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Solving sets of linear equations; Matrix inversion Ax=b Input Matrix(A) Result vector(b) -8 1 2 0 5 7 -3 10 2 1 -2 -2 Inverse Matrix (1/A) Solution vectorx=(1/A)b -0.14865 0.054054 -0.22973 1 0.054054 0.162162 -0.18919 2 -0.12162 0.135135 -0.82432 3

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fig10-1Solving sets of linear equations; Matrix inversionAx=bInput Matrix(A)Result vector(b)-812057-31021-2-2Inverse Matrix (1/A)Solution vectorx=(1/A)b-0.14864864860.0540540541-0.229729729710.05405405410.1621621622-0.18918918922-0.12162162160.1351351351-0.82432432433

fig10-2Solving sets of equations:Gauss-Seidel iterationInit FlagInitialEquationsSolutionsValues01.00000000570.999999936702.00000004522.0000000452033

solverSolving sets of equations, solver method011.428571428615.111111111116.5396825397