Thevenin and Norton Theorems

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    Thevenin Theorem in Sinusoidal Steady Analysis

    Aim: To obtain a simple equivalent circuit for a 1-port circuit thatconsists of linear, time-invariant resistors, capacitors, inductorsand independent sources.

    Thevenin Equivalent:

    +

    _v

    i

    1-port

    circuit

    +

    _V

    I

    +_

    ZTH

    VTH

    ZTh Thevenin impedance

    Equivalent impedance between terminalswhen sources are set to zero.

    VTh Open circuit voltage

    THThVIZV

    The voltage of the port when the port isleft as open circuit.

    Thevenin Theorem insinusoidal steadyanalysis: A 1-port circuitthat consists of linearresistor, capacitor,

    inductors andindependent sources hasa Thevenin equivalentcircuit in sinusoidalsteady state if the port

    voltage phasor can beuniquely determined for agiven port currentphasor, in other words, ifthe 1-port is current-controlled.

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    Norton Theorem in Sinusoidal Steady Analysis

    Aim: To obtain a simple equivalent circuit for a 1-port circuit thatconsists of linear, time-invariant resistors, capacitors, inductorsand independent sources.

    Norton Equivalent:

    +

    _v

    i

    1-port

    circuit

    Norton Theorem insinusoidal steadyanalysis: A 1-port circuitthat consists of linearresistor, capacitor,

    inductors andindependent sources hasa Norton equivalentcircuit in sinusoidalsteady state if the port

    current phasor can beuniquely determined for agiven port voltage phasor,in other words, if the 1-port is voltage-controlled.

    NNIVGI

    +

    _V

    I

    YNIN

    GN Norton conductance

    IN Short circuit current

    Equivalent conductance betweenterminals when sources are set to zero.

    The current through the port when the

    port is short-circuited.

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    How to obtain Thevenin equivalent circuit?

    +

    _

    V

    I

    1-portcircuit

    Connect a sinusoidal current source to the port.

    I*V*

    +

    _ Solve the circuit using sinusoidal steady analysis

    and obtain a relation between phasors I* and V*.

    Use I=I* and V=-V* to obtain a relationbetween I and V.

    +

    _V

    I

    1-portcircuit

    Set the values of independent sources tozero.

    Calculate the equivalent impedance ZTh = V / I. Assume that I=0 (open-circuit the port) and

    calculate Vth=V taking into account allindependent sources .

    There exist two methods for this!

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    How to obtain Norton equivalent circuit?

    Connect a sinusoidal voltage source to the port. Solve the circuit using sinusoidal steady analysis

    and obtain a relation between phasors I* and V*.

    Use I=-I* and V=V* to obtain a relationbetween I and V.

    +

    _V

    I

    1-portcircuit

    Set the values of independent sources tozero.

    Calculate the equivalent admitance GN = I / V. Assume that V=0 (short-circuit the port) and

    calculate IN=I taking into account allindependent sources .

    There exist two methods for this!

    +

    _

    V

    I

    1-portcircuit

    I*

    V*

    +

    _

    +-

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    Thevenin Equivalent: THTH VIZV

    If 1-port is not current-controlled there is no Thevenin eq..

    Norton Equivalent:NNIVYI

    If 1-port is not voltage-controlled there is no Norton eq..

    0THZTH

    TH

    THZ

    VVZ

    I 1 ,0THZ No Norton equivalent!

    ,0NY No Thevenin equivalent!

    NY

    NI

    0NYN

    N

    NY

    II

    YV

    1

    THV

    THZ

    Interchange between Thevenin and Norton

    From Thevenin to Norton:

    From Norton to Thevenin:

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    Example 1: Find the Thevenin equivalent circuit for the following circuit!

    Example 2: Find the Norton equivalent circuit for the following circuit! Check your answercomparing it to Example 1.

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    Circuit(Network) Functions in Sinusoidal SteadyAnalysis

    +

    _E1

    IS

    linear,time-

    independentelements

    0

    0

    )()(0

    000

    s

    d

    TI

    I

    VV

    jwNjwM

    IAA

    )(jwT

    How does Vdk affect Is ? Depending on w!

    Ssk

    d IwT

    wTcofactorwV

    k )(det

    )()( ,

    Assume that

    there is only one

    source.

    0

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    +

    _E1

    IS

    )(

    )()(

    jwQ

    jwP

    I

    wV

    S

    dk

    )(jwP are polynomials

    in (jw) with real coefficients.)(jwQ

    m

    m

    n

    n

    S

    d

    jwbjwbjwb

    jwajwajwa

    I

    wVk

    )(...)()(

    )(...)()()(2

    21

    2

    21

    This depends on thecircuit but not on thevalue of Is .

    linear,time-

    independentelements

    Circuit(Network) Functions in Sinusoidal SteadyAnalysis

    How does Vdk affect Is ? Depending on w!

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    One can define many other circuit functions:

    )(

    )(

    wI

    wV

    s

    dk Impedance Function

    )(

    )(1

    wI

    wV

    s

    Input Impedance Function

    )(

    )(

    1 jwV

    jwVkd Voltage Transfer Function

    )()(

    jwIjwI

    s

    k Current Transfer Function

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    Symmetries of Circuit Functions

    Lemma: Let be a polynomial in complex variable s withreal coefficients.

    1)

    2) (z is called as a root of n(z).)

    jwssn ),(

    )()( snsn

    0)(0)( znzn

    Proof: 011

    1 ...)( nsnsnsnsnk

    k

    k

    k

    Rnnnn

    kk

    011 ,,...,

    1) ...)( 0111 nsnsnsnsnk

    k

    k

    k

    01

    1

    1... nsnsnsn

    k

    k

    k

    k

    01

    1

    1... nsnsnsn

    k

    k

    k

    k

    )(sn

    2) 00)(0)( znzn

    0)(0)()()( znznznznFrom (1)

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    Circuit function: )(

    )(

    )( jwd

    jwn

    jwH

    )(

    )()(jwHj

    ejwHjwH

    Symmetry Property: The magnitude of any circuit function is an evenfunction of w and its phase is an odd function of w.

    Proof:

    )()()(

    jwdjwnjwH

    )()()(

    jwdjwnjwH

    )()(

    jwdjwn

    jwjw and from Lemma)(

    )()(

    jwd

    jwnjwH

    )( jwH

    )()()()( jwHjwHjwHjwHw

    Since the phase of is .z z )()( jwHjwH

    Theorem: For a circuit in sinusoidal steady state, any circuit function is

    well-defined and is the ratio of two polynomials in (jw) with real

    coefficients if det(T(jw)) is nonzero.

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    +_ Vs (t) 1-portcircuit

    so VjwHV )(

    Result:In order to find the behaviour of the circuit for the frequency w, one

    should find and .sVjwH ,)( sVjwH

    ),(

    sVj

    ss eVV

    oVj

    oo eVV

    sV

    s

    jwH

    o eVejwHV

    )()(

    sVjwH

    so

    eVjwHV

    )(

    )(

    so VjwHV )( so VjwHV )(

    sso VjwHwtVjwHtv )(cos)(