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1 Lecture 4 Professor Hicks Inorganic Chemistry (CHE151) The Mole The mole is a counting unit like couple, dozen, gross etc. 1 mole of anything = 6.02 10 23 of that thing 6.02 10 23 is called Avogadro’s number Amedeo Avogadro Amedeo Avogadro

The Mole Amedeo Avogadro

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1

Lecture 4 Professor Hicks

Inorganic Chemistry (CHE151)

The Mole

• The mole is a counting unit like couple,

dozen, gross etc.

1 mole of anything = 6.02 1023 of that thing

• 6.02 1023 is called Avogadro’s number

Amedeo AvogadroAmedeo Avogadro

2

Avocado/Avogadro

Amedeo AvogadroAmedeo Avogadro

Avocado Avogadro

Counting units

• Used to express large numbers conveniently

• Why is 12 a counting unit?

• Dozens, 12 inches/foot, 12 hour clocks etc.

• Remember Avogadro’s number also a counting unit

3

Avogadro's Number

as a counting unit

• 6.02 x 1023 = one mole like 2 = 1 couple; 12 = 1 dozen; 144= 1 gross

N

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6.02 x 1023 amu

• another way to express

large numbers like:

- scientific notation

- unit prefixes

counting unit size

couple 2

dozen 12

gross 144

mole 6.02 x1023

the mole is big because atoms are very small

1 mole neutrons

Example: Convert 1.75 x 1017 gold atoms into units

of moles of gold atoms

Example: Convert 1055 bagels

into units of dozens of bagels

1055 bagels x

1 dozen bagels =12 bagels

1 dozen bagels

12 bagels = 87.9 dozen bagels

old unit

( number of bagels)

new unit

( dozens of bagels) conversion

factor

1.75 x 1017 gold atoms x 1 mole gold atoms

6.02 x 1023 gold atoms = 2.91 x 10-7

moles gold atoms

old unit

number of gold atoms new unit

moles of gold atoms conversion

factor

1 mole gold atoms = 6.02 x 1023 gold atoms

4

moles

of atoms number

of atoms

multiply

Avogadro's

number

divide

Avogadro's

number

dozens

of bagels

number

bagels

multiply

by 12

divide

by 12

Avogadro's number is

also a conversion factor

3.5 x 1022 amu x 1.0 g

6.02 x1023 amu = 0.058 g

old unit conversion factor

new unit

amu grams

6.02 x1023 amu = 1.0 g (Avogadro's number)

like 1 pound = 453.59 g

1 km = 0.62137 miles

2.54 cm = 1 inch

Example: Convert 3.5 x 1022 amu into grams.

5

Molar Mass 1 mole

phosphorus

molar mass

phosphorous = 30.974

grams

mole

molar mass

mass of one mole P atoms

atomic mass

average mass of one P atom

like the mass of a dozen donuts

like the mass of a single donut both reflect how heavy a

substance is but in different units

Why did they make Avogadro’s

number (the number of amu in a

gram) the counting unit used in

chemistry (the mole)?

6

amu grams

divide by

Avogadro's

number

number

atoms

number

moles divide by

Avogadro's

number

30.97 amu

atom 30.97 grams

mole

Atomic

mass

Molar

mass

6.02 x 1023 amu = 1.0 gram

6.02 x 1023 atoms = 1.0 mole atoms

as mass conversion factor

as a counting unit

Molar mass is a conversion factor

0.487 mole He atoms x 4.00 g helium

1 mole helium atoms = 1.95 g helium

old unit

moles conversion factor

molar mass

new unit

grams

mass moles

7

Molar mass is a conversion factor

1.23 grams arsenic × 1 mole arsenic atoms

74.922 grams arsenic

= 1.64 x 10-2 moles

of arsenic atoms (or

You could just say

moles of arsenic) old unit

grams conversion factor

1 / molar mass new unit

moles

Here honey have some arsenic

with your tea. BTW I just took out

a large life insurance policy on you

3 ways to describe amounts of an element like

grams & pounds; liters & mL; inches & cm etc.

