Upload
others
View
1
Download
0
Embed Size (px)
Citation preview
1
3 | 10http://themalloryfamily.net
CHAPTER 4Work
http://themalloryfamily.net 4 | 11
Work
• Work - the product of the magnitude of the force (F) and the parallel distance (d) through which the object moves
• work = force x parallel distance• W = Fd• Mechanically, work involves both force and
motion
Section 4.1
http://themalloryfamily.net 4 | 12 http://themalloryfamily.net 4 | 13
No work is done because there is no movement (d = 0)
Section 4.1
•10 •11
•12 •13
2
http://themalloryfamily.net 4 | 14 http://themalloryfamily.net 4 | 15
Work Being Done Applied force (F) through a distance (d)
Section 4.1
http://themalloryfamily.net 4 | 16
Work - Units
• SI System– W = Fd newton x meter = Nꞏm = joule (J)
• British System– W = Fd pound x foot = foot-pound (ft-lb)
Section 4.1
Nꞏm = joule (J)N = newton = kgꞏm/s2
J = kgꞏm2/s2
http://themalloryfamily.net 4 | 17
Working against Something
• When work is done, we generally feel the other part of Newton’s third-law force acting against us
• Gravity and friction are common agents working against work
• In the case of gravity, we must apply force to overcome the force of gravity (weight = w = ma)
• Work = W= Fd = wd = mad – (d is the distance lifted)
Section 4.1
•14 •15
•16 •17
3
http://themalloryfamily.net 4 | 18
Energy
• The ability to do work. An object or system that possesses energy has the ability to do work
• When work is done by a system, the amount of energy of the system decreases ↓
• When work is done on a system, the system gains energy ↑
• Work is the process by which energy is transferred from one object to another
• Work and Energy have the same units – joules
Section 4.2 http://themalloryfamily.net 4 | 19
Kinetic Energy
• Kinetic Energy - the energy an object possesses because of its motion, the energy of motion
• kinetic energy = ½ x mass x (velocity)2
• Ek = ½mv2
• If an object is already moving• Work = change in kinetic energy• W = k = Ek2 – Ek1 = ½mv2
2 - ½mv12
Section 4.2
http://themalloryfamily.net 4 | 20
Potential Energy
• Potential Energy - the energy an object has because of its position or location, the energy of position
• Most potential energy is due to gravity• Remember that:
– Work = Force x distance (W = Fd)– Weight is a force (w = ma where a=9.80 m/s2)
• Therefore W = mad– Grav. potential energy = weight x height
• Ep = madSection 4.2 http://themalloryfamily.net 4 | 21
•18 •19
•20 •21
4
http://themalloryfamily.net 4 | 22
Gravitational Potential Energy
• The gravitational Potential Energy is equal to the work done and this is equal to the weight times the height
• W = Ep = mad• Example: How much work is done lifting a 1.0
kg book to the height of 1m?• Work = W = (1.0 kg) (9.8 m/s2) (1m) = 9.8 J• This is also the amount of Ep that the book has
at a height of 1m
Section 4.2 http://themalloryfamily.net 4 | 23
Potential Energy
• Depends only on the initial and final positions (difference in height - d) and is independent of path
• If we disregard any frictional loss, it takes the same amount of work (W) to lift the mass (m), no matter the path
Section 4.2
http://themalloryfamily.net 4 | 24
Work = change in potential energy• Work = W = Ep = mad = mad• In the previous examples the d is actually d• Work is done when there is a change in position• Therefore the reference point for measuring
heights is arbitrary (but must be internally consistent)
Section 4.2 http://themalloryfamily.net 4 | 25
Reference Point No matter which scale – d is the same
Section 4.2
•22 •23
•24 •25
5
http://themalloryfamily.net 4 | 26
Conservation of Energy
• Energy can neither be created nor destroyed.• In changing from one form to another, energy is
always conserved• The total energy of an isolated system remains
constant• (total energy)time1 = (total energy) time2• The total energy does not change with time
Section 4.3 http://themalloryfamily.net 4 | 27
Conservation of Mechanical Energy
• To simplify we will deal with ideal systems – in which energy is only in two forms – kinetic and potential
• Total Energy = Ek + Ep
• Conservation of energy(Ek + Ep)1 = (Ek + Ep)2
(½mv2 + mad)1 = (½mv2 + mad)2
Section 4.3
http://themalloryfamily.net 4 | 28
Conservation of Energy Finding Kinetic and Potential Energies
• A 0.10 kg stone is dropped from a height of 10.0 m. What will be the kinetic and potential energies of the stone at the heights indicated in the figure (neglect air resistance).
