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C«ng nghÖ dËp nguéi

Ch ¬ng Ii

Söa tinh

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Ch­¬ng­Ii.­Söa­tinh­

2.1.­söa­tinh­theo­vong­ngoµi.2.1.1. Qu¸ tr×nh c¾t h×nh – söa

tinh.Qu¸­tr×nh­c¾t­h×nh­söa­tinh­bao­gåm:­C¾t­ph«i,­n¾n­ph«i,­®Æt­ph«i­vµo­khu«n,­c¾t­gät­söa­tinh.

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2.1.2. L îng d söa tinh.- L­îng­d­­®Ó­söa­tinh­(y)­®­îc­lÊy­®ång­®Òu­gi÷a­kÝch­th­íc­nhá­nhÊt­cña­ph«i­vµ­kÝch­th­íc­lín­nhÊt­cöa­s¶n­phÈm­sau­khi­söa­tinh.

- L­îng­d­­®Ó­söa­tinh­phô­thuéc­vµo­®é­sai­lÖch­vÒ­h×nh­d¹ng­cña­ph«i,­tr¹ng­th¸i­mÆt­c¾t­vÇ­ph­¬ng­ph¸p­®Æt­ph«i­vµo­khu«n­söa­tinh.­(®­îc­tra­trong­sæ­tay­dËp­nguéi).

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C¸c­trÞ­sè Khu«n­c¾t­h×nh Khu«n­söa­tinhSöa­tinh­1­lÇn Söa­tinh­

nhiÒu­lÇn

-KÝch­th­íc­cèi

-KÝch­th­íc­chµy-L­îng­d­­söa­tinh-L­¬ng­d­­tæng­céng

Dc=­D­+y­+­Zmin

Dch­=­D­+­y

­y­(tra­b¶ng)

∆­=­Zmin­+­y

Dc=­D­+n.y­+­Zmin

y­(tra­b¶ng)

∆­=­Zmin­+­y

Dc­=­Dmin

(D lµ kÝch th íc lín nhÊt cña s¶n phÈm sau khi söa tinh)

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2.1.3. Lùc söa tinh.-­Lùc­söa­tinhnhá­h¬n­so­víi­lùc­c¾t­kho¶ng­(30­–­40)%,­®­îc­tÝnh­theo­c«ng­thøc.

­­­­­­­­­­Ps = ∆. L. c.(1 + c) (kg)

- §èi­víi­khu«n­dËp­cèi­cã­v¸t­mÐp. Ps = ∆. L. c. k (kg)

Trong­®ã:­­∆ - lµ­l­îng­d­­tæng­céng­1­phÝa

­­­­­­­­­­­­­­­­­L­­-­lµ­chu­vi­s¶n­phÈm­­­­­­­­­­­­­­­­­c,­k­–­lµ­hÖ­sè­phô­thuéc­vµo­vËt­liÖu­cña­ph«i.

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2.1.4.­Khu«n­söa­tinh­vßng­ngoµi.

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2.1.5.­Söa­tinh­mÆt­ngoµi­b»ng­ph­¬ng­ph¸p­Ðp.

-­Sö­dông­®èi­víi­c¸c­s¶n­phÈm­nhá,­ph¼ng,­h×nh­d¸ng­phøc­t¹p,­cã­chiÒu­dµy­tõ­3­–­7­mm

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- Lùc­Ðp­®­îc­tÝnh­theo­c«ng­thøc­­­­­­­­­­­­­­­­­­­­­­­P­=­q.­F­­­(kg)Trong­®ã:­-­q­–­lµ­¸p­suÊt­Ðp­­§èi­víi­thÐp­mÒm,­®ång­q­=­35­–­45­­kg/mm2

­§èi­víi­thÐp­cøng­q­=­50­–­60­­kg/mm2

­­-­F­–­lµ­diÖn­tÝch­cña­ph«i­Ðp,­mm2.

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- L­îng­d­­trªn­mçi­nguyªn­c«ng­kh«ng­v­ît­qu¸­0.2­mm­vÒ­1­phÝa,­mÆt­c¾t­vu«ng­gãc­víi­mÆt­®Çu,­kh«ng­cã­vÕt­nøt,­ba­via.

- KÝch­th­íc­ph«i­®­îc­tÝnh­theo­c«ng­thøc:­­­­­­­­­­­­­­­Dp = D – 0.8∆ + Z + k (mm)

Trong­®ã:­D­–­lµ­kÝch­th­íc­danh­nghÜa­cña­s¶n­phÈm­∆­-­Dung­sai­theo­kÝch­th­íc­cña­s¶n­phÈm­Z­–­Khe­hë­gi÷a­chµy­vµ­cèi.­k­–­l­îng­d­­®Ó­Ðp.­­K­=­0,2­–­0,4­mm

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2.2.­söa­tinh­theo­lç.Dïng­®Ó­chÕ­t¹o­lç­chÝnh­x¸c­khi­chiÒu­dµy­vËt­liÖu­®Õn­3,5­mm.­­§é­chÝnh­x¸c­®¹t­0.01­–­0.03­mm,­®é­nh¸m­®¹t­cÊp­7­–­8.

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2.2.1. Qu¸ tr×nh söa tinh lç.

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2.2.2. L îng d ®Ó söa tinh lç.L­îng­d­­®Ó­söa­tinh­lç­®­îc­x¸c­®Þnh­theo­c«ng­thøc.

­­­­­­­­­­­­­­y1 = a + b (mm)

­­y1­lµ­l­îng­d­­®Ó­söa­tinh­lç

­­a­­hÖ­sè­kÓ­®Õn­¶nh­h­ëng­cña­ph­¬ng­ph¸p­gia­c«ng­lç­s¬­bé.­

­­b­­lµ­hÖ­sè­kÓ­®Õn­c¸ch­chän­chuÈn­khi­söa­tinh.

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2.2.3. Lùc söa tinh lç.Lùc­söa­tinh­lç­®­îc­x¸c­®Þnh­theo­c«ng­thøc.

c­-­lµ­hÖ­sè­phô­thuéc­vµo­vËt­liÖu­

)1.(..2

cLyZ

P cs

(kg)

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2.2.4. KÝch th íc chµy söa tinh lç.KÝch­th­íc­cña­chµy­söa­tinh­lç­®­îc­x¸c­®Þnh­theo­c«ng­thøc;

­­­­­­­dch = (d + ∆) + i mm

­d­–­lµ­kÝch­th­íc­nhá­nhÊt­cña­lç­sau­khi­söa­tinh.

∆­-­Dung­sai­chÕ­t¹o­lç­(dung­sai­trªn)­i­–­lµ­l­¬ng­co­cña­lç,­­mm­­­­§èi­víi­®ång­thau­i­=­0.005­–­0.01­mm­­­­­­­­­­­­­­­­­thÐp­mÒm­i­=­0.008­–­0.015­mm

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2.2.5. Söa tinh lç kh«ng phoi.

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