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PUBLIC WORKS DEPARTMENT, UDAIPUR DESIGN OF SUBMERSIBLE BRIDGE ON PADLA JAWAR MINES ROAD TEJHANS INVESTMENTS CIVIL & STRUCTURAL ENGINEERING CONSULTANTS

Submersible Bridge Padla Jawarmines Road Design and Drawings

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  • PUBLIC WORKS DEPARTMENT, UDAIPUR

    DESIGNOF

    SUBMERSIBLE BRIDGEON PADLA JAWAR MINES ROAD

    TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS

  • DESIGN SUBMERSIBLE BRIDGEACROSS SUKANAKA NALAH

    ON UDAIPUR- JHAMAR KOTADA ROADNEAR MATOON VILLAGE

    INDEX

    S.No

    Particulars Page

    1. Preamble

    2. Hydraulic Design

    3. Stability Check for Pier in Different Load Cases

    4. Computation of Reinforcement in Pier

    5. Design of Pier Footing

    6. Design of Pier Footing Cap

    7. Stability Check for Abutment in Different Load Cases

    8. Design of Abutment Footing

    9. Cross Sections & L Section of the River

    10. Geotechnical Investigation Report

    11. General Arrangement Drawing

    12. Details of Pier Complete Drawing

    13. Pier Reinforcement Details

    14. Details of Bottom Anchorage of Pier

    15. Details of Reinforcement in Pier cap

    16. Deck Slab Anchorage Detail

    17. Details of Abutment Complete Drawing

    18. Details of Approach Slab

  • 1 Design Notes SUBMERSIBLE BRIDGE PADLA JAWAR MINES ROAD_6A9E4FC1

    DESIGN OF SUBMERSIBLE BRIDGEON PADLA JAWAR MINES ROAD

    PREAMBLE

    Type of Bridge

    The bridge shall be a Submersible bridge. The HFL is 99.480 m

    and the proposed deck level is 99.975 m.

    Decking Arrangement

    The Deck Slab shall be 8400 mm wide i.e. 7500 mm carriage way and

    450 mm wide Kerb (with recesses) on each side. There shall be 25 mm

    wide expansion joint between the adjacent deck slabs along the length of

    the bridge. The location of proposed road is right angle to the direction of

    flow.

    There shall be 5 Nos. of spans. The centre to centre distance for the

    spans shall be 6600 mm.

    Standard RCC Solid Slab Superstructure with right effective span 6 M

    without footpath shall be provided in accordance to the Ministry of Surface

    Transport (Roads Wing), New Delhi drawings.

  • 1 Design Notes SUBMERSIBLE BRIDGE PADLA JAWAR MINES ROAD_6A9E4FC2

    It is proposed to construct Deck Slab 8400 mm wide i.e. 7500 mm

    carriage way and 450 mm wide Kerb (with recesses) on each side. There

    shall be 25 mm wide expansion joint between the adjacent deck slabs along

    the length of the bridge.

    As per requirement of use in the proposed bridge the deviation with

    respect to these drawings shall be as follows:-

    1. Pier Cap Width 1000 mm [In the reference drawing the

    pier cap width is 800 mm]. The width of piers shall be 1000 mm. Due

    to this change the Centre to Centre distance shall be 6600 mm (centre

    to centre over piers). For all spans the clear span shall be 5600 mm

    and the centre to centre distance shall be 6600 mm. The length of

    reinforcement shall be modified as per these geometrical

    requirements however spacing of the reinforcement shall not be

    altered.

    2. Kerb & Railing: - The total width of Kerb & railing shall be

    450 mm. The Kerb will have recesses to allow water to pass from top

    of the deck from u/s to d/s.

    3. Reinforcement Detailing: - The reinforcement detailing is

    suitably modified as required for the modifications referred above in

    points 1 to 2.

    The proposed decking arrangement is shown in Drawing D01 titled

    as Decking arrangement.

    Design Loads

    The following loads have been considered in the design of deck slab

    and for the stability of the sub structure:-

    [A] Maximum of the following cases

    I. One lane of IRC class 70R on carriage way

    II. One lanes of IRC Class A on carriage way

  • 1 Design Notes SUBMERSIBLE BRIDGE PADLA JAWAR MINES ROAD_6A9E4FC3

    III. Two lanes of IRC Class A on carriage way

    IV. Three lanes of IRC Class A on carriage way

    V. One lane of IRC class 70R and one lane of IRC Class A on carriage

    way

    VI. One lane of IRC class AA TRACKED VEHICLE on carriage way

    In order to account for two adjacent slabs the resultant reactions and

    moments have been multiplied by 2 for stability check of the sub structure.

    [B] Other Loads

    a) Footpath load of 5KN/Sqm.

    b) Wearing coat land of 2 KN/Sqm.

    Safe Bearing Capacity

    No detailed sub soil investigation is carried out. From visual inspection

    it is observed that the foundation rock is safe against the eroding effects of

    the water flow and other climatic conditions.

    As per presumptive Safe Bearing capacity Guidelines the Safe Bearing

    Capacity adopted for design is 450 kN/ Sq M.

    Depth of Foundation/Founding Level

    For the footings near bore hole 1 to 3 the hard rock is available

    in 2 m to 4 m depth from the river bed level and as per codal provisions the

    foundation is to be embedded in 1.2 m depth however it is proposed to

    embed the foundation 1.5 m in the rock.

    Scour Depth

    The computation of scour depth provided in the design is a part of

    formal design steps and when hard rock is encountered there is no need to

    embed the foundation in accordance to the scour depth.

    Annular Space Filling Around Foundation Footing

  • 1 Design Notes SUBMERSIBLE BRIDGE PADLA JAWAR MINES ROAD_6A9E4FC4

    As per the suggestion given for protection of footing (Ref. Hand book

    for Bridge Engineer copy enclosed as (Annexure TEJ04) the annular space

    around footing shall be filled with PCC 1:2:4 upto the rock level.

    The provision is in accordance to there suggestions.

    Reinforcement Detail & other Detail of Deck slab

    Ministry of surface transport details drawings are enclosed

    which contains miscellaneous details of deck slab including

    reinforcement drawing.

    The right effective span of the proposed bridge is 6 m.

    The length along the centre line of road between pier centers is 6.60 m.

    The deck slab pertaining to 6 m. right effective span shall

    be provided as given in MOST drawings No. SD/101, SD/102, SD/103,

    SD/104 AND SD/110.

    In the drawing the clear right span is 5600 mm. The

    proposed bridge shall have clear right span as 5600 mm conforming to

    the standard drawing adopted.

    Bearing detail

    Tar paper bearing shall be providing on top of pier cap &

    abutment cap.

    Approach slab

    The detail of approach slab is enclosed as drawing TEJ-03.

    Pier Cap Detail

    Pier cap drawing is enclosed as annexure TEJ-05.

  • Hydraulic CalculationComputation of Discharge 1 Flood calculation by Area Velocity Method (As per Article- 5 of IRC SP-13)

    Q = A x V WhereA = 156.45 m2 A = Cross sectional area in m2

    P = 76.30 m P = Perimeter calculated in mS = 1 IN 231 S = Slope as per drain LS taken at

    Proposal siten = 0.033 n = Rugosity coefficient

    (As per IRC SP-13)V = I/nx (A/P) 2/3 x(S) 1/2 V = Velocity in m/sec.

    = 3.22 m/sec.Q = 503.77 Cumecs

    Linear Water Way CalculationRegime Surface width of the stream is given by :- L = 4.8 (Q)1/2

    DESIGN OF SUBMERSIBLE BRIDGE ON PADLA JAWAR MINES ROAD

    Regime Surface width of the stream is given by :- L = 4.8 (Q)1/2= 107.74 m

    Looking to the Financial Resourse Availability constraints adopt 5 Spans of 5.60 M each.This will cause contraction and afflux. Calculation is done for the same to fix deck level.Effective linear water way proposed = 5 x 5.6 = 28 M

    Total 28 MScour Depth Calculation(As per clause no. 703.2.2.1 of IRC : 78.1983)

    dsm = 1.34x (Db2 /Ksf) 1/3 WhereDb = The discharge in Cumecs per meter widthKsf = the silt factor

    = 1.5Effective linear waterway = Width of waterway - Obstructed width of piper

    = 52.80 - ( 4 x 1.2 )= 48.00 m

    Db = 503.77 / 48.00= 10.5 Cumecs per metre width

  • dsm = 5.62 m

    Afflux CalculationAs per IS: 7784 (Part -I) 1975Molesworth Formula for Afflux

    Afflux h = ((V2/17.85) +0.0152)x(A2/a2-1)Where,

    h = afflux in m,v = Velocity in the unobstructed stream in m/s,A = the unobstructed sectional area of the river in m2

    a = the obstructed sectional area of the river at the cross drainage work in m2.As per Annexure- 1

    Unobstructed Area of Flow after Bridge Construction = 52.800 x 2.60 = 137.3 m2

    A = 137.28 m2

    As per Clause No. 703-2-3-1 of IRC 78-1983 considering Scour at the pier two times of calculated scour depth below the highest flood level butrock is available on the site, so foundation level is considered as 1.5 in rock.

    A = 137.28 m2

    V = 3.22 m/sec.

    HFL : 99.480 mTop Level of Deck slab : 99.975 m

    Thickness of Slab and Wearing Coat 0.675 mLength Of Slab 52.800 m

    Height of Obstruction 0.180 mArea obstructed by deck slab 52.800 x 0.18

    = 9.50 m2

    HFL : 99.480 mSoffit of Deck slab : 99.300 m

    Average river bed level = 96.880 mNos. of pier = 4

    Height of Obstruction 99.480 - 96.880 = 2.600 mArea obstructed by one pier : = 1.2 x 2.60

    = 3.12 m2

    Computation of Area obstructed by Piers

    Computation of Area obstructed by Deck Slab

  • For 4 Nos. of piers = 4 x 3.12A1 = 12.48 m2

    Average ground level = 97.500 mHeight of Obstruction 99.480 = 97.500 = 1.980 mArea obstructed by one Abutment : A2 = (0.40+0.75)/2 x 1.98

    = 1.14 m2

    For two Abutments = 2 x 1.14= 2.28 m2

    Total area of obstruction due to slab,piers and abutments A = A0 +A1 + A2

    = 9.50 + 12.48 + 2.28= 24.26 m2

    Actual Area of flow a = 137.280 - 24.26= 113.02 m2

    Afflux h = 0.29 m

    Computation of Area obstructed by Abutments

    Afflux h = 0.29 mAfflux flood level = 99.480 + 0.29 = 99.770 m Obstructed Velocity V = Q/a - Obstructed Velocity = 503.77 / 113.02

    = 4.46 m/secHowever we consider design velocity 5.00 m/sec.Afflux flood level = 99.770 mTop Level of Deck slab : = 99.975 m

    This is just above the Afflux flood level.Hence OK.

  • TEJHANS INVESTMENTS

    HIGHEST FLOOD LEVEL 99.480 MCHAINAGE G.L. DEPTH OF

    FLOW INM

    LENGTHOF FLOW

    AVERAGEDEPTH OF

    FLOW

    CROSSSECTIONAL

    AREA OF FLOW

    WETTEDPERIMETER

    0.00 101.140 0.00 0.00 0.00 0.00 0.003.00 100.820 0.00 3.00 0.00 0.00 0.006.00 100.680 0.00 3.00 0.00 0.00 0.009.00 100.700 0.00 3.00 0.00 0.00 0.00

    12.00 100.360 0.00 3.00 0.00 0.00 0.0015.00 99.920 0.00 3.00 0.00 0.00 0.0018.00 99.850 0.00 3.00 0.00 0.00 0.0021.00 99.630 0.00 3.00 0.00 0.00 0.0024.00 99.340 0.14 3.00 0.07 0.21 3.0027.00 98.920 0.56 3.00 0.35 1.05 3.03

    CIVIL & STRUCTURAL ENGINEERING CONSULTANTS2/227 Shiv Colony, BANSWARA Mob.-

    9414868322

    DETERMINATION OF VELOCITY AT PROPOSEDSUBMERSIBLE BRIDGE ON PADLA JAWAR MINES ROAD

    HYDRAULICS Page 7 Date 2/15/2014

    27.00 98.920 0.56 3.00 0.35 1.05 3.0330.00 98.730 0.75 3.00 0.66 1.97 3.0133.00 98.630 0.85 3.00 0.80 2.40 3.0036.00 98.310 1.17 3.00 1.01 3.03 3.0239.00 96.560 2.92 3.00 2.05 6.14 3.4742.00 96.210 3.27 3.00 3.10 9.29 3.0245.00 96.170 3.31 3.00 3.29 9.87 3.0048.00 96.140 3.34 3.00 3.33 9.98 3.0051.00 95.970 3.51 3.00 3.43 10.28 3.0054.00 96.190 3.29 3.00 3.40 10.20 3.0157.00 96.110 3.37 3.00 3.33 9.99 3.0060.00 96.140 3.34 3.00 3.36 10.07 3.0063.00 96.100 3.38 3.00 3.36 10.08 3.0066.00 96.040 3.44 3.00 3.41 10.23 3.0069.00 96.090 3.39 3.00 3.42 10.25 3.0072.00 96.030 3.45 3.00 3.42 10.26 3.0075.00 96.780 2.70 3.00 3.08 9.23 3.0978.00 97.130 2.35 3.00 2.53 7.58 3.0281.00 97.110 2.37 3.00 2.36 7.08 3.0084.00 99.120 0.36 3.00 1.37 4.10 3.6187.00 99.110 0.37 3.00 0.37 1.10 3.0090.00 99.110 0.37 3.00 0.37 1.11 3.0093.00 99.330 0.15 3.00 0.26 0.78 3.0196.00 99.480 0.00 3.00 0.08 0.23 3.0099.00 99.770 0.00 3.00 0.00 0.00 0.00