• ET = Ek + Ep will be true at all heights.
• At the moment the stone is released ET= Ep (Ek = 0)
• At the moment the stone hits the ground ET = Ek (Ep = 0)
Section 4.3 http://themalloryfamily.net 4 | 29
Solve for Ep and Ek at heights indicated
• At any height, the potential energy Ep = mad
• d = 10 m: Ep = (0.10 kg)(9.8 m/s2)(10.0 m) = 9.8 J• d = 7 m: Ep = (0.10 kg)(9.8 m/s2)(7.0 m) = 6.9 J• d = 3 m: Ep = (0.10 kg)(9.8 m/s2)(3.0 m) = 2.9 J• d = 0 m: Ep = (0.10 kg)(9.8 m/s2)(0 m) = 0 J• ET = Ek + Ep
• Ek = ET - Ep
Section 4.3
•26 •27
•28 •29
6
http://themalloryfamily.net 4 | 30
Solve for Ep and Ek at heights indicated
Height(m)
ET(Joules)
Ep(Joules)
Ek(Joules)
10.0 9.8 9.8 0
7.0 9.8 6.9 2.9
3.0 9.8 2.9 6.9
0 9.8 0 9.8
Section 4.3
ET = Ek + Ephttp://themalloryfamily.net 4 | 31
Magnitude of Velocity
• Potential Energy (Ep) converted = mad• Converted into Kinetic Energy (Ek) = ½mv2
• Since all the Ep is converted into Ek just before hitting the ground, we can use this to compute the speed or magnitude of velocity
• Therefore: ½mv2 = mad• ½v2 = ad (cancel m’s)• v2 = 2ad (solve for v)
Section 4.3
2ad• v =
http://themalloryfamily.net 4 | 32
Power – SI System
• Power - the time rate of doing work
• SI Units J/s = Watt (1 J/s = 1 W)• For example a 100W light bulbs uses 100
joules/second of electrical power or 100 Watts• Careful not to confuse W (work) with W (watt)
Section 4.4
worktime
Wt
Fdt
• Power = = =
http://themalloryfamily.net 4 | 33
Force of 1.0 N to raise a mass 1.0 m, the amount of work done is 1.0 J. If this work is done in 1.0 s, then the power is 1.0 W
Section 4.4
•30 •31
•32 •33
7
http://themalloryfamily.net 4 | 34
Quantity Unit SymbolEquivalent
Units
Force newton N Kgꞏm/s2
Work joule J Nꞏm
Energy joule J Nꞏm
Power watt W J/s
A Review of SI Units
Section 4.4 http://themalloryfamily.net 4 | 35
Energy
• No matter what type of energy that we speak of – chemical, electrical, mechanical – the main unifying concept is the conservation of energy
• We cannot create or destroy energy, but we can change it from one form to another
Section 4.5
http://themalloryfamily.net 4 | 36
Forms of Energy
• Thermal (heat) Energy – related to the kinetic and potential energies on a molecular level
• Gravitational potential energy – from an object’s position, stored gravitational energy
• Electrical energy – associated with the motion of electric charges
• Chemical energy – molecular bonds• Radiant energy – sun• Nuclear energy – rearrangement of nuclei
– Fission – breaking apart of larger nuclei– Fusion - smaller nuclei are put together
Section 4.5 http://themalloryfamily.net 4 | 37
Fossil Fuels
• Fossil Fuels – oil, gas, coal - from once living organisms; basically stored solar and chemical energy
• Oil – from marine organisms (U.S. imports more than 50% of our needs)
• Gas – from marine organisms (most is produced domestically)
• Coal – from terrestrial (land) plants (the U.S. has large reserves, but environmental problems in coal mining)
• Methane hydrate – crystalline form of natural gas and water (research on possible usage)
Section 4.5
•34 •35
•36 •37
8
http://themalloryfamily.net 4 | 38
Approximate Relative Fuel Consumption in the
U.S.Fuels for Electrical
Generation
http://themalloryfamily.net 4 | 39
Alternate and Renewable Energy Sources
• Alternate energy sources – energy sources not based on fossil fuels or nuclear processes.
• Renewable energy sources – energy sources that cannot be exhausted.
• In large part these types of energies overlap.
