d d d A I TA B B C C D D= + = = =

    /Cchbiniththnglintcsanghthngrirctrongkhnggiantrngthi

    theophngphphnhthang?(TrongI lmatrnnv. , , ,A B C D lccmatrn

    trngthitronghlintcv , , ,d d d d A B C D lccmatrntrngthitronghrirc)

    1 1

    . ; ; ;2 2 2

    d d d d TA TA TA

    A I I B I C C D D

    = + = = =

    1 1

    . ; . . ; ;2 2 2

    d d d d TA TA TA

    A I I B I T B C C D D

    = + = = =

    1

    . ; . . ; ;2 2 2d d d d

    TA TA TAA I I B I T B C C D D

    = + = = =

    1

    . ; . . ; ;2 2 2

    d d d d TA TA TA

    A I I B I T B C C D D

    = + = = = /NuhthngiukhinxungtuyntnhcmhnhnhhnhtrnthhmtruyntcahhcxcnhtheocngthcnonuhmtruyntcakhuZOHl:

    ( ) ( )-1 1- pTLGW p e

    p=

    ?

    ( ) ( ){ } ( )

    ( ). 1 .

    LTLG LT

    W p

    Z W p W p z Z p

    =

    ( ) ( ){ } ( ) ( ){ }1. 1 .LG LT LTZ W p W p z Z W p=

    ( ) ( ){ } ( ) ( )1. 1 . LTLG LTW p

    Z W p W p z Zp

    =

    ( ) ( ){ } ( ) ( )1. 1 . LTLG LTW p

    Z W p W p z Zp

    = +

    /NuhthngiukhinxungtuyntnhcmhnhnhhnhtrnthhmtruyntcahkncxcnhtheocngthcnonuhmtruyntcakhuZOHl:

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 42

    ( ) ( )-1 1- pTLGW p e

    p=

    ?

    ( )( )( )

    ( ){ }( ) ( ) ( ){ }1 . .

    LTk

    LG LT FH

    Z W pY zW z

    U z Z W p W p W p= =

    +

    ( ) ( )( )

    ( ) ( ){ }( ) ( ){ }.

    1 .LG LT

    kLG FH

    Z W p W pY zW zU z Z W p W p

    = =+

    ( )( )( )

    ( ) ( ){ }( ) ( ) ( ){ }

    .

    1 . .

    LG LTk

    LG LT FH

    Z W p W pY zW z

    U z Z W p W p W p= =

    +

    ( )( )( )

    ( ) ( ){ }( ) ( ) ( ){ }

    .

    1 . .

    LG LTk

    LG LT FH

    Z W p W pY zW z

    U z Z W p W p W p= =

    /BiniZcakhu

    ( )1 p a+?

    ( )1 1 .aTe Z

    ( )11 1 .aTe Z

    ( )11 1 .aTe Z

    ( )11 1 .aTe Z +

    /invoccvtr1,2,3,4tronghnhtrntheongthtnmtscu

    trctrngthicahrirc?

    , , ,d d d d B C A D

    , , ,d d d d B C D A

    , , ,d d d d B D A C

    , , ,d d d d B A C D

    /Phngtrnhsaiphnsau:

    ( ) ( ) ( ) ( )3 22 6 5 0y i y i y i y i + + + =

    tngngviphngtrnhnotrong4trnghpdiy?

    ( ) ( ) ( )2 1 5 0y j y j y j+ = + + =

    vi 1j i= +

    ( ) ( ) ( )2 1 5 0y j y j y j+ + =

    vi 1j i= +

    ( ) ( ) ( )2 1 5 0y j y j y j+ + + =

    vi 1j i= +

    ( ) ( ) ( )2 1 5 0y j y j y j+ + + =

    vi 2j i= +

  • 7/31/2019 Dieu Khien Tu Dong - Ngan Hang de Thi

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 43

    /Viiukinutrittiu,hmtruyntmatrncbiudindidngno?

    ( )( )

    ( )( )

    1d d d

    Y zW z C ZI A B

    U z

    = =

    ( )( )

    ( ) ( )

    12

    d d d

    Y zW z C ZI A B

    U z

    = =

    ( )( )( )

    ( )d d dY z

    W z C ZI A BU z

    = =

    ( )( )( )

    ( )1

    d d

    Y zW z C ZI A B

    U z

    = =

    /Chohiukhinlintctuyntnhcbiudindidngphngtrnhtrngthi:

    [ ]

    1

    2

    1

    2

    0.5 1.5 1.2 3 0

    1 0 .

    x ux

    xy

    x

    = +

    =

    Vichuklymu ( )0.25T s= ,chuynhthngnysangdngrirctheophngphptnhgnngohmbcnht?