    102.00 100.160 0.00 3.00 0.00 0.00 0.00105.00 101.890 0.00 3.00 0.00 0.00 0.00

    TOTAL 105.00 156.45 76.30

    HYDRAULICS Page 7 Date 2/15/2014

  • CHAINAGE G.L. DEPTH OFFLOW IN

    M

    LENGTHOF FLOW

    AVERAGEDEPTH OF

    FLOW

    CROSSSECTIONAL

    AREA OF FLOW

    WETTEDPERIMETER

    A 156.45 SQMP 76.30 MR 2.05 MN 0.033S 1 IN 231V 3.22 M/SECQ 503.44 CUMECS

    Discharge calculated by empirical formula is 460.97 CUMECS503.44 CUMECS

    Hence Design Discharge = 503.44 CUMECSwhich is Less than

    The design engineer visually observed the river to ascertain theRoughness Coefficient n for the Manning's formula. Upon visualinspection of the river in the vicinity of the proposed bridge site itwas found that the River bed surface is good with clean straightbanks, no rifts or deep pools however containing some weeds andstones. Roughness Coefficient pertaining to these characteristics is0.033

    HYDRAULICS Page 8 Date 2/15/2014HYDRAULICS Page 8 Date 2/15/2014

  • COMPUTATION OF DISCHARGE BY IMPERICAL FORMULAE Catchment Area M = 14 Sq Km

    INGLIS FORMULA For small areasFor small areasQ=123.2M1/2 Q = 460.97 Cumecs

    For all types of catchmentsQ=123.2M/((M+10.36)1/2) Q = 349.46 Cumecs

    Maximum of All 460.97 Cumecs

  • Check Against UpliftThe uplift force shall be maximum when the flow level is Just at near deck level. THIS WILL BE IN CASE OF AFFLUX FLOOD LEVEL 99.77 MTotal Height = 0.29 MMaximum Uplift Pressure = 0.29 x 10 = 2.9 kN/SqmArea of Slab under effect of buoyancy = 6.80 x 8.4 = 57.12 SqmUplift Force on Slab = 57.12 x 2.9 = 165.65 kN

    Self Weight of Slab = 6.80 x 8.40 x 0.60 x 24.00 = 822.53 kNSelf Weight of Wearing Coat = 6.80 x 7.50 x 0.075 x 24.00 = 91.80 kN

    Kerb = 2X6.8 x 1.50 x 0.50 x 24.00 = 244.80 kNTOTAL 1159.13 kN

    Net Uplift Pressure = 165.65 - 1159.13 = -993.48 kN< 0 Hence Ok.

    Check Against SlidingRefer Stability Check of PierWATER CURRENT IN TRANSVERSE DIRECTION ( ACROSS THE BRIDGE)As per IRC- II ( 6-1966) clause 213.5 For V= 5.00 m/sec Maximum velocity being 1.414 x mean velocity (1.414= Root of 2)Obstructed Velocity = V Cos 20 0 = 5.00 x Cos 20 0

    = 4.702v2 = 44.16The soffit of the deck is at = 99.30 M The afflux Flood Level is 99.77 MDRAG FORCE ON DECK SLAB DUE TO AFFLUX

    Area Obstructed = 6.80 x 0.290 = 1.97 Sqm

    Drag Force on Slab = 52.00 x k x v2 x Area Obstructed= 52.00 x 1.50 x 44.16 x 1.97 / 100 = 67.92 kN

    Dia of Anchor Bars 32 mmPermissible Shear Stress 190 N/mm2

    Shear Force Resisted by one Anchor Bar = ( 0.785 x 32 2 /4 )x 190 / 1000 = 38.19 kNNumber Of Bars Provided Per slab 10 Nos.Total Shear Resisted = 10 x 38.19 = 381.9 kNFACTOR OF SAFETY = 381.9 / 67.92022 = 5.63

    > 2.00 Hence OK

    ANCHORAGE OF DECK SLAB TO SUBSTRUCTURE

    In the case of a submersible bridge, the deck slab is near the plane of maximum velocity. To counteract the sliding action due tovelocity of flow, loss of weight of slab due to buoyancy, the tilting forces due to eddies and currents and the disturbing forces due todebris or trees floating down the stream , it is necessary to anchor the deck slab to the substructure.

    One possible solution to this anchorage is as shown in detailed drawing. The aim in this anchorage is to secure the deck slab to piersor abutments against uplift or lateral thrust and at the same time allow lateral movement due to expansion and contraction due totemperature effects the arrangement will be evident from the sketch given in the detailed drawing.

  • Chainage inM (u/s ord/s)

    RL in M

    (75.00) 96.345(60.00) 96.305(50.00) 96.240(40.00) 96.215(30.00) 96.185(20.00) 96.125(10.00) 96.075

    - 96.03010.00 95.99020.00 95.97030.00 95.87040.00 95.85550.00 95.80560.00 95.77070.00 95.69575.00 95.695 Ch RL75.00 95.695 -75.00 96.345

    (75.00) 96.345 75.00 95.695

    DISTANCE 150 MFALL 0.65 MSLOPE 1 IN 231

    Reference Poits

    DETERMINATION OF BED SLOPE OF THE RIVERDESIGN OF SUBMERSIBLE BRIDGE ON

    PADLA JAWAR MINES ROAD

    96.20096.30096.400

    L SECTION OF RIVER BED

    3 Stability Analysis SUBMERSIBLE BRIDGE PADLA JAWAR MINES ROAD Page 8 Date 2/15/2014

    95.60095.70095.80095.90096.00096.10096.200

    (100.00) (80.00) (60.00) (40.00) (20.00) - 20.00 40.00 60.00 80.00 100.00

    Series1

    3 Stability Analysis SUBMERSIBLE BRIDGE PADLA JAWAR MINES ROAD Page 8 Date 2/15/2014

  • CASE- 1 FOR SERVICE CONDITION AT R. L.92.97 M 167.80 14.27 175.48 21.95CASE- 2 FOR IDLE CONDITION AT R. L.92.97 M 127.06 13.28 134.74 20.96CASE- 3 FOR WIND FORCE AT SERVICE CONDITION AT R. L.92.97 M 168.42 13.65 176.10 21.32CASE- 4 FOR WIND FORCE AT IDLE CONDITION AT R. L.92.97 M 127.68 12.66 98.69 41.66 135.36 20.34CASE- 5 FOR ONE SPAN DISLODGED CONDITION AT R. L.92.97 M 110.47 -4.55 81.48 24.44 60.64 17.62

    Maximum 176.10 -4.55 Minimum

    CASE- 6 FOR SERVICE CONDITION AT R. L.93.97 M 358.09 -37.88 361.34 -34.63CASE- 7 FOR IDLE CONDITION AT R. L.93.97 M 262.43 -23.05 265.68 -19.80CASE- 8 FOR WIND FORCE AT SERVICE CONDITION AT R. L.93.97 M 359.09 -38.89 362.34 -35.63CASE- 9 FOR WIND FORCE AT IDLE CONDITION AT R. L.93.97 M 303.85 16.36 307.10 19.61

    Maximum 362.34 -38.89 Minimum

    ABSTRACT OF BASE PRESSURE AND STRESSES

  • DESIGN DATA

    1 RIGHT EFFECTIVE SPAN = 5.60 M2 SPAN C/C OF PIERS = 6.80 M3 OVERALL WIDTH OF PIER CAP = 8.40 M4 H.F.L. = 99.48 M5 BUOYANCY6 AT FOOTING LEVEL = 100.00 %7 AT PIER LEVEL = 100.00 %8 AQUEDUCT FALLS UNDER ZONE-II

    SO SEISMIC CASE IS NOTGOVERNING HERE.

    TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS2/227 Shiv Colony, BANSWARA Mob.- 9414868322

    DESIGN OF PIER AND CHECK FOR STABILITY- SUBMERSIBLE BRIDGE ON PADLA JAWAR MINES ROAD

    STABILITY CHECK FOR PIER Page 9 Date 2/15/2014

    8 AQUEDUCT FALLS UNDER ZONE-IISO SEISMIC CASE IS NOTGOVERNING HERE.

    9 FLOOD DISCHARGE = 503.44 CUMECS10 RIVER BED SLOPE = 1 IN 23111 DESIGN VELOCITY = 5.00 m/sec12 BED LEVEL OF THE HEIGHEST PIER = 96.03 M

    13 SAFE BEARING CAPACITY = 45.00 t/m2 450.00 kN/m214 TOP LEVEL OF FOUNDING ROCK = 94.47 M15 EMBEDMENT OF PIER IN HARD

    ROCK= 1.50 M

    16 FOUNDATION LEVEL OF THEHIGHEST PIER

    = 92.97 M

    17 DECK LEVEL OF THE BRIDGE = 99.975 M18 TOP LEVEL OF THE PIER CAP = 99.300 M19 LEVEL DIFFERENCE OF PIER CAP

    TOP AND FOUNDING LEVEL= 6.33 M

    CHECKING STABILITY OF PIER AT R.L.92.97 M FOOTING LEVELA DEAD LOAD CALCULATION

    SUPER STRUCTURESelf Weight of Slab = 6.80 x 8.40 x 0.60 x 24.00 = 822.53 kN

    Self Weight of Wearing Coat = 6.80 x 7.50 x 0.075 x 24.00 = 91.80 kNKerb = 2X6.8 x 0.45 x 0.32 x 24.00 = 46.27 kN

    TOTAL 960.60 kNSUB STRUCTURE

    Pier Cap

    STABILITY CHECK FOR PIER Page 9 Date 2/15/2014

  • TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS2/227 Shiv Colony, BANSWARA Mob.- 9414868322

    Pier Cap = 1.00 x 8.40 x 0.30 x 24.00 = 60.480 kNTOTAL 60.480 kN

    PierPier Rectangular portion = 1.00 x 7.90 x 3.48 x 24.00 = 659.808 kN

    Pier Curved portion = 3.14 / 4 x 1.00 x 1.00 x 3.48 x 24.00 = 65.563 kNFlared Portion bottom = 0.50 x 0.60 x 0.30 x 24.00 = 2.160 kN

    = 3.14 / 4 x 1.20 x 1.20 x 0.60 x 24.00 = 16.278 kNTOTAL 749.235 kN

    Weight of Pier Above H.F.L. = 0.000 kNWeight of Pier Below H.F.L. = 749.23 - 0.00 = 749.235 kN

    Weight of Sub Structure with 15% Buoyancy = 0.00 + ( 749.23 x 22.50 / 24.00 ) = 702.408 kNFooting SIZE 9.30 M x 3.00 M x 0.60 M

    Weight without Buoyancy = 9.30 x 3.00 x 0.60 x 24.00 = 401.760 kNWeight with 100% Buoyancy = 9.30 x 3.00 x 0.60 x 14.00 = 234.360 kN

    Total Weight of Substructure Without Buoyancy

    STABILITY CHECK FOR PIER Page 10 Date 2/15/2014

    Weight with 100% Buoyancy = 9.30 x 3.00 x 0.60 x 14.00 = 234.360 kNTotal Weight of Substructure Without Buoyancy

    = 60.48 + 749.23 + 401.76 = 1211.475 kNTotal Weight of Substructure With Buoyancy

    = 60.48 + 702.41 + 234.36 = 997.248 kN

    B LIVE LOAD CALCULATIONMaximum Reaction due Live Loadincluding Impact = 582.00 x 1.00 = 582.00 kNRefer Live load Computation sheetshowing maximum reaction

    = 58.20 T which is = 582.00 kN

    TOTAL LONGITUDINAL MOMENT DUE TO LIVE LOAD & BREAKING FORCEMaximum Longitudinal moment due toLive Load including Impact andBreaking Force = 106.00 x 1.00 = 106.00 kN-mRefer Live load Computation sheetshowing maximum reaction = 10.60 T- m

    which is = 106.00 kN-m

    TOTAL TRANSVERSE MOMENT DUE TO LIVE LOAD & BREAKING FORCEMaximum Transverse moment due toLive Load including Impact andBreaking Force = 531.00 x 1.00 = 531.00 kN-m

    STABILITY CHECK FOR PIER Page 10 Date 2/15/2014

  • TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS2/227 Shiv Colony, BANSWARA Mob.- 9414868322

    Refer Live load Computation sheetshowing maximum reaction = 53.10 T- m

    which is = 531.00 kN-m

    C LOADS DUE TO WATER CURRENTWATER CURRENT IN LONGITUDINAL DIRECTION ( ALONG THE BRIDGE)As per IRC- II ( 6-1966) clause 213.5 For V= 5.00 m/sec

    Obstructed Velocity = V Sin 20 0 = 5.00 x Sin 20 0= 1.71

    2v2 = 5.84Total SUBMERGED Height = 5.01 M 5.84 4.71 4.56 0.00

    FORCE ON DECK SLAB BETWEEN Deck Level 99.975 M to Soffit Level 99.300 M2v2 = ( 5.84 + 4.71 ) /2 = 5.27

    Since the bridge is at Zero Degrees skew from the direction of current as per IRC- II ( 6-1966) clause 213.5 it should be designed for (20+0) =20 Degrees or (20-0) = 20 Degrees whichevergives higher quantum of water current forces.

