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Hadrons and Nuclei : Scattering
Lattice Summer SchoolLattice Summer School
Martin Savage
Summer 2007
University of Washington
Why Scattering with Lattice QCD ?
Reproducing what is known is important check of lattice QCD, but intrinsically not interesting----not new physics e.g. NN scattering at physical pion mass
Calculating quantities that cannot be determined (well) any other way is the underlying motivation e.g. YN scattering , nnn , weak-YN,
d¾d (mq)
Courtesy of W. Tornow,data from TUNL,calculations by
Present Nuclear Theory fails to Reproduce Precise expts (2)
p → KProduction)
p → p Scattering)
n → KProduction)
p → p Scattering)
Hyperon-Nucleon Scattering Experiments
Kozi Nakai (KEK)(talk given at Hypernuclear 2006 (Mainz))
Beam
SCITIC0
Production p Scattering
Production p Scattering
Hyperon-Nucleon Scattering Experiments Kozi Nakai (KEK)
susuu
Weak decay
Strong scatter
Neutron Stars (1)Why are we interested in scattering of
strange baryons (and mesons) ?
Supernova Remnant ? neutron stars or black holes ,or black holes ,
…….. kaon condensation , strange baryons ? ….... kaon condensation , strange baryons ? …..
Neutron Stars (2)
AtmosphereEnvelopeCrustOuter CoreInner Core
HomogeneousMatter
LasagnaNuclei +
Neutron superfluid
n-superfluid and p superconductor
Reddy and Pageastro-ph/0608360
Neutron Stars (3) : Hyperons in Neutron Matter
n
n
YN interactions shift the mass of Y in a neutron background
H » ®§ y§ nyn + M (0)§ § y§ + ::::
!³M (0)
§ + ®½n
´§ y§ + :::: Mean¡ Field
Neutron Stars (4)
Vacuum - Masses
With Interactions -- meson exchange model
WithOUT Interactions
We Need QCD Calculations to Improve upon Model Calcs
Reddy and Pageastro-ph/0608360
Low-Energy Scattering, Phase-Shifts and Scattering
Parameters (1)
Ã+ = ei kz + f (µ)ei kr
r
¾ =
Zd
d¾d =
Zd jf (µ)j2
f (µ) =1k
X
l
(2l +1) ei±l sin±l Pl(cosµ)
!1k
ei±0 sin±0 + ::: =1
kcot±0 ¡ ik
Analytic function of com energy
Review :
Low-Energy Scattering, Phase-Shifts and Scattering
Parameters (2)
kcot± = ¡ 1a
+ 12rk2 + :::
a = Scattering Length r = Effective Range
Can take any value Size dictated by range of interaction
Maiani-Testa no-go Theorem (1)
(s) ?
S-matrix elements cannot be extracted from infinite-volume Euclidean-space correlation functions except at kinematic thresholds.
Maiani-Testa no-go Theorem (2)j ppiout = Sy j ppi in
outhpp j ppi in = inhpp jSj ppi in
= ei2± (below inelastic thresholds)
Consider the Euclidean-space correlation function associated with a source J(x) that couples to two protons
GE (t1; t2;q) = h0j©q(t1)©¡ q(t2)J (0)j0i
J(0)
(s-wave to s-wave)
©q(t)
©¡ q(t)Interpolating fields
for proton
Maiani-Testa no-go Theorem (3)
This dominates at long times unless 2 Eq is equal to the minimum value of En
Away from Kinematic threshold…..cannot isolate S-matrix elements from Euclidean space correlators
h0jÁ(0;0)jpi =p
Z
©q =R
d3x e¡ iq¢x Á(x;t)
GE (t1;t2;q) = h0j©q(t1)©¡ q(t2)J (0)j0i
=Z
(2Eq)2e¡ E q (t1+t2 ) [ R (J ) + 2Eq Pq(J ;t2) ]
R (J ) =12
( outhppjJ (0)j0i + inhppjJ (0)j0i )
Pq(J ;t2) = PX
n
hpqj©¡ q(0)jniconnout outhnjJ (0)j0ie¡ (E n ¡ 2E q )t2
Maiani-Testa no-go Theorem (4)
R(J ) =12
( outhppjJ (0)j0i + inhppjJ (0)j0i )
= jouthppjJ (0)j0i j cos±
GM (t1; t2; q) =Z
(2Eq)2e¡ iE q (t1+t2 )
outhppjJ (0)j0i
=Z
(2Eq)2e¡ iE q (t1+t2 ) jouthppjJ (0)j0i jei±
In Minkowski space 2EqPq(J ;t2) !