    [ ]

    1

    2

    1

    2

    1.125 0.375 0.25.

    0.5 1.75 0

    1 0 .

    xu

    x

    xy

    x

    = +

    =

    [ ]

    1

    2

    1

    2

    1.125 0.375 0.25.

    0.5 1.75 0

    1 0 .

    xu

    x

    xy

    x

    = +

    =

    [ ]

    1

    2

    1

    2

    1.125 0.375 0.25.0.5 1.75 0

    1 0 .

    x ux

    xy

    x

    = +

    =

    [ ]

    1

    2

    1

    2

    1 0.375 0.25.

    0.5 1.75 0

    1 0 .

    xu

    x

    xy

    x

    = +

    =

  • 7/31/2019 Dieu Khien Tu Dong - Ngan Hang de Thi

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 44

    CHNG 7. PHN TCH V THIT K H THNG RI RC /xttnhnnhcamththngrirc,taphilmg? Tmnghimcaphngtrnhviphnbiudinhthng Tmnghimcaphngtrnhsaiphnbiudinhthng Lpmatrnquanstc

    Lpmatrniukhinc /Nghimtngqutcaphngtrnhsaiphnctrngcho: Khngthngtinktlun Qutrnhqucahthng Qutrnhxclpcahthng Tnhiukhinccahthng /Tronghrirc,qutrnhxclpnhhngntnhnnhcahthng? ng Sai

    /( )cos sinT j T +

    luncmodulegiihnbngbaonhiu? 10 -1 1 0

    /NuTz e=thvi 0 > tac:

    1z >

    1z <

    1z >

    1z =

    /HrircsnnhnunghimcaPTTcahthng: Nmngoingtrnnv Nmtrongngtrnnv Nmtrnngtrnnv Nmgcta /Hrircsbingiinnhnu: PTTcmtnghimnmtrnngtrnnvvccnghimcnlinmtrongngtrnnv PTTcmtnghimnmngoingtrnnv TtcccnghimcaPTTnmngoingtrnnv TtcccnghimcaPTTnmtrongngtrnnv /Hrircskhngnnhnu: TtcccnghimcaPTTnmtrongngtrnnv PTTcmtnghimnmngoingtrnnv PTTcttcccnghimnmtrnngtrnnv PTTcmtnghimnmtrnngtrnnvvccnghimcnlinmtrongngtrnnv

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 45

    /Mththngcgiliukhincnutacthtmcmtvectoriu

    khin ( )u i chuynchthngtmttrngthibanubtk ( )0x nmttrng

    thicuibtk ( )n ? Trongmtkhongthigianvhn

    Trongmtkhongthigianhuhn

    Phichuynvtrngthi ( )0 ngaylptc

    Hduytrtrngthiim ( )x n

    /Cthdngcctiuchunxtnnhchohlintcxtnnhchohrirc? ng Sai /Hrirctntikhnngnnhvtn.iunyhlintckhngc? Sai ng /iukincnmthrircnnhlcchscaPTTdng,nghaysai? Sai ng /Gishrirccathcctrng:

    ( ) 10 1 1...

    l ll lA z a z a z a z a

    = + + + + .

    xtiukinnnhcahthngtheotiuchunJurytaphitm ( )1A ,thnghal:

    Thay 1z = vo ( )A z

    Thay 0z = vo ( )A z

    Thay 1z = vo ( )A z

    Thay 1l= vo ( )A z /TheotiuchunJury,munxttnhnnhcahrirccPTTdng:

    1

    0 1 1... 0l l

    l la z a z a z a

    + + + + = ,hthngphithamnbaonhiuiukinrngbuc? 4l+

    1l+

    3l+

    2l+

    /Theophngphpbinibotonhnhdng,iukin1z >stngngvi

    iukinnocav ? Nmbnphitrcotrongmtphngv Nmbntritrcotrongmtphngv

    Nmtrntrcotrongmtphngv Nmtrongngtrnnvtrongmtphngv /Nghimringcaphngtrnhsaiphn

  • 7/31/2019 Dieu Khien Tu Dong - Ngan Hang de Thi

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 46

    ctrngchoqutrnhqucahthng Khngchothngtinvnlunthayi Dngxttnhnnhcahthng ctrngchoqutrnhxclpcahthng /nhnghatnhiukhincvquanstccahrircgingvihlin

    tc? ng Sai

    /VipTz e= v

    Tz e=thvi 0 > stngngvinghimcaphngtrnhnm

    vtrnotrongmtphngz? Nmtrongngtrnnv Nmngoingtrnnv Cthnmbtcutrongmtphngz Nmtrnngtrnnv

    /Vi pTz e= vT

    z e

    = thvi 0 = (nghimnmtrntrco jcamtphngphc)stngngvinghimccimgtrongmtphngz ? Nmgcta Nmbnngoingtrnnv Nmbntrongngtrnnv Nmtrnngtrnnv /GishrirccPTT:

    1

    0 1 1... 0l l

    l la z a z a z a

    + + + + = .Theophngphpbinibotonhnhdng,tatbinph?

