~ 6 ' GD-DT BAC LI&U ICY THI GIAI TOAN T R ~ N MAY TTNH CAM TAY NAM 2014

~ i ? CHTNH 'r~0'c M6n tlli: I O A N L6p: 12 FIG: GDPT NgAy llli : 0711 21201 4

so' LU'QC CACI r GIAI VA IIU'ONG DAN CHAM THI

Q u y ~1~11: Hoc .cinli /ririh hby llbrr /k/ cciclr grill, c611g 1hli.c 47 tltlrig, lei/ quo /iMh /obn vbo 6 /r ing liin lri 17ili /01ir1 C'iic kk/ qlul lir111 < ~ ( ? I I ~ I ~ I I S , 11 i i1 lrl7611g c6 chi lirj~~h C L I /II;, dtlsoc I I ~ ~ I ~ I 411h cl7inh

, \

s i c 16; -/ c11k $56 llhd11 /h6]7 (7h~11 .s(111 ~ / i ; l l / ? I I ~ J ,

:c b) ~ h o h i m sh y = f ( x ) = - c6 dh Lh/ (c) . Tim toa LtG llai di6m c"c 'I-,

\/7iGG - 12

cqc ti& vii tin11 khoAng chch giira hai cti&ll C L ~ C tl-i cila dh 111, (c) .

CBch giii v i I<& qui --pp.-..---. ~ --p.p-.p--p- ~

+ 7ir h ing bikn thiOn suy ra I : , , = 041545 _ -0,3022472521 vi

1 !I, 1 252

+ Ggi A, B 1B liai diem crrc hi.

a ) (sin : i - 2 cos : i ) (3& - 8 cos 1 ) - 10 cos' i , - 1 - 8 .

PP- - --- .-~ - - - -

CAch giiii \/A ~ ~- 1dt clui ~ --.. r T i ! L 1 a) Ta c6: (sin :L - 2 cos 1:) ( 3 6 - 8 cus 1 : - I O cus :I.: 4- 8

I 2 o 3h (sill :I: - 2 cos 1-1 - 1 - ((i cos : i : - 8 sill :I: cos :I: - 8 ) = 0

1 Dat t = sill 3; - 2 cos I ( ( ~ 1 5 h ) + 6 cusi :I: - 8 sill 1: cos : I : - 8 = 21' - 10.

1 PI7 da cho trh thin11 2 t L -1 3 &L - 10 1 (1 r-

45 2 I 7r Vbi t = --- , dat sill c~ - --- , cos t u - -- . la dirge sill ( :r - CT) = sill -

2 l.6 f i 6

qui : n: 2: 1,6307 4- Ii:2n ; :I: z 3,7251 I I1:27r (k: E Z) - - -. - -- - - -

b) Ta c6: 20 14 4- 7.' - ??PI ?

2014 + 7' ++ n: = 2y 4- 2 (vi hdm f ' ( t ) = nghjch bikn t1.h IW )

I % ' - - --p-pp-.-p.--. .. - .. -. -. --- -- -. . . . -- -- I Thay vio PT 7 ' t 12' = 202 - 1 14 , ta d q c 7"" t 12" - ilOy -- 54 = 0 (3). I-

Suy ra PT (3) co ltl1611g q u a hai nghicm. ~ . . . . . -. -

Sir d1111g c11il.c 112ilg SOLVE tim cl~rqc hai ngliicm c i ~ a PT (3): :rj z 0,024587581 ; I -. . - -- - . - -

Tir do tim dirgc tucrng irng :I. zz 2,049 175 lG2 ; 2: zz -0,685037132 .

.1: zz 2, 0492 1 : -0,6850 I<& qui : I-Ic d5 cho co hai nghi+m

: 0 , 0 2 4 ~ ' I N zz - 1,3125 '

H i i 3 (5.0 llii'm). C.110 hai dB) s6 (:l:,, ) v i ( ) c l ~ r ~ c u6c d/nli hoi 7, = - 1 , y, = 2 .

:1: c ) 'l'illll =

:rj~II1.l - - - - - - - - - -- - -. -. . - - - - - - - - -

.- CRch gi i i va kt3 qu;i

- - - - - - - - - - - - - - - -

A - -1, B = 2, Ad = 1

1 b) Grin: ,4 = -- 1, f l - 2, :~:. [, F; :.- - - - -

2 Ghi vao may: M ~ ~ ~ + ~ : ~ = ~ r \ + ~ ~ : ~ = ~ - I - - 2 B : E = E + C + n : A = ~ : B = D I3km phim m lien tikp. kt q u i : ,S x 342,21 l 2

---p-ppp-p.- ~

c) Gin: A - -1, R - 2, Ad --I 1

Ghiviomity: Ad = Ad -1- 1 : C - :3,I 4-613: D - rI-2B : C t D : ,I =: C : B = U I3km phim lien tiip. ~ 6 t qiri: F z 6

th6 viit q u y trinh chung C I I O C ~ C C ~ L I ) . .- --

B i i 4 (5 , (1 diin?). ----

Cho tam giac A RC vu6ng tgi A c6 A B = 4, IG ; goc A CIU -- 34", cac d~rbng phiin giac

trong BM v3 CN (Ad c A C , N E A B ) C & nhau tai I .

a) Tinh (16 clai cac doan BA/( vB CN

b) 'l'inh dien tic11 tam giac IA$N .

I a) Tsong tam gihc vubng AL(('. co

1 .- - Di$n tich tam gi ic IMN: ~ l l , , A , = - 1114. IN. sill MlN

2

qua: S,,, = 0,8732 -- -- - -- -. .- - - . - - . - . . -- . - -- . . - . - -- -. - - -- 1 -. 075 - 1

13Bi 5 (5,O ( f l ; ~ , l ) . 'l.rCn cgrili D A . Dl3 cua lil. cl1C11 ABCL) I ~ ! I c6c c l i h M , N suo cho

D M 7 D N - - - - -- = Ii: ( I , : > 0 ). Me1 m$t ph5ng (0) di clila NlN \!i~ song song vki DC chia ti~.

M A 12. N B cliel i IAm hnj l,ll$n. 'l'im gii' t1.1 d i ~ n g ci~;r A:, OiPt t i s t 1116 tic11 cira Iphhn cllisn din11 A vi, phhn

2014 chirir clinh 11 Ii -.

2015 .-------p-p.------.---- -

-. <:;icl~ ~ i i i v h kit qu5 _ - X'L _ - - . - - - - - - - - ~ p . - DiCm F

Goi K = (tr) n A C , I = (0) n CB . Vi (cr) song song vbi DC nen N I / / h ! ! I ~ / / D C .

V (-'I< C I -- -

7 X : l ' a c b : . / ) . ( ' I \ / -- L -- pp '7 1,: - :+ v/, ( ./,./ = 1 1 ( 1 ) :

V 1 19(1,:-1-1) (A: -1- 1)

l.'il. ( 1 ), (2). (3) suy ra

I/ - ~~

71,: ( 3 I I,: ..I- 5( I ) -. .. .

