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NAME _______________________
ID # _______________________
ORGANIC CHEMISTRY I (2301)
9:30 – 10:45 am, August 2, 2012
Final Exam There will be two ways that you can pick up your graded Final Exam:
You can pick up your graded exam from Andy at office hours that he will hold on Monday, August 6th (9:30-10:30 am) at Coffman Union Starbucks.
Alternately, you will be able to pick up your graded exam from Chemistry department staff in 115 Smith beginning Monday, August 6th at noon. Exams that are not picked up within two weeks will be disposed of.
A periodic table, a chart of reaction conditions, and a table of typical NMR chemical shifts are attached to the back of this exam as aids. Otherwise, you are not permitted to use any other materials (including notes, books, or electronic devices of any kind). Right now, write your name and student ID number at the top of this page. When the exam begins, please write your name at the top of the next page. You may use pen or pencil. However, re-grades will be considered only for exams completed in pen. Please write your answers in the boxes/spaces provided. If your answer is not in the appropriate space (say, for example, it’s on the back of the page), draw us an arrow and/or note telling us where to look.
2
NAME _______________________
Scoring: 1. _________ / 14 6. _________ / 25 2. _________ / 15 7. _________ / 16 3. _________ / 12 8. _________ / 16 4. _________ / 15 9. _________ / 29 5. _________ / 8 Total Score: _________ / 150
1. (14 pts) For each of the pairs of acids (or bases) below, Draw the conjugate base (or acid). Circle whether you think the first acid (or base) is more or less acidic (or basic) than the
second. Acid Conjugate Base Base Conjugate Acid
is
MORE ACIDIC
LESS ACIDIC
than
is
MORE BASIC
LESS BASIC
than
N
H
H
H
H
HO
H
H
O
H3C CH3
OH
H3C CH3
3
2. (15 pts) For the anion drawn at right, in the boxes provided:
Draw all significant resonance structures. In each structure, draw all atoms, bonds, lone pairs of electrons, and formal charges. Then, circle which resonance structure you think is the most significant, and which is the least. Circle only one MOST and one LEAST.
Draw a Lewis wedge/dashed-bond structure that illustrates the most stable three-dimensional conformation of the molecule. Draw all atoms, bonds, and charges, but omit lone pairs.
In the boxes provided, write the hybridization state on any atom heavier than hydrogen.
3. (12 pts) Each of the reactions below and on the next page is drawn with two possible
products. If one of the two products predominates, circle that preferred product. If the two products are produced equally, circle “BOTH”. If neither product would result from the reaction, circle “NEITHER”. Circle one answer only.
C CH
H
H
C
HO
C
H
H
H
3-dimensional representation
CN H
H
H
C
O H
C
H
H
H
O
atom hybridizations:
MOST or LEAST significant?
C CC C
resonance structure
MOST or LEAST significant?
BOTH (equally)
NEITHER
EtOH
Br
CH3
CH3
CH3
CH3
CH3
CH3
4
4. (15 pts) For each of the reactions below, fill in the empty box corresponding to the major
product. Wherever appropriate, illustrate stereochemistry in your drawings (using wedge and dashed bonds). If multiple enantiomers or diastereomers are produced, indicate this in the answer box (e.g., by writing “+ enantiomer”, etc.)
Br2
BOTH (equally)
NEITHER
(1 equiv) C C CH3H3C
H3C
CH3
Br
Br
H3CCH3
Br Br
Br Br
BOTH (equally)
NEITHER
mCPBA
H
CH3
H3C
HO
H3C H
H CH3
O
H CH3
H3C H
H2SO4
H2O
N
O
O
Br
(NBS)
AIBN
CH3
5
5. (8 pts) Each of the reactions below is drawn with two possible reaction conditions. If only
one of the two reaction conditions would generate the given molecule as the major product, circle those conditions. If both sets of conditions would accomplish the reaction, circle “BOTH”. If neither set of reaction conditions would succeed, circle “NEITHER”. Circle one answer only.
