H3-12MM- Calculus - Gradient of a Curve at a Point and the Gradient Function

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  • 8/13/2019 H3-12MM- Calculus - Gradient of a Curve at a Point and the Gradient Function

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    Mathematical Methods Unit 2

    CalculusH Gradient of a curve at a point and the gradient functionExample 1

    Consider the function() .Let P be the point (1, 0) and let Q be a point h units to the right of P.

    Find the gradient of the chord PQ and hence find the gradient at point P.

    Example 2

    For a curve with equation .

    a. Find the gradient of chord AB where A is the point (1, -1) and B is the point b. Find the gradient of AB when c. Find the gradient of the curve at A.

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    The Gradient of a curve at any point.Recall:The gradient of a function represents the rate at which a function is changing. To find thegradient of a curve at any point, we need to find the gradient of the tangent of the curveat thatpoint.

    This gradient can be approximated by calculating the gradient of the chord that connects twopoints that lie close to one another i.e. finding the average rate of changebetween the twopoints.

    Consider the points A to E on the graph of .3)( 2xxf

    Using the CAS calculator, the gradient of the tangent at A is ________.

    Investigating the gradients of chords connecting A to points close to A we get:

    Gradient of AE:12

    12

    xx

    yym

    =

    Gradient of AD:12

    12

    xx

    yym

    =

    Similarly, the gradients of AC and AB become better estimatesof the gradient of the tangentat A.

    Chord Gradient of chord

    AE

    AD

    AC

    AB

    Gradient of tangent at A

    As the distance between the two points approaches zero, the line connecting the two pointsresembles the gradient of the tangent at .Ax The gradient of the chordbecomes an accurateestimate of the gradient of the tangent at this point.

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    In general:

    Let A be any point on the curve, where the coordinates of point A are represented by )).(,( xfx

    Let B be another point on the curve so that the difference between the x - coordinates of A

    and B is equal to .h The coordinates of point B would thus be )).(,( hxfhx

    Then, the gradient of the chord AB(the average rate of change) is:

    12

    12

    xx

    yym

    As point B moves closer to point A, the distance between their x coordinates, or ,h

    approaches zero. The gradient of the chord ABbecomes an accurate estimate of the gradientof the tangent.

    i.e as

    h

    xfhxfh

    )()(,0 gradient of the tangent at point A

    The gradient of the tangent to the curve (the instantaneous rate of change) is:

    0,)()(

    lim0

    hh

    xfhxfh

    This limit is referred to as the gradient function, derivative function, )(),(' fDxf x ,dx

    dyor the

    derivative of ).(xf The process of obtaining )(' xf is called differentiationand evaluating the

    above limit is known as differentiation from first principles.

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    Example 3

    Find the derivative of() using first principles

    Example 4

    a. Find the derivative of() using first principles

    b. Hence find the gradient when ie find ()

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    Example 5

    a. Find the derivative of() using first principles

    b. Hence find the gradient when

    Ex 19B 1