21 71,:' 1 350h: - L -

~ . . . --r

1 92 (1,; -1- 1)' .- 71): ( ; 3 1 L ; ~1~ 50) 1441),? - 1 ~ i372A: 4 36 I

1X11ig l ~ ~ i l i SOILVI: giAi \/:I ( i l l 1 c l ~ r ~ ~ c 1,: I<& q u i : I,: ~2 2,3827

~ ~ - --- . - - - -- -- ~~ - .. - - -- - ~

I 3 i i 6 ( j , O dic; ,~?) . ('110 1 1 i l i I 1 ~ : I I I I giAc CIC!,I A, C ~ I I I I I (1, Y= 7.,12.1a.i, (~'110 l i i ~ i l i 11.011 Ol 11Gi [iC13 Ili~iIl t;101

pi3c (1211 cqlili A). (0 111ii1 l , l i ~ ~ i l i i~ i l i (:111i gii'lc ( 1 ; ~ A l I,Cli 11;:oili , . *.I . . . .. '\ ; ,'.,

lii~ili 11.011 0). ha l i i~ i l i clir<~c (0 1iii11i a; cIiC11 tic11 l~511g , Y 1 . l11~1ig (: I I I I ,i'

I.' '..,

>' I I A c I I c t i I I A , i d 0, , ('110 Iii111i t1.011 /-.. . - .- -...T. .. .. . . ..--, .(.

,( *'% j'.,, ::l 0, nci liCp liinli lam giric cl?u A , . li) I I ~ ~ L L I j~liii~i Iij~ili (;l~il gihc CICLI , ,; , ',%.., s.,:. i ,+ -,A, . . ,,I ' .

, , , ? 4 ' ?. .',. A) I ~ C I I 1.1goi1i l i i~ i l i 11.011 0) . 1x1 lii 1111 ~ I L I , O C 1;) I I I < I \ I u') (1 iC11 [icli ,J,./" ,.. , ,. .: ,j., "., ::

? A A i L - d i

lidng S L . cir ili!rv 1iii.n (isl, lye nl i i r vij!:. I liiili $5 1.d

T -- ,$ 4.- S) -1- . . . - - t~ Sl ,! 1 .! I

....... GIAM t11i 1 : ........ G i h m t l ~ i 2: ....... MZ phach: I--19 va ten thi siilh: ........................................... Si3 biio danh: ..........

............ ........................................................ 'l'ru. b n g . - - - - - - - - -- - - -. - -. -. .-ppppp-- -- . .. . - - ......

MBn thi: VAT LY Lop: 12 He: GDPT Thoi gian: 120 phut (K1~6ng I<; thdi ginn giuo d i ) Ngay thi: 07/12/2014 * Chi1 9: - ~k thi nay g61n 07 trang, 06 bai. inRi bai 5 di&m.

- Thi sinh Ian1 bai trqc tikp VBO ban dk thi nay.

DIEM CUA TOAN RAI THI

i -. -

Ring sh l3lng chir

MA PHACI-I (Do Chu tic11 Hoi dbng ghi)

Qui djnh: - Thi silih phai ghi du ccic llluc bph&n /rin /he0 .sir h~rbng d& c i a giai71 thz; - Th; sinh ldr71 bui /vyc ti& vdo ban d$ /hi cd pli~ich dinli kkn, n?y: - Bdi /hi phai dtrqc vikr bing lnBt l o ~ i bzif, nl(it thzi. 1 1 1 ~ ~ : khdng vikt bing niyc d6, bZit chi; kh6ng dr"c

dcimh d&zi hay lhnl ki hi& riing; phdn viit hdlig ph~ii dz'ing tl~zrcie gcrcl~ chko: lhdng dzrqc /iV. X ~ U bkng bi t k;i/ C L ~ C I I gi fk; cn bzit xda).

- T ~ a i vdi cac di$ti trin, /hi sinl7 .YE bj l o ~ i . - Thi sinh trinh bdy cdch gibi, c6ng th2i.c dp dung, kit yzrb tilih todn viro ci tl.dng liin k$ biri tocin. C'dc' kit

q u ~ i linh gun dzi~ig, n iu khdng cci chi dill h c1.1 /hi , d z r~) '~ ngi111 d i ~ h chilih X ~ C tdi 4 chQ ~6 ph~17 thGp phdn .sati &?'z4 phcjy.

Rai 1 : (5 di&m) Tir A (do cao A C = H = 3,s n), ) ~igubi ta tha

mot v$t roi tv do. Cung luc do, tir B cach C 1118t doan BC = H nglrbi ta n6in mot v$t khac v6i v$n thc diu T,,

hgp mot goc cx v6i phuang ngang v& phia vat t h ~ nhat I I I I

- . .------ (hi1111 vC). Tinh a vB o,, d& hai vat co th& gap d u g ~ nhau - - - - _ I 7-._ 'llo ,:--- , -.

khi chung dang chuy&n dong. I I I I Don vi t inh gdc ( '), vdn t i c (m/s).

B C

,

........ Gihm thi 1 : CJiBlli .thi 2: ....... MZ. phich: ....... E-19 va tkn tlii sinh: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Si, bao d a n k ..........

........................................................ ............ TI'ruivng: -- - -. - ..... -- -. .- - - - - - ......... -- -- -- - - - -.

Met 6ng dai I = 0.9 rri met ddu kin. ,net dbu 116. 13bu 116 dugc cim thing dirng vio met

cl~$u thuy ngdn (Hg) sao c l ~ o n6 cach mat thoang n161 ltl~oai~g 6 = 0,75 1 1 ~ . Tim I thoa~~g cach tir

d$o kin dkil I I I ~ C tliily ngdn trong long ang. Ap suit khi q ~ ~ Y & ~ 11,) = 105 PO. Trong 1uwg rieng

cua t l ~ i ~ y ngdn 1 i 13,G. 10J N/?r) , ' .

Don v i tinl?: klzoang ccicl? (MZ). -p---.------.-----p-.----.-...., ........... .-...--.-.p--....--.--..--. ~

Cach @i --.pp..--..-p----...--.- ~ . ..........

K B ~ wi --

Bai 3: (5 di&m)

Mot die11 ti^ bay vao mot tp die11 phing vhi I , = . 1 0 7 s theo phlrong song song v6i

cac ban. Khi ra lthoi tp dien, hat bi lcch theo phucyng vu6ng g6c v6i cac ban mat doan h = G p ~ ~ ~ , * ~ ~ ~ . .

Cic ban t~ die11 dai 1 = 6 cut, cach nhau d -; 3 i . r I 2 . . Tinh hi& die11 thi U giGa hai ban tu dien.

130 va t2i1 thi sinl~: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .. Mii phach: . . . . . . .

SA bao dai111: . . . . . . . . . . P hongtl~i : . . . . . . . . . . . . - -- -. . - -.

Mot vgt p l ~ i h g 11l10 AB dat trubc va song song vbi lnat man, cach inan mot khoang L = 100 m1.. D3t ill@ t h i u ltinh hei tu vao giii.a vgt va iiiin, song song vbi vat. sao cho di&i~i A

cila vat b tr&n tryc cliinh. Ta tim dugc hai vi tri 0, va 0, cila thiu kinh cho an11 r8 net c i a v$t

tr&n man, Bnh nay ghp 2 li11 anh ltia. Tim ti@u cu cua thiu ltinh.

Bai 5: (5 biiin) Mot coil lsc 10 xo 11~111 ngang cO do cirng 1: = 100 N / r n , v$t nho co kh6i loqng

712 = 100 9 . Til. vi tri c2n bing, ng~rbi ta tic dung l&n vat nho mot l~rc lthbng d8i, co do l&n

F = 4 N hu&ng theo phucrng ilgang triing v6i tryc 10 xo, lam cho lo xo gian ra va dao dong. Tinh

thbi gian ngin nhet 1ck tir lchi vat chju t ic dung l!rc din khi 10 xo giln 5,s cm, .

