SOLUCIONES Guía de Ejercicios pH

Embed Size (px)

Citation preview

  • 8/2/2019 SOLUCIONES Gua de Ejercicios pH

    1/7

    Universidad Tecnolgica Metropolitana

    Qumica Industrial

    Qumica General II

    1

    SOLUCIONES Gua de Ejercicios de pH

    1. Cul es el pH de 250 mL de:a) KOH 0.45 M

    pOH = log OH pH = 14 pOH

    pOH = log 0.45 pH = 14 0.34

    pOH = 0.34 pH = 13.66

    b) Ca(OH)2 0.078 M

    +2

    20.078 M 2 0.078 M0.078 M

    0.156 M

    Ca(OH) Ca 2 OH

    pOH = log OH pH = 14 pOH

    pOH = log 0.156 pH = 14 0.80

    pOH = 0.80 pH = 13.20

    c) HClO4 0.068 M

    +pH = log H

    pH = log 0.068

    pH = 1.16

    d) HNO3 0.045 M

    +pH = log H

    pH = log 0.045

    pH = 1.34

    2. Cul es el pH de 300 mL de:a) CH3COOH 0.066 M

    5

    aK 1.75 10

    3 3

    3

    e e a

    3

    CH COOH CH COO H

    0 0 0

    0.066 M

    CH COO HK K K

    CH COOH

    Si

    Sf x x x

    25

    6 2

    6

    3

    1.75 10 0.066

    1.155 10

    1.155 10

    1.07 10 M

    x

    x

    x

    x

    x

    +

    3

    pH = log H

    pH = log 1.07 10

    pH = 2.97

  • 8/2/2019 SOLUCIONES Gua de Ejercicios pH

    2/7

    Universidad Tecnolgica Metropolitana Dallits Sagredo Oyarce

    Qumica Industrial

    Qumica General II

    2

    b) HNO2 0.68 M4

    aK 4.5 10

    2 2

    2

    e e a

    2

    HNO H NO

    0 0 0

    0.68 M

    H NOK K K

    HNO

    Si

    Sf x x x

    24

    4 2

    4

    4.5 100.68

    3.06 10

    3.06 10

    0.017 M

    x

    x

    x

    x

    x

    +pH = log H

    pH = log 0.017

    pH = 1.76

    c) NH3 0.024 M5

    bK 1.8 10

    4 4

    4

    e e b

    4

    NH OH NH OH

    0 0 0

    0.024 M

    NH OHK K K

    NH OH

    Si

    Sf x x x

    25

    7 2

    7

    4

    1.8 100.024

    4.32 10

    4.32 10

    6.57 10 M

    x

    x

    x

    x

    x

    4

    pOH = log OH pH = 14 pOH

    pOH = log 6.57 10 pH = 14 3.18

    pOH = 3.18 pH = 10.82

  • 8/2/2019 SOLUCIONES Gua de Ejercicios pH

    3/7

    Universidad Tecnolgica Metropolitana Dallits Sagredo Oyarce

    Qumica Industrial

    Qumica General II

    3

    3. Cul es el pH de 100 mL de solucin que tiene disuelto:a) 0.7 mL de HCl gm m mL32 % 1,19

    33

    1.19 gc 32 gp0.83 gc 0.26 gp

    1 mL 0.7 mL 100 gc 0.83gc

    1 mol 7.12 10 moles7.12 10 moles 0.0172 M

    36.5 g 0.26 gp 100 mL 1000 mL

    x x

    x x

    +pH = log H

    pH = log 0.0172

    pH = 1.76

    b) 0.4 g de NaOH, de un m m90 %

    3

    3

    90 gp 1 mol0.36 gp 9 10 moles

    100 gc 0.4 gc 40 g 0.36 gp

    9 10 moles0.09 M pOH = log OH pH = 14 pOH

    100 mL 1000 mL

    pOH = log 0.09 pH = 14 1.04

    pOH = 1.04 pH = 12.96

    x x

    x

    c) 0.8 mL de NH3 5gm m mL b62 % 0.9 K 1.8 10

    0.9 gc 62 gp0.72 gc 0.44 gp

    1 mL 0.8 mL 100 gc 0.72gc

    1 mol 0.025 moles0.025 moles 0.25 M

    17 g 0.44 gp 100 mL 1000 mL

    x x

    x x

  • 8/2/2019 SOLUCIONES Gua de Ejercicios pH

    4/7

    Universidad Tecnolgica Metropolitana Dallits Sagredo Oyarce

    Qumica Industrial

    Qumica General II

    4

    4 4

    4

    e e b

    4

    NH OH NH OH

    0 0 0

    0.25 M

    NH OHK K K

    NH OH

    Si

    Sf x x x

    25

    6 2

    6

    3

    1.8 100.25

    4.5 10

    4.5 10

    2.12 10 M

    x

    x

    x

    x

    x

    3

    pOH = log OH pH = 14 pOH

