Upload
paul-compton
View
29
Download
3
Embed Size (px)
DESCRIPTION
The waves spread out from the opening!. 5. Diffraction 1) What it is? The bending of waves behind obstacles or apertures into the ”shadow region”, that can be considered as interference of many waves. 2) Haw to observe? - PowerPoint PPT Presentation
Citation preview
The waves spread out from
the opening!
5. Diffraction1) What it is? The bending of waves behind obstacles or apertures into the ”shadow region”, that can be considered as interference of many waves.
2) Haw to observe?Diffraction is most pronounced when the wavelength of the wave is similar to the size of the obstacle or aperture. For example, the diffraction of sound waves is commonly observed because the wavelength of sound is similar to the size of doors, etc.
•Light will diffract around a single slit or obstacle.•The resulting pattern of light and dark stripes on a screen is called a diffraction pattern (fringes).•This pattern arises because different points along a slit create wavelets that interfere with each other just as a double slit would.
1
3) Diffraction from a single slit
D/2
D/2
1r
2r
x
y
21
121 sin D
First minimum (dark):
1sinD
Minima (dark fringes):
,...3,2,1
sin
m
mD m tanxy
D
mm
sin tan smallFor
Dm
Dm
tot 2
D
mxm
y
2
Example: In order to obtain a good single slit diffraction pattern, the slit width could be:A. /100 ; B. /10; C. ; D. 10;
E.100
3a) Diffraction from a single slit (intensity)
Minima (dark fringes):
,...3,2,1
sin
m
mD m
Example: Light of wavelength 610 nm is incident on a slit 0.20 mm wide and the diffraction pattern is produced on a screen that is 1.5 m from the slit. What is the width of the central maximum?
mmm
m
mmy
D
mxym
2.91510.91020.0
106105.122 3
3
9
1
?2
5.1
20.0
610
1
y
mx
mmD
nm
Example: Light of wavelength 687 nm is incident on a single slit 0.75 mm wide. At what distance from the slit should a screen be placed if the second dark fringe in the diffraction pattern is to be 1.7 mm from the center of the screen?
mm
m
mmx
m
Dyx
D
mxy m
m
93.0687.02
75.07.1
106872
1075.0107.19
33
?
7.1
75.0
687
2
x
mmy
mmD
nm
4
4) Multiple slits (Diffraction grating)•A diffraction grating consists of a large number of equally spaced narrow slits or lines. •A transmission grating has slits, while a reflection grating has lines that reflect light.
•The more lines or slits there are, the narrower the peaks.
Two slits
Six slits
Parameters:
NdLdD
; ;
0 :for is This D5
The maxima of the diffraction pattern are defined by:
4a) Diffraction gratings and not monochromatic light
...2,1,0
sin
m
md m
4b) The Spectrometer and Spectroscopy
•A spectrometer makes accurate measurementsof wavelengths using a diffraction grating or prism.
•The wavelength can be determined to high accuracy by measuring the angle at which the light is diffracted.
•Atoms and molecules can be identified when they are in a thin gas through their characteristic emission lines.
Example: A diffraction grating has 5000 lines per cm. The angle between the central maximum and the fourth order maximum is 47.2°. What is the wavelength of the light?
?
4
2.47
1025000/1
//
4
4
1
m
cmcm
LNNLd
md m sin
md m /sin
nm
cm
367cm1067.3
4/2.47sin1025
4
Example: A diffraction grating has 6000 lines per centimeter ruled on it. What is the angular separation between the second and the third orders on the same side of the central order when the grating is illuminated with a beam of light of wavelength 550 nm?
?
550
106
6000/1
23
15
1
nm
m
cmd
dm
md
m
m
/sin
sin
6.40
66.0106105502sin
99.0106105503sin
23
1592
1593
mm
mm
7
5) Circular apertures. Limits of resolution
D 1sinThin slits:
Circular apertures: D 22.1sin 1
DR 22.1 1
Example: The Earth and Moon are separated by about 400x106 m. When Mars is 5x1010 m from Earth, could a person standing on Mars resolve the Earth and its Moon as two separate objects without a telescope? Assume a pupil diameter of 5 mm and λ = 550 nm.
?/
5
550
105
1040010
6
R
mmD
nm
mx
my
Dx
yR 22.1
yes!
1011.022.1105
1055022.122.1
108105
10400
33
9
310
6
R
R D
m
m
x
y
x
yRayleigh criterion: two images are just resolvable when the center of the diffraction disk of one image is directly over the first minimum in the diffraction pattern of the other
8