12
( outhppjJ (0)j0i ¡ inhppjJ (0)j0i )
Luscher (1)
Compute something else !!!! Work in finite-volume and look at energy-levels
Non-Relativistic QM analysis = Lee + YangE (j )
0 = h0(0)j V j0(j ¡ 1) i ;
J-th order g.s. energy-shift
Unperturbed g.s. wavefunction
J-th order contribution to g.s. wavefunction
Lee + Yang (2)
k =2¼L
n
n = (nx;ny;nz)
hrjki =1
L3=2ei k¢r
hr1;r2jk;¡ ki =1L3
eik¢(r1¡ r2)
Periodic B.C. give r ! r + mL
Lee + Yang (3) : Energies
V = ´ ±3(r1 ¡ r2)
¢ E0 = E (1)0 + E (2)
0 + :::
=´L3
2
4 1 ¡´M4¼2L
X
n6=0
1jnj2
+ :::
3
5
Lee + Yang (4) : Threshold Scattering
V = ´ ±3(r1 ¡ r2)
f = ¡¹2¼
Zd3r V(r) ¡
¹ 2
¼
Zd3r1
Zd3r2 V(r1) G+(r1;r2)V(r2) + :::
= ¡¹ ´2¼
+¹ 2´2
¼
Zd3p
(2¼)3
1jpj2 + i²
+ :::: = a
´ = ¡4¼aM
·1 ¡ 4¼a
Zd3p
(2¼)3
1jpj2 + i²
+ :::¸
Lee + Yang (4) : Combining
V = ´ ±3(r1 ¡ r2)
¢ E0 = ¡4¼aM L3
2
4 1 +³ a
¼L
´0
@¤ jX
n6=0
1jnj2
¡ 4¼¤ j
1
A + :::
3
5
Luscher (5) : True in QFT !!Below Inelastic thresholds and lattices L >> R
UV regulator
Measure on lattice
S(x) = lim¤ j ! 1
¤ jX
j
1jj j2 ¡ x2
¡ 4¼¤j
pcot ±(E ) =1
¼LS
µpL2¼
¶
Luscher (6) : Methodology?
(x,t)
(y,t)
source
G(0;0)2 (t)
hG(0)
1 (t)i 2 ! e¡ (E 2¡ 2M )t
G(p1=0;p2=0)2 (t) =
Zd3x
Zd3y G2(y;t;x;t;0;0) ! A2 e¡ E 2t
G(p=0)1 (t) =
Zd3x G1(x;t;0;0) ! A1 e¡ M t
Luscher (7) : Methodology?
G(0;0)2 (t)
hG(0)
1 (t)i 2 ! e¡ (E 2¡ 2M )t
T = E2 ¡ 2M = 2p
q2 + M 2 ¡ 2M
pcot ±(T) =1
¼LS
µqL2¼
¶
Many-Bosons (1)
3-boson interaction
E0(n;L) =
4¼aM L3
nC2
(
1¡³ a
¼L
´I +
³ a¼L
´2 £I 2 +(2n ¡ 5)J
¤
+³ a
¼L
´3 h¡ I 3 ¡ (2n ¡ 7)I J ¡
¡5n2 ¡ 41n +63
¢K ¡ 8(n ¡ 2)(2Q +R)
i)
+nC364¼a4
M L6(3
p3¡ 4¼) log(¹ L) +n C2
8¼2a3
M L6r +n C3
´3(¹ )L6
+O¡L ¡ 7
¢:
numbers
3-Bosons (1)
E0(3;L) =12¼aM L3
(
1¡³ a
¼L
´I +
³ a¼L
´2 £I 2 + J
¤
+³ a
¼L
´3 h¡ I 3 +I J + 15K ¡ 8(2Q +R)
i)
+64¼a4
M L6(3
p3¡ 4¼) log(¹ L) +
24¼2a3
M L6r
+1L6
´3(¹ ) + O¡L ¡ 7
¢
I=2 Simplest hadronic scattering process
Physics Wise Computationally
C(t) =G(0;0)
2 (t)hG(0)
1 (t)i 2 !