Don vt tinh: th&i gian (s). -- -.

~ h & ~ i i i i -- 1

-- --p--.--p-.--. -. ~ -.-..-.-....--....pp... ~

--

K B ~ p1

~ ~..

, . * , , I ,

........ Giain thi I : Giam thi 2: ....... Mii phach: ....... 1-10 va tEn thi sinh: ........................................... S& bio danh: ..........

........................................................ ............ A- I'hong thi:

Bai 6: ( 5 dik~n) Doan inach AB g6111 hai doan mach AM va MR mkc nbi tiep. Doan mach AM IB mQt cuan

dung thay d6i duqc, c6 gia tri hOu han va khac kh6ng. Dat vao hai diu doan ~nach AB mat dien

i p ,(,,4, = 100&cos(100iit) V . ~ i k u chinh die11 dung clia tu dien dk thng dien Ap hieu dung

((iAI i UAIIl) dat gih tr/ cuc dai. Tim gii tr/ cuc dgi cua thng dien ap hi&u dung nay

~ 6 ' GIAO DUC - DAO TAO KY THI GIAI TOAN T R ~ N MAY TINH CAM TAY NAM 2014

Dl? C H ~ N H THUC

M8n thi: H ~ A HOC Lop: 12 He: THPT Thoi gian: 120 philt (Ichdng k6 1hti.i gian giao d i )

Qui djnll: Thi sinh trinh bdy vhn tht cdch gidi, cdng th2i.c dp dung, /<kt qud tinh todn vdo 6 trhng liin 1~2 bdi torin. Cric kit qud tinh gdn dGng, nku khdng cd chi dinh cy thi) duqc ng&m dinh chinh xdc r6i 4 chi? sSphdn thGp phrin saw dku

Bai 1 : (5 di6in) Ciiu 1: '18u 92 la in$t chit phdng xa. Sau nhi&u lan phdn 1-2 lien tikp m i thbi gian sang clia chc hat nhdn trung gian I$ dil ngkn d& c6 thk b6 qua sv c6 inat clia clli~ilg trong cac san phiin chuykn hob . Phvong trinh ph6i1g xa nhv sau: 238 92 u + ':; pb + X C ~ + yp-

a/ Xac d/nh cac he s6 x va y? b/ Thvc nghiein cho bi&t tai thbi di&m lchio s6t mat in& dQ uranynit c6 ty I& giira kh6i lugng ';:u cb11 lqi VB kh6i luqng ' : :~h la 0,0453. C11u lc9 bin hliy cila *:,"u la 4,5592 1.1 o9 nBm. H2y tinh tu6i clia inHu d i ul-anynit. CGu 2: Coi nguydn tir Flo ( ' l F ) 1I in$t hinh c6u c6 dubng ltinh 10-lo in v i hat nhdn cfing la inat llinh ciu c6 dvbng kinh 10- '~in.

a/ 1<116i l~rgng cila inat nguy&n tu flo tin11 theo galn IB bao nhibu? b/ Tin11 ty kh6i clia hat nhln nguy&n tii ilo? C/ Tinh tj. 14 th& tich clia hat nhdn so vbi t11k tich cila toin nguy&n tii flo?

Cach gi6i - ---

Ciiu 1: a/ ';;u + 2 , " i ~ b + ~ : k ~ e + ))-ye

Ap dyng dinh lugt: bao toan nuclon v$ bao toAn die11 tic11

b/ ':u + ' ~ ~ b + 8 f ' f 1 e + 6 - ' ~ 1 ?

Goi t la tu6i cila mHu d6 => s6 hat ';:u cbn lei b thbi di&in t la

238 +1) 4,55921.1o9.1n(

238 T . Ill(-

206.0,0453 - 206.0,0453 + 1)

t = - = 2,155.10" In 2 In 2

Tu6i clia mHu d l uranynit 1$2,155.10'~ n5m.

a/ kh6i lueqng mat nguyin tli flo: 19

= 3 ,156 .10-*~~ 6,02.loU

b/ Tj. kh6i clia hat nhln nguyin tir: rn 3,156. lo-'" d = - = = 6,0275.1 O'Qg 1 nz3 11 A ~ ( + . ~ ~ - I ~ ) ' 3

c/ Tj. lb th6 tich cua hat ilhlil SO vbi toan nguy&n tir flo:

BBi 2: (5 di&m) Hqp cl&t A2B6 c6 tang s6 hat trong phi11 tir 1 l 392, trong 66 s6 hat inang dibn nhiiu han s6 hat lh6ng mang didn 18 120 hat, s6 lth6i c i ~ a A it hon s6 kh6i ciia B l l 8.T6ng s6 11at trong A ~ ' it hail cua B- la 16. 11 Xlc djnh A,B. 21 6 700Uc, A2B6 phln li thanh AB3. ~ i k t cBng thirc chu tao Lewis ciia AB3 v l A2B6. a/ Cho bikt ltiku 1ai hoa cda nguydn tir A troilg AB3 v l A2B6. b/ ~ i 6 u li&n ltkt giira cac nguy&n tir trong AB3 v l A2B6 C/ Cho bikt dang hinh hpc ciia AB3.

Chch gi5i 1/ 4ZA + 2NA + 12ZB + 6NB = 392

4zA - 2NA + 12zB - 6N13= 120 - Z A - N A + ZB + No = 8 -2zA - N A + 2 z B + NB = 1 2

= > Z A = 13 =>A: A1 nhBinvaZg = 17 = > B : C1 clo 21 CBng thirc chu tao: cua AlCl, v i A12C16

2. a/ Trong AlC13 nhbm lai l1Oa sp2 ; trong A12C16 nh81n lai hoa

sp3 2.b/ Trong AlC13 c6 3 li6n ltkt cong h6a tr/ c6 cpc; trong A12C16 co 6 li6n ltkt c$ng hoa tr/ co c ~ c va 2 lien lt6t cho nhhn. 2.c/ Dylg hinh hgc clia AlC13 : tam giac phing

Bai 3: (5 diim) ~ 6 i vbi phi11 irng thutn ngh/ch pha lchi 2 SO2 + 0 2 i 2 SO3

a. Ngubi ta cho vao binh kin th& tic11 lch8ng dhi 3,O lit ~ n $ t h6n hap g6in 0,20 ~ n o l SO3 vh 0,15 11101 SO2. CBn bang h6a hgc dlrgc thikt lap tgi 25'C v i Bp suat chung cila he lh 3,20 atm. IHBy tin11 ti 14 oxi trong 11611 hap luc cdn bing.

b. Thi nghi&m lthac, cilng h 25'C, ng~rbi ta cho vao binh tr6n y 11101 lthi SO3. 6 trang thdi ciin bing thiy c6 0,105 mol 02. Ti1111 ti I& SO3 b/ phdn huy, thanh phin 116~ hop l d ~ i vB bp suit chung c i a h4

I

CLich giai a.