    STABILITY CHECK FOR PIER Page 11 Date 2/15/2014

    2v2 = ( 5.84 + 4.71 ) /2 = 5.27Area Obstructed = 8.40 x 0.47 = 3.95 Sqm

    Force on Pier = 52.00 x k x v2 x Area Obstructed= 52.00 x 1.50 x 5.27 x 3.95 / 100 = 16.24 kN at R.L. 99.535 M

    Moment @ R. L. 94.57 M = 16.24 x 4.97 = 80.65 kN-mMoment @ R. L. 93.97 M = 16.24 x 5.57 = 90.39 kN-mMoment @ R. L. 92.97 M = 16.24 x 6.57 = 106.63 kN-m

    FORCE ON PIER CAP BETWEEN RL 99.300 M TO 99.000 M2v2 = ( 4.71 + 4.56 ) /2 = 4.63

    Area Obstructed = 8.40 x 0.30 = 2.52 Sqm

    Force on Pier = 52.00 x k x v2 x Area Obstructed= 52.00 x 1.50 x 4.63 x 2.52 / 100 = 9.11 kN at R.L. 99.150 M

    Moment @ R. L. 94.57 M = 9.11 x 4.58 = 41.71 kN-mMoment @ R. L. 93.97 M = 9.11 x 5.18 = 47.17 kN-mMoment @ R. L. 92.97 M = 9.11 x 6.18 = 56.28 kN-m

    FORCE ON PIER BETWEEN RL 99 M TO 94.470 M2v2 = ( 4.56 + 0.00 ) /2 = 2.28

    Area Obstructed = 7.33 x 8.90 = 65.28 Sqm

    Force on Pier = 52.00 x k x v2 x Area Obstructed= 52.00 x 1.50 x 2.28 x 65.28 / 100 = 116.10 kN at R.L. 96.735 M

    Moment @ R. L. 94.57 M = 116.10 x 2.17 = 251.36 kN-mMoment @ R. L. 93.97 M = 116.10 x 2.77 = 321.03 kN-mMoment @ R. L. 92.97 M = 116.10 x 3.77 = 437.13 kN-m

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    TOTAL LONGITUDINAL MOMENT DUE TO WATER CURRENTMoment @ R. L. 94.57 M = 80.65 + 41.71

    + 251.36 = 373.72 kN-mMoment @ R. L. 93.97 M = 90.39 + 47.17

    + 321.03 = 458.59 kN-mMoment @ R. L. 92.97 M = 106.63 + 56.28

    + 437.13 = 600.04 kN-mWATER CURRENT IN TRANSVERSE DIRECTION ( ACROSS THE BRIDGE)As per IRC- II ( 6-1966) clause 213.5 For V= 5.00 m/sec Maximum velocity being 1.414 x mean velocity (1.414= Root of 2)Obstructed Velocity = V Cos 20 0 = 5.00 x Cos 20 0

    = 4.702v2 = 44.16

    Total Height = 5.01 M 44.16 35.56 34.46 0.00FORCE ON DECK SLAB BETWEEN Deck Level 99.975 M to Soffit Level 99.300 M

    2v2 = ( 44.16 + 35.56 ) /2 = 39.86Area Obstructed = 6.80 x 0.000 = 0.00 Sqm

    STABILITY CHECK FOR PIER Page 12 Date 2/15/2014

    Area Obstructed = 6.80 x 0.000 = 0.00 Sqm

    Force = 52.00 x k x v2 x Area Obstructed= 52.00 x 1.50 x 39.86 x 0.00 / 100 = 0.00 kN at R.L. 99.535 M

    Moment @ R. L. 94.57 M = 16.24 x 4.97 = 80.65 kN-mMoment @ R. L. 93.97 M = 16.24 x 5.57 = 90.39 kN-mMoment @ R. L. 92.97 M = 16.24 x 6.57 = 106.63 kN-m

    FORCE ON PIER CAP BETWEEN RL 99.300 M TO 99.000 M2v2 = ( 35.56 + 34.46 ) /2 = 35.01

    Area Obstructed = 1.50 x 0.30 = 0.45 Sqm

    Force on Pier = 52.00 x k x v2 x Area Obstructed= 52.00 x 1.50 x 35.01 x 0.45 / 100 = 12.29 kN at R.L. 99.150 M

    Moment @ R. L. 94.57 M = 9.11 x 4.58 = 41.71 kN-mMoment @ R. L. 93.97 M = 9.11 x 5.18 = 47.17 kN-mMoment @ R. L. 92.97 M = 9.11 x 6.18 = 56.28 kN-m

    FORCE ON PIER BETWEEN RL 99 M TO 94.470 M2v2 = ( 34.46 + 0.00 ) /2 = 17.23

    Area Obstructed = 7.33 x 1.00 = 7.33 Sqm

    Force on Pier = 52.00 x k x v2 x Area Obstructed= 52.00 x 1.50 x 17.23 x 7.33 / 100 = 98.58 kN at R.L. 96.735 M

    Moment @ R. L. 94.57 M = 116.10 x 2.17 = 251.36 kN-mMoment @ R. L. 93.97 M = 116.10 x 2.77 = 321.03 kN-mMoment @ R. L. 92.97 M = 116.10 x 3.77 = 437.13 kN-m

    TOTAL TRANSVERSE MOMENT DUE TO WATER CURRENT

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    Moment @ R. L. 94.57 M = 80.65 + 41.71 =+ 251.36 373.72 kN-m

    Moment @ R. L. 93.97 M = 90.39 + 47.17 =+ 321.03 458.59 kN-m

    Moment @ R. L. 92.97 M = 106.63 + 56.28 =+ 437.13 600.04 kN-m

    D SEISMIC CONDITION

    E WIND FORCESlab

    Area = 6.60 x 0.68 = 4.46 Sqmheight of C.G. above Bed level = 99.54 - 96.03 = 3.51 m

    According to Clause 212.3 IRC -6 -1966 Wind pressure = 82.71 Kg/Sqm = 0.83 kN/SqmWind Force = 4.46 x 0.83 = 3.68 kN

    According to clause 222.1 of IRC : 6- 1966 the Aqueduct is situated in the standard Zone- II ; therefore theaqueduct need not to be designed for Seismic Forces.

    STABILITY CHECK FOR PIER Page 13 Date 2/15/2014

    Wind Force = 4.46 x 0.83 = 3.68 kNMoment @ R. L. 94.57 M = 3.68 x 4.97 = 18.29 kN-mMoment @ R. L. 93.97 M = 3.68 x 5.57 = 20.51 kN-mMoment @ R. L. 92.97 M = 3.68 x 6.57 = 24.19 kN-m

    Pier CapArea A1 = 1.00 x 0.30 = 0.30 SqmArea A2 = 0.00 x 0.60 = 0.00 Sqm

    Total 0.30 SqmY = ( 0.30 x 0.90 )+ ( 0.00 x 0.30 ) / 0.30 0.90 M

    height of C.G. above Bed level = 99.15 - 96.03 = 3.12 mAccording to Clause 212.3 IRC -6 -1966 Wind pressure = 81.86 Kg/Sqm = 0.82 kN/Sqm

    Wind Force = 0.30 x 0.82 = 0.25 kNMoment @ R. L. 94.57 M = 0.25 x 4.58 = 1.12 kN-mMoment @ R. L. 93.97 M = 0.25 x 5.18 = 1.27 kN-mMoment @ R. L. 92.97 M = 0.25 x 6.18 = 1.52 kN-m

    (I) Pier from R.L. 99.300 to 96.03 MArea = 1.20 x 3.27 = 3.92 Sqm

    height of C.G. above Bed level = 97.67 - 96.03 = 1.63 mAccording to Clause 212.3 IRC -6 -1966 Wind pressure = 78.60 Kg/Sqm = 0.79 kN/Sqm

    Wind Force = 3.92 x 0.79 = 3.08 kNMoment @ R. L. 94.57 M = 3.08 x 3.10 = 9.55 kN-mMoment @ R. L. 93.97 M = 0.25 x 3.69 = 0.91 kN-mMoment @ R. L. 92.97 M = 0.25 x 4.69 = 1.15 kN-m

    TOTAL TRANSVERSE MOMENT DUE TO WIND FORCEMoment @ R. L. 94.57 M = 18.29 + 1.12 + 9.55 +

    = 28.97 kN-m

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    Moment @ R. L. 93.97 M = 20.51 + 1.27 + 0.91 += 22.69 kN-m

    Moment @ R. L. 92.97 M = 24.19 + 1.52 + 1.15 += 26.86 kN-m

    CASE- 1 FOR SERVICE CONDITION AT R. L.92.97 MVERTICAL LOADS

    DEAD LOAD CALCULATIONSUPER STRUCTURE = 960.60 kNSUB STRUCTURE = 1211.47 kN Without Buoyancy 2172.07SUB STRUCTURE = 997.25 kN With BuoyancyLIVE LOAD = 582.00 kNTotal Load without Buoyancy = 2754.07 kNTotal Load with Buoyancy = 2539.84 kNTotal LONGITUDINAL MOMENT = 600.04 + 106.00 = 706.04 kN-mTotal TRANSVERSE MOMENT = 600.04 + 531.00 = 1131.04 kN-m

    C.S.A. = 9.30 x 3.00 = 27.90 m2

    BASE PRESSURE CALCULATION

    STABILITY CHECK FOR PIER Page 14 Date 2/15/2014

    Total TRANSVERSE MOMENT = 600.04 + 531.00 = 1131.04 kN-mC.S.A. = 9.30 x 3.00 = 27.90 m2

    Ixx = 1/6x 9.30 x 3.00 2 = 13.95 m3

    Iyy = 1/6x 9.30 2 x 3.00 = 43.25 m3

    STRESS with Buoyancy = ( 2539.84 / 27.90 )+ / - ( 706.04 / 13.95 )+ / - ( 1131.04 / 43.25 )= 91.03 + / - 50.61 + / - 26.15

    Pmax = 91.03 + 50.61 + 26.15= 167.80 kN/m2

    < 450 kN/m2 Hence O.K.Pmin = 91.03 - 50.61 - 26.15

    = 14.27 kN/m2> 0 Hence O.K.

    STRESS without Buoyancy = ( 2754.07 / 27.90 )+ / - ( 706.04 / 13.95 )+ / - ( 1131.04 / 43.25 )= 98.71 + / - 50.61 + / - 26.15

    Pmax = 98.71 + 50.61 + 26.15= 175.48 kN/m2

    < 450 kN/m2 Hence O.K.Pmin = 98.71 - 50.61 - 26.15

    = 21.95 kN/m2> 0 Hence O.K.

    CASE- 2 FOR IDLE CONDITION AT R. L.92.97 M (WHEN THERE IS NO LIVE LOAD)SUPER STRUCTURE = 960.60 kN A CHECK OF STABILITY DUE TO BUOYANCY EFFECTSUB STRUCTURE = 1211.47 kN Without BuoyancySUB STRUCTURE = 997.25 kN With Buoyancy

    STABILITY CHECK FOR PIER Page 14 Date 2/15/2014

  • TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS2/227 Shiv Colony, BANSWARA Mob.- 9414868322

    LIVE LOAD = 0.00 kNTotal Load without Buoyancy = 2172.07 kNTotal Load with Buoyancy = 1957.84 kN

    STRESS with Buoyancy = ( 1957.84 / 27.90 )+ / - ( 600.04 / 13.95 )+ / - ( 600.04 / 43.25 )= 70.17 + / - 43.01 + / - 13.88

    Pmax = 70.17 + 43.01 + 13.88= 127.06 kN/m2

    < 450 kN/m2 Hence O.K.Pmin = 70.17 - 43.01 - 13.88

    = 13.28 kN/m2> 0 Hence O.K.

    STRESS without Buoyancy = ( 2172.07 / 27.90 )+ / - ( 600.04 / 13.95 )+ / - ( 600.04 / 43.25 )= 77.85 + / - 43.01 + / - 13.88

    Pmax = 77.85 + 43.01 + 13.88= 134.74 kN/m2

    STABILITY CHECK FOR PIER Page 15 Date 2/15/2014

    Pmax = 77.85 + 43.01 + 13.88= 134.74 kN/m2

    < 450 kN/m2 Hence O.K.Pmin = 77.85 - 43.01 - 13.88

    = 20.96 kN/m2> 0 Hence O.K.