BOTH would work
NEITHER would work
Na2Cr2O7 H2SO4
1. (COCl)2, DMSO -60 °C 2. Et3N (Swern oxidation)
BOTH would work
NEITHER would work
Na, NH3
Pd, BaSO4 quinoline, H2 (g)
(Lindlar’s catalyst)
OH O
O
H
Br
CH3O Na
6
6. (25 pts) When the epoxide-alcohol starting material below is deprotonated with NaH, the resulting alkoxide reacts with itself to open the epoxide. That reaction, followed by acidic workup, can produce two different products; the difference between the products is dictated by which epoxide carbon is attacked by the alkoxide.
In this problem, we will name the products A and B, which are formed by protonation of intermediates A and B. (a) Using “electron pushing”, draw a mechanism that illustrates the formation of
intermediates A and B from the alkoxide. I’ve drawn the starting material for you—just add curved arrows to my structure. Then, draw the structures of intermediate A and intermediate B. Wherever appropriate, illustrate stereochemistry.
(b) Is intermediate A intermediate B?
O
H
H CH3
OH
1. NaH
(-H2)
O
H
H CH3
O Na
intermediate A
intermediate B
product A
product B
2. H3O+
2. H3O+
intermediate B
O
H
H CH3
O
O
H
H CH3
O
push electrons
here
intermediate A
MORE STABLE
than
the SAME
ENERGY as
LESS STABLE
than(Circle one.)
7
(c) On the potential energy diagram below, draw two curves that represent the two reactions you drew in part (a). The starting material (alkoxide) energy has already been drawn for you—you need to connect this starting point to energies of the reaction transition states, intermediate A, and intermediate B.
(d) How would the rate of the two reactions be affected if the starting material were a thiol instead of an alcohol? Assume that the thiolate on the right has the same energy as the alkoxide above, and that the sulfur-containing intermediates AS and BS are also the same energy as intermediates A and B. Would the thiolate react
the alkoxide? (Circle one.)
E
reaction coordinate
starting alkoxide intermediates A/B
O
H
H CH3
O
O
H
H CH3
S
FASTER than
the SAME RATE
as SLOWER
than
8
7. (16 pts) Draw a mechanism (using “electron pushing”) for each of the reactions shown on the next page. Draw each mechanistic step explicitly; don’t cheat by combining multiple processes in a single step. Use only the molecules shown in the problem; don’t invoke generic species. (E.g., don’t use “H-A” as a generic acid.)
Mechanism:
H2SO4 OH
9
8. (16 pts) For each set of starting materials and products shown below, propose a multistep synthesis. In addition to the molecules shown, you can use any reagents and reactions we’ve learned about in class. You might discover multiple answers to this problem; draw only your best (one) synthetic route. Feel free to draw an incomplete route—we will give you partial credit where we can.
Multistep synthesis:
C C HH
OH
H3C
OBr
Br
10
9. (29 pts) Acrylonitrile, the starting material on the right, can be polymerized into polyacrylonitrile (a component of plastic consumer goods) by heating it in solvent, but heating acrylonitrile in a mixture of ethanol and water generates a small molecule product instead. This product was isolated and characterized by NMR and IR spectroscopy and mass spectrometry; the spectra of this product are shown on the next two pages. High-resolution mass spectrometry determined an exact mass of 99.06840 amu for the highest-mass (parent, M+) peak in the MS spectrum, which corresponds to a molecular formula of C5H9NO.
(a) Based on the features in the IR spectrum below, what functional groups would you
expect the unknown molecule to have? Circle all answers that apply.
IR Spectrum:
(b) What is the structure of the product? In the box on the next page, draw the molecule’s
structure, including all hydrogens. Then, considering the 1H NMR spectrum,
C(sp2)
H
C C
C(sp)
H
C O
CN C5H9NO
H2O CH3CH2OH
100
50
0
4000 3000 2000 1500 1000
Tra
nsm
ittan
ce (
%)
(wavenumbers, cm-1)
2256
2982
O
H
C(sp3)
H
N
H
C N C C C N
11
Circle each group of equivalent H’s; Assign a 1H chemical shift () to each circled group, within 0.05 ppm; Connect any pair of coupled, inequivalent groups of H’s with a double-headed arrow,
and then label that arrow with the corresponding coupling constant (J).