2 S 0 2 + O2 + 2 S 0 3 (1) ban d:.u 0,15 0,20 luc cb (0,15 + 22) z - (0,20 - 22) ~ 6 n g s6 11101 lthi lilc c i n bing

n , = 0,15 + 22 + z + 0,20-2z =0,35 + z 1',V = nlRT => 111 = PIV/(RT) = 3,2.3/(0,082.298) = 0,393 => z = 0,043.

b. 2 SO2 + 0 2 + 2 so3 (2)

ban dAu 0 0 Y luc cb 2. 0,105 0,105 (y - 2. 0,105). - 1 - 1 _+ - . r r ~ 6 : -.L.: / I \ . .A /? \ .,I ,.,. , I , , , , ,,2 T . , A

pppp--p--- I cbng V ndn ta co: K = const 1 0,5didin 2

"?YO, - - (0,20 - 2.0,043)'

Theo (1): K = --- 2 = 5,43

H , ~ ( , .no2 (0.1 5 + 0.086)'.0,043 2

"'so, Theo (2) - - (Y-0,21)'

= 5.43 n o .no (0,21)'.0,105

2 => y -0,42 y + 0,019 = 0 . y , = 0,369 y2 = 0,05 15 < 0,105 (loai bo nghiein y2 nay).

Do do ban d i u co y = 0,369 in01 SO, ; phBn li 0,2 1 in01 1G11 ti 1c SO3 phi11 l i la 56,9 1 % Luc ciin bing: t6ng s6 n ~ o l khi lh 0,369 + 0, 105 = 0,474 in01

TiY pt trang thii: P2V = n2RT n2 RT/ V = 0,474.0,082.298/3 = 3,86 atin.

Bl i 4: (5 diim) Cho c ic s6 lidu sau: c h i t

I (1tJ.inol- ) sozv8 (J. inol-'.~<-')

Ta co: (phan ung) = AGO298

C,l1,0kI - ( AGO298

C2H4 + AGO298 )

= - 168,6 -< 68,12 - 228,59) = - 8,13 1tJ Vi A G ~ ~ ~ ~ (phi11 irng) < 0 ndn phin h11g xay ra theo chi&u thu&n.

b AS0298 (phin hlg) = ~ " 2 9 8 C2H,0H -( s0298 ' ~ ' 2 9 8 )

C 2 H , H z ( '

= 282,O - (2 19,45 + 188,72) = - 126,17 J.I<-' = A13°298 - TASo298

+ ~ 1 3 ' 2 ~ 8 = AGO298 + TAS0298 = -8130+298.(- 126,17)=-45728,66J<O

, Phan irng toa nhiet.

a) d 2 5 ' ~ phi11 irng xiy ra the0 chi& nio? b) Phin irng trEn toa nhiet hay thu nl~iet?

Rli 5: (5 diBm) 1-1611 hqp X g6111 Fe va mijt kiln loai R c6 ho i tr/

4

Vhi phucmg trinh hoa hoc: C21H4 (k) + N20 (h) ig=2 C2I-15013 (h)

C2H50H (11) - 168". 282,O

Chch giai a) C2H4 (It) + H 2 0 (11) C2I-150H (h)

C2H4 (I<) H20 (h) 68,12 -228,59 "1 2 19,45 188,72

~ i 6 m

kl18ng ddi. t l o l tan hoan toin 5,5 gain X trong dung dich HCI du thu dugc 4,92492 lit lthi 6 27,3"C, 1 atm. M$t ldlric, 11oa tan hoan toan cing 5,5 gain X trong dung djch HNO, 1 ,OM (]Ay d ~ r 10%) thi thu du-gc 2240 1111 hAn hgp kl1i Y &in N20, NO (6 dktc) cb ti kh6i so vbi hdn hqp gain NO, C21-I6 1s 1,14 v i dung dich Z.

a) XQc din11 kim loai R va tin11 phln triinl kh6i luqng cila c ic kiln loai tl-ong X. b) Cho dung cljc11 Z t ic d ~ n g vbi 400 1111 dung djch NaOI-I thky xu$( hi&n 9,25 gain

kit tlia. Tinh nang d+ in01 clia dung djch NaOH, biit Fe(OII)3 l i i t tila hoan toin. ( C :12, 0: 16, N:14, Na: 23, Fe: 56, Mg: 24, Zn: 65, Al: 27, Ca: 40, Cu: 64)

Fe + 2HC1- FeCI2 + H2 (2) + X tac dung vbi HN03

Qua tl-inh oxi h6a: Fe - ~ e " + 3e; R - R"' + ne

Qua trinh l&G: 2N03- + IOH' + 8e - N 2 0 + 51-120 NO3- + 4H' +3e -+ NO -k 21-120

- Ggi x, y lkn l~rqt la sA in01 N 2 0 v i NO trong h811 hgp Y, ta co:

- Ggi a, b lkn lugt la s6 in01 cua R vB Fe trollg 5,5 gall1 hdn hgp X. Theo dfi liien d& cho va c ic phuang trinh, ta c6 he:

- Dung djch Z g a ~ ~ ~ : A13' (0,l mol); ~e"(0,05 mol); NO3-

- Cho NaOH vio dung dich 7, thi: F-I' -I- OH- - H 2 0 (3) ~ e " -I- 30H- - Fe(CH)3 (4) ~ 1 " + OH- - A I ( O H ) ~ (5)

a I . -IT- r A I I A T T \ 1- I / \

) a x & lugng k&t tila ~ e ( 0 1 - 1 ) ~ ~ 1 ~ 0 , 0 5 . 1 0 ~ 5,35 gain

=> X6t hai trubng hgp: * 1.1-1 (1): NaOH khBng 66 d& kit tila hkt AI~': sb in01 OH- c in dGng ll: (0,058 + 0,05.3 + 0,05.3) = 0,358 in01

9,25 - 5,35 3 s6 in01 clja Al(OH)3 IB = 0,05 (inol) < s6 mol A?'

7 8 0,25 dikin

* TI-1. (2): A I ~ ' phbi1 irilg sinh ra cb AI(OH)3 v l [AI(OH)4]- ~6 in01 NaOH = 0,058 + 0,05.3 + 0,1.3 3- (0,l - 0,05) = 0,558 in01

0,358 3 ~ 6 n ~ 60 c6a dung djch Na0l-l la: CM = - - - 0,895 M

074

Bhi 6: (5 di&m) Ngub.i ta ddng 16,8 lit kh8ng lchi h diBu kien chuin d6 dbt chiy hoin tohn 3,21 gam h6n hgp A 2 ainino axit kk tikp nhau c6 cung c6ng thirc tang quit CnI-12n+102N . 13Bn hop lchi thu dugc sau phi11 irng dugc lam kh6 dugc h6n hgp khi B, cho B qua dung djch Ca(O1-I)2 d ~ r thu Rugc 9,s gain k&t tba. ( 0 2 chikin 20% v i N2 chi&ill 80% th& tic11 kl16ng lchi) 11 Tim c6ng thirc phbn tir v l lch6i lugng clia 2 amino axit. 21 ~ k u cho khi B vlo bin11 c6 dung tic11 16,8 lit h nhi&t da 136,s°C, tinh i p suit trong biilh luc nay. ( 0 = 16,N = 14,I-I = 1; C = 12; Ca = 40; )

0,s di&m

Cach ~ i 5 i

Dat c6ng thirc chuilg cua 2 ainiilo axit: C,f12,+,0,N

- X flx

Cho B vao dung djch CE~(OH)~ C02 + CE~(OH)~ + CaC03 -t H 2 0 (2)

1 4 % + 4 7 x = 3 , 2 1 ~ ~ = 0 , 0 4 va 7i=2,375

CBng thirc phln tli v l cBng thirc ciu tao: - C2Ij5O2N ; 112N-CH2-C00kl - C3F1702N ; H2N-CH2-CH2- COOH

VB C113-CH(hTF12)-C001-I

---H&t---

Thi sinh i d m cdch ichdc mii d h g vzn cho diim t6i do.