    CASE- 3 FOR WIND FORCE AT SERVICE CONDITION AT R. L.92.97 MSUPER STRUCTURE = 960.60 kNSUB STRUCTURE = 1211.47 kN Without BuoyancySUB STRUCTURE = 997.25 kN With BuoyancyLIVE LOAD = 582.00 kNTotal Load without Buoyancy = 2754.07 kNTotal Load with Buoyancy = 2539.84 kNTotal LONGITUDINAL MOMENT = 600.04 + 106.00 = 706.04 kN-mTotal TRANSVERSE MOMENT = 600.04 + 26.86 + 531.00 = 1157.91 kN-m

    STRESS with Buoyancy = ( 2539.84 / 27.90 )+ / - ( 706.04 / 13.95 )+ / - ( 1157.91 / 43.25 )= 91.03 + / - 50.61 + / - 26.78

    Pmax = 91.03 + 50.61 + 26.78= 168.42 kN/m2

    < 450 kN/m2 Hence O.K.Pmin = 91.03 - 50.61 - 26.78

    = 13.65 kN/m2> 0 Hence O.K.

    STRESS without Buoyancy = ( 2754.07 / 27.90 )+ / - ( 706.04 / 13.95 )+ / - ( 1157.91 / 43.25 )= 98.71 + / - 50.61 + / - 26.78

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    Pmax = 98.71 + 50.61 + 26.78= 176.10 kN/m2

    < 450 kN/m2 Hence O.K.Pmin = 98.71 - 50.61 - 26.78

    = 21.32 kN/m2> 0 Hence O.K.

    CASE- 4 FOR WIND FORCE AT IDLE CONDITION AT R. L.92.97 M [ NO LIVE LOAD ]SUPER STRUCTURE = 960.60 kNSUB STRUCTURE = 1211.47 kN Without BuoyancySUB STRUCTURE = 997.25 kN With BuoyancyLIVE LOAD = 0.00 kNTotal Load without Buoyancy = 2172.07 kNTotal Load with Buoyancy = 1957.84 kNTotal LONGITUDINAL MOMENT = 600.04 kN-mTotal TRANSVERSE MOMENT = 600.04 + 26.86 = 626.91 kN-m

    STABILITY CHECK FOR PIER Page 16 Date 2/15/2014

    Total TRANSVERSE MOMENT = 600.04 + 26.86 = 626.91 kN-mSTRESS with Buoyancy = ( 1957.84 / 27.90 )+ / - ( 600.04 / 13.95 )+ / - ( 626.91 / 43.25 )

    = 70.17 + / - 43.01 + / - 14.50Pmax = 70.17 + 43.01 + 14.50

    = 127.68 kN/m2 98.69 41.66< 450 kN/m2 Hence O.K.

    Pmin = 70.17 - 43.01 - 14.50= 12.66 kN/m2

    > 0 Hence O.K.P3 = 70.17 + 43.01 - 14.50

    = 98.69 kN/m2 12.66 127.68< 450 kN/m2 Hence O.K.

    P4 = 70.17 - 43.01 + 14.50= 41.66 kN/m2

    > 0 Hence O.K.STRESS without Buoyancy = ( 2172.07 / 27.90 )+ / - ( 600.04 / 13.95 )+ / - ( 626.91 / 43.25 )

    = 77.85 + / - 43.01 + / - 14.50Pmax = 77.85 + 43.01 + 14.50 49.33 106.37

    = 135.36 kN/m2< 450 kN/m2 Hence O.K.

    Pmin = 77.85 - 43.01 - 14.50= 20.34 kN/m2

    > 0 Hence O.K. 20.34 135.36

    Stress Diagram

    Stress Diagram

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    CASE- 5 FOR ONE SPAN DISLODGED CONDITION AT R. L.92.97 MSUPER STRUCTURE = 480.30 kNSUB STRUCTURE = 1211.47 kN Without BuoyancySUB STRUCTURE = 997.25 kN With BuoyancyLIVE LOAD = 0.00 kNTotal Load without Buoyancy = 1691.77 kNTotal Load with Buoyancy = 1477.55 kNTotal LONGITUDINAL MOMENT = 600.04 kN-mTotal TRANSVERSE MOMENT = 600.04 + 26.86 = 626.91 kN-m

    STRESS with Buoyancy = ( 1477.55 / 27.90 )+ / - ( 600.04 / 13.95 )+ / - ( 626.91 / 43.25 )= 52.96 + / - 43.01 + / - 14.50

    Pmax = 52.96 + 43.01 + 14.50= 110.47 kN/m2 24.44 81.48

    < 450 kN/m2 Hence O.K.Pmin = 52.96 - 43.01 - 14.50

    = -4.55 kN/m2

    STABILITY CHECK FOR PIER Page 17 Date 2/15/2014

    = -4.55 kN/m2P3 = 52.96 + 43.01 - 14.50

    = 81.48 kN/m2 -4.55 110.47

    P4 = 52.96 - 43.01 + 14.50= 24.44 kN/m2

    STRESS without Buoyancy = ( 1691.77 / 27.90 )+ / - ( 600.04 / 13.95 )+ / - ( 0.00 / 43.25 )= 60.64 + / - 43.01 + / - 0.00

    Pmax = 60.64 + 43.01 + 0.00= 103.65 kN/m2 17.62 103.65

    Pmin = 60.64 - 43.01 - 0.00= 17.62 kN/m2

    P3 = 60.64 + 43.01 - 0.00= 103.65 kN/m2 17.62 103.65

    P4 = 60.64 - 43.01 + 0.00= 17.62 kN/m2

    CASE- 6 FOR SERVICE CONDITION AT R. L.93.97 MVERTICAL LOADS

    DEAD LOAD CALCULATIONSUPER STRUCTURE = 960.60 kN

    Stress Diagram

    Stress Diagram

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  • TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS2/227 Shiv Colony, BANSWARA Mob.- 9414868322

    SUB STRUCTURE = 809.71 kN Without BuoyancySUB STRUCTURE = 762.89 kN With BuoyancyLIVE LOAD = 582.00 kNTotal Load without Buoyancy = 2352.31 kNTotal Load with Buoyancy = 2305.48 kNTotal LONGITUDINAL MOMENT = 373.72 + 106.00 = 479.72 kN-mTotal TRANSVERSE MOMENT = 373.72 + 531.00 = 904.72 kN-m

    C.S.A. = 12.00 x 1.20 = 14.40 m2

    Ixx = 1/6x 12.00 x 1.20 2 = 2.88 m3

    Iyy = 1/6x 12.00 2 x 1.20 = 28.80 m3

    STRESS with Buoyancy = ( 2305.48 / 14.40 )+ / - ( 479.72 / 2.88 )+ / - ( 904.72 / 28.80 )= 160.10 + / - 166.57 + / - 31.41

    Pmax = 160.10 + 166.57 + 31.41= 358.09 kN/m2

    < 8000 kN/m2 (that is 8 N/mm2 ) Hence O.K.

    STABILITY CHECK FOR PIER Page 18 Date 2/15/2014

    < 8000 kN/m2 (that is 8 N/mm2 ) Hence O.K.Pmin = 160.10 - 166.57 - 31.41

    = -37.88 kN/m2> (- 3600 kN/m2 (that is 3.6 N/mm2 ) Hence O.K.

    STRESS without Buoyancy = ( 2352.31 / 14.40 )+ / - ( 479.72 / 2.88 )+ / - ( 904.72 / 28.80 )= 163.35 + / - 166.57 + / - 31.41

    Pmax = 163.35 + 166.57 + 31.41= 361.34 kN/m2

    < 8000 kN/m2 (that is 8 N/mm2 ) Hence O.K.Pmin = 163.35 - 166.57 - 31.41

    = -34.63 kN/m2> (- 3600 kN/m2 (that is 3.6 N/mm2 ) Hence O.K.

    CASE- 7 FOR IDLE CONDITION AT R. L.93.97 MSUPER STRUCTURE = 960.60 kNSUB STRUCTURE = 809.71 kN Without BuoyancySUB STRUCTURE = 762.89 kN With BuoyancyLIVE LOAD = 0.00 kNTotal Load without Buoyancy = 1770.31 kNTotal Load with Buoyancy = 1723.48 kN

    STRESS with Buoyancy = ( 1723.48 / 14.40 )+ / - ( 373.72 / 2.88 )+ / - ( 373.72 / 28.80 )= 119.69 + / - 129.76 + / - 12.98

    Pmax = 119.69 + 129.76 + 12.98= 262.43 kN/m2

    < 8000 kN/m2 (that is 8 N/mm2 ) Hence O.K.Pmin = 119.69 - 129.76 - 12.98

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  • TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS2/227 Shiv Colony, BANSWARA Mob.- 9414868322

    = -23.05 kN/m2> (- 3600 kN/m2 (that is 3.6 N/mm2 ) Hence O.K.

    STRESS without Buoyancy = ( 1770.31 / 14.40 )+ / - ( 373.72 / 2.88 )+ / - ( 373.72 / 28.80 )= 122.94 + / - 129.76 + / - 12.98

    Pmax = 122.94 + 129.76 + 12.98= 265.68 kN/m2

    < 8000 kN/m2 (that is 8 N/mm2 ) Hence O.K.Pmin = 122.94 - 129.76 - 12.98

    = -19.80 kN/m2> (- 3600 kN/m2 (that is 3.6 N/mm2 ) Hence O.K.

    CASE- 8 FOR WIND FORCE AT SERVICE CONDITION AT R. L.93.97 MSUPER STRUCTURE = 960.60 kNSUB STRUCTURE = 809.71 kN Without Buoyancy

    STABILITY CHECK FOR PIER Page 19 Date 2/15/2014

    SUB STRUCTURE = 809.71 kN Without BuoyancySUB STRUCTURE = 762.89 kN With BuoyancyLIVE LOAD = 582.00 kNTotal Load without Buoyancy = 2352.31 kNTotal Load with Buoyancy = 2305.48 kNTotal LONGITUDINAL MOMENT = 373.72 + 106.00 = 479.72 kN-mTotal TRANSVERSE MOMENT = 373.72 + 28.97 + 531.00 = 933.68 kN-m

    STRESS with Buoyancy = ( 2305.48 / 14.40 )+ / - ( 479.72 / 2.88 )+ / - ( 933.68 / 28.80 )= 160.10 + / - 166.57 + / - 32.42

    Pmax = 160.10 + 166.57 + 32.42= 359.09 kN/m2

    < 8000 kN/m2 (that is 8 N/mm2 ) Hence O.K.Pmin = 160.10 - 166.57 - 32.42

    = -38.89 kN/m2> (- 3600 kN/m2 (that is 3.6 N/mm2 ) Hence O.K.

    STRESS without Buoyancy = ( 2352.31 / 14.40 )+ / - ( 479.72 / 2.88 )+ / - ( 933.68 / 28.80 )= 163.35 + / - 166.57 + / - 32.42

    Pmax = 163.35 + 166.57 + 32.42= 362.34 kN/m2

    < 8000 kN/m2 (that is 8 N/mm2 ) Hence O.K.Pmin = 163.35 - 166.57 - 32.42

    = -35.63 kN/m2> (- 3600 kN/m2 (that is 3.6 N/mm2 ) Hence O.K.

    CASE- 9 FOR WIND FORCE AT IDLE CONDITION AT R. L.93.97 M

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  • TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS2/227 Shiv Colony, BANSWARA Mob.- 9414868322

    SUPER STRUCTURE = 960.60 kNSUB STRUCTURE = 809.71 kN Without BuoyancySUB STRUCTURE = 762.89 kN With BuoyancyLIVE LOAD = 582.00 kNTotal Load without Buoyancy = 2352.31 kNTotal Load with Buoyancy = 2305.48 kNTotal LONGITUDINAL MOMENT = 373.72 kN-mTotal TRANSVERSE MOMENT = 373.72 + 28.97 = 402.68 kN-m

    STRESS with Buoyancy = ( 2305.48 / 14.40 )+ / - ( 373.72 / 2.88 )+ / - ( 402.68 / 28.80 )= 160.10 + / - 129.76 + / - 13.98

    Pmax = 160.10 + 129.76 + 13.98= 303.85 kN/m2

    < 8000 kN/m2 (that is 8 N/mm2 ) Hence O.K.Pmin = 160.10 - 129.76 - 13.98

    = 16.36 kN/m2> (- 3600 kN/m2 (that is 3.6 N/mm2 ) Hence O.K.

    STABILITY CHECK FOR PIER Page 20 Date 2/15/2014

    > (- 3600 kN/m2 (that is 3.6 N/mm2 ) Hence O.K.

    STRESS without Buoyancy = ( 2352.31 / 14.40 )+ / - ( 373.72 / 2.88 )+ / - ( 402.68 / 28.80 )= 163.35 + / - 129.76 + / - 13.98

    Pmax = 163.35 + 129.76 + 13.98= 307.10 kN/m2

    < 8000 kN/m2 (that is 8 N/mm2 ) Hence O.K.Pmin = 163.35 - 129.76 - 13.98

    = 19.61 kN/m2> (- 3600 kN/m2 (that is 3.6 N/mm2 ) Hence O.K.