Mass Moles Number

atoms

multiply

molar

mass

divide

molar

mass

divide

Avogadro's

number

multiply

Avogadro's

number

amu grams Avogadro's number

also converts

amu to grams

divide

Avogadro's

number

multiply

Avogadro's

number

8

What is the mass in grams of 19.00 amu?

How many amu are there in 1.16 g?

9

How many phosphorous atoms are there in 6.66

moles of phosphorous (atoms)?

How many moles of iron (Fe) atoms are in 17.4

g of Fe?

10

How many grams of silver (Ag) are there in 5.3

moles of Ag (atoms)?

What is the mass in grams of 6.66 × 109 sodium

(Na) atoms?

11

How many carbon atoms are present in 2.718 g

of carbon (C)?

What is the mass in grams of a single atom of

Co-60?

12

1 mole NO2

molecules

6.02 x 1023

NO2 molecules

Mole concept for compounds

• As a counting unit the mole is also applied

to molecules, ions, and formula units

1 mole CaCl2

formula units

6.02 x 1023

CaCl2 formula units

Ca2+

Cl- Cl-

1 CaCl2

formula unit

Counting moles of wheels in moles cars

1 mole cars = 6.02 x 1023 cars

How many moles of wheels are in 1 mole of cars?

4 wheels

per 1 car

4 wheels

1 car

4 dozen wheels

1 dozen cars 4 moles wheels

1 mole cars

13

Why do chemists use moles?

• Ratios of moles are the same as ratios of atoms

- 4 wheels per 1 car

- 4 dozen wheels per 1 dozen cars

- 4 moles wheels per 1 mole cars

• Amounts are easier to express without lots of

zeros

• Equivalent to counting atoms, but more

convenient

All

4 to 1

Molar mass of a compound

• Sum of all elements atomic masses

• Can be interpreted as either

- average mass in amu for each formula unit or

- grams for each mole of formula units

What is the molar mass of CaCl2?

Ca 1 x 40.078

2 Cl + 2 x 35.45

110.98 amu CaCl2

formula unit or

grams CaCl2

mole CaCl2

14

Molar mass (of a compound)

is (also) a conversion factor

0.789 moles NO2 molecules x = 36.29 g NO2

old unit

moles conversion factor

molar mass

new unit

grams

46.00 g NO2

1 mole NO2

mass moles

46.00 g/mol

NO2

N 1 x 14.02 g/mol

O 2 x 15.99 g/mol multiply

molar mass

Example. Convert 0.789 moles of NO2 into mass of NO2

When we refer to moles of a molecular compound it must be moles of

molecules so we do not need to say the word molecule

Molar mass (of a compound)

is (also) a conversion factor

6.66 grams C6H12O6 x 1 mole C6H12O6

180.10 grams C6H12O6 = 3.70 x 10-2 moles

C6H12O6 molecules old unit

grams conversion factor

1 / molar mass

new unit

moles

mass moles C 6 x 12.01

H 12 x 1.008

O 6 x 15.99

180.10 g/mol

C6H12O6

Example. Convert 6.66 grams of glucose C6H12O6 into moles of glucose

divide

molar mass

15

Mole concept for Molecular Elements

• Molecules of a molecular element can specified in

moles

• Note the language when referring to molecular

elements:

– If we say a mole of bromine or a mole of molecular

bromine we mean a mole of the diatiomic molecules

– Example: I reacted 2.5 moles of bromine mean

2.5 moles of Br2 were reacted

– If we mean to specify a number of bromine atoms

we must use the word atom

– Example 5.0 moles of SeBr2 molecules contains

10 moles of bromine atoms

Molar mass is a conversion factor

4.68 grams bromine x 1 mole bromine

159.808 grams bromine = 2.93x 10-2 moles

bromine (molecules)

old unit

grams conversion factor

1 / molar mass

new unit

moles

Br 2 × 79.904

159.808 g/mol

16

3 different units to describe amounts of a compound

like length of an object can be expressed in mm,

cm, inches, etc.

mass

compound

moles of

formula units,

molecules,

atoms,

or ions

number

formula units,

molecules,

atoms,

or ions

multiply

molar

mass

divide

molar

mass

divide

Avogadro's

number

multiply

Avogadro's

number

17

How many moles of molecular sulfur are in

165.123 grams of molecular sulfur?