SO CIAO DUC - DAO TAO ICY THI GIAI TOAN T R ~ ~ N MAY TINH CAM TAY NAM 201 4

DII CHINH THU'C

M6a thi: SINH HOC Lap: 12 H?: GDYT

Qui dj~ili: Hoc .shh 11-inh h 4 ~ \)&IT /GI cdch giiri. c6ng 1hri.c hj, C / ; I I I ~ , kh/ qu6 firzh /oh11 in20 6 /r6'ng 1ic;'n I& /,&I foh11. ('tic ki t qtln finh g ~ i ~ ~ dzi~ig, 17iu k116np cd chi di1111 clc thk, d t~qc rig6ni &nh chin11

r .

xhc rGi 4 c11G .v6 plidul /h43 p116n scru C I ~ I j,h&j~.

I C I U ~ N G DAN CI-IAM (GOM 06 TRANG)

BQi 1: (5 dikm) d ngvhi, qua trinh phdn giAi hi& khi hoan toail inQt phlll tir gluchzn dB sli. dung 2

ATP d& hoat hoa 6 giai doan duhng phdn. Mat bic si ilgubi My ilOi dba rillg Bng njilg 80 kg va "ng6n" hit timg db l~rqng

ATP m6i ngay Anh (chi) giii thich di&u iliy di~ng khBng? ~ i & t khau p l ~ i i ~ 5n clia nglriri My 80 kg hoat dGng trung bin11 il l& ngay 15 3000 I<cal; 1 ATP = 507,18 1 Oglmol; 1 cal = 4,1840 J; 1 11101 gluc6zc~ = 2870 I d .

- Theo d& bai ta c6 phuong trinh 116 hip: C6131206 + GO2 --> 6 C 0 2 + 61-120 + 36ATP - Ta c6: 3000 ltcal = 3000 x 1000 x 4,1840 = 12552000 J =

12552 1t.J - Theo ph~rnng trinh: s6 rnol gluc6za can d~rgc sir dung:

12552 : 2870 - 1255212870 ]no1 - S& in01 ATP c$n duqc sir dung: ( 1255212870) x 36 mol - ~ h 6 i lugng ATP m8i ngay d i Bbc si ilgubi My 80 kg ph8n giai: [(1255212870) x 361. 507,1810 = 79853,9696 g ~ 7 9 , 8 5 4 0 kg ATP - Phin tram kh6i l~rgng ATP so viri kh6i llrqng co th; Bac ST: 79,8540 . 100180 = 99,8 175% - ~ 6 t lu$n: ~ i b u Bhc si n6i l i dling, vi ik6i luqng ATP in&

ngiy 611g ti&u t h ~ ld~oing 99,8175% kh6i luqng ca thd 6ilg ta.

(0954 ~ i i u Bic ST n6i 1 i di~ng, v i 1ddi llrqng ATP in% nghy 6ng tieu thu ld~oang 99,8175% kh6i llrgng cn th& 6ng ta. (1,Od)

Lupu -J: - N&U HS tinh lu8n /<kt qud 12552/2870, cho kbt quLi snu lihi ldm trdn sd Id 79853.6197 se" lcl~dng cho di&w 6 phdn ki t quu6 (c61 b2n phcii)

T------- ----- (+ Kh6i Iup~ng ATP 1n6i n@y d& Bric si ngud.i

80 lcg ylzcin gibi = 84290,3013 g = 84,2903 kg + ~ h i n ttrZi171 khdi l ~ , * ~ n g A TP so v6i khdi l w n g co.

t h i Bdc si = 105.3629% ), vgn cho diAn tdi r h .

BAi 2: ( 5 di&m) d mot chlillg vi khu&~, n&u dugc nu6i cby irong di&u kien pH = 3 tlli thbi gian thi he

la 30 philt, cbn n&u iruhi cby b diBu ki&n pH = 4 thi thbi gian th& he la 20 philt. Dem nuhi ciy 10' tt& bao vi k11u8n noi tren trong 3 gib: 113 thbi gian nu6i cby trolrg 1116i tnrbng c6 do pH = 3; sau do C I I L I ~ & I sang ln6i trut~ng co do pH = 4. ~ i & t rang thk vi khuin nay trji qua pha tiem ph6t 6 rn6i tnrbng pl-I = 3 vhi thbi gian 30 phul va 6 in6i trvhng pH = 4 vhi Lhbi gia1 40 phi~t. Tinh s 6 ti! bAo vi lthuan duqc tao ra.

Cachih i -- - ---

- Thbi gian llu6i c&b nl6i t r~rbi~g c6 p1-1 = 3 la: 113 . 3 = 1 (gib). Vi g - 30 . phut . = 112 (gib) v l thhi gian pha tie111 phat la 30 phut 3 S6 t6 bao duac tao ra 6 in6i tr~rbng nay sau 1 gib la: N, = N o . 2' = 2. lo4 (t i bao)

- Thbi gian nu6i cdy b m6i trubng co pH = 4 la: 3 - 1 = 2 (gib). Vi g = 20 ph6t v i tllbi gian pha ti& phat la 40 phi~t 3 S6 tk bAo dugc tao ra sau thai giail nu6i c$y 6 ca 2 1116i tr~rbng la: N2 = N I . 24 = 2. 10'. 24 = 3 2 . lo4 (t i bao)

- N, = 2. lo4 (t i bao) (2,04

- N2 = 32 . 10' (tk bao) (3706)

BAi 3: ( 5 dikm)

Hey cho bi&i ty It % s6 phiin tir ATP thu duqc khi plrln giai mot phdn tli gluc8zn b 1116i Ang 11ghie11l SB 2, 3, 4 SO vhi 6ng nghitm sh 1 .

3.2. Mot dung d/ch chlia gluc6zu vh NaCl vbi ll&ng do lin lvqt 18 0,02M vh 0,OlM. Hgy xac d/nh ap suit thim thiu cila dung dich bi&t nhi&t do c i~a dung d/ch la 2 7 ' ~ .

3.1. Tiin hanh thi oghiem vhi 4 allg nghieill chira than11 phhn lchac nhau nh~r sau:

-- 4 Gluc6zcr va cac

t& bao bin11 lhubng

(kh6ng 6xi)

01% ,a

Tllirnll y ~ A ~ ~

Chch giBi 3.1. - ong nghie~n s 6 1: dign la diy d i ~ cBc giai dog11 116 hip hi& I t l ~ i nen nZng luqng t11u Cj~rqc la: 2 + 2 + 32 = 36 ATP. -

1 2 3 va ti

it& bao bin11 t$ bho chit th~rbng

(c6 dAy bu 6xi)

--

-

n--- ... i:c A n I ? , . A . . .

-- Iirgng thu d ~ r g c 1i 2 A?']). - o n g nghiem s6 3: khbng did1 ra 116 11ip n&11 khiing tgo n8ng lugng ATP. - o n g ng11iCm s8 4: di2n ru 116 116p ltj khi n@n n8ng luyng ihu dugc 1i 2 ATP. - Ty 1e O/o s6 1~l12il f i r ATP thu dugc Ithi pl15n giii 11161 phiin t~ glucbzcr 6: L

+ 011g SS 2 SO vbi Sng ~6 1 - (2136) x loo= 5,5556%.