1H NMR Spectrum:
the product (C5H9NO)
Format for answer to (c):
Cl Cl
H H
H H
H H
= 2.2 ppm
= 3.8 ppm
J = 7.0 Hz
12
(c) In an electron-ionization (EI) mass spectrometry experiment, parent ions often fragment into daughter ions that give information about the parent’s molecular structure. In the EI mass spectrum below, the parent mass peak at m/z = 99 corresponds to a radical cation (M•+) that fragments into ions with mass 84 and 59. In the boxes below, draw the structures of these ions. You do not need to do electron pushing to answer this question—just draw the cations. On all ion structures, make sure to specifically illustrate where the formal charge lies.
Mass Spectrum:
100
0
Rel
ativ
e In
tens
it y
m/z
20 40 60 80 100
99
84
59
54
M•+ (C5H9NO+, m/z = 99)
fragment ion with m/z = 59 fragment ion with m/z = 84
Final Exam Chart of Reaction Conditions
Cl2 or Br2, h
H2SO4 H2O
1. BH3•THF 2. H2O2, OH-
Cl
O
OO
H
(mCPBA)
mCPBA H2O
KMnO4 (cold, dilute)
H2O, OH-
1. O3 2. (CH3)2S
Pt/H2(g)
NaNH2
Na NH3
HgSO4 H2SO4 1. KMnO4
KOH, 2. H3O
+
Pd, BaSO4 H2(g)
(quinoline)
N
(NBS)
h or AIBN
N
O
O
Br
Na2Cr2O7 H2SO4 1. (COCl)2
DMSO -60 °C 2. Et3N
(Swern oxidation)
TsCl pyridine
SOCl2 pyridine
PBr3
1. O3 2. H2O
KMnO4 H2O, pH 7
Per
iodi
c Ta
ble
of th
e E
lem
ents
C
hem
istr
y R
efer
ence
She
et
Cal
iforn
ia S
tand
ards
Tes
t
Sod
ium
22.9
9
Na
11
Ato
mic
num
ber
Ele
men
t sym
bol
Ave
rage
ato
mic
mas
s*
Ele
men
t nam
e
Hyd
roge
n1.
01H1
Lith
ium
6.94Li3
Sod
ium
22.9
9
Na
11
Pot
assi
um39
.10
19 K
Nic
kel
58.6
9
Ni
28
Rub
idiu
m85
.47
Rb
37
Rut
herfo
rdiu
m
(261
)
Rf
104
Mol
ybde
num
95.9
4
Mo
42
Ger
man
ium
72.6
1
Ge
32
1 1A
2 2A
1 2 3 4
7 7B
11 1B
12 2B
13 3A
16 6AK
ey 8
5 6 7
9 8B
10
14 4A
15 5A
17 7A
18 8A
3 3B 4 4B
5 5B
6 6B
Cop
per
63.5
5
Cu
29
Cob
alt
58.9
3
Co
27
Hel
ium
4.00
He2
Bor
on10
.81
B5
Car
bon
12.0
1
C6
Nitr
ogen
14.0
1
N7
Oxy
gen
16.0
0
O8
Flu
orin
e19
.00
F9
Neo
n20
.18
Ne
10
Alu
min
um26
.98
Al
13
Sili
con
28.0
9
Si
14
Pho
spho
rus
30.9
7
P15
Sul
fur
32.0
7
S16
Chl
orin
e35
.45
Cl
17
Arg
on39
.95
Ar
18
Cal
cium
40.0
8
Ca
20
Sca
ndiu
m44
.96
Sc
21
Tita
nium
47.8
7
Ti
22
Chr
omiu
m52
.00
Cr
24
Iron
55.8
5
Fe
26
Zin
c65
.39
Zn30
Gal
lium
69.7
2
Ga
31
Ars
enic
74.9
2
As
33
Sel
eniu
m78
.96
Se
34
Bro
min
e79
.90
Br
35
Kry
pton
83.8
0
Kr
36
Str
ontiu
m87
.62
Sr
38
Yttr
ium
88.9
1
Y39
Zirc
oniu
m91
.22
Zr
40
Nio
bium
92.9
1
Nb
41
Tech
netiu
m(9
8)Tc
43
Rut
heni
um10
1.07
Ru
44
Rho
dium
102.