    1

    1

    vz

    v+=

    1

    1

    vz

    v

    =

    +

    1

    vz

    v=

    +

    1vz

    v

    +=

    /Mcchcaphngphpbinibotonhnhdng? dngcctiuchunisxtnnhchohlintc tngbccaphngtrnhctrng,lmchohthngnnhhn xtnnhchohrirc PTTcrtgnhn /Nhnxthrirckmnnhhnhlintclnghaysai? Sai ng /Cctiuchdngnhgichtlngqucahlintckhngcpdngchohrirc? Sai ng

  • 7/31/2019 Dieu Khien Tu Dong - Ngan Hang de Thi

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 47

    /Nhngtiuchnosauydngnhgihthngtrongminkhnggiantrngthi? Tnhiukhincvquanstc Tnhiukhinc,tnhquanstcvthigianqu Tnhiukhinc,tnhquanstcvtnhnnh

    Tnhiukhinc,tnhquanstcvquiuchnhcci /Saisxclpcahrirccxcnhtheocngthcnodiy?

    ( ) ( ) ( ) ( )1

    1lim lim 1i z

    e e iT z E z

    = =

    ( ) ( ) ( ) ( )1

    1lim lim 1i T z

    e e iT z E z

    = =

    ( ) ( ) ( ) ( )1lim lim 1

    i T z T e e iT z E z

    = =

    ( ) ( ) ( ) ( )11

    lim lim 1

    i T z

    e e iT z E z

    = = +

    /Tiuchunnnhtheonguynlgcquaycahthngrirctngngvitiuchunnovxtnnhcahknvhhlintc? Mikhailope Routh Hurwitz Nyquist

    /NuPTTcahrirccbc lththeotiuchunJury,taphilpbngJurycshngbngbaonhiu?

    2 1l 2 2l

    2 3l

    2l /GishthngrirccPTTdng:

    ( ) 10 1 1... 0

    l ll lA z a z a z a z a

    = + + + + =

    ththeotiuchunJury,iukincnkimtrautinbithchocnnhkhngl:

    ( )1 0A >

    ( )1 0A

    /NuttcccnghimcaPTTphnbgcphntthIvIV(nghimphclunithnhcp)thtnsdaongcahthngnmtrongkhongno?

    0 < <

    2 0 < <

    0 2< <

  • 7/31/2019 Dieu Khien Tu Dong - Ngan Hang de Thi

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 48

    2 2 < < /MttrongnhngiukinhthngrirccphngtrnhctrngnnhtheotiuchunJuryl:

    ( )1 0A =

    nu lchnv ( )1 0A < nu ll

    ( )1 0A > nu lchnv ( )1 0A < nu ll

    ( )1 0A nu ll

    ( )1 0A >

    nu lchnv ( )1 0A =

    nu ll /NunghimcaPTTlim5(nmtrntrcOC)nhhnhtrnthhthngsdaongvitnsbngbaonhiu?

    2

    2 / ulngbinthincatnhiurakhinghimcaPTTlim6trnhnhdi?

  • 7/31/2019 Dieu Khien Tu Dong - Ngan Hang de Thi

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  • 7/31/2019 Dieu Khien Tu Dong - Ngan Hang de Thi

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 50

    c b a d

    /GishthngcPTTdng:22 3 4 0z z+ + = ,saukhidngphngphpbini

    botonhnhdngtacphngtrnhtngngl:

    28 4 3 0v v + =

    29 4 3 0v v+ + =

    29 4 3 0v v + =

    29 4 3 0v v =

    /iukinhthngcPTTbcnhtdng: 0 1 0a z a+ = nnhtheophngphpbotonhnhdngl?

    0 1a a

  • 7/31/2019 Dieu Khien Tu Dong - Ngan Hang de Thi

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 51

    /HthngxungcmttrongkhnggiantrngthisiukhinchontonkhivchkhimatrnM chngbngn .MatrnM cxydngthno?