-k o n g sb 3 so viri bng d 1 = (0136) x 100= 0%.

+ 011g SS 4 SO viri 611~ SS I - (2136) x loo= 5 , 5 ~ x i % .

(Luu jj: N ~ U HS tinll nrjwg /~rp.ng thu &rgc cho h6 h& hiku /chi la 38 ATP, rl~i t j lc Y6 clio dug ngghicm s6 2 vd s 6 4 id. 5,2632% thi v$a cho di6'111 16i da)

3.2. Glucbzcr la logi chit tail Ithbng diCn li nen i = 1. c h i t tan NaCl

lthi tan trong dung djcli thi die11 li hoan toail than11 ~ a ' va Cl- n & n c o h ~ s 6 i = = 1 + l(2 - 1 ) = 2 - Ap sui t thim th6u do glucbza g ly ra la:

0,082 x (273 +27) x 0,02 = 0,492 (atm) - Ap sui t th im th$u do NaCl gly i-a la:

0,082 x (273 +27) x 0,O I x 2 = 0,492 (atm) - til~lll thiu c i ~ a dullg djcl1 = 0,492 + 0,492 = 0,984 (alm)

--

- o n g ~a 2 SO viri S1lg

s6 1 = 5,5556'31 (1,Od) - 6 n g sS 3 so vbi dilg

1 = O N (1,Od) - Ong s8 4 so vai allg

s6 1 = 5,5556% (I,Od)

Bai 4: (5 di6111) Mot chu Iti tiin 6 ngu*bi trirbng thanh binh th~rbng lceo dai khoang 0,8 gily (s) va g6in

3 pha: pha co ti111 nhl, p l ~ a co tiim thit va pha d%n chung, tucrng 13ng vdi ti I$ 1 : 3 : 4. MQt BBc ST n6i vbi hen11 1111211 X (30 tudi) ring: "Nh/p ti111 cua cb do duyc la 95 l:nlphut l2i 1thA nhanh".

a. Anh (chi) co nhgn xdt gi v6 chuin doin clia B i c ST? So s h h tang thbi gian co v6i t6ng thbi gian d ln c i ~ a tiin h benh nhdn X? Thbi gian dl11 c i ~ a t8m nhi va t lm tldt h bdnh nhln X la bao nl~i@u?

b. N ~ U l u ~ * n g mau bum trong nlQt phht ra lch6i tiim cua c6 ta la 2,457 litlphut, 1~116i lugng iniu trong tim 6 cu8i tlnl thu 1s 78 in1 tlli kh6i luyng mau trong tiin h cuhi t d n ~ trucmg cua c6 ta la bao nllieu?

Cach giai ----- a. Nhan xet v6 chud11 doan cua BBc ST: Nhjp t i ~ n cua 11girb.i t r~rbng thanh binh thuirng: 60 : 0,8 = 75

lanlpl~ut. -Nh$n xkt: Nhjp ti111 6 b$llh 1111iil X nhailh hon nhip tim 6 ngui~ i trubng than11 binh thubng la: 95 - 75 = 20 nhip. Vay chuin doan cua Bac ST la dune.

- ~ 1 1 ~ ~ 1 1 doan cua BAc ST la Ali n 0 / I ~ A I

-- -ppppp

- Ta co thhi giaii cua 1 chu lci tin1 h b&nh nhln X 18: 60195 (gily)

-1- ~ 6 n ~ thbi gian co cila tim: (118 + 318) . 60195 = 0,3 158 (giiy)

+ ~ 6 n ~ thbi gian d$n ciia tim: (718 + 518) . 60195 = 0,9474 (gigy)

I<& lu@11: Tllbi gian tin1 d2n 1611 han 0,9474 - 0,3 158 = 0,63 16 giiiy so vbi thbi gian tin1 co.

+ Thiri gian d3n cua t im nhi = 718 . 60195 = 0,5526 (giiy) + Thbi gian dZn ciia trim th$t = 518 . 60195 = 0,3947 (gily) b. ~ h 8 i l~rqng ma11 trong tim d? cu6i ti111 truang:

(2,457 .1000/95) + 78 = 103,8632 ml

(0,Sit) -Tl~bi gian tiin d3il 1611 11011 0,63 16 giiiy so vbi thdi gian tin1 CO. ( I , O q

(0, sit) (0, 5 4

I I 2 Bai 5: (5 di&m)

Co hai gen I v i I1 vbi t6ng chi& dii 18 0,9 18 prn . Phbn tir pr6tein hotin chinh do gen 1 tallg hqp co s6 axit a~niil nhi&u h o i ~ s8 axit amin c i ~ a phbn tu prbt&in 11oBn cllinh do gel1 I1 tallg hqp 18 100 axit amin. Khi 2 gen nhBil d8i, m8i trubng nGi b8o c~ulg chp 28200 nucli%3tit tu do d& hinll thallh clic gel1 con.

a. Tinh s6 l ib nhbn d6i c i ~ a hai gen I va 11. b. Phi11 tu mARN duqc t6ng hqp t~ gen I ra 11goai t i bao chit v i d~rqc 1n6t sb

rib6xBin dk11 d6 dich mil. I<hi ribBx61n cubi ciiilg vh-a ti&p xuc vbi mARN thi m8i tnrbng nOi bio dB cung chp dugc 120 axit amin. Tinh sb ribBx8in tham gia qua trinh tang hgp pr6t&in n6i t r h . Cho bi&t cAc rib6xiim trugt cach d&u tr&n lnARN va khoBng cach giDa hai rib8x8111 lck c$n l i 8 1,6 A'.

c. Gen I bi dot bi&n m6t di Illat doan, doan bj dil.t vao gen I1 tao than11 hai gel1 I11 vii IV c6 chi$u dAi bing nhau. Hai gen 111 va IV cimg Iirn nhi$m vu tallg hqp mARN; tren inBi dogn mARN d&u co 5 rib6xBm truqt qua mat luqt vA thng s6 axit aillin tq do duqc 1118i trirbng nQi bAo cung cap d& djch m3 la 17960 axit a1ni11. Tin11 s6 1811 phien m3 cua gen I11 vA IV. Cho bi&t s6 plliin tir pr8t0in duqc dich m l tir gel1 I11 = 315 s6 phiin tG pr8ti.in duqc djch 1~13 ti( gen IV.

Cich giii --

a. - Goi N 1 i s6 nuclE6tit ciia gen. Ta co:

NI + lVI I= (2 ~ 0 , 9 1 8 x l o 4 ) : 3,4 = 5400(1) m (N1/6 - 2 ) - (N11/6 - 2 ) = 100 a N , - 1 2 - N l l + 1 2 = 6 0 0 m Nl - Nil = 600 (2) ~3~ (1) + (2) a N I = 3000; NII = 2400.

- G Q ~ x la s6 dqt nh3n d6i cila gen I, y la sb dgt nh5n d8i cua gel1 11. Ta co:

NI x (2' - 1) + NII x (2' - 1) = 28200 m 3000 x (2" - 1) + 2400 x (2' - 1) = 28200 a 5 x ( 2 ' - 1 ) + 4 x ( 2 ' - 1 ) = 4 7 ~ 5 x 2 " + 4 x 2 ' = 5 6 a 4 x 2 ' = 5 6 - 5 ~ 2 ' > O

-- -- < 5615 = 1 1,2

Vay gen I nhrin d6i 3 1411; gcn I1 nhin dAi 2 1$i. 1 1111i11 d8i 3 1211;

gen 11 nh5n d6i 2 1411.