    STABILITY CHECK FOR PIER Page 20 Date 2/15/2014

  • R.L. 93.57 M TO 94.17 MFOR SERVICE CONDITION

    VERTICAL LOADSSUPER STRUCTURE = 960.60 kNSUB STRUCTURE = 809.71 kN Without BuoyancySUB STRUCTURE = 762.89 kN With BuoyancyLIVE LOAD = 582.00 kNTotal Load without Buoyancy = 2352.31 kNTotal Load with Buoyancy = 2305.48 kNTotal LONGITUDINAL MOMENT

    Moment @ R. L. 93.97 M = 479.72 kN-mTotal TRANSVERSE MOMENT

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    REINFORCEMENT CALCULATION IN PIER IN LOWER FLARED PORTION

    STEEL IN FLARED PIER BASE Page 19 Date 2/15/2014

    Total TRANSVERSE MOMENTMoment @ R. L. 93.97 M = 933.68 kN-m

    CONCRETE MIX M-30CHARACTERISTIC STRENGTH OF REINFORCEMENT 415 N/mm2PERMISSIBLE STRESSESIN STEEL 190IN CONCRETECHARACTERISTIC STRENGTH OFConcrete fck = 20 N/mm2Permissible Compressive Stress inBending cbc = 8 N/mm2Permissible Compressive Stress in DirectCompression cc = 8 N/mm2

    ct = 3.6 N/mm2Ultimate Axial Load PU = 1.5 X 2352.31 = 3528.465 kNUltimate Longitudinal Moment MU = 1.5 X 479.72 = 719.5792 kN-mUltimate Transverse Moment MU = 1.5 X 933.68 = 1400.527 kN-mINCREASE WHEN WIND CONDITION IS CONSIDERED 33.33 %Neglecting area of Cut and Ease water parts Rectangular Section considered is

    8900 mm x 2000 mmAssume cover as 75

    d1/d = 85 / 2000 = 0.0425

    STEEL IN FLARED PIER BASE Page 19 Date 2/15/2014

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    PU/(fck b d) = 3528.47 x 1000 / ( 20 x 8900 x 2000 )= 0.0099

    FOR LONGITUDINAL MOMENTMu/(fck b d

    2) = 719.58 x 1000000 / ( 20 x 8900 x 2000 2 )= 0.0010

    CRITERIA 1 FOR MINIMUM STEEL Pt = 0.8 % OF CROSS SECTION AREA OF COLUMN REQUIRED FOR COMPRESSION

    Area Required due to Compression = 2305.48 x 1000 / 8= 288185 mm2

    The point lies below the range of applicability. Hence provide minimum percentage of steel

    Refer Chart 31 & 32 of Design Aids for Reinforced concrete SP-16 the point lies below the range of applicability. Hence provide minimumpercentage of steel.

    STEEL IN FLARED PIER BASE Page 20 Date 2/15/2014

    = 288185 mm2Area of steel @ 0.8% = 0.8 x 288185 / 100

    = 2305 mm2

    CRITERIA 2 FOR MINIMUM STEEL Pt = 0.3 % OF GROSS SECTION AREA OF COLUMNArea of steel @ 0.3% = 0.3 x 8900 x 2000 / 100

    = 53400 mm2

    PROVIDE STEEL AREA = 53400 mm2NO. OF 20 MM BARS = 170 Nos.SPACING = 120 MMFOR TRANSVERSE MOMENT

    Mu/(fck b d2) = 1400.53 x 1000000 / ( 20 x

    8900 x 2000 2 )= 0.0020

    TRANSVERSE REINFORCEMENTShear Force to be resisted by the pier In Accordance to IS 1893

    933.68 / 11.87 = 78.64 kNCheck for Shear

    Refer Chart 31 & 32 of Design Aids for Reinforced concrete SP-16 the point lies below the range of applicability. Hence provide minimumpercentage of steel.

    STEEL IN FLARED PIER BASE Page 20 Date 2/15/2014

  • TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS2/227 Shiv Colony, BANSWARA Mob.- 9414868322

    Nominal Shear Stress = 78.64 x 1000 / ( 8900 x 2000 )= 0.00 N/mm2

    Pt 0.30Permissible Shear Stress = 0.40 N/mm2 Refer table 61

    According to IRC 21-1987 Clause 306.3Dia of Transverse Reinforcement = 20 / 4 = 5 mm

    Provide 12 mm dia ringsPitch of the Transverse should be least ofa) Least lateral Dimension = 2000 mmb) 12 d = 12 x 12 = 144 mmc) 300 mm = 300 mmd) As per IS IS 13920:1993 Cl. 7.4.6 < or = 100 mm

    Nominal Shear Reinforcement will suffice

    STEEL IN FLARED PIER BASE Page 21 Date 2/15/2014

    c) 300 mm = 300 mmd) As per IS IS 13920:1993 Cl. 7.4.6 < or = 100 mm

    Provide 12 mm dia rings @ 100 mm c/c.This spacing is in accordance to IS 13920:1993 Cl. 7.4.6CODE OF PRACTICE FOR DUCTILE DETAILING OF REINFORCED CONCRETE STRUCTURES SUBJECTED TO SEISMIC FORCESCheck for Size of Hoop Reinforcement Refer IS 13920:1993 Cl. 7.4.8

    Ash= 0.18 Sh (Fck/Fy)x(Ag/Ak-1)S = 100.00 mmh = 300.00 N/mm2 (Spacing of long. bars+ effective cover) or 300 mm whichever is less

    Fck = 30.00 N/mm2 Cover 75 mm to main reinforcementFy = 415.00 N/mm2

    Ag = 2000.00 mm2 Considering 1 mm Wide PierAk = 1894.00 mm2 Considering 1 mm Wide Pier Effective

    Hence Ash = 21.85 mm2

    Ash ProvideD = 113.04 mm2 Which is OKd) As per IS IS 13920:1993 Cl. 7.4.6 < or = 100 mm

    Provide 12 mm dia rings @ 100 mm c/c.This spacing is in accordance to IS 13920:1993 Cl. 7.4.6CODE OF PRACTICE FORDUCTILE DETAILING OF REINFORCED CONCRETE STRUCTURES SUBJECTED TO SEISMIC FORCESABSTRACTLONGITUDINAL REINFORCEMENT 20 MM BARS 120 MM However Adopt spacing as 150 mmTRANSVERSE REINFORCEMENT 12mm dia rings @100mm c/c.

    STEEL IN FLARED PIER BASE Page 21 Date 2/15/2014

  • R.L. 94.17 M TO 100.80 MFOR SERVICE CONDITION

    VERTICAL LOADSSUPER STRUCTURE = 960.60 kNSUB STRUCTURE = 1211.47 kN Without BuoyancySUB STRUCTURE = 997.25 kN With BuoyancyLIVE LOAD = 582.00 kNTotal Load without Buoyancy = 2754.07 kNTotal Load with Buoyancy = 2539.84 kNTotal LONGITUDINAL MOMENT

    Moment @ R. L. 94.17 M = 706.04 kN-mTotal TRANSVERSE MOMENT

    Moment @ R. L. 94.17 M = 1131.04 kN-mCONCRETE MIX M-20

    TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS2/227 Shiv Colony, BANSWARA Mob.- 9414868322

    REINFORCEMENT CALCULATION IN PIER SUBMERSIBLE BRIDGE ACROSS AYAD RIVER ON OLD BHUPALPURA - NEW BHUPALPURA ROAD NEAR POLICE CHOWKI

    STEEL IN PIER Page 19 Date 2/15/2014

    CONCRETE MIX M-20CHARACTERISTIC STRENGTH OF REINFORCEMENT 415 N/mm2PERMISSIBLE STRESSESIN STEEL 190IN CONCRETECHARACTERISTIC STRENGTH OFConcrete fck = 20 N/mm2Permissible Compressive Stress inBending cbc = 8 N/mm2Permissible Compressive Stress in DirectCompression cc = 8 N/mm2

    ct = 3.6 N/mm2Ultimate Axial Load PU = 1.5 X 2754.07 = 4131.105 kNUltimate Longitudinal Moment MU = 1.5 X 706.04 = 1059.067 kN-mUltimate Transverse Moment MU = 1.5 X 1131.04 = 1696.567 kN-mINCREASE WHEN WIND CONDITION IS CONSIDERED 33.33 %Neglecting area of Cut and Ease water parts Rectangular Section considered is

    7900 mm x 1000 mmAssume cover as 75

    d1/d = 85 / 1000 = 0.0850PU/(fck b d) = 4131.11 x 1000 / ( 20 x 7900 x 1000 )

    = 0.0261FOR LONGITUDINAL MOMENT

    STEEL IN PIER Page 19 Date 2/15/2014

  • TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS2/227 Shiv Colony, BANSWARA Mob.- 9414868322

    Mu/(fck b d2) = 1059.07 x 1000000 / ( 20 x 7900 x 1000

    2 )= 0.0067

    CRITERIA 1 FOR MINIMUM STEEL Pt = 0.8 % OF CROSS SECTION AREA OF COLUMN REQUIRED FOR COMPRESSION

    Area Required due to Compression = 2539.84 x 1000 / 8= 317480 mm2

    Area of steel @ 0.8% = 0.8 x 317480 / 100= 2540 mm2

    CRITERIA 2 FOR MINIMUM STEEL Pt = 0.3 % OF GROSS SECTION AREA OF COLUMNArea of steel @ 0.3% = 0.3 x 7900 x 1000 / 100

    The point lies below the range of applicability. Hence provide minimum percentage of steel

    Refer Chart 31 & 32 of Design Aids for Reinforced concrete SP-16 the point lies below the range of applicability. Hence provide minimumpercentage of steel.

    STEEL IN PIER Page 20 Date 2/15/2014

    Area of steel @ 0.3% = 0.3 x 7900 x 1000 / 100= 23700 mm2

    PROVIDE STEEL AREA = 23700 mm2NO. OF 20 MM BARS = 75 Nos.SPACING = 230 MMFOR TRANSVERSE MOMENT

    Mu/(fck b d2) = 1696.57 x 1000000 / ( 20 x

    7900 x 1000 2 )= 0.0107

    TRANSVERSE REINFORCEMENTShear Force to be resisted by the pier In Accordance to IS 1893

    1131.04 / 11.87 = 95.27 kNCheck for Shear

    Nominal Shear Stress = 95.27 x 1000 / ( 7900 x 1000 )= 0.01 N/mm2

    Pt 0.30Permissible Shear Stress = 0.40 N/mm2 Refer table 61

    According to IRC 21-1987 Clause 306.3Dia of Transverse Reinforcement = 20 / 4 = 5 mm

    Nominal Shear Reinforcement will suffice

    Refer Chart 31 & 32 of Design Aids for Reinforced concrete SP-16 the point lies below the range of applicability. Hence provide minimumpercentage of steel.

    STEEL IN PIER Page 20 Date 2/15/2014

  • TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS2/227 Shiv Colony, BANSWARA Mob.- 9414868322

    Provide 12 mm dia ringsPitch of the Transverse should be least ofa) Least lateral Dimension = 1000 mmb) 12 d = 12 x 12 = 144 mmc) 300 mm = 300 mmd) As per IS IS 13920:1993 Cl. 7.4.6 < or = 100 mm

    Provide 12 mm dia rings @ 100 mm c/c.This spacing is in accordance to IS 13920:1993 Cl. 7.4.6CODE OF PRACTICE FOR DUCTILE DETAILING OF REINFORCED CONCRETE STRUCTURES SUBJECTED TO SEISMIC FORCESCheck for Size of Hoop Reinforcement Refer IS 13920:1993 Cl. 7.4.8

    Ash= 0.18 Sh (Fck/Fy)x(Ag/Ak-1)S = 100.00 mmh = 300.00 N/mm2 (Spacing of long. bars+ effective cover) or 300 mm whichever is less

    Fck = 30.00 N/mm2 Cover 75 mm to main reinforcementFy = 415.00 N/mm2

    STEEL IN PIER Page 21 Date 2/15/2014

    Fy = 415.00 N/mm2

    Ag = 1000.00 mm2 Considering 1 mm Wide PierAk = 894.00 mm2 Considering 1 mm Wide Pier Effective

    Hence Ash = 46.28 mm2

    Ash ProvideD = 113.04 mm2 Which is OKd) As per IS IS 13920:1993 Cl. 7.4.6 < or = 100 mm

    Provide 12 mm dia rings @ 100 mm c/c.This spacing is in accordance to IS 13920:1993 Cl. 7.4.6CODE OF PRACTICE FORDUCTILE DETAILING OF REINFORCED CONCRETE STRUCTURES SUBJECTED TO SEISMIC FORCESABSTRACTLONGITUDINAL REINFORCEMENT 20 MM BARS 230 MMTRANSVERSE REINFORCEMENT 12mm dia rings @100mm c/c.