A2
A21
e¡ (E 2¡ 2M )t
log·
C(t)C(t + 1)
¸
! E2(t) ¡ 2M = T(t) = 2p
q2(t) + M 2 ¡ 2M
pcot±(T(t)) =1
¼LS
µq(t)L2¼
¶
I=2 Beane et al, arXiv:0706.3026
m¼ aI =2¼¼ = ¡
m2¼
8¼f 2¼
(
1+m2
¼
16¼2f 2¼
"
3logµ
m2¼
¹ 2
¶¡ 1 ¡ lI =2
¼¼ (¹ )
#)
(2007)
Lattice m/f is the way to go
m¼aI =2¼¼ = ¡
m2uu
8¼f 2
(
1+m2
uu
(4¼f )2
"
4lnµ
m2uu
¹ 2
¶
+ 4~m2
j u
m2uu
ln
Ã~m2
j u
¹ 2
!
¡ 1+ 0¼¼(¹ )
#
¡m2
uu
(4¼f )2
"~¢ 4
j u
6m4uu
+~¢ 2
j u
m2uu
·ln
µm2
uu
¹ 2
¶+1
¸ #
+~¢ 2
j u
(4¼f )20P Q (¹ ) +
a2
(4¼f )20a2 (¹ )
)
:
Two-flavor mixed-action Chen, O’Connell, Walker-Loud
m¼aI =2¼¼ = ¡
m2¼
8¼f 2¼
(
1 +m2
¼
(4¼f ¼)2
·3ln
µm2
¼
¹ 2
¶¡ 1 ¡ lI =2
¼¼ (¹ ) ¡~¢ 4
j u
6m4¼
¸)
Kand KK Scattering
Lattice QCD + Chiral Symmetry
b = 0.125 fm
(S. Beane, P. Bedaque, T. Luu, K. Orginos, E. Pallante, A.Parreno, mjs)
K+ + K+ K+
Baryon Potentials from LQCD
Why bother with the scattering amplitude…just calculate the potential,and use that in the Schrodinger equation !!!
h0jO1(x;t0)i®O1(y;t0)
j¯ jÃ0i = Z(S;I )
N N (jrj) h0jN (x;t0)i®N (y;t0)
j¯ jÃ0i + :::
O1(x;t)i® = ²abc qi ;c
®
¡qa;T C°5¿2qb
¢(x;t)
GN N (x;y;t) = h0jO1(x;t)i®O1(y;t)j
¯ J (0)j0i
=X
n
h0jO1(x;0)i®O1(y;0)j
¯ jÃn ihÃn jJ (0)j0ie¡ E n t
2En
Baryon Potentials from LQCD (2)
• Potential between two infinitely massive mesons is well-defined• e.g. B-mesons in the HQ limit – E = V(R)• r is a constant of the motion
UE (r) = E +12¹
r 2GN N
GN N
12¹
r 2GN N + UE (r) GN N = E GN N
trivially
1 ] Energy-dependent potential…i.e. each different energy requires a different potential….not as useful as it first sounds !!!
2 ] NOT unique … only constrained to reproduce ONE quantity …. ( E0 )
Q Q Q QDirect
Exchange
BB t-channel Potentials ... Insight into NN ?
