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MAT 125 – Applied Calculus 1.4 Straight Lines

MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class We will be learning the following concepts in Section 1.3: The Cartesian Coordinate System

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Page 1: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

MAT 125 – Applied Calculus1.4 Straight Lines

Page 2: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

2 Today’s Class

We will be learning the following concepts in Section 1.3: The Cartesian Coordinate System

The Distance Formula

The Equation of a Circle

We will be learning the following concepts in Section 1.4: Slope of a Line

Equations of Lines

Dr. Erickson

Page 3: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

3

Slope of a Nonvertical Line

If (x1, y1) and (x2, y2) are two distinct points on a nonvertical line L, then the slope m of L is given by

2 1

2 1

y yym

x x x

(x1, y1)

(x2, y2)

y

x

L

y2 – y1 = y

x2 – x1 = x

Dr. Erickson

Page 4: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

4

Slope of a Vertical Line

Let L denote the unique straight line that passes through the two distinct points (x1, y1) and (x2, y2). If x1 = x2, then L is a vertical line, and the slope is undefined.

(x1, y1)

(x2, y2)

y

x

L

Dr. Erickson

Page 5: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

5

Slope of a Nonvertical Line

If m > 0, the line slants upward from left to right.

y

x

L

y = 2

x = 1

m = 2

Dr. Erickson

Page 6: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

6

Slope of a Nonvertical Line

If m < 0, the line slants downward from left to right.

m = –1

y

x

L

y = –1

x = 1

Dr. Erickson

Page 7: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

7

Sketch the straight line that passes through the point (1, 2) and has slope – 2.

1 2 3 4 5 6

y

x

6

5

4

3

2

1

Example 1

Dr. Erickson

Page 8: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

8

Find the slope m of the line that goes through the points (–2, –2) and (4, –4).

Example 2

Dr. Erickson

Page 9: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

9

Let L be a straight line parallel to the y-axis. Then L crosses the x-axis at some point (a, 0), with the x-coordinate given by x = a, where a is a real number. Any other point on L has the form (a, y), where y is an appropriate number. The vertical line L can therefore be described as x = a

Equations of Lines

(a, y )

y

x

L

(a, 0)

Dr. Erickson

Page 10: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

10 Equations of LinesLet L be a nonvertical line with a slope m.

Let (x1, y1) be a fixed point lying on L and (x, y) be variable point on L distinct from (x1, y1).

Using the slope formula by letting (x2, y2) = (x, y) we get

Multiplying both sides by x – x1 we get

1

1

y ym

x x

1 1( )y y m x x

Dr. Erickson

Page 11: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

11 Point-Slope Form of an Equation of a Line

An equation of the line that has slope m and passes through point (x1, y1) is given by

Dr. Erickson

1 1( )y y m x x

Page 12: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

12

Find an equation of the line that passes through the point (2, 4) and has slope –1.

Example 5

Dr. Erickson

Page 13: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

13

Find an equation of the line that passes through the points (–1, –2) and (3, –4).

Example 6

Dr. Erickson

Page 14: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

14 Parallel Lines

Two distinct lines are parallel if and only if their slopes are equal or their slopes are undefined.

Dr. Erickson

Page 15: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

15 Perpendicular Lines

If L1 and L2 are two distinct nonvertical lines that have slopes m1 and m2, respectively, then L1 is perpendicular to L2 (written L1 ┴ L2) if and only if

Dr. Erickson

12

1m

m

Page 16: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

16

Example 7

Find an equation of the line that passes through the point (2, 4) and is perpendicular to the line

Find an equation of the line that passes through the origin and is parallel to the line joining the points (2,4) and (4,7).

3 4 22 0.x y

Dr. Erickson

Page 17: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

17

Crossing the Axis

A straight line L that is neither horizontal nor vertical cuts the x-axis and the y-axis at, say, points (a, 0) and (0, b), respectively.

The numbers a and b are called the x-intercept and y-intercept, respectively, of L.

(a, 0)

(0, b)

y

x

L

y-intercept

x-intercept

Dr. Erickson

Page 18: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

18 Slope Intercept Form of an Equation of a Line

An equation of the line that has slope m and intersects the y-axis at the point (0, b) is given by

y = mx + b

Dr. Erickson

Page 19: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

19 Example 8Find the equation of the line that has the following:

m = –1/2; b = 3/4

Dr. Erickson

Page 20: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

20 Example 9Determine the slope and y-intercept of the line whose equation is 3x – 4y + 8=0.

Dr. Erickson

Page 21: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

21Example 10

Dr. Erickson

Page 22: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

22 General Form of an Linear Equation

The equation

Ax + By + C = 0

where A, B, and C are constants and A and B are not both zero, is called the general form of a linear equation in the variables x and y.

Dr. Erickson

Page 23: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

23 Theorem 1

An equation of a straight line is a linear equation; conversely, every linear equation represents a straight line.

Dr. Erickson

Page 24: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

24 Example 11Sketch the straight line represented by the equation 3x – 2y +6 = 0.

Dr. Erickson

Page 25: MAT 125 – Applied Calculus 1.4 Straight Lines. Today’s Class  We will be learning the following concepts in Section 1.3:  The Cartesian Coordinate System

1.4 Straight Lines

25 Next Class

We will discuss the following concepts: Functions

Determining the Domain of a Function

Graphs of Functions

The Vertical Line Test

Please read through Section 2.1 – Functions and Their Graphs in your text book before next class.

Dr. Erickson