    STEEL IN PIER Page 21 Date 2/15/2014

  • FOR WIND AT SERVICE CONDITIONLength of footing lf 9.30 mWidth of Footing lb 3.00 mWidth of Pier 1.00 mVertical Load P 2754.07 kNLongitudinal Moment Me 706.04 kN-mTransverse Moment Mb 1157.91 kN-mArea in Tension = y x lb 0.00 m2 0.00 %Maximum Pressure before Redistribution 176.10 kN/m2

    Maximum Pressure After Redistribution = pxK 176.10 kN/m2

    TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS2/227 Shiv Colony, BANSWARA Mob.- 9414868322

    DESIGN OF PIER FOOTING

    FOOTING DESIGN Page 44 Date 2/15/2014

    Maximum Pressure After Redistribution = pxK 176.10 kN/m2Maximum Stress at Edge of Pier 176.10 kN/m2Distance From Face of Pier to the Edge 1.00 mStress at the Edge of Pier 117.40 kN/m2Average Stress on Cantilevered Area 146.75 kN/m2Area of the Cantilever Portion 1.00 m2Distance of Centroid of the Stress inCantilever Portion

    0.53 m

    Moment about the Face of Pier 78.27 kN-mCONCRETE GRADE M20FOR THIS GRADE cbc 7 N/mm2m 13.33

    st 200factor k 0.318j 0.894R 0.996Effective Depth Required 280 mmAdopt Total Depth 600 mmCover 50 mmAssume Bar Dia 16 mmKeeping A Cover Of 50 mm Effective Depth 542 mm

    FOOTING DESIGN Page 44 Date 2/15/2014

  • TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS2/227 Shiv Colony, BANSWARA Mob.- 9414868322

    Adopt Effective Depth 542 mmSteel Required Ast 808 mm2Area Of One Bar 201 mm2Spacing S 249 mmProvide Bars Of Dia And Spacing 16 mm Adopt spacing as 240 mmArea Of Distribution Steel 2000 mm2Dia Of Bar For Distribution Steel 20 mm

    Area Of One Bar In Distribution Reinforcement 314 mm2Using The Bars Spacing Required 157 mmProvide Bars Of Dia And Spacing 20 mm 150 mm

    Provide Bars Of Dia And Spacing forTop Main Steel 12 mm 150 mm

    FOOTING DESIGN Page 45 Date 2/15/2014

    Provide Bars Of Dia And Spacing forTop Main Steel 12 mm 150 mmProvide Bars Of Dia And Spacing forTop Distribution Steel 12 mm 150 mm

    CHECK FOR SHEAR (As per IRC 21-1987 Cl. 304.7)Critical Section is at a distance equal to effective depth from pier face 542 mmSection of Shear from end of pier 0.46 mMaximum Stress at Edge of Pier 176.10 kN/m2Stress at the Section for Shear Check 153.70 kN/m2Average Stress on Cantilevered Area 164.90 kN/m2Shear Force 75.52 kNV=V' + M/d tanB (B=0) Hence V =V'Actual Shear Stress 0.14 N/mm2Percentage Steel 100As/bd 0.15Tc 0.23 N/mm2k=1Permissble Shear Stress = k Tc 0.23 N/mm2

    Dia Of two Legged Stirrups 12 mm

    < Actual Shear Stress hence ShearReinforcement should be provided

    FOOTING DESIGN Page 45 Date 2/15/2014

  • TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS2/227 Shiv Colony, BANSWARA Mob.- 9414868322

    Area Of One Bar In Distribution Reinforcement 113 mm2Using The Bars Spacing Required s= Asw ts d/V 324 mmProvide Bars Of Dia And Spacing 12 mm Adopt spacing as 150 mm

    FOOTING DESIGN Page 46 Date 2/15/2014FOOTING DESIGN Page 46 Date 2/15/2014

  • 1.00 m

    1.00 m

    3.00 m

    0.00 m

    117.40kN/m2 176.10 kN/m2

    STRESS DIAGRAM

    DESIGN OF PIER FOOTING

  • DESIGN OF PIER CAP :-D.L./ M Width along bridgeDL. Of Slab = 0.975 x 15 x. 2.4 = 35.10 TD.L. of Wearing coat = 0.075 x 12 x. 2.4 = 2.16 T

    TOTAL 37.26 T D.L. of Slab & Wearing coat on half of the pier =

    37.26 / 2 = 18.63 T L.L. on Pier cap including impact along bridge

    = 82.50 x 1.1375 = 93.84 T (Refer Live Load Computation) Dispersion width across the span for 70 T TRACKED VEHTCLE = 6.695 M ( Refer Solid slab design page SS-16) Live Load u.d.l. on Pier = 93.84 / 6.695 = 14.02 T

    Per M width Total Load on Half = 18.63 + 14.02 = 32.65 T of pier along bridge Per M widthEffective depth of slab =90-2.5-2.5/2 = 86.25 cmPlacement of the live load at effective depth from the support ( taking support width 750 mm)Eccentricity = 71.25 -75/2 = 33.75 cm = 0.34 M

    32.65 x 0.34 11.02 T - M/M width=

    11.02 x 10.00 = 110.2 kN-M/M width

    Bending Moment along the bridge =

    5 Design of Pier Cap Pier Cap 1

    =11.02 x 10.00 = 110.2 kN-M/M width

    This moment is too small hence it will not/be the governing B.M.Moment in pier cap 110.20 kN-mCONCRETE GRADE M30FOR THIS GRADE cbc 10 N/mm2m 9.33

    st 200factor k 0.318j 0.894R 1.422Effective Depth Required 278 mmAdopt Total Depth 1200 mmCover 50 mmAssume Bar Dia 25 mmKeeping A Cover Of 50 mm Effective Depth 1138 mmAdopt Effective Depth 1137.5 mmSteel Required Ast 542 mm2Area Of One Bar 491 mm2Spacing S 905 mmProvide Bars Of Dia And Spacing 25 mm 100 mm Adopt spacing as 100 mmProvide Bars Of Dia And Spacing for Top Main Steel 25 mm 100 mmProvide Bars Of Dia And Spacing for Bottom Steel 16 mm 100 mm

    PIER SECTION ACROSS BRIDGEDEAD LOAD MOMENT PER METRE Width across bridge :-Slab D.L. 0.975 x 15 x. 2.4 = 35.10 TD.L. of Wearing coat = 0.075 x 12 x. 2.4 = 2.16 T

    5 Design of Pier Cap Pier Cap 1

  • TOTAL 37.26 TD.L. of Slab & Wearing coat on half of the pier =

    37.26 / 2 = 18.63 T/ M widthL.L on pier = 64.69 T

    Dispersion width along the span for70 T Tracked vehical = 5.3 M

    L.L. . per M width on pier = 64.69 / 5.3 = 12.21 T/ M widthTotal D.L. + L.L. on half of Pier across 18.63 + 12.21 = 30.84 Tbridge per M width Per M widthThe Live Load is with clearance from the Footpath and kerb. The cantilever portion of pier cap and width of footpath is 1500 mmHence There is no eccentricity.

    30.84 x 0 0.00 T - M/M widthProvide Minimum steelMinimum Reinforcement calculation for Pier cap :- As per clause 710.8.2, IRC- 78 - 2000, the thickness of pier cap shall be at least 200 mm However the thickness of Pier cap here is 1200 MM. Grade of Concrete M 30Minimum Shrinkage and Temperature reinforcement required as per Clause 305.10 IRC 21-2000in any RC structure is 250 Sq mm per m in each direction. Allowable maximum spacing is 300 mm.Shrinkage and Temperature reinforcement required = 250 x 1.2 = 300 mm2

    Bending Moment across the bridge =

    5 Design of Pier Cap Pier Cap 2

    Shrinkage and Temperature reinforcement required = 250 x 1.2 = 300 mm2

    Provide 25 mm tor reiforcement @ 100 mm c/c ( 14 Nos.) in top along the pier capProvide 16 mm tor reiforcement @ 100 mm c/c ( 14 Nos.) in bottom along the pier capArea of Steel Provided at top= (14x 491) = 6874 mm2 > 300 mm2 OK

    Area of Steel Provided at bottom= (14x 201) = 2814 mm2 > 300 mm2 OKCHECK FOR SHEAR ALONG BRIDGE DIRECTION

    V = 30.84 TShear Force 308.40 kNV=V' + M/d tanB (B=0) Hence V =V'Actual Shear Stress 0.27 N/mm2Percentage Steel 100As/bd 0.25Tc 0.23 N/mm2k=1Permissble Shear Stress = k Tc 0.23 N/mm2

    Dia Of two Legged Stirrups 16 mm

    Area Of One Bar In Distribution Reinforcement 201 mm2Using The Bars Spacing Required s= Asw ts d/V 296 mmProvide Bars Of Dia And Spacing 16 mm 100 mm Adopt spacing as 100 mm

    HOWEVERProvide 16 mm tor 2 legged vertical stirrups @ 100 mm centre to centre along the pier capProvide 16 mm tor 2 legged horizontal stirrups @ 100 mm centre to centre along the pier cap

    < Actual Shear Stress hence ShearReinforcement should be provided

    5 Design of Pier Cap Pier Cap 2

  • SHEAR CHECK ACROSS BRIDGE DIRECTIONV = 20.3 TShear Force 203.00 kNV=V' + M/d tanB (B=0) Hence V =V'Actual Shear Stress 0.18 N/mm2Percentage Steel 100As/bd 0.25Tc 0.23 N/mm2k=1Permissble Shear Stress = k Tc 0.23 N/mm2

    HOWEVERProvide 16 mm tor 2 legged vertical stirrups @ 100 mm centre to centre along the pier capProvide 16 mm tor 2 legged horizontal stirrups @ 100 mm centre to centre along the pier cap

    > Actual Shear Stress hence No ShearReinforcement is required.

    5 Design of Pier Cap Pier Cap 35 Design of Pier Cap Pier Cap 3

  • LIVE LOAD CALCULATION :-

    [1] CLASS AA TRACKED VEHICLE :-

    (a) Dispersion width along the span

    According to clause 305.13 IRC- 21-2000

    = Length of Contact + 2 (Wearing coat + depth of Slab)

    = 3.6 + 2 ( 0.075 + 0.775 )

    = 5.3 M(b) Dispersion width across the span

    According to clause 305.13 IRC- 21-2000

    be = K x ( 1 - x/Le ) +bwK = A Constant having the value depending upon the ratio(L1/Le where.be = the effective width of the slab on which the load acts.Le = Effective Spanx = the distance of c.g. of concentrate load from the near supportbw = The breadth of concentration area of the load i.e. Dimension of the tyre or track contact area over the road surfaceHeve ,

    Le = 10.00 M & L1 = 7.00 M

    = = 0.7

    5 Design of Pier Cap Live load tracked vehicle 4

    = L1 7.00 Le 10.0Value of K = 2.4

    bw = 0.85 + 2 x 0.075 = 1.0 M

    X = L 102 2

    be = 2.4 x 4 ( 1 - 5/10) + 1 = 5.8 MImpact factor is 13.75% as pere IRC Section-II, Clause - 211-3 (a) (i)

    DISPERSION ACROSS SPAN (CLASS AA TRACKED VEHICAL)The tracked vehicle is placed at a distance of minimum clearence of 1-2 m from Kerb Dispersion across span = C/C distance between wheels + width from centre of wheel on clearence side + Least on other side or halp the dispersion of one wheel. = 2.05 + 1.93 + Least of 2.715 OR 5.8/2 = 2.05 + 1.93 + 2.715 = 6.695Impact factor = 1.1375 Total load with impact= 70 x 1.1375 = 79.63 T = Intensity of Load

    = T/M79.63 = 2.24

    = = 0.7

    = = 5.0 M

    5 Design of Pier Cap Live load tracked vehicle 4

  • Maximum Reaction

    Reaction RA= 2.24x 3.00 x 1.50 /10.00= 1.01 T

    Reaction RB= 2.24x 3.00 -1.01= 5.71 T

    DISPERSION ALONG SPAN (CLASS AA TRACKED VEHICLE)(a) Dispersion width along the span :- tp = tc = 2 (tw + ts ) tp = width of dispersion parallel to span tc = width of tyre contact area parallel to span ts = Overall depth of slab tw = Thickness of Wearing coatDispersion along the span = 0.15 + 2 ( 0.075 + 0.775 ) = 1.9 M Dispersion between two wheel is overlapping hence restricted to 1-2 M = Dispersion combined for two wheels = C/c distance between + Longitudinal two wheels dispersion = 1-2 + 1.9 = 3.1 M ( along the span )Impact factor = 1.1375

    For Maximum reaction at support the Centre of gravity of the loads should beadjacent to one support should be adjacent to one support

    5.30 x 6.695 = 2.24

    5 Design of Pier Cap Live load tracked vehicle 5

    Impact factor = 1.1375 Total load with impact= 70 x 1.1375 = 79.63 T = Intensity of Load =

    Maximum Reaction

    Reaction RA= 7.91x 3.00 x 1.50 /10.00= 3.56 T

    Reaction RB= 7.91x 3.00 -3.56= 20.17 T

    For Maximum reaction at support the Centre of gravity of the loads should beadjacent to one support should be adjacent to one support

    T/M79.63 = 7.911.90 x 5.30

    5 Design of Pier Cap Live load tracked vehicle 5

  • DESIGN OF Abutment CAP SUBMERSIBLE BRIDGE PADLA TO JAWAR MINES ROADDESIGN OF Abutment CAP :-D.L./ M Width along bridgeDL. Of Slab = 0.675 x 8.4 x. 2.4 = 13.61 TD.L. of Wearing coat = 0.075 x 7.5 x. 2.4 = 1.35 T

    TOTAL 14.96 T D.L. of Slab & Wearing coat on half of the Abutment =

    14.96 / 2 = 7.48 T L.L. on Abutment cap including impact along bridge

    = 58.20 x 1.1375 = 66.20 T (Refer Live Load Computation) Dispersion width across the span for 70 T TRACKED VEHTCLE = 6.695 M ( Refer Solid slab design page SS-16) Live Load u.d.l. on Abutment = 66.20 / 6.695 = 9.89 T

    Per M width Total Load on Half = 7.48 + 9.89 = 17.37 T of Abutment along bridge Per M widthEffective depth of slab =90-2.5-2.5/2 = 86.25 cmPlacement of the live load at effective depth from the support ( taking support width 750 mm)Eccentricity = 71.25 -75/2 = 33.75 cm = 0.34 M

