Konstruksi Beton, Pembesian Metoda Lentur nP e m b e s i a n G e s e r

D = 10,000 kg begel D 8 Mpuntir = 0.500 tmv Permanen b = 25 cm d = 4.75 cm D 19 Geser ijin lentur dgn puntir

Temporer ht = 50 cm h = 45.3 cm Jml 1 bi = 10.800 kg/cm2Ft = 769.5 cm2

selimut = 3 cm Baris bmi = 27.000 kg/cm2Ut = 119 cm

Geser ijin lentur

K 400 bi = 8.60 kg/cm22.6 Mt

U 24 bsi = 13.60 kg/cm2 ai = 1392 kg/cm2 = 3 + = 4.061 b' = = 6.50 kg/cm2

bmi = 21.60 kg/cm20.45 + ht/b ht . b2

D b'' = Mt/(b.Ft) b + b' = 16.601 kg/cm2 < bmi…OK

b = = 10.10 kg/cm2= 2.60 kg/cm2 > bi… Perlu Tul.Puntir

7/8.b.h As = 1.01 cm2

b + b'' = 12.70 kg/cm2 <s

t = 1.50 as = As a/(t.b)

kg/cm2 = 37.25 cm as = As a/(s.b) Amem = Mt x Ut /(2 x sa x Ft)

= 4.41 cm = 2.78 cm2

Dipakai Begel : D8 - 37.25

Perhitungan Pembesian Geser Beton Bertulang

Dihitung dengan Metoda "PBI 1971"

Beban ( v ) Tul.Utama

Pembesian Geser u/ Balok PersegiISI HANYA PADA HURUF WARNA MERAH SAJA