18

19

Calculate the number of C, H, and O atoms in

1.75 g of squaric acid, C4H2O4

20

Calculate the molar mass of a compound if

0.258 mole of it has a mass of 25.3 g.

Molarity (M)

• Unit of concentration

molarity = moles

liter

• Conversion factor from volume of

a homogenous solution to moles

molarity

moles

liter × liters

× volume

= moles

= # moles in that volume

21

molarity

divide

stoichiometric

number

mass

compound

moles of

formula units,

molecules,

atoms,

or ions

number

formula units,

molecules,

atoms,

or ions

multiply

molar

mass

divide

molar

mass

multiply

molar

mass

divide

molar

mass

divide

Avogadro's

number

multiply

Avogadro's

number

divide

Avogadro's

number

multiply

Avogadro's

number

equivalents

multiply by

volume liters M × V = # moles

Example: What is the molarity of glucose (C6H12O6) in a solution made by dissolving 100.0 grams of glucose in enough water to make 250.0 ml of solution

1) molarity has units of liters

convert mL liters 250.0 mL x 10-3 liter

1.0 mL = 0.2500 L

2) Convert mass C6H12O6 to moles

100.0 grams x 1 mole

180.16 grams = 0.5551 moles

Molarity = # moles

#liters =

0.5551 mol

0.2500 L = 2.220 M glucose

22

Example: How many moles of NaCl are in

50.5 ml of a 0.250 M NaCl solution?

1) molarity has units of liters

convert mL liters

0.250 M NaCl x 0.0505 liters

50.5 mL x 10-3 liter

1.0 mL = 0.0505 L

= 0.0126 moles NaCl

x 0.0505 liters solution = 0.0126 moles NaCl 0.250 moles NaCl

liter solution

or if you write out the base units of molarity

23

How many moles of MgCl2 are present in 160.0 mL of

0.36 M MgCl2 solution?

How many moles of Mg2+ ions are in 160 mL?

How many moles of Cl- ions are in 160 mL?

24

How many grams of NaOH are present in 36.0 mL of a

2.50 M solution?

Calculate the volume in mL of a solution required to

provide the following:

(a) 2.14 g of sodium chloride from a 0.270 M solution

25

Serial dilutions

• Homogenous solutions uniform throughout

1.000 gram

of blue compound

in 1000.000 mL of water

1.000 mL

+ 999.000 mL

water

1.000 mL

+ 999.000 mL

water

1.000 mL

contains

0.0000000001000 grams

(1.000 nanogram)

of blue compound

0.001000 grams

of blue compound

in 1000.000 mL

compared to a scale

that is limited to

0.001 g ( 1 mg)

0.00000100 grams

of blue compound

in 1000.000 mL

Dilution Formula MconcVconc = MdilVdil

concentrated

stock solution

Mconc = 12.0 M HCl

1) add 10 ml

HCl stock

Vconc = 0.010 lit

water

2) add water to

500 ml mark Mconc x Vconc = # moles HCl

12 M x 0.010 lit

= 0.12 moles HCl

added

500 ml flask

# moles HCl = # moles HCl

taken from stock after adding water

Used to prepare a dilute solution

from a concentrated stock solution

Mdil = MconcVconc

Vdil

12 x 0.010

0.50 = M = 0.24 M adding water did not change # moles

HCl but it did change molarity of HCl

Vdil = 0.50 lit

Mdil = 0.24 M

added

26

2.5 liters

Water is added to 125.0 mL of a 0.66 M NaNO2 solution

until the volume of the solution is exactly 250 mL. What

is the concentration of the final solution?

27

A 35.2-mL, 1.66 M KMnO4 solution is mixed with 16.7

mL of 0.892 M KMnO4 solution. Calculate the

concentration of the final solution.