91
Rh
45
Pal
ladi
um10
6.42
46
Silv
er10
7.87
Ag
47
Cad
miu
m11
2.41
Cd
48
Indi
um11
4.82
In49
Tin
118.
71
Sn
50
Ant
imon
y12
1.76
Sb
51
Tellu
rium
127.
60
Te52
Iodi
ne12
6.90I53
Xen
on13
1.29
Xe
54
Ces
ium
132.
91
Cs
55
Bar
ium
137.
33
Ba
56
Lant
hanu
m13
8.91
La
57
Haf
nium
178.
49
Hf
72
Tant
alum
180.
95
Ta73
Tung
sten
183.
84
W74
Rhe
nium
186.
21
Re
75
Osm
ium
190.
23
Os
76
Irid
ium
192.
22Ir77
Pla
tinum
195.
08
Pt
78
Gol
d19
6.97
Au
79
Mer
cury
200.
59
Hg
80
Tha
llium
204.
38
Tl
81
Lead
207.
2
Pb
82
Bis
mut
h20
8.98
Bi
83
Pol
oniu
m(2
09)
Po84
Ast
atin
e(2
10)
At
85
Pd
Rad
on(2
22)
Rn
86
Fran
cium
(223
)
Fr
87
Rad
ium
(226
)
Ra
88
Act
iniu
m(2
27)
Ac
89
Dub
nium
(262
)
Db
105
Sea
borg
ium
(266
)
Sg
106
Boh
rium
(264
)
Bh
107
Has
sium
(269
)
Hs
108
Mei
tner
ium
(268
)
Mt
109
Mag
nesi
um24
.31
Mg
12
Ber
ylliu
m9.
01Be4
Van
adiu
m50
.94
V23
Man
gane
se54
.94
Mn
25
* If
this
num
ber
is in
par
enth
eses
, the
n
it r
efer
s to
the
atom
ic m
ass
of th
e
mos
t sta
ble
isot
ope.
Pra
seod
ymiu
m
140.
91
Pr
59
Men
dele
vium
(258
)
Md
101
Cer
ium
140.
12
Ce
58
Neo
dym
ium
144.
24
Nd
60
Pro
met
hium
(145
)
Pm61
Sam
ariu
m15
0.36
Sm62
Eur
opiu
m15
1.96
Eu
63
Gad
olin
ium
157.
25
Gd
64
Terb
ium
158.
93
Tb65
Dys
pros
ium
162.
50
Dy
66
Hol
miu
m16
4.93
Ho
67
Erb
ium
167.
26
Er
68
Thu
lium
168.
93
Tm69
Ytte
rbiu
m17
3.04
Yb
70
Lute
tium
174.
97
Lu71
Tho
rium
232.
04
Th90
Pro
tact
iniu
m23
1.04
Pa
91
Ura
nium
238.
03
U92
Nep
tuni
um(2
37)
Np
93
Plu
toni
um(2
44)
Pu
94
Am
eric
ium
(243
)
Am95
Cur
ium
(247
)
Cm96
Ber
keliu
m(2
47)
Bk
97
Cal
iforn
ium
(251
)
Cf
98
Ein
stei
nium
(252
)
Es
99
Fer
miu
m(2
57)
Fm
100
Nob
eliu
m(2
59)
No
102
Law
renc
ium
(262
)
Lr
103
Co
pyr
igh
t ©
200
8 C
alifo
rnia
Dep
artm
ent
of
Ed
uca
tio
n