Section 4.6
http://themalloryfamily.net 4 | 40
Chapter 4 - Important Equations
• W = Fd (Work)
• Ek = ½mv2 (Kinetic Energy)
• Ep = mgh (Potential Energy)
• Total Energy = Ek + Ep
• P = W/t (Power)
Review
2gh• v =
Quantity Unit SymbolEquivalent Units
Force newton N Kgꞏm/s2
Work joule J Nꞏm
Energy joule J Nꞏm
Power watt W J/s
http://themalloryfamily.net 4 | 41
𝑚 11,000
𝑐 1100
𝑘 1,000
𝑣ΔxΔ𝑡
𝑎Δv⃑Δ𝑡
𝑑12 𝑔𝑡2
𝐹 𝑚𝑎 𝑊 𝑚𝑔 𝐸 ℎ𝑓
𝑊𝑏𝑜𝑦 𝑣𝑏𝑜𝑦 𝑊𝑔𝑖𝑟𝑙 𝑣𝑔𝑖𝑟𝑙(momentum)
𝑊 𝐹𝑑
𝐾𝐸 12 𝑚𝑣2
𝑃𝐸 𝑚𝑎𝑑
𝑣 2𝑔ℎ⃑
𝑃𝑊𝑡
𝑇𝑘 𝑇𝐶 273 𝐻𝑒𝑎𝑡 𝑆𝐻 𝑚 Δ𝑡
𝐻𝑒𝑎𝑡 𝐿𝑓 𝑚
𝐻𝑒𝑎𝑡 𝐿𝑣𝑚 𝑃1
𝑃2
𝑇1
𝑇2
𝑣 𝑓𝜆
𝑇1𝑓
𝑛𝑐
𝑐𝑚
𝑉 𝐼𝑅 𝑃 𝑉𝐼
Stuff you now know…Stuff you need for the Final
•38 •39
•40 •41
9
3 | 42http://themalloryfamily.net
Bring for the final:• Pen (or pencil)• Calculator• 3”x5” card• Ruler• Test 6 (astronomy)
http://themalloryfamily.net 4 | 43
Questions…4. How much work is required to lift a 4.0 kg concrete block to a
height of 2.0 m?
h = 0.0mm = 4.0 kg
h = 2.0mm = 4.0 kg
http://themalloryfamily.net 4 | 44
Questions…12. Which has more kinetic energy: a 0.0020 kg bullet traveling at 400
m/s or a 6.4 x 107kg ocean liner traveling at 10 m/s (20 knots)? Justify your answer.
v = 10 m/sm = 6.4 x 107 kg
v = 400 m/sm = 0.0020 kg
http://themalloryfamily.net 4 | 45
Questions…15. What is the potential energy of a 3.00 kg object at the bottom of a
well 10.0 m deep as measured from ground level? Explain the sign of the answer.
h = 0.00 mm = 3.00 kg
h = -10.0 mm = 3.00 kg
•42 •43
•44 •45
10
http://themalloryfamily.net 4 | 46
Questions…16. How much work is required to lift a 3.00 kg object from the
bottom of a 10.0 m deep well?
h = 0.00 mm = 3.00 kg
h = 10.0 mm = 3.00 kg
http://themalloryfamily.net 4 | 47
Questions…20. A 35.0 kg child starting from rest slides down a water slide with a
vertical height of 20.0 m. What is the child’s speed ata. Halfway down the slide’s vertical distance? b. Three quarters of the way down?
http://themalloryfamily.net 4 | 48
Questions…20. A 35.0 kg child starting from rest slides down a water slide with a
vertical height of 20.0 m. What is the child’s speed ata. Halfway down the slide’s vertical distance? b. Three quarters of the way down?
http://themalloryfamily.net 4 | 49
Questions…20. A 35.0 kg child starting from rest slides down a water slide with a
vertical height of 20.0 m. What is the child’s speed ata. Halfway down the slide’s vertical distance? b. Three quarters of the way down? h = 20.0 m
m = 35.0 kg
h = 10.0 mm = 35.0 kg
h = 5.0 mm = 35.0 kg
h = 0.0 mm = 35.0 kg
•46 •47
•48 •49
11
http://themalloryfamily.net 4 | 50
Questions…24. A 130 lb student races up stairs with a vertical height of 8.0 m in
5.0 s to get to a class on the second floor. How much power in watts does the student expend in doing work against gravity?
http://themalloryfamily.net 4 | 51
Questions…24. A 130 lb student races up stairs with a vertical height of 8.0 m in
5.0 s to get to a class on the second floor. How much power in watts does the student expend in doing work against gravity?
h = 0 mw = 130 lbst = 0 s
h = 8.0 mw = 130 lbst = 5.0 s
http://themalloryfamily.net 4 | 52
Don’t forget your homework!!!Test Next Week on
Chapters 3 & 4
•50 •51
•52