- I<hi ribbx8m cubi citilg visa tiep xuc vhi inARN thi cli~ra djcli n ~ i i nen s6 axit aniin (a,) - 0.

Ggi 11 1i s6 ribAx6m, ta cb:

nhu sau: Giao tis ellira (A, B, D) = giao t3 chda (a, b, d) = 35% Giao tir cl~tia (A, B, d) = giao tb ch6a (a, b, D) = 9,5% Giao tb chua (A, b, D) = giao tis chira (a, B, d) = 4,5% Giao tir c l~ua (a, B, D) = giao tb c h h (A, b, d) = 1% a. I-IZy xAc bjnh trinh t!r s ip xip cac gel1 tl-G11 r~hizrn s i c th& (su dung 3 ge~z tr6i A, B,

D d l ~nivlh IIQO), Ichoang chch giaa cac gel1 theo don vi cM (centiMovgnn) b. Xic djnh he s6 trung hgp trong trlrbng hqp IrCn.

- ~ h l ~ g ~6 axit an1ii1 ~ ~ 1 1 g ~ A p : 11/2x[2.a, 4- (11 - ]).dl = 120

u nl2x[2.0 1 (11 - 1).8] = 120 C34n2-411- 120=O a n 2 - 11 - 30 = 0 3 Ta thu buac nghicm la 11 = 6; 11 = -5 (loai) V$y sb ribax6ln Id 6. C.

- ~ h i k u dai gen I11 = chi& d i i gel1 1V = 91 80 : 2 = 4590 A' 3 NIII = NIV = 2700. - Goi z 1;i sb 14n phiCn 1115 ciia gen 111.

t la sd l i n phi& 1115 cila gcn IV. - sb phbn tir protein la: 17960 : (270016 - I) = 40 - Taco: 5z + 51 = 40 (1)

5z - 3t (2) Ti r ( l )va(2) 3 z = 3 ; t = 5

V$y gen 111 phi2n m,i 3 lA11; gen IV phi&n ITIS 5 1h1.

(Lu-u y: N ~ I A hgc sinh tinh theo criclq khdc mii ding ddp dn vzn cho dtj diB~n) 7 - --

BBi 6: (5 ctiCm)

- ~6 rib6x6m 18 6 (1,06)

- Gel1 I11 p h i h 1113 3 lh1; gcn 1V phiell 111B 5 I . (2,Od)

--

6.1. 6 mat Jodi thuc vat, geri A quy din11 thBn cao trQi hoan toail so viri a quy djnh thbn tbip, gel1 B quy d/nll q~ la tron troi hoan toan so viri gen b quy din11 quh dai. Cac cap gen nay nim tr&o cling mot cap nhig~n s ic th& Csy ddj hap tir v& 2 cap gel1 giao p h $ ~ viri cby thin th&, qui tron thu duqc dbi con phA11 li Hheo ti 1e: 3 10 cgy thgn cao, qua tron : 190 cdy thin cao, qlli dii : 440 c8y thGn th&, qu8 trhn : 60 thin thbp, qua dai. Cho bikt k116ng co bet bi6n xay ra. Tin11 t$n s6 hoan vi gitia hai gen noi tren.

6.2. Met ccu th& cb 3 cap gen dj hap nBm tr&n cung 1n8t cjp nhiein shc thk, bing ph~mng phhp lei phiin tic11 ng~rbi ta xac d/nh dugc c a thd do dZ tao ra 8 loai giao tir v61 ti le

aB db-i P c6 ki&u gen d j hap -

nb LIB

- M i cby thin thip, qua tron dbi P : - tao giao tir & chiim nb

ti I$ 0,5 z Ciy dj hqp 2 cgp gel1 dbi P (Aa, Bb) teo giao tti ab chi&n ti 1e la: 0,06/0,5 = 0,12. Diy 16 giao tir hoin vj. - - V$y t$l s6 hobn v j giaa hai gen noi tr&n la: 2 x 0,12 = 0,24 = 24%.

6.2. a. Xac djnh trinh tlr sbp x6p cac gel1 tren nhi$m sbc thk,

lthoang cach gifia cac gen: + Co th& Inang 3 c3p gen di 119 n i m tr&n ci~ng 1 c@p

NST, cho 8 loai giao tir 3 Co hi&n tugng trao d6i cheo kep. + 2 loai giao tir (A, B, D) va (a, b, d) chi6111 ti Ie cao nhbt

z Dby 18 2 loai giao tlL Inang gen li&n Itit 3 Cac gel1 trGi A, B, D cung n$m tr&n 1 NST, cfing nhu cac gen Ian a, b, d cung I I $ I ~ tr&n 1 NST tucrng dhng.

-1 2 logi giao tii (a, B, D) vB (A, b, cl) chi&m ti le th& nhit z Dby 18 logi giao tli d~rqc hinh thanh do trao d6i chio kep. 3 Trinh tr,l' cac gel1 tr&n NST la: B A D .

4- Ttr cac loai giao tti (A, b, D) = (a, B, d) = 4,5% va (a, B, D) - (A, b, d) = I%. Chung dku chira thanh phin gen: (A, b) va (a, B) 3 IChoang chch gins hai gel1 B va A: 2x4,5% + 1 % = 10% =

10cM.

+ Tir cac loqi giao tii (A, B, d) = (a, b, D) = 9,5% v6 (a, B, D) = (A, b, d) = 1%. Chhng d&u cllira thanh phin gen: (A, d) va (a, D) 3 Ichoang cach giga hai gen A vA D: 2s9,50/0 t 1% = 20% =

20cM.

z Khoang cach giaa hai gel1 B va D: 10% + 20% = 30% =

30cM. (Hay khoang each B - D lb Icl~ocing cdch gii2a 2 gen da:u rntit = 100% - 2 ~ 3 5 % = 30% = 30 cM) b.

Xhc djnh he sb triing hap: i- T ~ I I sb trao d$i cheo ltep thlrc t i = 2 x 1'Yo = 2%. -t T B ~ s6 trao d6i cheo ltep li tbuy&t = 10Y0 x 20% = 2%

3 ~e s6 trung hpp = ( 2 ~ ~ 2 % ) . I O O = 100% ( I I L Z ~ he sB trirr~g Izop = I )

- I - ~ I I s6 hoa11 vi giVa hai gel1 0,24 (hay 24%)

- Trinh tu. cac gel1 tren NST la: B A D (1,OA)

- Khoang cach giVa hai gen B va A = 10% = 10cM. (0956)

- Khoang cach giaa hai gel1 A v i D = 20% = 20cM. ( 0 , W - IChoang cach giga hai gen B v6 D =30% = 30cM. (0,56)

- I I ~ s6 trung hqp = 100% (hay h i s6 triing I z ~ p = I )

fn C i r b

Qui cl j11 l i : Tlii xi~ilr /ri/111 hdv \)&/I i&/ cricli giUi, cring rhrk 617 d!lng, lie/ y i l i i rhih /oibi 1120 ,j rr.617~~ / I 1 I o ( i k , k i / quo /iwh g&~7 diing, i i i i l lchrklg nj chi djnh c5ri / / IC d~i,<)r- ngi;/77 iljiih c h b h Y ~ L , /rii -/ c/i$ ,xh/~hijii //1@/7 / 1 / 7 ~ ? / 7 .sr111 ( . / i l l ,717i i j~ .