    pOH = log 2.12 10 pH = 14 2.67

    pOH = 2.67 pH = 11.33

    d) 1.4 mL de CH3COOH 5gm m mL a90 % 1.09 K 1.75 10

    1.09 gc 90 gp1.52 gc 1.36 gp

    1 mL 1.4 mL 100 gc 1.52gc

    1 mol 0.02 moles0.02 moles 0.2 M

    60 g 1.36 gp 100 mL 1000 mL

    x x

    x x

    3 3

    3

    e e a

    3

    CH COOH CH COO H

    0 0 0

    0.2 M

    CH COO HK K K

    CH COOH

    Si

    Sf x x x

    2

    5

    6 2

    6

    3

    1.75 100.2

    3.5 10

    3.5 10

    1.87 10 M

    xx

    x

    x

    x

    +

    3

    pH = log H

    pH = log 1.87 10

    pH = 2.72

  • 8/2/2019 SOLUCIONES Gua de Ejercicios pH

    5/7

    Universidad Tecnolgica Metropolitana Dallits Sagredo Oyarce

    Qumica Industrial

    Qumica General II

    5

    4. Cul es la M de una solucin de:a) HCl de pH = 3.7 4H 1.99 10 M

    b) HNO3 de pH = 2.5 3H 3.16 10 M

    c) KOH de pH = 13.2

    pOH = 14 pH

    pOH = 14 13.2

    pOH = 0.8

    OH 0.15M

    d) NaOH de pH = 12.8

    pOH = 14 pH

    pOH = 14 12.8

    pOH = 1.2

    OH 0.063M

    e) NH3 de pH = 8.35

    bK 1.8 10

    6

    pOH = 14 pH

    pOH = 14 8.3

    pOH = 5.7

    OH 1.99 10 M

    4 4

    6 6

    4

    e e b

    4

    NH OH NH OH

    1.99 10 M 1.99 10 M

    NH OH

    K K KNH OH

    Sf x

    2

    6

    5

    12

    45

    7

    4

    1.99 101.8 10

    3.96 10NH OH

    1.8 10

    NH OH 2.2 10 M

    x

    x

  • 8/2/2019 SOLUCIONES Gua de Ejercicios pH

    6/7

    Universidad Tecnolgica Metropolitana Dallits Sagredo Oyarce

    Qumica Industrial

    Qumica General II

    6

    f) CH3COOH de pH = 4.95

    aK 1.75 10

    5H 1.25 10 M

    3 3

    5 5

    3

    e e a

    3

    CH COOH CH COO H

    1.25 10 M 1.25 10 M

    CH COO HK K K

    CH COOH

    Sf x

    2

    5

    5

    10

    35

    6

    3

    1.25 101.75 10

    1.56 10CH COOH

    1.75 10

    CH COOH 8.91 10 M

    x

    x

    5. Cul es la concentracin:a) v v% de 300 mL de solucin que tiene disuelto 2 mL de etanol

    v v

    2 mL EtOH

    0.66 %300 mL soluc 100 mL soluc

    x

    b) m v% de 200 mL de agua que disuelve 0.4 g de NaNO3

    3 mv

    0.4 g NaNO0.19 %

    200.4 mL soluc 100 mL soluc

    x

    c) m m% de 1200 g de solucin que tiene disuelto 30 g de CuSO4

    4 m

    v

    30 g CuSO

    2.5 %1200 g soluc 100 g soluc

    x

  • 8/2/2019 SOLUCIONES Gua de Ejercicios pH

    7/7

    Universidad Tecnolgica Metropolitana Dallits Sagredo Oyarce

    Qumica Industrial

    Qumica General II

    7

    6. Cul es el pH de una mezcla:a) 200 mL HCl 0.035 M + 300 mL de HCl 0.066 M

    0.035 moles 0.007 moles HCl1000 mL 200 mL

    x 0.066 moles 0.0198 moles HCl1000 mL 300 mL

    x

    0.007 moles HCl + 0.0198 moles HCl = 0.0268 moles HCl

    200 mL solucin + 300 mL solucin = 500 mL solucin

    +

    0.0268 moles HCl0.053 M

    500 mL 1000 mL

    pH = log H

    pH = log 0.053

    pH = 1.27

    x

    b) 48 mL NaOH 0.1 M + 100 mL NaOH 0.5 M + 50 mL de agua

    0.1 mol0.0048 moles NaOH

    1000 mL 48 mL

    x

    0.5 moles0.05 moles NaOH

    1000 mL 100 mL

    x

    2

    0.0048 moles NaOH + 0.05 moles NaOH = 0.0548 moles NaOH

    48 mL solucin + 100 mL solucin + 50 mL H O = 298 mL solucin

    0.0548 moles NaOH0.18 M

    298 mL 1000 mL

    pOH = log OH pH = 14 pOH

    pOH = log 0.18 pH = 14 0.74

    pOH = 0.74 pH = 13.26

    x