    17.37 x 0.34 5.87 T - M/M width=

    5.87 x 10.00 = 58.7 kN-M/M width

    Bending Moment along the bridge =

    6 Design of ABUTMENT SUBMERSIBLE BRIDGE PADLA JAWAR MINES ROAD Abutment Cap 1

    =5.87 x 10.00 = 58.7 kN-M/M width

    This moment is too small hence it will not/be the governing B.M.Moment in Abutment cap 58.70 kN-mCONCRETE GRADE M20FOR THIS GRADE cbc 7 N/mm2m 13.33

    st 200factor k 0.318j 0.894R 0.996Effective Depth Required 243 mmAdopt Total Depth 450 mmCover 50 mmAssume Bar Dia 16 mmKeeping A Cover Of 50 mm Effective Depth 392 mmAdopt Effective Depth 392 mmSteel Required Ast 838 mm2Area Of One Bar 201 mm2Spacing S 240 mmProvide Bars Of Dia And Spacing 16 mm 200 mm Adopt spacing as 100 mmProvide Bars Of Dia And Spacing for Top Main Steel 16 mm 200 mmProvide Bars Of Dia And Spacing for Bottom Steel 16 mm 200 mm

    Abutment SECTION ACROSS BRIDGEDEAD LOAD MOMENT PER METRE Width across bridge :-Slab D.L. 0.975 x 15 x. 2.4 = 35.10 TD.L. of Wearing coat = 0.075 x 12 x. 2.4 = 2.16 T

    6 Design of ABUTMENT SUBMERSIBLE BRIDGE PADLA JAWAR MINES ROAD Abutment Cap 1

  • TOTAL 37.26 TD.L. of Slab & Wearing coat on half of the Abutment =

    37.26 / 2 = 18.63 T/ M widthL.L on Abutment = 64.69 T

    Dispersion width along the span for70 T Tracked vehical = 5.3 M

    L.L. . per M width on Abutment = 64.69 / 5.3 = 12.21 T/ M widthTotal D.L. + L.L. on half of Abutment across 18.63 + 12.21 = 30.84 Tbridge per M width Per M widthThe Live Load is with clearance from the Footpath and kerb. The cantilever portion of Abutment cap and width of footpath is 1500 mmHence There is no eccentricity.

    30.84 x 0 0.00 T - M/M widthProvide Minimum steelMinimum Reinforcement calculation for Abutment cap :- As per clause 710.8.2, IRC- 78 - 2000, the thickness of Abutment cap shall be at least 200 mm However the thickness of Abutment cap here is 1200 MM. Grade of Concrete M 30Minimum Shrinkage and Temperature reinforcement required as per Clause 305.10 IRC 21-2000in any RC structure is 250 Sq mm per m in each direction. Allowable maximum spacing is 300 mm.Shrinkage and Temperature reinforcement required = 250 x 1.2 = 300 mm2

    Bending Moment across the bridge =

    6 Design of ABUTMENT SUBMERSIBLE BRIDGE PADLA JAWAR MINES ROAD Abutment Cap 2

    Shrinkage and Temperature reinforcement required = 250 x 1.2 = 300 mm2

    Provide 25 mm tor reiforcement @ 100 mm c/c ( 14 Nos.) in top along the Abutment capProvide 16 mm tor reiforcement @ 100 mm c/c ( 14 Nos.) in bottom along the Abutment capArea of Steel Provided at top= (14x 491) = 6874 mm2 > 300 mm2 OK

    Area of Steel Provided at bottom= (14x 201) = 2814 mm2 > 300 mm2 OKCHECK FOR SHEAR ALONG BRIDGE DIRECTION

    V = 30.84 TShear Force 308.40 kNV=V' + M/d tanB (B=0) Hence V =V'Actual Shear Stress 0.79 N/mm2Percentage Steel 100As/bd 0.72Tc 0.23 N/mm2k=1Permissble Shear Stress = k Tc 0.23 N/mm2

    Dia Of two Legged Stirrups 16 mm

    Area Of One Bar In Distribution Reinforcement 201 mm2Using The Bars Spacing Required s= Asw ts d/V 102 mmProvide Bars Of Dia And Spacing 16 mm 100 mm Adopt spacing as 100 mm

    HOWEVERProvide 16 mm tor 2 legged vertical stirrups @ 100 mm centre to centre along the Abutment capProvide 16 mm tor 2 legged horizontal stirrups @ 100 mm centre to centre along the Abutment cap

    < Actual Shear Stress hence ShearReinforcement should be provided

    6 Design of ABUTMENT SUBMERSIBLE BRIDGE PADLA JAWAR MINES ROAD Abutment Cap 2

  • SHEAR CHECK ACROSS BRIDGE DIRECTIONV = 20.3 TShear Force 203.00 kNV=V' + M/d tanB (B=0) Hence V =V'Actual Shear Stress 0.52 N/mm2Percentage Steel 100As/bd 0.72Tc 0.23 N/mm2k=1Permissble Shear Stress = k Tc 0.23 N/mm2

    HOWEVERProvide 16 mm tor 2 legged vertical stirrups @ 100 mm centre to centre along the Abutment capProvide 16 mm tor 2 legged horizontal stirrups @ 100 mm centre to centre along the Abutment cap

    > Actual Shear Stress hence No ShearReinforcement is required.

    6 Design of ABUTMENT SUBMERSIBLE BRIDGE PADLA JAWAR MINES ROAD Abutment Cap 36 Design of ABUTMENT SUBMERSIBLE BRIDGE PADLA JAWAR MINES ROAD Abutment Cap 3

  • Thickness of Deck Slab 600 mm

    Thickness of Approach Slab 300 mm

    Height below Approach Slab 6705 mm

    Length of Heel projection 2750 mm Offset 250 mm

    Length of Toe projection 2100 mm Offset 600 mm

    Width of Stem 1050 mm

    Thickness of Abutment Cap 450 mm

    Thickness of Dirt Wall 300 mm

    Depth of Footing 600 mm

    300

    RL 99.975 M

    300 APPROACH SLAB

    DECK SLAB 600

    DIR

    T W

    ALL

    300

    AbutMENT Drawing Page 4 Date 2/15/2014

    450 PIER CAP

    250HEEL TOE

    600

    600

    RL 92.970 M

    2750 1050 2100

    5900

    TYPICAL SECTION OF THE ABUTMENT TYPABUT-01

    DIR

    T W

    ALL

    6705

    300

    5355

    AbutMENT Drawing Page 4 Date 2/15/2014

  • (a) Data Preliminary dimensions : Assumed as in Fig. TYPABUT-01Superstructure : RCC Slab Bridge Total Width of Slab = 15 m

    overall length = 11.10 mType of abutment : Reinforced concreteLoading : As for National HighwayBack fill : Gravel with angle of repose = 35 o

    18 kN/m3Angle of internal friction of soil on wall, z = 17.5 o

    Approach slab : R.C. slab 300 mm thick, adequately reinforcedLoad from superstructure per running metre of abutment wall:Dead load = 129.00 kN/m Total (2172.07/2) Kn in 8.40 m wide SlabLive load = 35.00 kN/m Total (582.00/2) Kn in 8.40 m wide Slab(Refer Stability Analysis for sub structure. The above two values are obtained from the calculations for superstructure, and are taken to act over awidth of 15 m).Bearing : Tar Paper Bearings

    Design of ABUTMENT

    TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS

    2/227 Shiv Colony, Banswara

    Unit weight of back fill, w =

    STABILITY CHECK ABUTMENT Page 5 Date 2/15/2014

    (C) Self weight of abutment

    (d) Longitudinal forces (i) Force due to braking

    Force due to 70 R wheeled vehicle = 0.2 x 1000 = 200 kNThis force acts at 1.2 m above the road level(Clause 214.3).

    Force on one abutment wall = 200 / 2 = 100 kNHorizontal force per m of wall = 100 / 8.4 = 11.91 kN/ m

    (ii) Force due to temperature variation and shrinkageAssuming moderate climate, variation in temperature is taken as + 17 oC as perClause 218.5 of Bridge Code.

    Coefficient of Thermal expansion = 1.17E-05 /oCStrain due to temperature variation = 17 x 0.0000117 = 1.99E-04

    From Clause 220.3, strain due to concrete shrinkage =2.00E-04

    Total strain due to temperature and shrinkage = 1.99E-04 + 2.00E-04 = 3.99E-04Horizontal deformation of deck due to temperature andshrinkage affecting one abutment =

    3.99E-04 x 11100 /2 = 2.21E+00 mm

    (Refer Stability Analysis for sub structure. The above two values are obtained from the calculations for superstructure, and are taken to act over awidth of 15 m).Bearing : Tar Paper Bearings

    Treating the section as composed of 6 elements as shown in Fig. 1the weight of each element and moment about the point O on the front toe arecomputed as in Table 1

    STABILITY CHECK ABUTMENT Page 5 Date 2/15/2014

  • TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS

    2/227 Shiv Colony, Banswara

    Modulus of Elasticity Ec = 5000x fck1/2 = 31220.19 N/mm2Horizontal Stress due to strain in longitudinal direction

    at bearing level = 3.99E-04 x 31220.19 = 12.45 N/mm2Horizontal Force due to strain in longitudinal direction

    at bearing level (For 1 m width of Slab) = 1.25E+01 x 900 = 11208.36 N/m= 11.21 kN/m

    (iii) Vertical reaction due to braking 200(1.2 + 0.975)Vertical reaction at one abutment = ---------------------- = 2.61 kN/m 11.10x15

    (d)Earth pressureActive earth pressure P = 0.5 wh2 Kawhere Ka is obtained from Equation (3.5)Ka = sec sin(-)/[(sin(+z)

    1/2 +{sin(+z) sin(-)/sin(-)}1/2]

    STABILITY CHECK ABUTMENT Page 6 Date 2/15/2014

    Ka = sec sin(-)/[(sin(+z)1/2 +{sin(+z) sin(-)/sin(-)}1/2]

    Where P= Total active pressure, acting at a height of 0.42 h inclined at z to the normal to the wall on the earth sidew = unit weight of earth fillh = height of wall = Angle subtended by the earthside wall with thw horizontal on the earth side = Angle of internal friction of the earthfillz = angle of friction of the earthside wall with the earth = Inclination of earthfill surface with the horizontal

    = 90 0 = 35 0

    z = 17.5 0 = 0 0

    Substituting values in Equation (3.5), we get Ka = 0.496 CoefficientHeight of backfill below approach slab = 6.71 m

    Active earth pressure =0.5 x 18 x 6.71 2 x 0.496

    = 200.69 kN/mHeight above base of centre of pressure = 0.42 x 6.71 = 2.82 m

    Passive pressure in front of toe slab is neglected.(e) Live load surcharge and approach slab

    Equivalent height of earth for live load surcharge as per clause 714.4 is 1.20 mHorizontal force due to L.L. surcharge =1.2 x 18 x 0.496 x 9.20 = 71.84 kN/mHorizontal force due to approach slab = 0.3 x 24 x 0.496 x 9.20 = 23.95 kN/m

    Total 95.79 kN/mThe above two forces act at 3.3525 m above the base.

    STABILITY CHECK ABUTMENT Page 6 Date 2/15/2014

  • TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS

    2/227 Shiv Colony, Banswara

    Vertical load due to L.L. surcharge and approach slab= (1.2 x 18 + 0.3 x 24 ) x 2.75 = 79.2 kN/m

    (f) Weight of earth on heel slabVertical load = 18 x2.75x (6.705 - 0.6) = 54.95 kN/m

    (g) Check for stability - overturningThe forces and their position are as shown in Fig. 1The forces and moments about the point O at toe on the base are tabulated as inTable 1 Two cases of lading condition are examined (i) Span loaded condition and (ii) Span unloaded condition.Case (i) Span loaded conditionSee Row 15 of Table 12.3Overturning moment about toe = 1035.27 kN-mRestoring moment about toe = 3008.97 kN-mFactor of safety against overturning = 3008.97 / 1035.27 = 2.91Location of Resultant from O > 1.5 Hence SafeX0 = ( MV - MH) / V= ( 1740.9 - 623.1) / 691.4 = 1.62 m

    STABILITY CHECK ABUTMENT Page 7 Date 2/15/2014

    X0 = ( MV - MH) / V= ( 1740.9 - 623.1) / 691.4 = 1.62 m=(3008.966 - 1035.272 ) / 909.948 ) = 2.17 m

    Eccentricity of resultantemax = B/6 = 5.9 /6 = 0.98 m

    e = (B/2 -X0) = 0.78 m < 0.80 m 2.95 - 2.17 = 0.78 m< 0.98 m

    Case (ii) Span unloaded conditionSee Row 11 of Table 12.3Overturning moment about toe = 958.93 kN-mRestoring moment about toe = 2915.86 kN-mFactor of safety against overturning = 2915.86 / 958.93 = 3.04Location of Resultant from O > 1.5 Hence SafeX0 = ( MV - MH) / V=

    =(2915.861 - 958.928 ) / 872.335 ) = 2.24 m(h)Check for stresses at base

    For Span loaded conditionTotal downward forces = 909.95 kN

    909.95 6 x 0.78Extreme stresses at base =

    Maximum Stress = 909.948/(5.9x1)(1 +(6x0.78/5.9)) = 276.57 kN/m2Minimum Stress = 909.948/(5.9x1)(1 -(6x0.78/5.9)) = 31.9 kN/m2

    STABILITY CHECK ABUTMENT Page 7 Date 2/15/2014

  • TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS

    2/227 Shiv Colony, Banswara

    SI.No. Arm

    m Mv MH1. D.L. from superstructure 129.00 - 2.48 319.920 -2. Horizontal force due to temperatre and shrinkage 0 11.21 6.41 - 71.8463. Active earth pressure 0 200.69 2.82 - 565.9464. Horizontal force due to L.L surcharge and approach

    slab0 95.79 3.3525 - 321.136

    Vertical load due to L.L.surcharge and approach slabSelf weight - part 1

    5.9x0.6x 24 =Self weight - part 2

    5.355x1.05x 24 =

    Table 1 Forces and Moments About Base for Abutment.