    ( ) ( )

    1 2' . ' . ...

    n nd d d d d M A B A B B

    =

    1 2. ' . ' ... 'n nd d d d d M A B A B B =

    1 2. . ... 1

    n nd d d d M A B A B

    =

    1 2. . ...

    n nd d d d d M A B A B B

    =

    /Vitnhiuvo ( ) ( )1u t t= ,saisxclpcahrirccxcnhtheocngthcno?

    ( ) ( ) ( ) ( ){ }1

    1

    lim 1 . .z LG LT FHe Z W p W p W p = +

    ( )( ) ( ) ( ){ }

    1lim

    1 . .z LG LT FHe

    Z W p W p W p =

    +

    ( )( ) ( ) ( ){ }

    1lim

    1 . .z T LG LT FHe

    Z W p W p W p =

    +

    ( )( ) ( ){ }11

    lim1 .z LT FH

    eZ W p W p

    =+

    / HthngxungcmttrongkhnggiantrngthisiukhinchontonkhivchkhimatrnN chngbngn .MatrnN cxydngthno?

    ( )

    1. ... .

    nd d d d d N C A C A C

    =

    ( )

    1' ' '. ... .

    nd d d d d N C A C A C

    =

    ( )

    1' '. ... .

    n

    d d d d d N C A C A C

    =

    ( )

    1' ' ' ' '. ... .

    n

    d d d d d N C A C A C =

    /Chohthngcbiudintrongkhnggiantrngthidng:

    ( )( )

    ( )( )

    ( )

    ( ) [ ]( )( )

    1 1

    2 2

    1

    2

    1 1 2 1

    1 2 1 1

    1 0

    x i x iu i

    x i x i

    x iy i

    x i

    + = + +

    =

    Matrniukhincvhngcamatrn?

    3 1

    1 1M

    = , ( )rank 1M =

  • 7/31/2019 Dieu Khien Tu Dong - Ngan Hang de Thi

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    Bn cng bcho sinh vini hc txa. Chsdng cho mc ch hc tp. 52

    3 1

    1 1M

    = , ( )rank 2M =

    3 1

    1 1M

    =

    , ( )rank 2M =

    3 1

    1 1M

    = , ( )rank 2M =

    /Chohthngcbiudintrongkhnggiantrngthidng:

    ( )( )

    ( )( )

    ( )

    ( ) [ ]( )

    ( )

    1 1

    2 2

    1

    2

    1 1 2 1

    1 2 1 1

    1 0

    x i x iu i

    x i x i

    x iy i

    x i

    + = + +

    =

    Matrnquanstcvhngcamatrn?

    1 1

    1 2N

    = , ( )rank 2N =

    1 1

    0 2N

    = , ( )rank 2N =

    1 1

    0 2N

    = , ( )rank 3N =

    1 1

    0 2N

    =

    ,

    ( )rank 2N =

    /HmtruyntcabiukhinPIDs?

    ( )( )

    ( )

    ( ). 112 1 .

    piPID d

    k zk T zW z k

    z T z

    += + +

    ( )( )

    ( )( )1 . 1

    2 1 .

    i dPID p

    k T z k zW z k

    z T z

    + = + +

    ( )( )

    ( )

    ( )1 . 12 1 .

    d iPID p

    k T z k zW z k

    z T z

    + = + +

    ( )( )

    ( )( )1 . 1

    2 1 .

    p dPID i

    k T z k zW z k

    z T z

    + = + +

    /Khitnhiuvo ( )u t t= ,saisxclpcahrirccxcnhtheocngthcno?

    ( )( ) ( ) ( ) ( ){ }1

    lim1 1 . .z LG LT FH

    Te

    z Z W p W p W p =

    +

    ( ) ( ) ( ) ( ) ( ){ }1

    1

    lim 1 1 . .z LG LT FHe z Z W p W p W p = +

  • 7/31/2019 Dieu Khien Tu Dong - Ngan Hang de Thi

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    ( )( ) ( ) ( ){ }1

    lim1 . .z LG LT FH

    Te

    Z W p W p W p =

    +

    ( )( ) ( ) ( ) ( ){ }1

    lim1 1 . .z LG LT FH

    Te

    z Z W p W p W p =

    + +

    /Tmhmtruyntcahthngchotronghnhd?

    ( ) 2 32 3 1 21

    W WW p

    W W W W =

    + +

    ( ) 1 22 3 1 21

    W WW p

    W W W W =

    + +

    ( ) 1 3

    2 3 1 21

    W WW p

    W W W W =

    + +

    ( ) 1 2 32 3 1 21

    W W WW p

    W W W W

    =

    + +