HU'CII'NG DAN CHAM (COM 03 TKANG)

I3hi I : (5 iiiC171). I-Te s6 cila x2 vB s' trolig liliai ~ r i k n nlii thirc (Vj I Y)"' tucvng irng IB a vh h. , (7

I-1a"y t i nh gin d i~ng t i s6 - . h

BBi 2: ( 5 ctiim). Mot mhy vi ti1111 tri gi3 ban d i u IB 8 tr ieu dhng. Sau m8i n5m sir clung. gig tri c i ~ a may giini 7% so vbi nL?m hu6c c16. FJoi sau bao n h i h nc?m sir d u n g t h i gia 11-1 c i ~ a may cbn lgi 2.5 ( I ieu d8ng :'

---- Cicli giiii

-.

vikt dugc c8ng thirc PI, = P(1 - r)".

7 I cos-s = -

7

Ikii 4: (.5 i i ;C i l r ) . Tinh ghi ililng Ithodng cricl~ g i k hai itikm c!rc dai diim cyc 1i&1 cila d6 tl i , him

BBi 5: ( 5 dikm). Clio tam giic ABC c6 AE3 = 7cm. A(' = 9~111. BC - 10cm. Tinh gin dirng di$n tich hinh q u ~ l gijri hgn b6i cling nlib AH clia dlri~ng ttl-on t5m 0 ngogi tiel, v6 i tam giic A B C v i liai b i n Icinli O A , Ol3.

. . .. . - - - . . . - -

CIicli giiii ~ ~

3 , 5 7 4: Rgo 11~111: y ' :: -.y - - \ - - -

2 3 3 I

y ' = O @ -((I.\- '-10s-14)-0 6

X I - 1.9209; XI - - 0,8098 I - 5 : 7

y l = y ( x l ) = = - .\-, .' - - \ - . Y , 4- 1 --3.013 I 2 6 3

y.;= y(x2) - 2,0775

--

I = - x, ) I - ( - ) = 5.7758 . .

CAch giii

S , = 6 (cm2) 1.0

1 .o

2 ~ ' - AB' j: cosAOl3 = c o s a =

2 K' 1.0

= 19,8128 (em2). S =19,8128 (cm2). 2.0

..~ ~

BBi 6: (5 diim) Clio hinh chop S.ABCD co day ABCD 1i liinh [hang v~16ng lai A vA D; mat hen SAD 18 tam giic ct6u vA vu6ng goc v6i mat p l i i ng (ABCD). ~ii.t 4 B = AD - 12,48cn,; ( ' D = 6 , 1 2 ~ 1 ~ .

I ) l ' i n h gitn di~ng t l i i tic11 kh6i ch6p S.ABCD. 2) Tin11 gin dilng Itlioing cich tir diim El d i n mat l ~ l i ~ n g ( ~ ~ ~ ) .

... . ~ ~ .-

Cich giiii --p--p.-p-p-- ~

S

,4 O '! '' "' '

.... . L .

D h C'

-.----P---~.----~.~-----.- ~ L

. . . - - . , . I& q~ii I ~ i % m --

1.0

1 .0

d ~ 5 , 7 7 6 8

1.0 1 .O

1.0

(igi AB - A D = (1 = 1 2 . 4 8 ~ ~ va DC - h = (,,I 2 cm.

1 ) '~116 tic11 1<h6i ch6p S.Al3CD :

'".DiCn lich tall1 giac SAC : S,, ,, = 2

:': .I<lioing cich tir 13 dhn (SAC) b ing : - 0; f i

Cl13 Icy GTl :. .......... Chfi Icy G7'2 : .......... M.5 phach:. .......... ........ EIQ va ten thi siiih:. .......................................... ~3 bao danl~:..

Phong thi:. ...........

Man thi: TOAN THCS Lop: 9 Ht: GDPT Tlloi gian: 120 plli~t (Khdng /& rh6i gilrn giao &) Ngay thi: 07/12/2014 *Chu 9: - tlii n8y gain OR tsang, 06 bii, in6i bii 5 didm.

- Thi siilh lain b i i trvc tiip vao bAn d& thi njy.

MA PHACH (Do Chu tjch Hoi d6ng ghi)

Qui dCnh: - Thi sinh phai ghi dti cdc tnuc dphdli tl.611 theo scr h~rbng d& cti~r gidn/ /hi: - Thi .sin17 lirnl hiri trqrc ti& vcjo ban di thi cd phcicli ilinh kBn7 niiy; - Bdi thi phbi dwqc viit bhng ni!jt loqi buf, nl!jt 1h7i I I I ~ ~ C ; khdng vikt bing mcrc LIU, but chi; khdng

dvqc cfrjnh dku hay 1h111 ki hi(;* ribng,. ph&n vikt hdngphai dilng thr,rbc gqch chCo: kh6ng d7,rqc t&y. .wda bing bkt kj, cdch gi (ki ca but x8a).

- Tvdi vbi cac diju trGn, thi sinh s P hi loni. . . - Thi sinh trinh bhy vbn tbt cdch gidi, cdng th~i.c 41 &ng, kit qzii tinh fohn viro 6 tr-ing liin k i /,ai

todn. Cdc kkr qua tin17 g i n dung niu khdng cti chi 4 n h cy t i ~ i , ~I~rgc ngAm dinh chinh .rdc toi 4 ch2 s iphdn th& ph~in sau d&u yhuJ~.

Bii 1: (5 didin) a) Tim c113 s6 th&p phdn thir 2201 ' tsong phtp chia 20 1 1 cho 20 14. b) Tinh gi8 tr/ cba bidu thirc: (Ghi kbt qu6 drrdi d ~ n g s8 ttr nhiPn)

F = 2222255555 x 7777788888

C115 lcy GT 1 : ........... .......................................... 1-19 v i t6i1 t l~ i sinh:.

Trubng THCS: . . . . . . . . . . . . . . . . . . . . . . . .I-luyen:. .............

......... SS bko danh:. Phong thi:. ...........

Bai 5: (5 di&m) Cho tan1 giac ARC vubng tai C. VE duivng trbn bin Icinll r noi ti&p tain giac ABC.

Goi tiip di&m c6a can11 AB v&i cluirng trhil l i D. ~ i & t BD = 111 = 3,572~111 v9 AD =

11 = 4,205~1~1. a) Tin12 dicn tich tan1 giac ABC. b) Tinh dien tich hinh cha nh$t CMDK (M thuoc canh CB, K thuoc canh CA).

,- * *

Chi7 lcy GT1:. ...... .... C11tl Icy GT2:. .......

......... Ho va ten t l ~ i sinh:. .......................................... s3 bao danh:. Trubng TIIC S : ....................... .lIuy!n:. ............. Phong thi:. ...........

Bai 6: (5 di&m) Cho tam giac ARC vuBng tai A. ~ i k t AB = 9,039~1~1, AC = 12,052~111. Til A vC

dlrbng phln giac AD va trung tuy&n AM (D va M thu$c BC). a) Tinh do d i i cac doan thing AM, BD. b) Tinh dien tich cac tain giac ADM.