    -

    1.68

    354.9185

    2.95

    19.0512 -

    7. 2.63

    8. 11.34 -

    134.95 -

    6. 84.96 -

    358.384.525

    H

    -

    250.632 -

    5. 79.20 -

    Details Force, kN Moment about O, kn-mV

    STABILITY CHECK ABUTMENT Page 8 Date 2/15/2014

    Self weight - part 25.355x1.05x 24 =

    Self weight - part 30.45x1.05x 24 =

    Self weight - part 40.3x0.3x 24 =

    Self weight - part 5 Triangular River Side1/2x1.6x5.655x24=

    Self weight - part 5 Triangular Earth Fill Side1/2x2.25x5.505x24=

    Weight of earth on heel slab part 1 Rectangular Portion

    0.5 x 6.105 x 18=Weight of earth on heel slab part 2 Triangular Portion

    1/2x2.25x6.105x18= Items 1 to 10 (Span unloaded condition)L.L. from Superstructure Class 70 R wheeled vehicle

    13. Vertical force due to braking 2.61 - 2.48 -14. Horizontal force due to braking 0.00 11.91 6.41 76.3431

    Items 11 to 14

    -

    10. 114.51 - 4.65 532.4889 -

    9. 152.69 3.90

    9. 108.58 - 1.57 170.1024 -

    -4.428

    -

    595.4715

    3008.97 1035.27

    2915.86 958.93

    86.625 -

    15. 909.95 319.60 -

    12. 35.00 - 2.475

    11. 872.34

    310.4675 -5.65

    1.68

    9. 2.16 -

    10. 54.95 -

    -

    2.05

    354.9185

    19.0512 -

    7. 2.63

    8. 11.34 -

    134.95 -

    6.479

    STABILITY CHECK ABUTMENT Page 8 Date 2/15/2014

  • TEJHANS INVESTMENTSCIVIL & STRUCTURAL ENGINEERING CONSULTANTS

    2/227 Shiv Colony, Banswara

    (Span loaded condition)NET LONGITUDINAL MOMENT 3008.97 - 1035.27 = 1973.69

    Maximum pressure = 276.57 kN/m2 < 450 kN/m2 permissible HENCE OK.Minimum pressure = 31.9 kN/m2 >0 (No tension) HENCE OK.

    (i) Check for slidingSee Row 15 of Table 1

    Sliding force = 319.60 kNForce resisting sliding = 0.6 x 909.95 = 545.97 kN

    Factor of Safety against sliding = 545.97 / 319.60 = 1.76(j) Summary > 1.5 Hence Safe

    The assumed section of the abutment is adequate.

    3008.97 1035.2715. 909.95 319.60 -

    STABILITY CHECK ABUTMENT Page 9 Date 2/15/2014STABILITY CHECK ABUTMENT Page 9 Date 2/15/2014

  • REDISTRIBUTION OF PRESSUREFOR WIND AT SERVICE CONDITION

    Length of footing lf 9.25 mWidth of Footing lb 5.90 mWidth of Abutment just above footing 5.05 mVertical Load P 909.95 kNLongitudinal Moment Me 1973.69 kN-mTransverse Moment Mb 0.00 kN-mArea in Tension = y x lb 0.00 m2 0.00 %Maximum Pressure before Redistribution 276.57 kN/m2

    Maximum Pressure After Redistribution = pxK 276.57 kN/m2Maximum Stress at Edge of Pier 276.57 kN/m2Distance From Face of Pier to the Edge 0.60 mStress at the Edge of Pier 248.44 kN/m2Average Stress on Cantilevered Area 262.51 kN/m2

    DESIGN OF ABUTMENT FOOTING

    ABUTMENT FOOTING DESIGN Page 10 Date 2/15/2014

    Average Stress on Cantilevered Area 262.51 kN/m2Area of the Cantilever Portion 0.60 m2Distance of Centroid of the Stress inCantilever Portion

    0.31 m

    Moment about the Face of Pier 48.10 kN-mCONCRETE GRADE M20FOR THIS GRADE cbc 7 N/mm2m 13.33

    st 200factor k 0.318j 0.894R 0.996Effective Depth Required 220 mmAdopt Total Depth 600 mmCover 50 mmAssume Bar Dia 12 mmKeeping A Cover Of 50 mm Effective Depth 544 mmAdopt Effective Depth 544 mmSteel Required Ast 494 mm2

    ABUTMENT FOOTING DESIGN Page 10 Date 2/15/2014

  • Area Of One Bar 113 mm2Spacing S 229 mmProvide Bars Of Dia And Spacing 12 mm 150 mm Adopt spacing as 150 mmArea Of Distribution Steel 1088 mm2Dia Of Bar For Distribution Steel 12 mm

    Area Of One Bar In Distribution Reinforcement 113.04 mm2Using The Bars Spacing Required 104 mmProvide Bars Of Dia And Spacing 12 mm 100 mm Adopt spacing as 150 mm

    Provide Bars Of Dia And Spacing forTop Main Steel 12 mm 150 mmProvide Bars Of Dia And Spacing forTop Distribution Steel 12 mm 150 mm

    CHECK FOR SHEAR (As per IRC 21-1987 Cl. 304.7)Critical Section is at a distance equal to effective depth from pier face 544 mmSection of Shear from end of pier 0.06 mMaximum Stress at Edge of Pier 276.57 kN/m2

    ABUTMENT FOOTING DESIGN Page 11 Date 2/15/2014

    Maximum Stress at Edge of Pier 276.57 kN/m2Stress at the Section for Shear Check 272.27 kN/m2Average Stress on Cantilevered Area 274.42 kN/m2Shear Force 15.37 kNV=V' + M/d tanB (B=0) Hence V =V'Actual Shear Stress 0.03 N/mm2Percentage Steel 100As/bd 0.14Tc 0.23 N/mm2k=1Permissble Shear Stress = k Tc 0.23 N/mm2

    Dia Of two Legged Stirrups 12 mm

    Area Of One Bar In Distribution Reinforcement 113 mm2Using The Bars Spacing Required s= Asw ts d/V 1601 mmProvide Bars Of Dia And Spacing 12 mm 150 mm Adopt spacing as 150 mm

    < Actual Shear Stress hence ShearReinforcement should be provided

    ABUTMENT FOOTING DESIGN Page 11 Date 2/15/2014

  • 5.05 m

    0.25 m 0.60 m

    Footing STRESS DIAGRAM Page 12 Date 2/15/2014

    5.90 m

    0.31 m

    272.27kN/m2 276.57 kN/m2

    STRESS DIAGRAM

    DESIGN OF ABUTMENT FOOTING

    Footing STRESS DIAGRAM Page 12 Date 2/15/2014

  • Minimum Shrinkage and Temperature reinforcement required as per Clause 305.10 IRC 21-2000in any RC structure is 250 Sq mm per m in each direction. Allowable maximum spacing is 300 mm.

    Shrinkage and Temperature reinforcement required per metre = 250 mm2Area Of One Bar 12 mm dia 113 mm2Spacing S 452 mmProvide Bars Of Dia And Spacing 12 mm 150 mmProvide Bars Of Dia And Spacing 12 mm 150 mmHORIZONTAL SHRINKAGE &TEMPERATURE REINFORCEMENT 12 MM BARS 150 MM In Vertical direction on all FOUR facesVERTICAL SHRINKAGE &TEMPERATURE REINFORCEMENT 12 MM BARS 150 MM In Lateral direction on all FOUR faces

    REINFORCEMENT CALCULATION IN ABUTMENT

    STEEL IN ABUTMENT Page 13 Date 2/15/2014STEEL IN ABUTMENT Page 13 Date 2/15/2014

  • DESIGN OF DIRT WALL AS COLUMN WITH BENDINGAXIAL LOAD ON THE DIRT WALL 31.60 KNASSUME WIDTH OF DIRT WALL 1000 MM EMIN/B 0.00ASSUME DEPTH OF DIRT WALL 300 MM EMIN/D 0.01MOMENT TRANSFERRED TO DIRT WALL 12.80 KN-MFACTORED AXIAL LOAD 47.40 KNFACTORED MOMENT 19.20 KN-MDIA OF LONGITUDINAL REINFORCEMENT 10 MMCLEAR COVER 40 MMd' 45 MMd'/D 0.15ADOPT d'/D 0.15PU/FCKBD 0.01MU/FCKBD2 0.01REINFORCEMENT EQUALLY DISTRIDUTED ON TWO SIDESUSING CHART NO- OF RCC DESIGN AIDS 33 CONC GRADE M-30P/FCK 0.01P 0.3 > Minimum Steel 0.2% Hence OKAS 900 SQ MMTOTAL NUMBER OF BARS REQUIRED 12NUMBER OF BARS ON EACH SIDE 6SPACING 200 MM

    7 Design of Dirt Wall SUBMERSIBLE BRIDGE PADLA JAWAR MINES ROAD Page 1 DIRT WALL REINFORCEMENT

    SPACING 200 MM

    Alternate design Considering dirt wall as cantilever

    B.M. = 12.80 KN-Mdeff reqd. = 12.80 x 10 6

    1000 x 0.972dpro 300 - 50 - 16

    2Ast = 12.80 X mm2

    200 X 0.917 x 245This steel is to be provided on back i.e. approach slab side

    Provide Vertical steel as followsOn River side 10mm bars @ 150 mm c/c = 524 mm2

    On Approach Slab side 10mm bars @ 150 Mm c/c = 524 mm2

    Minimum steel required in Horizontal direction= 0.002 x 1000 x 250= 500 mm2

    i.e. 250 mm2 on each faceprovide 10 @ 250 mm c/c = 314 mm2

    ABSTRACT

    10 6 = 284.87

    > 118.7 mm (OK)

    = 118.7 mm

    = 245 mm

    7 Design of Dirt Wall SUBMERSIBLE BRIDGE PADLA JAWAR MINES ROAD Page 1 DIRT WALL REINFORCEMENT

  • VERTICAL REINFORCEMENT IN SHAPE OF STIRRUPS on both facesDIA 10 mmSPACING 150 mm

    HORIZONTAL REINFORCEMENT BAR DIA on both facesDIA 10 mmSPACING 250 mm

    7 Design of Dirt Wall SUBMERSIBLE BRIDGE PADLA JAWAR MINES ROAD Page 2 DIRT WALL REINFORCEMENT7 Design of Dirt Wall SUBMERSIBLE BRIDGE PADLA JAWAR MINES ROAD Page 2 DIRT WALL REINFORCEMENT

  • 96.110

    99.000

    76.80

    99.110

    83.40

    90.00

    96.100

    57.00

    96.150

    63.60

    97.110

    70.20

    GENERAL ARRANGEMENT DRAWING OF PROPOSED SUBMERSIBLE BRIDGE ON PADLA - JAWAR MINES ROAD

    PLAN

    A1

    CHAINAGEIN METER

    RIVER BEDLEVEL

    66006600

    6600

    SECTIONAL ELEVATION

    HIGH FLOOD LEVEL 99.480 MDECK LEVEL 99.975 MA2

    66006600

  • SE

    CT

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    A-A

    150150

    2200600

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    13800

    9300

    150150

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    600

    1500

    600VARIABLE

    300600300

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    12 MM

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    c/c

    20 MM

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    120 MM

    C/C

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    12 MM

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    16 MM

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    240 MM

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    .L. 92.67R

    .L. 92.970

    R.L. 93.570

    R.L. 93.870

    R.L. 98.775

    R.L. 99.375

    R.L. 99.975

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    600600

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    230 MM

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    920 mm

    c/c

    1000

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  • 150150

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    150150

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  • 1000 mm

    R.L. 98.100 M

    R.L. 98.700 M

    R.L. 99.300 M

    75

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    R.L. 98.850M

    R.L. 99.300M

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    in any direction.

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    150 mm

    c/c BO

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    R.L. 94.700M

    R.L. 95.000M

    R.L. 95.600M

    12 MM

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    SUBMERSIBLE BRIDGE PADLA JAWAR MINES.pdf1 GAD SUBMERSIBLE BRIDGE PADLA JAWAR MINES ROAD.pdf2 PIER SECTION AND PLAN.pdf3 PIER FOOTING AND PIER REINFORCEMENT.pdfPLAN OF ANCHOR HOLES.pdfDECK SLAB ANCHORING.pdfABUTMENT DRAWING ELEVATION.pdfABUTMENT DRAWING REINFORCEMENT DETAIL.pdfDIRT WALL DRAWING.pdf