B B
B B
¼ ¼¼
B-meson has I = 12 ; sl = 1
2
Quenched Potential : Hairpins
No strong anomaly´0 is also a pseudo-Goldstone boson
G´´ (q2) =i
(q2 ¡ m2¼+ i²)
+i(M 2
0 ¡ ®©q2)(q2 ¡ m2
¼+ i²)2
V (Q)(r) =1
8¼f 2¾1 ¢r ¾2 ¢r
µg2
A¿1 ¢¿2
r+ g2
01¡ ®©
r¡ g2
0M 2
0 ¡ ®©m2¼
2m¼
¶e¡ m¼r
Dominates at long-distances
Nucleons on the Lattice
~
¾x =
phG2i ¡ hGi2
hGi ! e(M N ¡ 32 m¼)t
3 ¼
Mesons are easy, Nucleons are hardand two nucleons are even harder !!!
G.P. Lepage, Tasi 1989
Large Scattering Lengths are OK !
Require : L >> r0
but ANY a
M = 350 MeV 2.5 fm lattices... YESTERDAY !!
M = 350 MeV 2.5 fm lattices... TODAY !!
NN on the Lattice
~E L2
~E L2
Deuteron1st continuum
1st continuum2nd continuum
(S. Beane, P. Bedaque, A.Parreno, mjs)
Effective Field Theory Calculation at Finite-Volume
NN Correlators
1S0
3S1 - 3D1
G
Fully-Dynamical QCDDomain-Wall Valence on rooted-Staggered Sea
Cn Exp[-En t]nC0 Exp[-E0 t]
NN Scattering (S. Beane, P. Bedaque, K. Orginos, mjs ; PRL97, 012001 (2006))
1S0 : pp , pn , nn 3S1-3D1 : pn : deuteron
a ~ 1/m
Scale-Invariance
NN is Fine-Tuneda1S0
np = ¡ 23:710§ 0:030fm ; r1S0np = +2:73§ 0:03
a3S1np = +5:432§ 0:005fm ; r3S1
np = +1:73§ 0:02
a >> r
Hyperon-N Interactions(S.Beane, P.Bedaque, T.Luu, K.Orginos, E.Pallante, A.Parreno, mjs , 2006)
|k| = 261 MeV |k| = 179 MeV
|k| = 255 MeV |k| = 169 MeV
Luscher Relation -- revisited
pcot ±(E ) =1
¼LS
µpL2¼
¶
V = 0 ! a = r = :::: = 0
S(´) = 1
Non-interacting particlesk =
2¼L
n
n = (nx;ny;nz)
T < 0 T > 0 Bound-state or Scattering state ?
Bound states are also described !!
° + pcot ±jp2=¡ ° 2 = 0
E ¡ 1 = ¡°2
M
·1 +
12°L
11¡ 2°(pcot ±)0
e¡ ° L + :::¸
pcot±(E ) =1
¼LS
µpL2¼
¶(S. Beane, P. Bedaque, A.Parreno, mjs)
Bound States vs Scattering States (1)
L = 200 b 1/r = M = 350 MeVa = 10, 5, 1, -1, -5, -10 fm
( )P L 2
2
p cot
´ =
b = 0.125 fm
Bound States
Bound States vs Scattering States (3)
L = 20 b 1/r = M = 350 MeVa = 10, 5, 1, -1, -5, -10 fm
( )P L 2
2
p cot
´ << ´0 ! most probably a bound state
´0´ =
NN Resource Requirementswith Current AlgorithmsNN Scattering Length fixed at 2 fm
for demonstrative purposes
Domain-Wall Propagator Generation ONLY !!
Does not include time for lattice generation
Contractions Usually
Lattice generation > propagator generation > contractions
Not so for nuclear physics
Need high statistics .. Many propagators per lattice
Large number of quarks in initial and final states
contractions » u! d! s!
= (A +Z)! (2A ¡ Z)! S!
P roton : N cont: = 223592 U : N cont: = 101494
nnn
Important for neutron rich nuclei Lattice calc. is not as easy as
Cannot have all at rest as they are fermions
Closing Remarks on Scattering
Two hadron scattering can be studied with lattice QCD by studying the energy eigenstates at finite-volume
Simplest system well-understood
Baryon-baryon systems still very primitive ..
a lot of room for improvement and contribution