PERCUBAAN SPM 2011 NEGERI TERENGGANU
MATHEMATICS PAPER 2SECTION B
1449/2
PANITIA MATEMATIK SMSTSP 2011
12(a) Xx 1.5 2 3 4 6 8 10 12 14
y 16 12 8 6 4 3 2.4 2 1.7
√ K1 √ K1 (b). graph
(c). (i) 6.5 ≤ x ≤ 6.9
√ P1 axes drawn in corect direction, uniform scale √ K2 * 9 points correctly plotted * curve passes trough all 9 points √ N1 *smooth continous curve
without any straight line using the given scalar.
√ p1 (c). (i) 8.55 ≤ y ≤ 8.59 √ p1
(d). y = -x +13
(b). graph
y = -x +13 √ K1 straight line corectly drawn
√ K1 corect equation of straight line
2.0 ≤ X1 ≤ 2.4 10.8 ≤ X1 ≤ 11.0 √ N1 √ N1
Q13. (a) (i) ( 0, 5 )
(ii) (3, 6)
√ P1
√ P2
(b) (i) T = Rotation, 900 anti clockwise, centre ( 0, 0 )
√ P3 S = Enlargement, scale factor of 2, centre ( 0, -1 ) √ P3
(c) Area JHKL = (2)2 X 7 √ K2
= 28 unit2 √ N1
Score Frequency Midpoint
10 – 19 3 14.5
20 – 29 6 24.5
30 – 39 10 34.5
40 – 49 15 44.5
50 – 59 12 54.5
60 – 69 9 64.5
70 – 79 5 74.5
Q14. (a)
√ P1 √ P1
(b) (i) 40 - 49 √ P1(b) (ii) √ K2
= 46.83 √ N1
freq
uenc
y
14.5 44.534.524.5 74.564.554.5
√ P1 axes drawn in corect direction, uniform scale √ K2 * 7 bars correctly drawn
* curve passes trough all 9 points √ N1 *smooth continous clines using the given scalar.
Q15. (a) plan
6 cm
3 cm
√ K1 Correct shape with rectangle ABCD, all solid lines.√ K1 AB > CB√ N1 measurement correct to ± 0.2 cm (one way) and all angles <A , <B, <C, <D. = 90° ± 1°
(b) (i)
6 cm
8 cm
√ K1 Correct shape with triangle BCF and trapezium HIML. All solid lines.
√ K1 BC = HI < HL< IM
√ N2 measurement correct to ± 0.2 cm (one way) and all angles <B , <H, <I, <C. = 90° ± 1°
(b) (ii) 5 cm
7 cm
8 cm2 cm
4 cm
√ K1 Correct shape with rectangle JINM and CDEF , all solid lines.
√ K1 CH < CF = FK < AB < FE < MI√ N2 measurement correct to ± 0.2 cm (one way) and all angles <A, <B , < C, <H, <I, <J. = 90° ± 1°
√ K1 dotted line KG
Q16 (a)
PQ√ P1
R
R = ( 60°S, 160 )
√ P1
√ P2
(b) θ X 60 = 60 X 60
3600 n.m√ K1
√ N1(c) (i) speed = distance / time
√ K1√ N1
(c) (ii) Distance of parallel of latitiude = 3600 n.m
θ = 120°
Longitude T = 120º - 20º = 100º W
√ K2
√ K1√ N 1